On 07.01.2015 01:45, Jeff Newmiller wrote:
The R for Windows FAQ item 2.2 States that installing to a network share is not
supported. I don't know how you ended up trying to use
\\ccofs1\Shared\Users\Dustin Batt
for your home directory, but that appears to be a problem for R. Somehow you
Dear all,
I am trying to build a maximum likelihood (ML) tree using the raxml
function of the package ips. I implemented the following script:
tr-raxml(seq.align,exec = /usr/bin/raxmlHPC,b = 100,
N = 10)
where tr is the resulting tree, seq.align is the DNA alignment created
with
Thanks, this is pretty good. Unfortunately I made an error in generating
the sample dataframe, this code better represents the situation:
data-data.frame(id=factor(rep(1:6,each=3)),
group=factor(rep(c('a','a','b','c','c','c'),each=3)),
x=runif(18,0,10),
Muchas gracias javier
Si javier cada columna representa un individuo y todos los individuos
tienen curvas con comportamientos muy parecidas entre si y lo q me referia
de los eventos es poder dividir cada curva en 4 secciones donde pueda
hallar la posicion o el indice de cada fila los maximos o
So, if I understood correctly, the mod$finalModel should be the resulted tree
after cross-validation, right?
It's the same as the original one.
names(mod)
mod$finalModel
chaidUS
Thanks!
Rodica
- Original Message -
From: Rodica Coderie rodikgeorgi...@yahoo.com
To: Max Kuhn
Hello,
Is anyone using plsrglm to do PLS regressions? I am having trouble
figuring out where my factor loadings are stored. For example, if I do a
PLS regression and have an object from this, what is the list element of
the object with the factor loadings?
Thanks very much
tmp - data.frame(a=rnorm(10), b=rnorm(10))
for (i in names(tmp)) hist(tmp[[i]], main=paste(histogram of, i))
On Wed, Jan 7, 2015 at 10:13 PM, John Sorkin
jsor...@grecc.umaryland.edu wrote:
I am trying to automatically produce a series of histograms from every column
of data frame with many
Dear Andrea.
First of all, the usual advice. If you have problems with a particular
function in a particular package, first try the package author. I just
happened to find your query.
Then, to your question.
On Jan 7, 2015, at 6:19 PM, Andrea Lamont alamont...@gmail.com wrote:
I am
Richard,
WOW! A totally new way to think about loop indices, many, many, thanks!John
John David Sorkin M.D., Ph.D.
Professor of Medicine
Chief, Biostatistics and Informatics
University of Maryland School of Medicine Division of Gerontology and Geriatric
Medicine
Baltimore VA Medical Center
10
I am trying to automatically produce a series of histograms from every column
of data frame with many columns.
The columns names of a shortened from of the data frame follow:
colnames-names(smdata)
colnames
[1] X13594_pre X15568_pre
I want to have
X13594_pre in the title of the first
I like to multiple the first and second column of a 10 x 3 matrix by
100. The following did not work. I need this in an operation with a
much larger scale. Any help?
aa-matrix(1:30,nrow=10,ncol=3); aa
bb-matrix(c(100,100,1),nrow=1,ncol=3); bb
dim(aa)
dim(bb)
aa*bb
Results:
On Wed, Jan 7, 2015 at 5:05 PM, Steven Yen sye...@gmail.com wrote:
I like to multiple the first and second column of a 10 x 3 matrix by 100.
The following did not work. I need this in an operation with a much larger
scale. Any help?
aa-matrix(1:30,nrow=10,ncol=3); aa
You can create a suitable matrix bb as below (note the byrow = TRUE argument)
aa-matrix(1:30,nrow=10,ncol=3); aa
bb-matrix(c(100,100,1),nrow=10,ncol=3, byrow = TRUE); bb
dim(aa)
dim(bb)
aa * bb
You can also use matrix multiplication, but that;s slightly more involved:
On Wed, Jan 7, 2015 at 3:15 PM, Peter Langfelder
peter.langfel...@gmail.com wrote:
You can create a suitable matrix bb as below (note the byrow = TRUE argument)
aa-matrix(1:30,nrow=10,ncol=3); aa
bb-matrix(c(100,100,1),nrow=10,ncol=3, byrow = TRUE); bb
dim(aa)
dim(bb)
aa * bb
You can
Thank you both. Both John and Peter's suggestions work great!!
At 06:17 PM 1/7/2015, John McKown wrote:
On Wed, Jan 7, 2015 at 5:05 PM, Steven Yen
mailto:sye...@gmail.comsye...@gmail.com wrote:
I like to multiple the first and second column
of a 10 x 3 matrix by 100. The following did not
I am having a problem with the function mat.regress in the psych package
that I was hoping someone would be able to give guidance on.
I have a correlation matrix that is [76,76] with the first column
representing the Y variable, the rest are the Xs. This is what my data
looks like:
I had the same error Error in as.ltraj(xy, id, date = da) : non unique dates
for a given burst, but from a different cause, that I'd like to share in
case others have the same issue.
My data came from GPS collars that collected dates and time in Greenwich
Mean Time (GMT). However, the package
Thanks Max!
You are right! I used the train function below and no model was built.
Do you know what can I use instead?
library(caret)
mod - train(x = USvoteS[,-1], y = USvoteS$vote3,
method = modelInfo,
trControl = trainControl(method = cv))
Thanks!
Rodica
The pyears() and survexp() routines in the survival package are designed for
these
calculations.
See the technical report #63 of the Mayo Biostat group for examples
Hello Terry,
Thank you so much for sending me this reference.
Pradip
Pradip K. Muhuri, PhD
SAMHSA/CBHSQ
1 Choke Cherry Road, Room 2-1071
Rockville, MD 20857
Tel: 240-276-1070
Fax: 240-276-1260
From: Therneau, Terry M., Ph.D. [mailto:thern...@mayo.edu]
Sent: Wednesday, January 07, 2015 4:39
Hi,
I would like to loop a specific code through multiple files ending in .CDF in
the same directory, but I am unsure of how to do that (new to R).
Can someone please help me with this-thank you.
This is the code I would like to loop:
xr-xcmsRaw(mh141210xg2_sccs_00101.CDF, profstep=0)
Thanks everyone for your help! This seems to have worked!
Best regards,
Dustin
-Original Message-
From: Uwe Ligges [mailto:lig...@statistik.tu-dortmund.de]
Sent: Wednesday, January 07, 2015 2:35 AM
To: Jeff Newmiller; Dustin Batt; r-help@r-project.org
Subject: Re: [R] Trouble with
Dear all,
This is to request for help on how to convert ncdf data to geoTIFF in R
with my script below;
my script is:
library(raster)
library(ncdf)
setwd('D:/Lund2015/CRU1982_2011')
prec1 - open.ncdf('D:/Lund2015/CRU1982_2011/
b8_cruts3.20_pre_19820101_20111231_1month_mean.nc')
print(prec1)
Cara,
Perhaps I a bit ignorant about mixed models, but I don’t understand why you
have the dependent variable included as a random effect.
The variable names you are using suggest an analysis of combined trials, so (1
| Site/Block/Strip.ID) seems more appropriate. Is this a factorial or a
Dear Tom,
You can’t do that with facet_grid() or facet_wrap(). You could try combine
several plots with grid.arrange().
p1 -
ggplot(subset(data, group ==
a),aes(x=x,y=y))+geom_point(aes(color=group))+facet_wrap(~id, nrow = 1) +
scale_colour_discrete(drop = FALSE)
p2 -
ggplot(subset(data,
raster() wants the filename, not a NetCDF connection.
(raster is one of *very* few high-level interfaces to NetCDF, so it's
somewhat unfamiliar to the norm)
Cheers, Mike
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing
See
?list.files
You can use it to populate object with files in working directory. Then you can
use tis object in loop.
Cheers
Petr
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of
Haznadar, Majda (NIH/NCI) [E]
Sent: Wednesday, January 07, 2015
On 2015-01-07 , at 16:29, Haznadar, Majda (NIH/NCI) [E]
majda.hazna...@nih.gov wrote:
Hi,
I would like to loop a specific code through multiple files ending in .CDF in
the same directory, but I am unsure of how to do that (new to R).
Can someone please help me with this-thank you.
Estimado Carlos Andres Perez Angarita
Entiendo lo que busca, o creo entenderlo, yo uso algo de esa tecnología,
podría ser adaptable a sus requerimientos.
En primer lugar es más simple trabajar con los datos ordenados de otra
forma, lo que usted dice columnas deberían ser filas, no es algo
29 matches
Mail list logo
