Hi,
On Mon, Sep 12, 2011 at 1:51 AM, Noah Silverman noahsilver...@ucla.edu wrote:
Hi,
I want to store the output of my program to a file. However, With subsequent
runs of my code, I'd like to append to the same log file.
Currently, I'm using:
outfile - file(log.txt, open=w)
Ahhh,
Makes sense.
I was too busy scouring the help file command. Didn't think to look at cat().
Thanks!
--
Noah Silverman
UCLA Department of Statistics
8117 Math Sciences Building #8208
Los Angeles, CA 90095
On Sep 11, 2011, at 11:10 PM, Steve Lianoglou wrote:
Hi,
On Mon, Sep 12, 2011
I am using 'tm' package for text mining and facing an issue with finding the
frequently occuring terms. From the definition it appears that findFreqTerms
and minDocFreq are equivalent commands and both tries to identify the
documents with terms appearing more than a specified threshold. However, I
Thank you very much for the suggestion. And while I'm here, thank you for
vegan and the documentation that goes with it.
I tried ordilabel(pl$arrows) but the labels only seem to be in two
dimensions.
I'm not a skilled enough user of R to edit the ordixyplot function - so I'll
pass on that
appreciate!
The following is my codes.
library(quantmod)
Loading required package: Defaults
Loading required package: xts
Loading required package: zoo
Attaching package: 'zoo'
The following object(s) are masked from 'package:base':
as.Date
Loading required package: TTR
If the answer is so obvious, could somebody please spell it out?
On Sep 11, 10:59 pm, Jason Edgecombe ja...@rampaginggeek.com wrote:
Try this:
http://cran.r-project.org/web/views/MachineLearning.html
On 09/11/2011 12:43 PM, Jay wrote:
Hi,
I used the rseek search engine to look for
li li-13 wrote:
Dear all,
Can anyone take a look at my program below?
There are two functions: f1 (lambda,z,p1) and f2(p1,cl, cu).
I fixed p1=0.15 for both functions. For any fixed value of lambda (between
0.01 and 0.99),
I solve f1(p1=0.15, lambda=lambda, z)=0 for the corresponding
R-help is all about solving R problems.
So here ya go:
http://www.portfolioprobe.com/2011/09/12/solve-your-r-problems/
--
Patrick Burns
pbu...@pburns.seanet.com
twitter: @portfolioprobe
http://www.portfolioprobe.com/blog
http://www.burns-stat.com
(home of 'Some hints for the R beginner'
and 'The
Dear R experts,
Suppose I have an data frame likes this:
example - data.frame(age=c(1,2,3, 4,5,6), height=c(100,110,120,130,140,150),
disease=c(TRUE, TRUE, TRUE, FALSE, FALSE, FALSE))
example
age height disease
1 1100TRUE
2 2110TRUE
3 3120TRUE
4 4130
Hello all,
Good day,
I have problem on how to remove the source code from the pdf output.Here I mean
this.
code in sweave Rnw files
=
x-c(1,2,3,4,5,6)
x
mean(x)
sd(x)
@
then would like it appear as
mean = 3.5
sd=1.3
x=1,2,3,4,5,6
thank you in advance
I have data of the form
tC - textConnection(
Subject Dateparameter1
bob 3/2/99 10
bob 4/2/99 10
bob 5/5/99 10
bob 6/27/99 NA
bob 8/35/01 10
bob 3/2/02 10
steve 1/2/99 4
steve 2/2/00 7
steve 3/2/01 10
steve 4/2/02 NA
steve 5/2/03 16
kevin 6/5/04 24
On Sep 12, 2011, at 09:41 , Patrick Burns wrote:
R-help is all about solving R problems.
So here ya go:
http://www.portfolioprobe.com/2011/09/12/solve-your-r-problems/
Grin.
Incidentally, I don't think it is quite true that I called you that infernal
guy at useR. I might have done so
Hi Steven:
How about this?
d - rep(20110101,24)
h - sprintf('%04d', seq(0, 2300, by = 100))
df - data.frame(LST_DATE = d, LST_TIME = h, data = rnorm(24, 0, 1))
df - transform(df, datetime = as.POSIXct(paste(LST_DATE, LST_TIME),
format = '%Y%m%d %H%M'))
library(zoo)
X
On Mon, Sep 12, 2011 at 9:41 AM, Patrick Burns pbu...@pburns.seanet.com wrote:
R-help is all about solving R problems.
So here ya go:
http://www.portfolioprobe.com/2011/09/12/solve-your-r-problems/
Sweet. :)
May I suggest a font change: anything but the default CM should do the
trick. For one
http://cran.r-project.org/web/views/
Look for 'machine learning'.
Dennis
On Sun, Sep 11, 2011 at 11:33 PM, Jay josip.2...@gmail.com wrote:
If the answer is so obvious, could somebody please spell it out?
On Sep 11, 10:59 pm, Jason Edgecombe ja...@rampaginggeek.com wrote:
Try this:
Dear Tom,
I think you failed to generate simulated outcome from the correct model. Hence
the zero variance of your random effects. Here is a better working example.
library(lme4)
fake2 - expand.grid(Bleach = c(Control,Med,High), Temp =
c(Cold,Hot), Rep = factor(seq_len(3)), ID = seq_len(8))
On Mon, Sep 12, 2011 at 9:21 AM, Twaha Mlwilo uddessy2...@hotmail.com wrote:
Hello all,
Good day,
I have problem on how to remove the source code from the pdf output.Here I
mean this.
code in sweave Rnw files
=
x-c(1,2,3,4,5,6)
x
mean(x)
sd(x)
@
then would like it appear as
Hello,
I have a time-series that has some missing samples.
I was thinking on completing them using either zero-order hold or linear
interpolation.
I am looking for an efiicient way (other than a loop...) of identifiying the
missing time slots and filling them.
Can you think of any methods that
Hi:
Here's one approach:
# date typo fixed in record 5 - changed 35 to 5
tC - textConnection(
Subject Dateparameter1
bob 3/2/99 10
bob 4/2/99 10
bob 5/5/99 10
bob 6/27/99 NA
bob 8/5/01 10
bob 3/2/02 10
steve 1/2/99 4
steve 2/2/00 7
steve 3/2/01 10
steve
Far be it from me to misquote someone.
On 12/09/2011 09:17, peter dalgaard wrote:
On Sep 12, 2011, at 09:41 , Patrick Burns wrote:
R-help is all about solving R problems.
So here ya go:
http://www.portfolioprobe.com/2011/09/12/solve-your-r-problems/
Grin.
Incidentally, I don't think it is
Please quote the prior thread, otherwise readers of this mailing list
will not get the context.
Uwe Ligges
On 12.09.2011 01:41, Briony wrote:
Thank you very much for the suggestion. And while I'm here, thank you for
vegan and the documentation that goes with it.
I tried
On Mon, Sep 12, 2011 at 1:58 AM, steven mosher mosherste...@gmail.com wrote:
I have date data as a numeric and hourly data in 0 to 2300 hours in a
dataframe.
d - rep(20110101,24)
h - seq(from = 0, to = 2300, by = 100)
df - data.frame(LST_DATE = d, LST_TIME = h, data =
Hi!
Try something like this:
subset(example, disease==TRUE)
subset(example, disease==FALSE)
On Mon, Sep 12, 2011 at 4:54 AM, C.H. chainsawti...@gmail.com wrote:
Dear R experts,
Suppose I have an data frame likes this:
example - data.frame(age=c(1,2,3, 4,5,6),
On 12.09.2011 13:16, Raphael Saldanha wrote:
Hi!
Try something like this:
subset(example, disease==TRUE)
subset(example, disease==FALSE)
Hmmm, I think the actual answer to the question is something along this
line:
sapply(example[names(example)!=disease],
function(x) t.test(x ~
On Mon, Sep 12, 2011 at 3:42 AM, marcel marcelcur...@gmail.com wrote:
I have data of the form
tC - textConnection(
Subject Date parameter1
bob 3/2/99 10
bob 4/2/99 10
bob 5/5/99 10
bob 6/27/99 NA
bob 8/35/01 10
bob 3/2/02 10
steve 1/2/99 4
steve
Dear Ehsan,
the cluster option is not implemented in 'eha', although you obviously get
no error if trying
I'll fix this. Thanks for the report. (So, use 'coxph' with cluster).
Göran
On Mon, Sep 12, 2011 at 4:43 AM, Ehsan Karim wilds...@hotmail.com wrote:
Sorry: there was an error in the
Thank you very much for the suggestion. And while I'm here, thank you for
vegan and the documentation that goes with it.
Function ordiplot3d uses scatterplot3d, and it returns also all
scatterplot3d items, like functions xyz.converter and points3d that
can be used for tuning labels.
I tried
In my mind this sequential classification task with feedback is
somewhat different from an completely offline, once-off,
classification. Am I wrong?
However, it looks like the mentality on this topic is to refer me to
cran/google in order to look for solutions myself. Oblivious I know
about these
Szeptember 12-től 26-ig irodán kívül vagyok, és az emailjeimet nem érem el.
Sürgős esetben kérem forduljon Kárpáti Edithez (karpati.e...@gyemszi.hu).
Üdvözlettel,
Mihalicza Péter
I will be out of the office from 12 till 26 September with no access to my
emails.
In urgent cases please contact
Hello,
I'd like to generate automatically all the possible combinations of a set of 8
variables (there are 535, too many to do it by hand). For example:
input: varA, varB, varC
output: varA+varB+varC
varA+varB
varA+varC
varB+varC
varA
How can I display a heatmap.2 with a column dendrogram without reordering
neither column or row?
library(vegan)
dissimilaritymatrix-data.matrix(vegdist(step3,method=bray))
library(gplots)
heatmap-heatmap.2(dissimilaritymatrix,dendrogram=column,Colv=T,
Rowv=F,key=TRUE, symkey=FALSE,
How can I display a heatmap.2 with a column dendrogram without reordering
neither column or row?
library(vegan)
dissimilaritymatrix-data.matrix(vegdist(step3,method=bray))
library(gplots)
heatmap-heatmap.2(dissimilaritymatrix,dendrogram=column,Colv=T,
Rowv=F,key=TRUE, symkey=FALSE,
A very basic query
This code plots OK the axis values are in bold but the axis labels are
not. how do I get them in bold too?
thanks
Nevil Amos
plot(c(1,1),xlim=c(0,450),ylim=c(0.7,1.4),xlab=Distance (cells) from
edge of grid,ylab=Resistance distance,
Hi!
How can I make a PerMANOVA in R comparing treatments in a matrix that looks
something like this:
Treatment 1 Treatment 2 Treatment 3
Species 1 0.6
0.2 0
Species 2 0
0.7 0.3
Species
Good afternoon,
After cuting a hierarchical tree using cutree(), how to check correspondances
between classes and branches?
This is what we do:
srndpchc - hclust(dist(srndpc$x[1:1000,1:3]),method=ward) #creation of
hierarchical tree
plclust(srndpchc,hmin=2) #visualisation
srndpchc2 =
one option is the following:
varNames - c(varA, varB, varC, varD)
f - function (i) {
combn(length(varNames), i,
function (x) paste(varNames[x], collapse = + ))
}
lapply(seq_along(varNames), f)
However, in case you're interested in performing a linear regression
with these
On Mon, Sep 12, 2011 at 4:59 AM, Laurent Fernandez Soldevila
l.fernand...@yahoo.fr wrote:
Good afternoon,
After cuting a hierarchical tree using cutree(), how to check correspondances
between classes and branches?
This is what we do:
srndpchc -
On 12.09.2011 12:30, Nevil Amos wrote:
A very basic query
This code plots OK the axis values are in bold but the axis labels are
not. how do I get them in bold too?
Add
font.lab=2
Uwe Ligges
thanks
Nevil Amos
plot(c(1,1),xlim=c(0,450),ylim=c(0.7,1.4),xlab=Distance (cells) from
edge
Thank you for your help
Yes i wanted to do the t test for all columns except for the grouping
column.
2011/9/12 Uwe Ligges lig...@statistik.tu-dortmund.de
On 12.09.2011 13:16, Raphael Saldanha wrote:
Hi!
Try something like this:
subset(example, disease==TRUE)
subset(example,
Hi,
Is there any function or command in R that show that how many times a
number is repeated in an array?
Regards,
Amir
--
___
Amir Darehshoorzadeh |Comp. Architecture Dept.
PhD Student |UPC-Campus Nord, C6-221
On 12/09/2011 9:03 AM, amir wrote:
Hi,
Is there any function or command in R that show that how many times a
number is repeated in an array?
?table
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the
On 09/12/2011 04:28 PM, vioravis wrote:
I am using 'tm' package for text mining and facing an issue with finding the
frequently occuring terms. From the definition it appears that findFreqTerms
and minDocFreq are equivalent commands and both tries to identify the
documents with terms appearing
Try this
ltr-LETTERS[1:3]
unique(apply(expand.grid(ltr,ltr,ltr),1,function(x)
paste(Var,unique(sort(x)),collapse=+,sep=)))
[1] VarA VarA+VarB VarA+VarC VarA+VarB+VarC VarB
VarB+VarC VarC
Andrej
--
Andrej Blejec
National Institute of Biology
Vecna pot 111
On 09/11/2011 03:42 PM, Jay wrote:
What R packages are available for performing classification tasks?
That is, when the predictor has done its job on the dataset (based on
the training set and a range of variables), feedback about the true
label will be available and this information should
dev.new(width=6, height=1.5,mar=c(0,0,0,0))
par(mfrow=c(1,1),mar=c(.5, .5, 1.5, .5), oma=c(.4, 0,.5, 0))
barplot(c(1,1,1,1,1,1),col=c(blue,purple,red,green,orange,yellow),
axes = FALSE)
I have a barplot that returns six colors in a line. I would like to get the
same six color blocks in a hexagram
I'm not sure this is the right location (maybe R-devel would be better).
-
In theory, practice and theory are the same. In practice, they are not - Albert
Einstein
--
View this message in context:
http://r.789695.n4.nabble.com/barplot-in-hexagram-layout-tp3807600p3807608.html
Sent from the
I've created a chart with times that employees have entered data on named tasks
as in the following example:
Employee - c(rep(Tom, 127),
rep(Dick, 121),
rep(Sally, 130)
)
Time - c(seq(as.POSIXct(2011-09-12 07:00:00), as.POSIXct(2011-09-12
14:00:00), 200),
seq(as.POSIXct(2011-09-12 07:00:00),
Hello , I have estimated the following model, a sarima:
p=9
d=1
q=2
P=0
D=1
Q=1
S=12
In R 2.12.2
Call:
arima(x = xdata, order = c(p, d, q), seasonal = list(order = c(P, D, Q),
period = S),
optim.control = list(reltol = tol))
Coefficients:
ar1 ar2 ar3 ar4 ar5
Gabor.. thanks.
zr - zooreg(rnorm(24), as.chron(2011-01-01), frequency = 24)
a couple issues: my date data has missing days and missing hours..
Sorry if I was not clear on
that.. I input it to a data frame and dates are of the form 20110101
and hours are in the format
0,100,200
The end goal
I would be grateful if anyone could tell me what the error message:
Error in NN[i, 1:length(od)] - od : subscript out of bounds
means for a large .csv file containing gps coordinates. I am using package
SPACECAP and have successfully run it with other .csv files but now keep
getting this error
Hello dear members,
I need to calculate by hand a local lineal regression so I need to compute a
kernel weight.
Does somebody knows how to get a kernel to use as weighted? I can calculate a
density kernel function and after pre-multiply it by the sample size. However I
know this is not
Hi
I need to use rep() to get a vector out, but I have spotted something very
strange. See the reproducible example below.
N - 79
seg - 5
segN - N / seg # = 15.8
d1 - seg - ( segN - floor(segN) ) * seg
d1# = 1
rep(2, d1) # = numeric(0), strange - why doesn't it
Hi,
On Mon, Sep 12, 2011 at 11:07 AM, vkent vivien.k...@gmail.com wrote:
I would be grateful if anyone could tell me what the error message:
Error in NN[i, 1:length(od)] - od : subscript out of bounds
It means that either i ends up being larger than the number of rows in
NN, or that
Hi all,
I have a time series a column vector with the ordered data so that the first
column is the first observation and so on.
The fact is that I want to run a multiple regression with only intercept.
My first task is to run the regression on the first observation (1 from 276)
and at the same
On Mon, Sep 12, 2011 at 11:57 AM, steven mosher mosherste...@gmail.com wrote:
Gabor.. thanks.
zr - zooreg(rnorm(24), as.chron(2011-01-01), frequency = 24)
a couple issues: my date data has missing days and missing hours..
Sorry if I was not clear on
that.. I input it to a data frame and
Dear Martin Morgan and Martin Maechler...
Here is an example of the computational time when a slot of a S4 class is of
another S4 class and when it is just one object. I'm sending you the data
file.
Thank you!
Best regards,
André Rossi
Hello.
I need to generate, using R code, an excel file with multiple sheets,
I wonder if any of you know how to do so.
Thanks for the help
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
On Mon, 2011-09-12 at 03:24 -0700, Briony wrote:
Thank you very much for the suggestion. And while I'm here, thank you for
vegan and the documentation that goes with it.
Function ordiplot3d uses scatterplot3d, and it returns also all
scatterplot3d items, like functions xyz.converter and
On Sep 12, 2011, at 10:28 AM, Damian Abalo wrote:
Hello.
I need to generate, using R code, an excel file with multiple sheets,
I wonder if any of you know how to do so.
Thanks for the help
See the following:
R Data Import/Export Manual: http://cran.r-project.org/doc/manuals/R-data.html
Hi André...
On 09/12/2011 07:20 AM, André Rossi wrote:
Dear Martin Morgan and Martin Maechler...
Here is an example of the computational time when a slot of a S4 class
is of another S4 class and when it is just one object. I'm sending you
the data file.
Thank you!
Best regards,
André Rossi
I will try stacking 5 barplots (with 5 bars per plot) and somehow only
showing the middle bar for the top and bottom plots and the two end bars for
the two middle plots.
-
In theory, practice and theory are the same. In practice, they are not - Albert
Einstein
--
View this message in
Here is the new code. It works just like I wanted.
dev.new(width=6, height=6.5,mar=c(0,0,0,0))
par(mfrow=c(5,1),mar=c(.5, .5, 1.5, .5), oma=c(.4, 0,.5, 0))
barplot(c(1,1,1,1,1),col=c(white,white,red,white,white), axes =
FALSE,border=NA)
barplot(c(1,1,1,1,1),col=c(orange,white,white,white,yellow),
Not so strange, in fact this is FAQ 7.31, and has to do (as you guess)
with the way that computers store numbers.
You need to do as you did, and use round() or floor() or similar to
ensure that you get the results you expect.
Sarah
2011/9/12 Benjamin Høyer bdho...@gmail.com:
Hi
I need to use
worked beautifully.
Thanks.
On Mon, Sep 12, 2011 at 9:45 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Mon, Sep 12, 2011 at 11:57 AM, steven mosher mosherste...@gmail.com
wrote:
Gabor.. thanks.
zr - zooreg(rnorm(24), as.chron(2011-01-01), frequency = 24)
a couple issues: my
I updated the code as follows:
dev.new(width=2.5, height=3,mar=c(0,0,0,0))
par(mfrow=c(5,1),mar=c(.5, .5, 1.5, .5), oma=c(.4, 0,.5, 0))
barplot(c(1,1,1,1,1),col=c(white,white,red,white,white), axes =
FALSE,border=NA)
barplot(c(1,1,1,1,1),col=c(orange,white,white,white,yellow), axes
=
Go to your R session.
First off, tell the R-help list how you got your csv file into R as NN.
read.csv() ? read.table()?
Then tell us exactly what code you're using. Where did i come from?
Also type in exactly the commands I gave you (four lines), and share the
output with the R-help list.
Here is another approach. A linear regression with a single binomial predictor
will give the same results as a pooled t-test (if you insist on non-pooled then
use sapply as previously suggested). The lm function will do multiple
regressions if given a matrix as the y-variable, so you can do a
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Benjamin Høyer
Sent: Monday, September 12, 2011 6:19 AM
To: r-help@r-project.org
Cc: t...@novozymes.com
Subject: [R] 1 not equal to 1, and rep command
Hi
I need to use
Em 9/9/2011 14:32, array chip escreveu:
Thanks all again for the suggestions. I agree with Wolfgang that
mcnemar.test() is what I am looking for. The accuracy is the
proportion of correct diagnosis compared to a gold standard, and I am
interested in which diagnosis test is better, not particular
Marc's links lists many packages. Of those, I would recommend
XLConnect.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Marc Schwartz
Sent: Monday, September 12, 2011 12:53 PM
To: Damian Abalo
Cc: r-help
Subject: Re: [R] Writting
Luis Felipe Parra wrote:
and as you can see in the results some coefficients (for example ar2 and
ar8) are different in the different R versions. does anybody know what
might
be going on. Was there any change in the arima function between the two
versions?
You asked the same
I may be totally off base with this, but I'm wondering what exactly this
would suggest or why you want to do it. Specifically multiple regression
with only intercept -- how is it multiple if you don't have any regressors?
Furthermore, you want to run a regression on a single data point --
really?
Hi,
I am trying to learn to use ggplot2 for what I had hoped would be a
fairly simple task. I have a relatively small data.frame (100 by 4).
The first column contains symbols. The 2nd, 3rd and 4th columns
represent percentage weightings for each symbol using 3 different
methodologies. For
Hi all,
I have a dataframe that includes data on individuals that are distributed
across multiple rows. I have aggregated the data using ddply, but I have
columns in the original data frame that are factors ( such as sites A,
B, and C) that I would like to include in the new data frame. I have
Hello,
I am trying to port one of my plotting S+ functions to R and I am having
difficulties!!! I am including here only the troublesome code!
I first produce a barplot, saving the positions of the bar's centers.
par(mar = c(6.1, 5.1, 4.1, 4.1), mgp = c(3, 3.0, 0))
ticks.loc -
Setting par(usr=something) does not survive the creating of a new high level
plot. Using par(new=TRUE) is to be avoided if at all possible (it just leads
to problems like yours), it would be better for you to use matlines instead of
matplot which adds lines to the current plot.
If you want to
I am using the package SPACECAP which provides an interface for R. I used
this interface to import the csv file into R as well as the other two csv
files that are required.
This is the output I get when querying the error message
Error in NN[i, 1:length(od)] - od : subscript out of bounds
Hi I am having difficulty interpretive the multiple regression output. I
would like to know what it means when one of the factors is assigned as the
intercept?
In my data I am looking at the relationship between environmental parameters
and biological production.
One of my variables in the
Dear list,
I am trying to fit some mixed models using packages lme4 and nlme.
I did the model selection using lmer but I suspect that I may have some
autocorrelation going on in my data so I would like to have a look using the
handy correlation structures available in nlme.
The problem is
Thanks, Bettina.
--
View this message in context:
http://r.789695.n4.nabble.com/findFreqTerms-vs-minDocFreq-in-Package-tm-tp3806644p3808134.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Hi,
I tried to do a nested Anova with the attached Data. My response
variable is survivors and I would like to know the effect of
(insect-egg clutch) size, position (of clutch on twig) and clone
(/plant genotype) on the survival of eggs (due to predation). Each plant
was provided with three
I have 2 columns for weight. There are NAs in each column but not for the
same observation. Some observations have values for both. I would want to
prioritize the WT2 values so I would like to do the following:
From this:
ID WT1WT2
1 134 NA
2 145 155
1
I have read it three times and still no concrete idea what you are actually
trying to do, mainly because there is no information as to which
level/variable you are aggregating on. It'd help if you provided the
aggregated data (or sample rows thereof) so that we know what you want the
result to be.
You are asking a question about a package that seldom appears on
rhelp, leading me to infer that there is not a large user community
that reads this mailing list. You are also not providing the data
needed to reproduced the problem. You would be better off taking the
time to contact the
Dear all,
I have a problem in writing a variable to a NetCDF-File.
My code works pretty well until the step put.var.ncdf():
# Get variables
#-
data1 - open.ncdf(PREC_me_03-1500.nc)
prec1 - get.var.ncdf(data1,PRECT)
dim.time - get.var.ncdf(data1,time2)
close.ncdf(data1)
You can do this using ifelse(). See example below.
x-rpois(100,100)
NA.x-sample(1:100,40)
x[NA.x]=NA
y-rpois(100,100)
NA.y-sample(1:100,40)
y[NA.y]=NA
z-ifelse(!is.na(y),y,ifelse(!is.na(x),x,NA))
HTH,
Daniel
holly shakya wrote:
I have 2 columns for weight. There are NAs in each column
jonas garcia garcia.jonas80 at googlemail.com writes:
I am trying to fit some mixed models using packages lme4 and nlme.
I did the model selection using lmer but I suspect that I may have some
autocorrelation going on in my data so I would like to have a look using the
handy correlation
This suggests that this is a dangerous office to be in because this is a
basic question. I am sure somebody in your office knows this. Anyway, the
baseline gives you the average value of the group that constitutes the
baseline when all other covariates are zero. Let's say you measure whether
men
On Mon, Sep 12, 2011 at 1:32 PM, Claudia Stocker
cstoc...@climate.unibe.ch wrote:
Dear all,
I have a problem in writing a variable to a NetCDF-File.
My code works pretty well until the step put.var.ncdf():
[...code omitted...]
R prints the following error:
#-
Error in
Justin,
Thanks for your help.
On Mon, Sep 12, 2011 at 2:19 PM, Justin Haynes jto...@gmail.com wrote:
the data you've given is all character vectors!
Yes, I'm sorry about that. I should not have used cbind when forming
my data.frame. It changed my numeric data to character. This command
Dear All:
I am calculating the relative importance of a regressor in a linear model.
Does anyone know how I can obtain/install the 'pmvd' computation type? I am
a US user.
Regards,
Y
--
View this message in context:
I already provided the link to the task view, which provides a list of
the more popular machine learning algorithms for R.
Do you have a particular algorithm or technique in mind? Does it have a
name?
How does sequential classification differ form running a one-off
classifier for each run?
Love the page.
Just out of interest, is this an updated version or the same ol'
Inferno document?
And why do I keep thinking you (Patrick Burns) are the Hab's coach? :-)
--
-
Sent from my Cray XK6
__
R-help@r-project.org mailing list
Thank you a lot Morgan. Your suggestion helped me to speed up my code. But
I still believe that the inefficience is an S4 issue.
Best regards,
André Rossi
2011/9/12 Martin Morgan mtmor...@fhcrc.org
Hi André...
On 09/12/2011 07:20 AM, André Rossi wrote:
Dear Martin Morgan and Martin
YAddo linkyox at gmail.com writes:
Dear All:
I am calculating the relative importance of a regressor in a linear model.
Does anyone know how I can obtain/install the 'pmvd' computation type? I am
a US user.
I didn't know what the heck you were talking about, but having looked
at
On 13/09/11 11:27, Carl Witthoft wrote:
Love the page.
Just out of interest, is this an updated version or the same ol'
Inferno document?
And why do I keep thinking you (Patrick Burns) are the Hab's coach? :-)
Now *that's* a blast from the past! Burns coached the Canadiens
way back
joerg stephan stephanj at rhrk.uni-kl.de writes:
Hi,
I tried to do a nested Anova with the attached Data. My response
variable is survivors and I would like to know the effect of
(insect-egg clutch) size, position (of clutch on twig) and clone
(/plant genotype) on the survival of eggs
Hi All,
I have a quick question on random forests. Simply, I am not sure how to read
the values of independent variables related to the highest value of a response
variable from all trees generated from random forests. It is easy to do this in
a single regression tree. But I am not clear how
I don't know R, so maybe I've done something wrong, but I'm working off an
example I saw on the web and wondering why as.POXIXct isn't returning the
same result on f$V1 as it is on z. Did I do something wrong? Or is it a
problem with my build?
f$V1
[1] 09/11/2011 13:46:39 09/11/2011 13:45:18
I have uploaded a datafile that contains the following two variables: time
(X value) and response (Y value). This is a fairly extensive file (with
16000 entries). I have two questions:
1. I want to use the following equation to regress Y on X: Y-hat = min +
(max-min)/(1 + (X/EC50)^Hillslope).
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