What you are doing wrong is both trying yourself and asking others to
violate Google's Terms of Service and (amongst other things) get your
IP banned along with anyone who aids you (or worse). Please don't.
Just because something can be done does not mean it should be done.
On Tue, May 24, 2016
This has nothing to do with R, per se. This is a statistical issue. You
need to work with a statistician, as your statistical background is
inadequate (google "mixed effects models") if you really need this.
Cheers,
Bert
On Tue, May 24, 2016 at 7:27 PM Neny Sitorus
Hi,
what is exactly mixed model analysis in R?
could someone give me a better description.
Thank you,
Neny
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
Hi Beatriz,
I'll guess that you have a number of files with names like this:
Samples_1.txt
Samples_2.txt
...
Each one can be read with a function like read.table and will return a
data frame with default names (V1, V2, ...). You then want to extract
the first element (column) of the data frame.
> On May 24, 2016, at 2:01 PM, Beatriz wrote:
>
>
> In my environment I have a data frame called Samples_1.txt.
> From this data frame I need to get variable V1. My code doesn't work. Thanks!
>
> $V1
>
> Note: I need to do it in this way because I have the
It is not clear (at least to me) what your actual task is. But, if
Samples_1.txt is the actual name of a data frame that exists in memory (and not
a filename), then you need to wrap the sprintf() in a get() function.
get(sprintf("Samples_%s.txt", 1))$V1
I am no expert on "computing on the
In my environment I have a data frame called Samples_1.txt.
From this data frame I need to get variable V1. My code doesn't work. Thanks!
sprintf("Samples_%s.txt", 1)$V1
Note: I need to do it in this way because I have the code into a for loop.
In my environment I have a data frame called Samples_1.txt.
From this data frame I need to get variable V1. My code doesn't work.
Note: I need to do it in this way because I have the code into a for loop.
sprintf("Samples_%s.txt", 1)$V1
__
Thank you very much, Dan.
These work great. Two more great answers to my question.
Matthew
On 5/24/2016 4:15 PM, Nordlund, Dan (DSHS/RDA) wrote:
You have several options.
1. You could use the aggregate function. If your data frame is called DF, you
could do something like
with(DF,
Thanks, Tom. I was making a mistake looking at your example and that's
what my problem was.
Cool answer, works great. Thank you very much.
Matthew
On 5/24/2016 4:23 PM, Tom Wright wrote:
> Don't see that as being a big problem. If your data grows then dplyr
> supports connections to external
Don't see that as being a big problem. If your data grows then dplyr
supports connections to external databases. Alternately if you just want a
mean, most databases can do that directly in SQL.
On Tue, May 24, 2016 at 4:17 PM, Matthew
wrote:
> Thank you very
Thank you very much, Tom.
This gets me thinking in the right direction.
One thing I should have mentioned that I did not is that the number of
rows in the data frame will be a little over 40,000 rows.
On 5/24/2016 4:08 PM, Tom Wright wrote:
> Using dplyr
>
> $ library(dplyr)
> $
You have several options.
1. You could use the aggregate function. If your data frame is called DF, you
could do something like
with(DF, aggregate(Length, list(Identifier), mean))
2. You could use the dplyr package like this
library(dplyr)
summarize(group_by(DF, Identifier),
Using dplyr
$ library(dplyr)
$ x<-data.frame(Length=c(321,350,340,180,198),
ID=c(rep('A234',3),'B123','B225') )
$ x %>% group_by(ID) %>% summarise(m=mean(Length))
On Tue, May 24, 2016 at 3:46 PM, Matthew
wrote:
> I have a data frame
I have a data frame with 10 columns.
In the last column is an alphaneumaric identifier.
For most rows, this alphaneumaric identifier is unique to the file,
however some of these alphanemeric idenitifiers occur in duplicate,
triplicate or more. When they do occur more than once they are in
I would probably write the function something like this:
t_count_na <- function(dataset,
variables = "all") {
if (identical(variables, "all")) {
variable_list <- names(dataset)
} else {
variable_list <- variables
}
apply(dataset[,variable_list], 1,
Hi All,
I need to create a data frame from scratch and fill variables created on the
fly with values. What I have so far:
-- schnipp --
# Example dataset
gene <-
c("ENSG0208234","ENSG0199674","ENSG0221622","ENSG0207604",
Hello Experts,
I am trying to scrap data from Google news for a particular topic using XML
and Curl Package of R. I am able to extract the summary part of the news
through *XPath* but in a similar way, I am trying to extract title and
Links of news which is not working.Please note this work is
Hi folks,
I am wondering if it is really possible via some R code which shall do
the following
1. Login to a Gmail account (account name and password will be provided to R)
2. Search for all mails which has a word "ABCD" in the mail body
3. Download all the attachments (if available) which will
> On May 24, 2016, at 8:49 AM, Witold E Wolski wrote:
>
> I have two inputs to sweep which are numeric (with a few NA's) but the
> output is NaN. How Why?
>
>
>> sum(!is.numeric(unlist(protquant)))
> [1] 0
>> sum(!is.numeric(normalize))
> [1] 0
>> normprotquant <-
Hello,
Maybe the following (untested).
table(df$Protocol[df$Speed == "SLOW"])
Hope this helps,
Rui Barradas
Citando ch.elahe via R-help :
> Hi all,
> I have the following df:
>
> $ Protocol : Factor w/ 48 levels "DP FS QTSE SAG",..: 2 3
> 43 42 31 36 37 30
Dear UserRs,
I have a little problem creating a file connection when working in parallel
(see the reproducable script below).
I am sure this is something obvious,
Can you enlighten me ?
Thanks,
Arnaud
# This part works
#
cat("This is a test file" , file={f <- tempfile()})
con
Hi all,
I have the following df:
$ Protocol : Factor w/ 48 levels "DP FS QTSE SAG",..: 2 3 43 42 31 36
37 30 28 5 ...
$ Speed : chr "SLOW" "SLOW" "SLOW" "VerySLOW" ...
How can I get the most frequent Protocol when Speed is "SLOW"?
Thanks for any help!
Elahe
I have two inputs to sweep which are numeric (with a few NA's) but the
output is NaN. How Why?
> sum(!is.numeric(unlist(protquant)))
[1] 0
> sum(!is.numeric(normalize))
[1] 0
> normprotquant <- sweep(protquant, 2, normalize, "-" )
> sum(is.nan(unlist(normprotquant)))
[1] 31
version R 3.3.0
Dear Prof. Wood
Thank you, again, for your immediate response.
Best,
Fotis
On Mon, May 23, 2016 at 4:32 PM, Simon Wood wrote:
> Q1: It looks like the model is not fully identifiably given the data and
> as a result igcCAT.ideo has been set to zero - there is no sensible
Estimados
¿Cómo se podría modificar el script o su source para lograr que en la salida
se vean de manera clara los números? En este ejemplo quedan parcialmente
afuera. Adjunto datos y script
Saludos
José
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