Hi,
just to add a few points to the discussion:
- rpart() is able to deal with responses with more than two classes.
Setting method=class explicitly is not necessary if the response is a
factor (as in this case).
- If your tree on this data is so huge that it can't even be plotted, I
On Thu, Sep 20, 2012 at 7:48 PM, maxbre mbres...@arpa.veneto.it wrote:
my reproducible example
test-structure(list(site = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L,
3L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
thank you all for your helpful replies
to bert
the problem with relation =same is the plotting along y axis of all
categories (samp.time) for all groups (sites); instead, I need to
plot along y axis just the categories for each group effectively having
a corresponding observation
to danny
Hi,
Another way of doing may be like this;
a - c(d, d, j, f, e, g, f, f, i, g)
b - c(a, g, d, f, g, a, f, a, b, g)
ta - table(a)
tb - table(b)
Function-function(Tab1,Tab2){elements=sort(unique(c(names(ta),names(tb
This is what I think;
Hive internally distributes the data. If you have set up Hive on single
core it will fetch the query results from that core. If you have multi-core
system on which you have setup the Hive, it will search all the cores for
the query submitted and results would be compiled
I do not know about the packages that you mentioned. I am trying to answer
your query based on the term socio-linguistic analytics.
There are packages like OpenNLP,OpenNLP.en,tm (Text Mining) that
might be of your interest.
Best,
Heramb
On Fri, Sep 21, 2012 at 1:04 AM, Trevor Jenkins
On 2012-09-20 21:34, Trevor Jenkins wrote:
Several years ago there were R implementations of a socio-linguistics
analysis method called Variable Rule Analysis namely rbrul and r-varb. Both
neither of the sites listed (in the method's WikiPedia page
deepayan, is that what you mean?
but still the problem persists: nor correct neither contiguous labelling!
I must probably reconsider everything from scratch: I'm bit confused now...
test$samp.time.new - with(test, reorder(samp.time:site, as.numeric(site)))
On Fri, Sep 21, 2012 at 8:47 AM, Heramb Gadgil heramb.gad...@gmail.comwrote:
I do not know about the packages that you mentioned. I am trying to answer
your query based on the term socio-linguistic analytics.
There are packages like OpenNLP,OpenNLP.en,tm (Text Mining) that
might be of your
On Fri, Sep 21, 2012 at 8:58 AM, Krzysztof Mitko kmi...@mm.st wrote:
On 2012-09-20 21:34, Trevor Jenkins wrote:
Several years ago there were R implementations of a socio-linguistics
analysis method called Variable Rule Analysis namely rbrul and r-varb.
Both
neither of the sites listed (in
Weeell , you were absolutely right.
Turns out I was trying to be too clever by allowing
for a different sized array in each call to a .C dll
within the same R script.
Changed it to the max size the script can request and
all is gas and gaiters.
Thanks for the pointer.
Cheers
There is also C5.0 in the C50 package. It tends to have smaller trees that C4.5
and much smaller trees than J48 when there are factor predictors. Also, it has
an optional feature selection (winnow) step that can be used.
Max
On Sep 21, 2012, at 2:18 AM, Achim Zeileis achim.zeil...@uibk.ac.at
Dear community,
I've an rpart object, and I know the CP I want. I'd like to know if it's
possible also to fix the number of terminal nodes I want.
Thanks in advance, u...@host.com as u...@host.com
--
View this message in context:
On 2012-09-20 21:07, Thomas Lumley wrote:
On Fri, Sep 21, 2012 at 6:43 AM, avinash barnwal
avinashbarnwal...@gmail.com wrote:
Hi,
http://en.wikipedia.org/wiki/Wilcoxon_signed-rank_test
We can clearly see that null hypothesis is median different or not.
One way of proving non difference is
Dear All,
We are currently working with very large datasets which even in R require
a lot of calculation time. Is there an option of including a function/
tool or something alike which shows the remaining time of calculation?
Just to see whether there is any progress or whether anything has
Dear All,
I am a PhD Candidate in Economics wondering whether you might know this: is it
possible to compute the Malmquist-Luenberger productivity index using R? Has
this index been programmed by someone in R as yet? I found that the standard
Malmquist productivity index has been programmed in
jennifer.moeller-gulland at de.pwc.com writes:
Dear All,
We are currently working with very large datasets which even in R require
a lot of calculation time. Is there an option of including a function/
tool or something alike which shows the remaining time of calculation?
Just to
2012/9/21 jennifer.moeller-gull...@de.pwc.com
jennifer.moeller-gull...@de.pwc.com:
Dear All,
We are currently working with very large datasets which even in R require
a lot of calculation time. Is there an option of including a function/
tool or something alike which shows the remaining time
A couple of years ago I noted that using the configure switch
--enable-R-shlib when buildig R made configure ignore any specified
external LAPACK library (I cannot recall if also the BLAS specification
was ignored) and use the internal one insted. I asked why, and was told
it was intentional.
I still haven't come up with a solution to the question below, and I have
another one. I frequently find myself in a situation where I have the list
of columns I want to aggregate over in the form of a vector of strings, and
I have to do something like the following:
dat[, list(mean.z = mean(z)),
Hi everyone, apologies if the answer to this is in an obvious place. I've
been searching for about a day and haven't found anything..
I'm trying to replicate Stata's confidence intervals in R with the survey
package, and the numbers are very very close but not exact. My ultimate
goal is to
Dear all,
In my R plot, I would like to add the title as Estimator vs. Eta,
where I want to use the greek letter eta.
I was trying to use expression(plain(Estimator vs.) *eta* ). It does not
seem to work.
Can anyone familiar with this give some help?
Thank you very much.
Hannah
On Sep 21, 2012, at 17:04 , li li wrote:
Dear all,
In my R plot, I would like to add the title as Estimator vs. Eta,
where I want to use the greek letter eta.
I was trying to use expression(plain(Estimator vs.) *eta* ). It does not
seem to work.
Can anyone familiar with this give some
Thanks for your suggestion,
The issue was resolved by Duncan's recommendation.
Now I am trying to obtain data from different pages from the same site
through a loop, however, the getURLContent keeps timing out, the odd part
is that I can access to the link through a browser with no issues at
On Fri, Sep 21, 2012 at 5:43 AM, Tjun Kiat Teo teotj...@gmail.com wrote:
I am trying to do parallel programming and I tried this
library(doSNOW)
library(foreach)
testfunc-function(x){
x-x+1
x
}
noc-2
cl - makeCluster(do.call(rbind,rep(list(localhost),noc)), type = SOCK)
... and she might also want an additional space between vs. and
eta, either by inserting it within the quotes explicitly or using:
expression(plain(Estimator vs.)~eta)
-- Bert
On Fri, Sep 21, 2012 at 8:15 AM, peter dalgaard pda...@gmail.com wrote:
On Sep 21, 2012, at 17:04 , li li wrote:
Max, I installed C50. I have a question about the syntax. Per the C50 manual:
## Default S3 method:
C5.0(x, y, trials = 1, rules= FALSE,
weights = NULL,
control = C5.0Control(),
costs = NULL, ...)
## S3 method for class ’formula’
C5.0(formula, data, weights, subset,
na.action = na.pass, ...)
I
Inline below.
On Fri, Sep 21, 2012 at 9:05 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
On Fri, Sep 21, 2012 at 5:43 AM, Tjun Kiat Teo teotj...@gmail.com wrote:
I am trying to do parallel programming and I tried this
library(doSNOW)
library(foreach)
testfunc-function(x){
Hello,
First of all, let me apologize that my statistics background is modest at
best.
I am doing some extreme value analysis on model output (WRF) which have the
following dimensions:
speed(time,lat,lon)
I am trying to fit the GPD (gpd.fit) to each point (time,lat,lon) to get a
return level
Hi all,
I have considered neural network to classify the health status of the cow.
I found a very neatly written R codes for classification method in
herehttp://home.strw.leidenuniv.nl/~jarle/IAC/RRoutines/classification-example.R
.
It would be very helpful if you can answer some of the
Hi,
Try this:
plot(0,0)
title(expression(paste(plain(Estimator vs. ),eta,sep= )))
A.K.
- Original Message -
From: li li hannah@gmail.com
To: r-help r-help@r-project.org
Cc:
Sent: Friday, September 21, 2012 11:04 AM
Subject: [R] Math expression in R plot
Dear all,
In my R
Thank you for the fast help!
I am not sure though if I understand the predict.lm business. The newdata
that I would make predictions from consists of six matrices, one for each
variable. Do I cbind the matrices like you suggest for the regression and
then convert them to a dataframe? How does R
Hi,
When I used BRugs (Version 0.8.0), I found a bug about the
findOpenBUGS way using OpenBUGS_PATH. I don't know how to contact
the developer, so I think someone here may help me.
The issue is: I want to use OpenBUGS/BRugs in a portable way in
windows, so I set the environment variable
On Fri, Sep 21, 2012 at 7:00 PM, Shuguang Sun shugu...@gmail.com wrote:
Hi,
When I used BRugs (Version 0.8.0), I found a bug about the
findOpenBUGS way using OpenBUGS_PATH. I don't know how to contact
the developer, so I think someone here may help me.
The easiest way to get in touch when
Hello,
Since no one took the bait, I've written some C code and run some tests.
The tests are divided in two parts, one uses a random vector 'x', the
other makes sure the condition will only be met at the end.v See below.
But first
1. Like Bert said, now your data. I've tested Milan's code,
On Fri, Sep 21, 2012 at 3:17 PM, MichelleNCSU mlcip...@ncsu.edu wrote:
Hello,
First of all, let me apologize that my statistics background is modest at
best.
I am doing some extreme value analysis on model output (WRF) which have the
following dimensions:
speed(time,lat,lon)
I am trying
On Sep 21, 2012, at 7:17 AM, MichelleNCSU wrote:
Hello,
First of all, let me apologize that my statistics background is modest at
best.
I am doing some extreme value analysis on model output (WRF) which have the
following dimensions:
speed(time,lat,lon)
How is this object
Dear all,
Does any one know whether there is a help forum for sas?
I know this is not relevant question to ask here but don't know
where else to ask.
Thank you.
Hannah
[[alternative HTML version deleted]]
__
R-help@r-project.org
On Sep 21, 2012, at 8:19 AM, arun wrote:
Hi,
Try this:
plot(0,0)
title(expression(paste(plain(Estimator vs. ),eta,sep= )))
A.K.
Will not throw an error, but perpetuates the misconception that plotmath
paste() has a 'sep' argument. The space comes from the first argument and the
sep
On Fri, Sep 21, 2012 at 8:48 PM, li li hannah@gmail.com wrote:
Dear all,
Does any one know whether there is a help forum for sas?
I know this is not relevant question to ask here but don't know
where else to ask.
Thank you.
Hannah
Dear Hannah,
Yes, I suppose this really isn't
Hi Everyone,
So I've been working a little with mzxml files generated from proteomics
data. The current packages available to read these are not sufficient for
what I am doing and I would like to build my own. The trouble I am having
is how do I read in an mzxml file without the available
Hello,
As for the first question, predict.lm with new data uses the formula
used in the fit so do not change the way you pass on your new data. If
the formula was Y ~ X1 + X2 you can use
newdata = data.frame(New1, New2)
newdata = data.frame(cbind(New1, New2))
but the order must be kept.
Dear R users,
I need help with translating these SAS codes into R with lme()? I have a
longitudinal data with repeated measures (measurements are equally spaced
in time, subjects are measured several times a year). I need to allow slope
and intercept vary.
SAS codes are:
proc mixed data =
Hi -
I'm curious if there is a way to get access to the location of the calling
script within R. I found one way of accessing it from this thread,
https://stat.ethz.ch/pipermail/r-devel/2008-April/048914.html, which
recommends using either:
parent.frame(2)$ofile
Or
FILE - (function() {
A little googling gave me the result of package caMassClass. Have you checked
that.
Best Regards,
Bhupendrasinh Thakre
Sent from my iPhone
On Sep 21, 2012, at 2:02 PM, Greg Barding gbard...@ucr.edu wrote:
Hi Everyone,
So I've been working a little with mzxml files generated from
Hello,
For questions like this,
install.packages('sos') # if not yet installed
library(sos) # load into R session
findFn('mzxml ')
The frist two look promising.
Hope this helps,
Rui Barradas
Em 21-09-2012 20:02, Greg Barding escreveu:
Hi Everyone,
So I've been working a little with
Hi,
I want to submit a package to CRAN and I am getting the following Note:
* checking CRAN incoming feasibility ... NOTE
New submission
How can I take care of this? And/or is it a big deal?
Thanks and sorry if this is something that I easily overlooked I have
googled this topic for a while
Dear useRs,
my question could be very basic for which i apologize in advance.
Each column of a matrix with dimensions 365 rows and 37 columns was drawn
against another matrix of dimensions 365 rows and 1 column. with that i was
able to draw 37 curves on the same axis.
now i want to draw an
Hello,
Something like this?
# Make up some data
mat - matrix(rnorm(100*37), ncol = 37)
mat - apply(mat, 2, cumsum)
avg - rowMeans(mat)
# matplot - matrix plot
matplot(mat, type = l)
lines(avg, lwd = 2)
I've also seen some very nice graphics for ploting many lines in ggplot2
using
On Sep 21, 2012, at 4:11 PM, eliza botto wrote:
Dear useRs,
my question could be very basic for which i apologize in advance.
Each column of a matrix with dimensions 365 rows and 37 columns was drawn
against another matrix of dimensions 365 rows and 1 column. with that i was
able to
And with ggplot2.
library(ggplot2)
library(scales)
dat - data.frame(id = seq_len(nrow(mat)), mat)
dm - reshape2::melt(dat, id = id)
dm$variable - as.ordered(dm$variable)
dm$avg - rowMeans(mat)
p - ggplot(dm, aes(x = id, y = value, group = variable))
p + geom_line(data = dm, colour =
Hello,
I would like to change the color of the borders of my boxplot. Using col= I am
able only to change the inside background of the boxplot, while I would like to
have it transparent andchange the border instead.
Any hint aamore than welcome,
Best,
Simone
Inviato da iPhone
?boxplot
... and note the border argument
-- Bert
On Fri, Sep 21, 2012 at 6:57 PM, Simone Gabbriellini
simone.gabbriell...@gmail.com wrote:
Hello,
I would like to change the color of the borders of my boxplot. Using col= I
am able only to change the inside background of the boxplot, while I
HI,
Similar graph in xyplot:
set.seed(1)
mat - matrix(rnorm(100*37), ncol = 37)
mat - apply(mat, 2, cumsum)
mat1-melt(mat)
library(latticeExtra)
p0-xyplot(value~X1,group=X2,data=mat1,type=l,ylab=mat1)
p1-xyplot(aggregate(mat1,list(mat1$X1),function(x)
HI,
Modified version of ggplot()
library(ggplot2)
set.seed(1)
mat1-melt(mat)
new1-aggregate(mat1,list(mat1$X1),function(x) mean(x))[,4]
mat2-within(mat1,{X2-as.factor(X2)})
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