Hello,
I am attempting to utilize the 'alabama' package to solve a constrained
nonlinear optimization problem.
The problem has both equality and inequality constraints (heq and hin
functions are used). All constraints are smooth, i.e. I can differentiate
easily to produce heq.jac and hin.jac
I am using PAM with k = 10 clusters, but I only get one cluster ID for all my
observations. I couldn't find any discussion about this in the help file, or
mailing lists.
Is there a reasonable explanation for this result ?
cIDs - pam(all, 10, cluster.only = TRUE, do.swap = FALSE)
table(cIDs)
#Hi all,
#Using the example data that follows, can someone please show me how to get
a scatterplot of points with #error bars in the Y direction. something like
this works for one Y:
xYplot(Cbind(y1, l1, u1) ~x1, data=y)
#but this:
xYplot(Cbind(y1, l1, u1) + Cbind(y2, l2, u2)~x1, data=y)
#
Dear all,
I have made couple logistic regressions, what making a distribution of some
event.
Currently, i store it like this:
o1 - lrm(...)
o2 - lrm(...)
o3 - lrm(...)
...
Then, i have made a function to peak required regression object from this
variables by it number:
get_object -
Dear Lists,
What is the appropriate software package for dumping say 20 PDFS in a
folder, then creating data visualization with frequency counts of
certain words as well as measure correlation within each file for
certain key relationships or key words.
I am doing text analysis of biases in
I have a problem with duplicated date_time stamps that I do not see as
duplicated.
I read a file with observations taken every 30 minutes:
aur2009=read.csv(paste(datadir,AUR_ECPP_2009.csv,sep=/),sep=;,stringsAsFactors=F)
aur2009[1:3,1:5]
Date.Time E_filled E_filled_flag LE_filled
See under Note in ?strptime:
Remember that in most timezones some times do not occur and some
occur twice because of transitions to/from summer time.
âstrptimeâ does not validate such times (it does not assume a
specific timezone), but conversion by âas.POSIXctâ) will do
Amit Patel amitrh...@yahoo.co.uk writes:
BHPLS1 - plsr(GroupingList ~ PCIList, ncomp = 10, data = PLSdata, validation
=
LOO)
and
BHPLS1 - plsr(GroupingList ~ PCIList, ncomp = 10, data = PLSdata, validation
=
CV)
[...]
Now I am unsure of how to utilise these to identify the
Amit Patel amitrh...@yahoo.co.uk writes:
x - loadings(BHPLS1)
my loadings contain variable names rather than numbers.
No, they don't.
str(x)
loadings [1:94727, 1:10] -0.00113 -0.03001 -0.00059 -0.00734 -0.02969 ...
- attr(*, dimnames)=List of 2
..$ : chr [1:94727] PCIList1 PCIList2
Ajay Ohri wrote:
What is the appropriate software package for dumping say 20 PDFS in a
folder, then creating data visualization with frequency counts of
certain words as well as measure correlation within each file for
certain key relationships or key words.
pdftotext + Unix™ for Poets + R
Hi,
I would like to ask you how to read an arrary from an *.xlsm file? I have tried
different packages such as xlsReadWrite and RODBC. Everything is performed on
the final versions of addons and R.
Additionally, when I tried the RODBC received the following error:
library(RODBC)
con =
and is it not possible to ignore savings time? My data are in UTC,
with no savings time changes
delme = strptime(aur2009[,1], %m/%d/%Y %H:%M,tz=UTC)
any(duplicated(delme))
[1] TRUE
delme = as.POSIXct(aur2009[,1], %m/%d/%Y %H:%M,tz=UTC)
any(duplicated(delme))
[1] TRUE
Agus
On Wed, May 18,
Dear Augustin: What are the duplicated times? Looks they really do occur twice
or more in your original data: perhaps two stamps less time apart than the
resolution of your clock?
delme[duplicated(delme)]
aur2009[[duplicated(delme),1]
On 18 May 2011, at 8:49 AM, Agustin Lobo wrote:
and is it
Dear All,
I am documenting a R package. That means writing the *.Rd files inside the \man
folder of the package structure
I was wondering how to write the symbol for an integral function in a formula.
Similar to this one in LaTeX:
\int_{0}^{10} \Omega(t)dt
I already tried
\deqn{\int_{0}^{10}
Hello,
I have a few questions concerning the DCC-GARCH model and its programming in
R.
So here is what I want to do:
I take quotes of two indices - SP500 and DJ. And the aim is to estimate
coefficients of the DCC-GARCH model for them. This is how I do it:
library(tseries)
p1 =
Dear experts:
Is it possible to create a new function based
on stats:::model.matrix.default so that an alternative factor coding is used
when the function is called instead of the default factor coding?
Basically, I'd like to reproduce the results in 'mat' below, without having
to explicitly
See the section on writing Mathematics in Rd file in the manual Writing
R Extensions. This will show how to produce high quality formulas in
LaTeX generated output and ASCII versions otherwise.
If you want to provide an excellent HTML version as well, the section on
Conditional text is also
Hi Dmitrij,
I think the usual way is to store the results in a list:
o - list()
o[[1]] - lrm(...)
o[[2]] - lrm(...)
o[[...]] -lrm(...)
then you can access the results like 0[[1]], 0[[2]] ...
Best,
Ista
On Tue, May 17, 2011 at 11:53 PM, Dmitrij Kudriavcev
dimitrij.kudriav...@ntsg.lt wrote:
Dear all,
I have data organized in a way like this
Data[[CharacteristicsList1]][[CharacteristicsList2]][[CharacteristicsList3]][[CharacteristicsList4]]
where CharacteristicsList4 there is a DF stored with various columns of name
V1,V2, ... , Vn
Is there an easy way to get a vector of all the
Hello List,
I would like to insert code from .r files into a LaTeX appendix
(possibly using Sweave).
I was considering:
results=tex,eval=true,echo=true=
source(file.r)
@
but I would just like to echo the code and not evaluate the code within
the file.
maybe:
results=tex,eval=true,echo=false=
Dear R users,
I would like to announce that on the CRAN is now available a new package
(SamplingStrata version 0.9) for the optimal stratification of sampling frames.
This package offers an approach for the determination of the best
stratification of a sampling frame, the one that ensures the
Dear R-users,
I'm looking for a way to query the gene ontology in R like in the GO browser
(AmiGO). I tried different packages (NCBI2R, GOsim ...) but I did not find the
way to extract genes names associated to a GO term. Could you tell me if there
is a way to do that?
Thanks,
Hervé
On Wed, May 18, 2011 at 1:44 PM, Karl Ove Hufthammer k...@huftis.orgwrote:
Ajay Ohri wrote:
What is the appropriate software package for dumping say 20 PDFS in a
folder, then creating data visualization with frequency counts of
certain words as well as measure correlation within each file
You will find a wider and more experienced audience for this question
on the Bioconductor mailing list.
--
David
On May 18, 2011, at 5:14 AM, LEMAITRE Hervé Université Paris Sud wrote:
Dear R-users,
I'm looking for a way to query the gene ontology in R like in the GO
browser (AmiGO). I
LEMAITRE Hervé Université Paris Sud herve.lemaitre at cea.fr writes:
I'm looking for a way to query the gene ontology in R
like in the GO browser (AmiGO). I tried different
packages (NCBI2R, GOsim ...) but I did not find the way
to extract genes names associated to a GO term. Could
you
Brian Oney zenlines at gmail.com writes:
Hello List,
I would like to insert code from .r files into a LaTeX appendix
(possibly using Sweave).
I was considering:
[snip]
Wouldn't it be easier to use the LaTeX listings package?
On Wed, May 18, 2011 at 7:15 AM, Axel Urbiz axel.ur...@gmail.com wrote:
Dear experts:
Is it possible to create a new function based
on stats:::model.matrix.default so that an alternative factor coding is used
when the function is called instead of the default factor coding?
Basically, I'd
Thank you for your advice, Tim.
I am reading your paper and other materials in your website.
I could not find R package of your bootknife method. Is there any R
package for this procedure?
(11/05/17 14:13), Tim Hesterberg wrote:
My usual rule is that whatever gives the widest confidence
I've pratically resolved my problem (the code is under that), but a last thing
is not perfect:
when I use the function plot to call after the function polygon, there is a
marge between my raster and the window. I think it's the axis of the function
plot(), but I have not found how delete it.
Thanks.
I was exactly reading the manual Writing R Extensions, on section Mathematics.
Where, it informs about basic LaTeX style support.
However, It seems like it does not support the LaTeX integral symbol \int, but
it does support i.e.: the summation symbol \sum.
Has anyone had this
Thank you, Ista, that exactly, what i was looking for :)
Regards,
Dmitrij Kudriavcev
2011/5/18 Ista Zahn iz...@psych.rochester.edu
Hi Dmitrij,
I think the usual way is to store the results in a list:
o - list()
o[[1]] - lrm(...)
o[[2]] - lrm(...)
o[[...]] -lrm(...)
then you can access
On May 17, 2011, at 7:13 PM, Lara Poplarski wrote:
Thank you all, this is exactly what I had in mind, except that I
still have
to get my head around apply et al. Back to the books for me then!
Read the lapply( ...) call as:
For every element in the object named `data`, send that element
You may be looking for the par settings of xaxs=i, yaxs=i, which
if you add them to the plot call will prevent the regular behavior
of adding 4% padding to the axis widths.
?par
-- David.
On May 18, 2011, at 8:27 AM, Pierre Bruyer wrote:
I've pratically resolved my problem (the code is
Dear R help,
Apologies for the less than informative subject line. I will do my
best to describe my problem.
Consider the following matrix:
mdat - matrix(c(1,0,1,1,1,0), nrow = 2, ncol=3, byrow=TRUE,
dimnames = list(c(T1, T2),
c(sp.1, sp.2, sp.3)))
Hi,
I am wondering if there is a way to change the pattern of the fill in
histogram in ggplot2? By default the fill is solid and I'd like to add some
sort of pattern to make it more visible that these are different levels of a
factor.
Thanks!
Chris
[[alternative HTML version deleted]]
On 18/05/2011 9:09 AM, Javi Hidalgo wrote:
Thanks.
I was exactly reading the manual Writing R Extensions, on section Mathematics.
Where, it informs about basic LaTeX style support.
However, It seems like it does not support the LaTeX integral symbol \int, but
it does support i.e.: the
Thanks Bill. Do you and others think that a link to this guide (or
another)should be included in the Posting Guide and/or R FAQ?
-- Bert
On Tue, May 17, 2011 at 4:07 PM, bill.venab...@csiro.au wrote:
Amen to all of that, Bert. Nicely put. The google style guide (not perfect,
but a
This is the first time I've seen an R Style Guide. I will admit that I
haven't looked for one previously, but nevertheless I still haven't seen
one. My code style simply evolved (perhaps, chugged along) by reading posts
from other users who post to the r-help community.
I regularly program with
Hi I am running the following code:
sym - c(sym1,sym2,sym4)
lifedxm - c(O-BD,O-WELL,O-UNI)
life - c(lifedxm,lifedxm,lifedxm)
tp - c(TP-ANY,TP-ANY, TP-ANY, TP-SUB, TP-SUB, TP-SUB, TP-CLIN
, TP-CLIN, TP-CLIN)
data - data.frame(sym,life,tp)
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Lara Poplarski
Sent: Tuesday, May 17, 2011 4:14 PM
To: r-help@r-project.org
Subject: Re: [R] subsetting a list of dataframes
Thank you all, this is exactly what I had in
Hi, all
I would like to use R to perform k-means clustering on my data which
included 33 samples measured with ~1000 variables. I have already used
kmeans package for this analysis, and showed that there are 4 clusters in my
data. However, it's really difficult to plot this cluster in 2-D format
data$tp - factor(data$tp, levels = c(TP-ANY,TP-SUB,TP-CLIN))
qplot(life,geom=bar,weight=sym,ylim=c(0,1),legend=F,data=data) +
facet_grid(. ~ tp)
On Wednesday, May 18, 2011 at 9:14 AM, Christopher Desjardins wrote:
Hi I am running the following code:
sym - c(sym1,sym2,sym4)
lifedxm -
There are a number of discussion threads on the google groups ggplot2 page:
here are two of them.
http://groups.google.com/group/ggplot2/browse_thread/thread/ca546f7f4d636deb/e0763a54b7735c35?lnk=gstq=fill+pattern#e0763a54b7735c35
Hi,
I'm new to R, and I'm a bit confused with the convolve() function.
If I do:
x-c(1, 2, 3)
convolve(x, rev(x), TRUE, open)
= 9 12 10 4 1
But I expected: 3 8 14 8 3 (like in Octave/MATLAB - conv(x, reverse(x)) )
3 2 1 x 1 2 3
= 3 2 1
0 6 4 2
0 0 9 6 3
= 3 8 14 8 3
The thing is, that
Hi,
I'm a PhD student in Milan (Italy). I read the OBrienKaiser example in
?Anova in the car package. I think that this is not a Manova split-plot
design. I need to know if someone knows a R code for MANOVA split-plot. Is
there someone who can help me?
Thanks for kindness
Riccardo
--
View this
Hi,
I am trying to use the gbif function in the dismo package and it
does not seem to work. I get the same error message every time:
Error in if (sp) geo - TRUE : argument is not interpretable as logical
It does not matter whether I query for my species of interest or if I
copy and paste those
Thanks! This is what I was looking for.
Apparently, it is not supported then it should be as integral, but in the pdf
version appears the integral symbol.
Regards,
Javier.
Date: Wed, 18 May 2011 09:39:28 -0400
From: murdoch.dun...@gmail.com
To: havyhida...@hotmail.com
CC:
I wonder if it makes sense to reduce the dimensionality of the variables
somehow?
David Cross
d.cr...@tcu.edu
www.davidcross.us
On May 18, 2011, at 9:41 AM, Meng Wu wrote:
Hi, all
I would like to use R to perform k-means clustering on my data which
included 33 samples measured with
Hi all,
This is a very basic question, but I just can't figure out why R is handling
a loop I'm writing the way it is.
Here is the script I have written:
grid_2_series-function(gage_handle,data_type,filename)
series_name-paste(gage_handle,data_type,sep=_)
Can’t you just embed it in the html as a symbol?
#x222b; or int;
I’d have thought you also just put it into straight into the document as a
character – ∫– , as long as the html is stored as unicode
U+222B
http://en.wikipedia.org/wiki/Integral_symbol
On 18 May 2011, at 4:04 PM, Javi Hidalgo
On Wed, May 18, 2011 at 7:41 AM, Meng Wu mengwu1...@gmail.com wrote:
Hi, all
I would like to use R to perform k-means clustering on my data which
included 33 samples measured with ~1000 variables. I have already used
kmeans package for this analysis, and showed that there are 4 clusters in
Hi,
The answer to (2) is that num_obs is a scalar, so length(num_obs) is 1.
You probably wanted to do
for (i in 1:num_obs)
instead.
Best wishes
Martyn
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of armstrwa
Sent: 18 May 2011
I knew it would be something simple. Thanks for catching that, Martyn.
Billy
--
View this message in context:
http://r.789695.n4.nabble.com/Loop-stopping-after-1-iteration-tp3532988p3533041.html
Sent from the R help mailing list archive at Nabble.com.
On May 18, 2011, at 11:18 AM, armstrwa wrote:
Hi all,
This is a very basic question, but I just can't figure out why R is
handling
a loop I'm writing the way it is.
Here is the script I have written:
grid_2_series-function(gage_handle,data_type,filename)
William,
num_obs obviously isn't a vector, therefore length(num_obs) will
evaluate to one. Hence your for loop control part will expand to
for (i in 1:1)
while it should probably read:
for (i in 1:num_obs)
Best
Hugo
On Wednesday 18 May 2011 17:18:15 armstrwa wrote:
Hi
Hello, I'm looking for a dataset for Quasipoisson regression. The result must
be significantly different from the classic poisson regression.
You can help me?
Please It is for my last university exam
Thanks a lot
--
View this message in context:
How does this compare to create.post() ?
Kevin
On Tue, May 17, 2011 at 3:44 PM, Daniel Malter dan...@umd.edu wrote:
Hi all,
I thought I would post code to send an email out of R. The code uses
Grothendieck and Bellosta's interface package rJython for executing Python
from R. The code
Didn't mean to snub you guys, Hugo and David. I didn't see your posts
before. Thanks for the advice.
--
View this message in context:
http://r.789695.n4.nabble.com/Loop-stopping-after-1-iteration-tp3532988p3533217.html
Sent from the R help mailing list archive at Nabble.com.
Hi, I am trying to run a simple logistic regression using lrm() to calculate a
odds ratio. I found a confusing output when I use summary() on the fit object
which gave some OR that is totally different from simply taking
exp(coefficient), see below:
When I run the code below on Macintosh and Windows, the plot comes out
fine. However, on Linux, the png generated is invalid from R console,
and loading strucchange crashes rkward. Is this a known issue on Linux
and, if so, is there a workaround? Many thanks!
require(strucchange)
data(RealInt)
I do not know. I was not aware and could hardly find any information on
create.post(). From what I have seen at first glance, it seems that
create.post() either opens your standard email program or web browser, which
the python code does not. Instead it needs the R-library interfacing Python.
I
Hi Meng,
I would like to use R to perform k-means clustering on my data which
included 33 samples measured with ~1000 variables. I have already used
kmeans package for this analysis, and showed that there are 4 clusters in my
data. However, it's really difficult to plot this cluster in 2-D
One idea: Pick the three largest clusters, their centers determine a plane.
project your data into that plane.
albyn
On Wed, May 18, 2011 at 06:55:39PM +0200, Claudia Beleites wrote:
Hi Meng,
I would like to use R to perform k-means clustering on my data which
included 33 samples
Why is a one unit change in x an interesting range for the purpose of
estimating an odds ratio?
The default in summary() is the inter-quartile-range odds ratio as clearly
stated in the rms documentation.
Frank
array chip wrote:
Hi, I am trying to run a simple logistic regression using lrm()
It's perfect, thank you!
I would like post the final code if someone need help in this subject, but I
try to correct
a last problem, how can I constrain the contourLines() function to take the
corner points of the map in his result ... it does not consider this point like
a contour point.
Le
Hello R-help
Below is the output from the predict() function. How can I assign $y to a
variable.
predict(function,df2)
$x
V1
1 36.28
2 34.73
3 33.74
4 69.87
5 58.88
6 89.44
7 43.97
8 41.94
9 33.34
10 38.47
11 35.16
12 42.94
13 46.76
14 53.24
15 52.43
16 50.40
17
I'm having difficulty overlaying maps when writing to a file graphics
device. My command sequence has the structure
plot(map1)
par(new = T)
plot(map2)
On the screen device, it works fine. When I attempt something like
png(file = map.png)
plot(map1)
par(new = T)
plot(map2)
dev.off()
only the
In case you're using Unix/Linux, have a look at
www.r-project.org/doc/Rnews/Rnews_2007-1.pdf
(page 30 - 32)
Wolfgang
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
Wolfgang Raffelsberger, PhD
IGBMC,
1 rue Laurent Fries, 67404 Illkirch Strasbourg, France
Tel (+33) 388
Hi, Im using R (TM package) for text mining and Im having problems
filtering articles out of my data set by local meta data.
Here is the code:
*data - (C:/
/19970331)*
* *
* *
*rs - ReutersSource(data , encoding = UTF-8)*
*RC - VCorpus(DirSource(data), readerControl = list(reader =
On Wed, 18 May 2011, Hasan Diwan wrote:
When I run the code below on Macintosh and Windows, the plot comes out
fine. However, on Linux, the png generated is invalid from R console,
and loading strucchange crashes rkward.
I can replicate nothing of this. I ran the script both in a plain R
While doing pls I found the following problem
BHPLS1 - plsr(GroupingList ~ PCIList, ncomp = 10, data = PLSdata, jackknife
=
FALSE, validation = LOO)
when not enabling jackknife the command works fine, but when trying to enable
jackknife i get the following error.
BHPLS1 -
I guess what you want is cat(readLines(file.r), sep = \n)
Regards,
Yihui
--
Yihui Xie xieyi...@gmail.com
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State University
2215 Snedecor Hall, Ames, IA
On Wed, May 18, 2011 at 4:03 AM, Brian Oney zenli...@gmail.com wrote:
Hi Peter,
Thanks for your help. A second simple question that I cannot solve is the
following.
labels = cutree(hc, h=500)
# members of cluster 1:
x[labels==1]
# members of cluster 2:
x[labels==2]
When x is = 8 the index numbers appear in the output:
[['[1]', '180066408', '180066464',
Hi,
I am trying to produce a grouped bar plot from a data.frame and I'm
having difficulties figuring out how to do so. My data is 500 rows by
4 columns and basically looks like so:
head(x)
V1V2V3V4
1 XOM 0.2317915 0.1610068 1.6941637
2 AAPL 0.6735488 0.7433611
Hi everyone,
I have a dataset of friendship with this format:
ego alter
47461 2
97421 3
14738 1NA
47472NA
974323
14739 21
4748313
97443 5
14740 314
47494NA
97454NA
14741 4NA
47505NA
9746513
1) This mailing list is not for homework.
2) I would recommend reading the introduction to R that comes with
every installation of R, since your answer is in there. Alternatively,
you could google R and quasi poisson.
On Wed, May 18, 2011 at 11:42 AM, ilpoeta84 antonioperfe...@gmail.com wrote:
Greetings,
I'm trying to simply reorder a data frame on the row numbers. So, for
example, instead of getting 1,2,3,4,5,6,7,8,9,10,11, ... 100 ..., I get
instead
1, 10, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 11, ... I've
tried commands such as
df - df[order(rownames(df)),] and
It looks like your row numbers are characters because that is the
sort sequence you are getting. Try
df - df[order(as.numeric(rownames(df))), ]
On Wed, May 18, 2011 at 2:42 PM, David Kaplan
dkap...@education.wisc.edu wrote:
Greetings,
I'm trying to simply reorder a data frame on the row
That did it. Thanks!!
David
===
David Kaplan, Ph.D.
Professor
Department of Educational Psychology
University of Wisconsin - Madison
Educational Sciences, Room, 1082B
1025 W. Johnson Street
Madison, WI 53706
email:
Hello,
I want to build a function to call up a column of a data.frame by the names of
the columns. I have column names that are sequentially named (col1, col2,
etc.). How do I change a character expression into something that will be
understood as a data.frame column. For example:
On May 18, 2011, at 1:35 PM, Asan Ramzan wrote:
Hello R-help
Below is the output from the predict() function. How can I assign $y
to a
variable.
Newvar - predict(function,df2)$y
--
David.
$x
V1
1 36.28
2 34.73
3 33.74
4 69.87
5 58.88
6 89.44
7 43.97
8 41.94
9
On May 18, 2011, at 3:12 PM, John Poulsen wrote:
Hello,
I want to build a function to call up a column of a data.frame by
the names of the columns. I have column names that are sequentially
named (col1, col2, etc.). How do I change a character expression
into something that will be
On 2011-05-18 12:12, John Poulsen wrote:
Hello,
I want to build a function to call up a column of a data.frame by the names of
the columns. I have column names that are sequentially named (col1, col2,
etc.). How do I change a character expression into something that will be
understood as a
On 2011-05-18 11:13, jctoll wrote:
Hi,
I am trying to produce a grouped bar plot from a data.frame and I'm
having difficulties figuring out how to do so. My data is 500 rows by
4 columns and basically looks like so:
head(x)
V1V2V3V4
1 XOM 0.2317915 0.1610068
On Wed, May 18, 2011 at 2:38 PM, Peter Ehlers ehl...@ucalgary.ca wrote:
On 2011-05-18 11:13, jctoll wrote:
Hi,
I am trying to produce a grouped bar plot from a data.frame and I'm
having difficulties figuring out how to do so. My data is 500 rows by
4 columns and basically looks like so:
Using my mind-reading skills, plot.Map(), while deprecated, does provide an
add= option.
If this doesn't help, you'll need to read the posting guide and provide (a lot)
more
information.
Ray Brownrigg
On Thu, 19 May 2011, michael.laviole...@dhhs.state.nh.us wrote:
I'm having difficulty
The following works to get an igraph object from a matrix edgelist:
dat2 - matrix(rep(seq(1,5,1), 4), nrow=10, ncol=2)
graph.edgelist( dat2 )
I tried with NA's but graph.edgelist did not allow NA's. Wouldn't you just
leave those rows out with NA's in them? An NA means there is no edge, right?
Hello,
I would like some help figuring out how to run
Covariable Logistic Regression in R. I've been searching for a while on how
to get this done in R (I have had the luck previously of using a software
package that just does it) and I am coming up empty handed. Any experience
or insights would
On May 18, 2011, at 15:47 , Alex Hofmann wrote:
Hi,
I'm new to R, and I'm a bit confused with the convolve() function.
If I do:
x-c(1, 2, 3)
convolve(x, rev(x), TRUE, open)
= 9 12 10 4 1
But I expected: 3 8 14 8 3 (like in Octave/MATLAB - conv(x, reverse(x)) )
3 2 1 x 1 2 3
= 3 2
If you plot:
df-data.frame(x=factor(1:100),y=rnorm(1000))
ggplot(df,aes(x=x,y=y))+geom_boxplot()
How do I remove those pesky margins on the sides of the plot area? Or
maybe just reduce their size to something more like the spacing of the
boxes?
Thanks,
Justin
Is this what you want? You can control how much space you
want to see on the sides of the plot:
df-data.frame(x=factor(1:100),y=rnorm(1000))
ggplot(df,aes(x=x,y=y))+geom_boxplot() + scale_x_discrete(expand=c(0,0))
Felipe D. Carrillo
Supervisory Fishery Biologist
Department of the Interior
US
Exactly!
Thanks, I couldn't find that anywhere!
On Wed, May 18, 2011 at 1:59 PM, Felipe Carrillo
mazatlanmex...@yahoo.com wrote:
Is this what you want? You can control how much space you
want to see on the sides of the plot:
df-data.frame(x=factor(1:100),y=rnorm(1000))
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How about reading the posting guide and afterwards searching the list
archive:
http://r.789695.n4.nabble.com/R-help-f789696.html
Searching for
Error: cannot allocate vector of size
will give you hundreds of results as this question is asked VERY frequently!
Jannis
On 05/18/2011 07:55
On 05/16/2011 06:18 PM, adele_thomp...@cargill.com wrote:
Re-sizing within the dev command works well. I'm not sure why I would need the
dev.off(). I have the plot commands run. Then I have the dev.copy2pdf command.
Thanks again for your help.
Well, you really should get into the habit of
First of all, use the correct terminology for the statistical method.
It is not productive to identify 'significant' genes unless you use quite
complex methods. This kind of endeavor would take at least 6 statistics
courses in order to be successful.
Frank
Anamaria Crisan wrote:
Hello,
I
I've never used an R command without reading the documentation first. I think
that would be impractical. I am not an expert at deciphering the documentation
though and I post here because I did in fact read the documentation, do
extensive google searches, ask friends/collegues and still find no
Hi Bert,
I think people should know about the Google Sytle Guide for R because, as I
said, it represents a thoughtful contribution to the debate. Most of its
advice is very good (meaning I agree with it!) but some is a bit too much (for
example, the blanket advice never to use S4 classes and
Apologies for continuing to ask about this but . . in my quest to fit a
gamma GLMM model to my data (see partial copy of thread below), I'm
exploring using hglm today. The question of the day has to do with the
errors I'm currently getting from the hglm package. Can hglm handle a model
with
On 19/05/11 10:26, bill.venab...@csiro.au wrote:
SNIP
Most of [the Google style guide's] advice is very good (meaning I agree with
it!) but some is a bit too much (for example, the blanket advice never to use
S4 classes and methods - that's just resisting progress, in my view).
SNIP
I must
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