Hi Jakub,
This is really a separate question. It is not really end-user related,
and should be asked on the R-devel mailing list. Nonetheless, some
answers below.
On 05/13/2016 03:55 PM, Jakub Jirutka wrote:
Hi,
I’m maintainer of the R package in Alpine Linux.
I read on multiple places
Hi,
I’m maintainer of the R package in Alpine Linux.
I read on multiple places that some packages needs R_HOME variable set to the
location where is R installed, so I’ve added it to the system-wide profile. Is
this correct, or a misinformation?
What system dependencies does R need to compile
ave() encapsulates the split/lapply/unsplit stuff so
transform(mydf, v1.mod = ave(v1, blocks, FUN=mynorm))
also gives what you got above.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Fri, May 13, 2016 at 7:44 AM, Massimo Bressan <
massimo.bres...@arpa.veneto.it> wrote:
> yes, thanks
>
>
yes, thanks
you pointed me in the right direction: split/unplist was the trick
I completely left behind that possibility!
here the final version
mynorm <- function(x) {(x - min(x, na.rm=TRUE))/(max(x, na.rm=TRUE) - min(x,
na.rm=TRUE))}
*PLEASE IGNORE THE PREVIOUS EMAIL, IT WAS SENT BY MISTAKE*
Hello Sarah
thanks a lot for your advice.
I followed your suggestions unitil the creation of "result"
The allocation of the values of result$distance to the matrix result.m,
however ,does not seem to work: it produces a matrix with
Sorry, you're right.
The result line should be:
result.m[cbind(factor(result$fcell), factor(result$cellneigh))] <-
result$distance
idcell <- data.frame(
id = seq_len(5),
fcell = sample(1:100, 5))
censDist <- expand.grid(fcell=seq_len(100), cellneigh=seq_len(100))
censDist$distance <-
Hello Sarah
thanks a lot for your advice.
I followed your suggestions unitl the creation of "result"
The allocation of the values of result$distance to the matrix result.m,
however ,does not seem to work: it produces a matrix with identical columns
corresponding to the last values of
You can also use match(code, unique(code)), as in
transform(dd.2, codex2 = paste0("Person", match(code, unique(code
It is not guaranteed that x!=y implies digest(x)!=digest(y), but it is
extremely
unlikely to fail. This match idiom guarantees that.
Bill Dunlap
TIBCO Software
wdunlap
Sarah,
Thank you very much. The following codes you sent to me work perfectly.
"IF(A2=\"\",\"\",1)" in R becomes "IF(A2="","",1)" in Excel. Wonderful!
Hank
Hongsheng (Hank) Liao, PhD.
Lab Manager
Center for Quantitative Fisheries Ecology
Old Dominion University
757-683-4571
>
If you want to stay with vertical bars, the barp() function in package plotrix
lets you stagger or rotate the labels:
> set.seed(42)
> Name=c("One","Two", "Three","Four", "Five", "Six", "Seven",
+ "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen",
+ "Fourteen", "Fifteen")
>
You can do this with split/unsplit:
> mydf.split <- split(mydf, mydf$blocks)
> str(mydf.split)
List of 3
$ a:'data.frame': 5 obs. of 3 variables:
..$ blocks: Factor w/ 3 levels "a","b","c": 1 1 1 1 1
..$ v1: num [1:5] 19 15 17 22 16
..$ v2: num [1:5] 35 31 35 31 39
$
This doesn't answer your actual question, but isn't it better practice
to use ISBLANK instead of ""?
As for your actual question, a check of the parts of your command at
the R prompt would probably reveal something interesting:
> paste("IF(A2=", dQuote(""), ",", dQuote(""), ",1)", sep="")
[1]
-- Mensaje reenviado --
De: Elkin Tabares
Fecha: 12 de mayo de 2016, 7:04
Asunto: Función auto.arima
Para: R-help-es@r-project.org
Hola a todos,
Estoy estimando un modelo arimax con la función auto.arima del paquete
forecast. Mi pregunta es de cómo
I am trying to add an equation with “” from R to an Excel workbook. However, I
have found that the Function “setCellFormula” doesn’t take the “” well while a
“” in Excel equation stands for a blank cell. I have tried NA(), EMPTY(), etc,
and none of them are what I want. Does anyone have
hi
I need to apply a user defined formula over some selected columns of a
dataframe by subsetting group of rows (blocks) and get back a new dataframe
I’ve been managed to get the the calculations right but I’m not satisfied at
all by the form of the results
please refer to my reproducible
Here is one way:
dd <- data.frame(var1=c("string1", "string2", "string3"), var2=c(3,7,4))
dd
with(dd, barplot(var2, names.arg=var1))
--Chris Ryan
Binghamton, NY
yoursurrogate...@gmail.com wrote:
> Hello, I can't post my code since it's on a work computer.
>
> But basically, I have a dataframe
I would like to conduct a survival analysis, examining a subject's
time to *next* appearance in a database, after their first appearance.
It is a database of dated events.
I need to obfuscate or anonymize or mask the subject identifiers (a
combination of name and birthdate). And obviously any
Thanks Duncan,
This type.convert works fine for me and gives me TSTMean with decimal, but I
want to add this result as a new column to my df as int or num, how can I do
this?
Thanks,
Elahe
On Friday, May 13, 2016 2:15 PM, Duncan Murdoch
wrote:
On 13/05/2016 7:56
> On May 13, 2016, at 6:56 AM, ch.elahe via R-help wrote:
>
> Hi all,
> I have a df which a part of this is:
>
> TSTMax :int 213 228 227 281
> TSTMin :int 149 167 158 176
> TSTMean:Factor w/94 levels "100,2" , "104,3" , ...
> I want to change the
On 13/05/2016 7:56 AM, ch.elahe via R-help wrote:
Hi all,
I have a df which a part of this is:
TSTMax :int 213 228 227 281
TSTMin :int 149 167 158 176
TSTMean:Factor w/94 levels "100,2" , "104,3" , ...
I want to change the TSTMean into numeric but by using
Hi all,
I have a df which a part of this is:
TSTMax :int 213 228 227 281
TSTMin :int 149 167 158 176
TSTMean:Factor w/94 levels "100,2" , "104,3" , ...
I want to change the TSTMean into numeric but by using
as.numeric(as.character(df$TSTMean)) I get too many NAs.
Is there
Hi,
I am going to program (what is called) the “friction model” in economics
and statistics. This model can be used for analysing the government
intervention. It looks like tobit but different. I can not deal with this
model by any R library. This model assume that government intervenes in the
Yo aporto esta web con manuale sde todo tipo pra R
http://www.ub.edu/stat/docencia/Cursos-R/Radvanced/
> Date: Fri, 13 May 2016 11:38:05 +0200
> From: c...@qualityexcellence.es
> To: miguel.angel.rodriguez.mui...@sergas.es
> CC: r-help-es@r-project.org
> Subject: Re: [R-es] Libro: Efficient R
On 11/05/16 17:11, Dominik Schneider wrote:
> Hi Simon, Thanks for this explanation.
> To make sure I understand, another way of explaining the y axis in my
> original example is that it is the contribution to snowdepth relative
> to the other variables (the example only had fsca, but my actual
Hi,
Here is the Biostrings solution in case you need to chop a long
string into hundreds or thousands of fragments (a situation where
base::substring() is very inefficient):
library(Biostrings)
## Call as.character() on the result if you want it back as
## a character vector.
Gracias Miguel por compartir...
Y añado otro:
http://www.joyce-robbins.com/wp-content/uploads/2016/04/effectivegraphsmro1.pdf
2016-05-13 11:04 GMT+02:00 :
> Por si os interesa
> https://csgillespie.github.io/efficientR/
>
> Un saludo,
> Miguel.
>
>
>
On 05/12/2016 10:25 PM, Alba Pompeo wrote:
Martin Morgan, I tried an HTTP mirror and it worked.
What could be the problem and how to fix?
Also, should I ignore the warning about ignoring environment value of R_HOME?
It depends on why you set the value in your environment in the first
place;
Hola,
Con data.table, para que ya no tengas problema de escalado...
#
library(data.table)
DT <- as.data.table(df)
DT[, ab := paste(DT$a, DT$b, sep ="_")]
DT[, fr_a := .N, by='a']
DT[, fr_ab := .N, by='ab']
DT[, res := (DT$fr_ab / DT$fr_a)]
DT[ ,c("ab", "fr_a", "fr_ab") := NULL]
#
On 05/12/2016 10:25 PM, Alba Pompeo wrote:
Martin Morgan, I tried an HTTP mirror and it worked.
What could be the problem and how to fix?
The problem is in the warning message
1: In download.file(url, destfile = f, quiet = TRUE) :
URL 'https://cran.r-project.org/CRAN_mirrors.csv': status
Por si os interesa
https://csgillespie.github.io/efficientR/
Un saludo,
Miguel.
Nota: A información contida nesta mensaxe e os seus posibles documentos
adxuntos é privada e confidencial e está dirixida únicamente ó seu
destinatario/a. Se vostede non é
Hola:
Aplicaré lo que dices de usar data.table.
Sobre hacer for, etc. Ya lo he hecho, pero pensaba que usar dplyr haría la
tarea más rápida por estar este implementado en C (si no me equivoco).
Siempre que puedo utilizo estas funciones, porque codificas menos y van más
rápido. En este caso el
Buenos días,
Por si alguien está interesado, aquí os envío la última oferta que nos ha
llegado a la comunidad.
Podéis contactar conmigo directamente o con emp...@r-es.org
Saludos,
Victoria
Junior Data Analyst.docx
Description: MS-Word 2007 document
Try a different mirror.
--
Sent from my phone. Please excuse my brevity.
On May 12, 2016 9:45:02 PM PDT, Mikko Hurme wrote:
>Hi!
>
>I also have problems when I try to install packages. I use R (v. 3.3.0)
>on
>iMac (v. 10.11.4).
>For instance:
>
>>
Hi!
I also have problems when I try to install packages. I use R (v. 3.3.0) on
iMac (v. 10.11.4).
For instance:
> install.packages("doBy")
Warning: unable to access index for repository
http://ftp.sunet.se/pub/lang/CRAN/src/contrib:
cannot open URL
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