Hi,
I have a list of n items and the ith element has m_i elements within it.
I want to do something like:
predicted.values- lapply(all.predicted.values,'[[',max.growth[[i]])
Where max.growth[[i]] is the element I want to extract from each of the ith
predicted elements. Thus, for example, I
[[7]]
[1] 0
[[8]]
[1] 0
[[9]]
NULL
On Oct 18, 2010, at 11:08 AM, Henrique Dallazuanna wrote:
Try this:
diag(sapply(all.predicted.values, '[[', 'max.growth'))
On Mon, Oct 18, 2010 at 12:59 PM, Gregory Ryslik rsa...@comcast.net wrote:
Hi,
I have a list of n items and the ith element
)x1[[x2]],all.predicted.values,max.growth)
might be what you want.
On Oct 18, 2010, at 5:17 PM, Gregory Ryslik wrote:
Unfortunately, that gives me null everywhere. Here's the data I have for
all.predicted.values and max.growth. Perhaps this will help. Thus I want
' and then attaching a '.txt' file,
or just pasting them in the email.
On Mon, Oct 18, 2010 at 2:40 PM, Gregory Ryslik rsa...@comcast.net wrote:
Hi Everyone,
This is closer to what I need but this returns me a matrix where each
element is a factor. Instead I would want a list of lists
Hi,
This might be me missing something painfully obvious but why does the cube root
of the following produce an NaN?
(-4)^(1/3)
[1] NaN
As we can see:
(-1.587401)^3
[1] -4
Thanks!
Greg
__
R-help@r-project.org mailing list
Hi Everyone,
I have a list of vectors like this (in this case it's 3 vectors but assume the
vector count and the length of each vector is not known):
[[1]]
[1] 9 5 7 2 14 4 4 3
[[2]]
[1] 3 6 25 2 14 3 3 4
[[3]]
[1] 28 4 14 3 14 2 4 5
What I want to do is take the average
9.33
14.67 13.67
[10] 10.00
Reduce(+, mylist)/length(mylist)
[1] 7.33 11.67 15.00 11.33 12.67 10.67 9.33
14.67 13.67
[10] 10.00
HTH,
Jorge
On Fri, Oct 29, 2010 at 6:46 PM, Gregory Ryslik wrote:
Hi Everyone,
I have
Hi,
I have a fairly complex object that I have written a print function for.
Thus when I do print(results), the R console shows me a whole bunch of stuff
already formatted. What I want to do is to take whatever print(results) shows
to console and then put that in a file. I am doing this using
Hi Everyone,
I am implementing a special case of Random forests. At one point, I have a list
of which I then sample for replacement. So if the list is 100 elements, I get
100 elements some of them duplicates. How can I easily get the elements that
were not included in the list? I realize i can
Hi,
Suppose I have array A with 100 elements all filled in with N/A. Array
B has 25 elements with actual values. Lastly, I have array C that
provides a map of where to put the elements from array A into array B.
Thus C would say put element 1 from B into element 3 from array A.
I realize I
###
(The sorting is not necessary. It's only there to make checking what
happened easier.)
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Gregory Ryslik
Sent: Sunday, 12 September 2010 8:54 AM
To: r-help@r-project.org
Subject
Hi,
I have a list of several hundred 2 dimensional matrices, where each matrix is n
x m. What I need to do is that for each n,m I need an average over all the
lists. This would collapse it down to just one nxm matrix. Any easy ways to do
that? As always, I'd like to avoid a for loop to keep
Sorry, I forgot to add that some of the entries in various matrices have NA in
them.
On Sep 12, 2010, at 3:40 PM, Gregory Ryslik wrote:
Hi,
I have a list of several hundred 2 dimensional matrices, where each matrix is
n x m. What I need to do is that for each n,m I need an average over
(+,mymats)
does what you want.
- Phil
On Sun, 12 Sep 2010, Gregory Ryslik wrote:
Hi,
I have a list of several hundred 2 dimensional matrices, where each matrix
is n x m. What I need to do is that for each n,m I need an average over all
the lists
23
HTH,
Dennis
On Sun, Sep 12, 2010 at 12:52 PM, Gregory Ryslik rsa...@comcast.net wrote:
Hi,
Doing that I get the following:
Browse[2] Reduce[+,results]
Error in Reduce[+, results] :
object of type 'closure' is not subsettable
You want parentheses there, not brackets; you're
Hi Everyone,
Thanks to everyone for their help. With your suggestions and some poking
around, the following works for what I need. It basically adds all the matrices
elementwise, and adds nothing if the element is NA. Thanks again! Code below:
**
mymats -
('+', lapply(mymats, function(x)replace(x, is.na(x), 0)))
On Sun, Sep 12, 2010 at 10:36 PM, Gregory Ryslik rsa...@comcast.net wrote:
Hi Everyone,
Thanks to everyone for their help. With your suggestions and some poking
around, the following works for what I need. It basically adds all
Hi Everyone,
I have written debugged and tested my code and it works (yay!). I recently
tried to parallelize it (1 core/per tree) and when I run the code I get an
error saying the object control was not found. I do have an object control in
my code but it always works fine as long as I am not
,
Greg
Sent via BlackBerry by ATT
-Original Message-
From: Uwe Ligges lig...@statistik.tu-dortmund.de
Date: Wed, 15 Sep 2010 10:56:54
To: Gregory Ryslikrsa...@comcast.net
Cc: r-h...@stat.math.ethz.ch
Subject: Re: [R] multiple cores/building fails
On 14.09.2010 21:50, Gregory Ryslik wrote
Hi,
I have a list of 5 main elements where each main element has 247 atomic entries
either 0 or 1. I need to get this into a 247x5 matrix so I do do.call(cbind,
mylist). However, it renumbers 0 to a 1 and the 1 to a 2 so that my matrix is
filled with 1's and 2's.
I understand I can fix it
, 2010, at 10:28 PM, David Winsemius wrote:
On Sep 20, 2010, at 10:12 PM, Gregory Ryslik wrote:
Hi,
I have a list of 5 main elements where each main element has 247 atomic
entries either 0 or 1. I need to get this into a 247x5 matrix so I do
do.call(cbind, mylist). However, it renumbers
, 2010, at 10:28 PM, David Winsemius wrote:
On Sep 20, 2010, at 10:12 PM, Gregory Ryslik wrote:
Hi,
I have a list of 5 main elements where each main element has 247 atomic
entries either 0 or 1. I need to get this into a 247x5 matrix so I do
do.call(cbind, mylist). However
Hi Everyone,
I am interested in taking the mode over several thousand matrices. I show an
example below. For the [1,1] entry of my mode matrix that I want to create I
would like to have a 2. For the [1,2] entry I would want a 2. For the [2,2]
entry it would be 4 and so forth. Earlier, I was
(names(which.max(table(x
apply(array(unlist(mymats), dim = c(length(mymats), dim(mymats[[1]]))), 1:2,
mode)
On Tue, Sep 21, 2010 at 10:47 AM, Gregory Ryslik rsa...@comcast.net wrote:
Hi Everyone,
I am interested in taking the mode over several thousand matrices. I show an
example below
AM, Gregory Ryslik rsa...@comcast.net wrote:
Hi Everyone,
I am interested in taking the mode over several thousand matrices. I show an
example below. For the [1,1] entry of my mode matrix that I want to create
I would like to have a 2. For the [1,2] entry I would want a 2. For the
[2,2
), dim = c(dim(mymats[[1]]), length(mymats))), 1:2,
mode)
The error was in c(length(mymats), dim(mymats[[1]]))
On Tue, Sep 21, 2010 at 3:19 PM, Gregory Ryslik rsa...@comcast.net wrote:
Ack, apologies for the previous email. What I meant to say is that the first
element is calculated
Perfect! Thank you!
On Sep 21, 2010, at 3:27 PM, Henrique Dallazuanna wrote:
Use this function:
mode - function(x, ...)
as.numeric(names(which.max(table(x, useNA = 'ifany'
On Tue, Sep 21, 2010 at 4:18 PM, Gregory Ryslik rsa...@comcast.net wrote:
Hi,
Much better! That seems
(which.max(table(x, useNA = 'ifany'
On Tue, Sep 21, 2010 at 4:18 PM, Gregory Ryslik rsa...@comcast.net wrote:
Hi,
Much better! That seems to work great. The only time it doesn't work is that
if all the elements are NA for a specific element. Then it gives me a
numeric(0) for that cell
out the useNA = 'ifAny' in the apply line. Thanks everyone
and especially Henrique for all your help!
Kind regards,
Greg
Begin forwarded message:
From: Gregory Ryslik rsa...@comcast.net
Date: September 21, 2010 4:08:33 PM EDT
To: Henrique Dallazuanna www...@gmail.com
Cc: r-h
Hi,
I have a list of of n elements (where n is unknown beforehand). Each element of
the list has two subelements. The first is a matrix, the second is a number. I
want to make a list of just the matrices.
I want to do something like mylists[[ ,2]] but that obviously doesn't work. Is
there a
On Thu, 30 Sep 2010, Gregory Ryslik wrote:
Hi,
I have a list of of n elements (where n is unknown beforehand). Each element
of the list has two subelements. The first is a matrix, the second is a
number. I want to make a list of just the matrices.
I want to do something like mylists[[ ,2
HI Everyone,
I am working with the following situation. I have n observations and j possible
outcomes and each one of the n observations is assigned a class from 1 to j.
Furthermore, this process is done m times (for some large m 1000).
What I want to do is create a misclassification matrix
0.2727273
TF
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Gregory Ryslik
Sent: Wednesday, October 06, 2010 10:19 AM
To: R Help
Subject: [R] misclassification matrix
HI Everyone,
I am working with the following
Hi Everyone,
In follow up to my previous question, I wrote some code that correctly makes a
confusion matrix as I need it. However, it only works when the numbers are
between 1 and n. If the possible outcomes are between 0 and n, then I can't
reference row 0 of the matrix and the code breaks.
Hi Everyone,
I am trying to figure out the spatstat package for the first time and am having
some trouble. Unfortunately, I can't post my data set but I'll hopefully post
enough details for some help.
I want to model the intensity of a spatial point process using 2 covariates
from my data.
to do it would be? Hopefully, I would get the fit using the image way and see
that the fits are consistent.
Thank you again for your help!
Kind regards,
Greg
On Apr 16, 2011, at 4:46 AM, Rolf Turner wrote:
On 16/04/11 15:50, Gregory Ryslik wrote:
Hi Everyone,
I am trying to figure out
Hi Everyone,
I'm running some simulations where eventually I need to table the results. The
problem is, that while most simulations I have at least one predicted outcome
for each of the six possible categories, sometimes the algorithm assigns all
the outcomes and one category is left out. Thus
with the wrong levels, turn it
back into a character string vector first.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Gregory Ryslik
Sent: Thursday, 3 March 2011 1:46 PM
To: r-help Help
Subject: [R] Non-conformable arrays
Hi,
I seem to be having somewhat of an unusual data input problem with some of the
data sets I'm working with and want to run a simulation on.
in the first data set I'm looking at, I have a text file where the spacing
between columns varies. I've attached a snippet. Is there a way to read
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