With your data set as the data.frame xx
library(reshape2)
xx - melt(xx)
dcast(xx, name ~ variable, sum)
--- On Sun, 11/7/10, Mohan L l.mohanphys...@gmail.com wrote:
From: Mohan L l.mohanphys...@gmail.com
Subject: [R] help to sum up data frame
To: r-help@r-project.org
Received: Sunday,
--- On Thu, 11/11/10, William Dunlap wdun...@tibco.com wrote:
From: William Dunlap wdun...@tibco.com
Subject: Re: [R] Populating then sorting a matrix and/or data.frame
To: Peter Langfelder peter.langfel...@gmail.com, r-help@r-project.org
Received: Thursday, November 11, 2010, 4:19 PM
Have a look at the reshape2 package. http://had.co.nz/reshape/
reshape2 is, to the user a slight modification of rehape but the author says it
is much faster.
The code below seems to do what you want.
-
xx - data.frame(market, price)
Indexing
(xx - matrix(1:4, nrow=2))
vec - 5:6
xx[2,] - vec
xx
--- On Sun, 11/14/10, cassie jones cassiejone...@gmail.com wrote:
From: cassie jones cassiejone...@gmail.com
Subject: [R] replace a row in a matrix
To: r-help@r-project.org
Received: Sunday, November 14, 2010, 10:59 AM
Dear
Alternatively give ggplot2 package a try:
x= c(1,5,7,-3,4)
y= c(2,4,-5,2,5)
xx - data.frame(x,y)
library(ggplot2)
qplot(x,y, data=xx)
--- On Sun, 11/21/10, madr madra...@interia.pl wrote:
From: madr madra...@interia.pl
Subject: [R] how to get rid of unused space on all 4 borders in
Someone was asking how to do a 16 category piechart in OpenOffice Calc and it
appears that it can not be done (which we, probably, should be happy about) but
I thought that I'd try it in ggplot2.
It works but I then thought I'd like to make the colours more distinctive but
fro some reason I
auguie baptiste.aug...@googlemail.com wrote:
From: baptiste auguie baptiste.aug...@googlemail.com
Subject: Re: [R] specifying colours in a ggplot2 piechart
To: John Kane jrkrid...@yahoo.ca
Cc: r-h...@stat.math.ethz.ch
Received: Tuesday, November 23, 2010, 2:02 PM
fixing the various typos in your
I think this is simpler but still not all that clean.
===
xx - structure(list(ID = 1:9, Age = c(10L, 10L, 10L, 11L, 11L, 11L,
10L, 10L, 11L), School = c(1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 2L
), Grade = c(98L, 97L, 92L, 90L, 80L, 70L, 80L,
library(gtools)
?mixedorder
--- On Sat, 7/17/10, Sebastian Gibb li...@sebastiangibb.de wrote:
From: Sebastian Gibb li...@sebastiangibb.de
Subject: [R] sort file names in numerical order
To: r-help@r-project.org
Received: Saturday, July 17, 2010, 4:31 AM
Hello,
I get some file names by
Assuming your data is in data.frame xx
library(reshape)
mm1 - melt(xx, id=c(ID))
cast(mm1, ID ~ variable )
=
--- On Mon, 7/19/10, Thomas Jensen thomas.jen...@eup.gess.ethz.ch
enum.list - function(x,y) {
mylist - NULL
for(i in 1:length(x)) {
mylist[[i]] - x[i]:y[i]
}
xx - unlist(mylist)
}
a - c(1,2,3)
b - a+2
(harry - enum.list(a,b) )
--- On Mon, 7/19/10, Suphajak Ngamlak supha...@phatrasecurities.com wrote:
From: Suphajak Ngamlak supha...@phatrasecurities.com
Will something like the %in% statements below help?
x1 - 1
x2 - 5
y1 - c(2,3)
y2 - c(4,5)
y3 - c(7,8)
x1 %in% y1 ||x2 %in% y2
x1 %in% y1 ||x2 %in% y3
--- On Tue, 7/20/10, Jim Maas jimmaa...@gmail.com wrote:
From: Jim Maas jimmaa...@gmail.com
Subject: [R] simplify if statement in R ?
A small useable data set would help immensely.
Have a look at ?dput as a way to supply one.
--- On Wed, 7/21/10, JGull8502 jason.gulli...@gmail.com wrote:
From: JGull8502 jason.gulli...@gmail.com
Subject: [R] Issues reshaping data
To: r-help@r-project.org
Received: Wednesday, July 21,
Try
str(influencia)
I don't think xtable is intended to print lists.
--- On Wed, 7/21/10, Silvano silv...@uel.br wrote:
From: Silvano silv...@uel.br
Subject: [R] xtable
To: r-help@r-project.org
Received: Wednesday, July 21, 2010, 4:15 PM
Hi,
How do I build a table from a regression
There is no simpler way. It's not automatic but it is fairly simple at the most
basic. It can get a bit complicated later.
ltxt - c(cat,dog)
x - 1:5
y - 1:5
plot (x,y, type='n', ann=FALSE)
lines(x,y,col=1,lty=solid)
points(x,y,pch=16)
legend(1,4,ltxt, pch=16)
--- On Thu, 7/22/10, Yogesh
I think that we need an example of what you are doing before anyone can really
answer that question.
At the moment we don't even know how you are plotting the scatterplot.
--- On Wed, 7/28/10, Sarah Chisholm sarah.chisholm...@ucl.ac.uk wrote:
From: Sarah Chisholm sarah.chisholm...@ucl.ac.uk
Yes, ?jpeg
--- On Tue, 8/3/10, linda.s samrobertsm...@gmail.com wrote:
From: linda.s samrobertsm...@gmail.com
Subject: Re: [R] save plot
To: gavin.simp...@ucl.ac.uk
Cc: r-help@r-project.org
Received: Tuesday, August 3, 2010, 5:36 PM
[I presume you addressed this to
Duncan Murdoch for a
It would really help if you could reduce the information below to a small
reproducible example, that is, some small bit of code that a reader can paste
into R and poke around at.
For sending a small sample dataset have a look at ?dput
I believe that this problem has been discussed on the
I believe Wu Gong has given you a solution. As a note you were probably
reading in the first two columns as either factors or characters and the last
one as numeric. You might want to try it again and then do a str() on the
resulting data.frame to see what was happening.
It can be
It looks like a path problem. I have not figured out how to handle it in Win 7
(new system last week) but have a look at
http://r.789695.n4.nabble.com/odfWeave-Error-td1595848.html#a1595848
which I think addresses the problem.
--- On Tue, 8/31/10, Michael Kubovy kub...@virginia.edu wrote:
Replying to my own post, it is a path problem.
I downloaded the UnZip and Zip binaries, the 5.51-1 UnZip and the most recent
Zip and then added a path to the UnZip directory, and odfWeave seems to be
working.
--- On Te, 8/31/10, John Kane jrkrid...@yahoo.ca wrote:
From: John Kane jrkrid
Can you give us a working example of what you are doing?
I don't understand why you would need a pch symbol for an error bar.
Perhaps if you are using an unboxed legend you could just use arrow() and
text() to add the error bar to the legend?
--- On Wed, 9/1/10, josef.kar...@phila.gov
You installed the package but probably forgot to load the library.
This works fine for me.
=
library(reldist)
x-c(541, 1463, 2445, 3438, 4437, 5401, 6392, 8304, 11904, 22261)
G-gini(x)
I believe that you will have to draw them in ggplot2 as someone mentioned or in
base graphics. Here is a rough first attempt that may give you some ideas.
xx - -3:4
yy - rep(-3,length(xx))
plot(xx,xx, type=n, xlim=c(-4, 5))
rect(xx, yy, xx+.5, xx )
It would help if you included a bit of sample data. See ?dput as a way of doing
this.
Also a good place to start is by looking at the package reshape. Have a look
at http://had.co.nz/reshape/ for some information on the package.
--- On Wed, 9/8/10, Jonathan Finlay jmfinl...@gmail.com wrote:
Like this?
x - 4:7
barplot(x, density=10, angle=180)
--- On Thu, 9/9/10, Steve Murray smurray...@hotmail.com wrote:
From: Steve Murray smurray...@hotmail.com
Subject: [R] Alignment of lines within barplot bars
To: r-help@r-project.org
Received: Thursday, September 9, 2010, 11:35 AM
Okay, I misread what you wanted.
Try this
==
x - 4:7
positions - barplot(x)
mid - x/2
arrows(positions-.5,mid,positions+.5,mid,angle=0)
==
--- On Thu, 9/9/10, Steve Murray
Are you trying to say that you don't really like barplots?
At least the OP did not ask for error bars as well. :)
--- On Fri, 9/10/10, Dennis Murphy djmu...@gmail.com wrote:
From: Dennis Murphy djmu...@gmail.com
Subject: Re: [R] adding labels above bars in a barplot
To: Antonio Olinto
?dotchart perhaps.
--- On Sun, 9/19/10, avsha38 avsha...@post.tau.ac.il wrote:
From: avsha38 avsha...@post.tau.ac.il
Subject: [R] Create Dot Chart
To: r-help@r-project.org
Received: Sunday, September 19, 2010, 10:46 AM
Hello everyone...
I would like to create a chart (see below), how
library(reshape)
melt(dataset) # assuming dataset is a data.frame.
--- On Mon, 9/28/09, baxterj j...@vt.edu wrote:
From: baxterj j...@vt.edu
Subject: [R] SAS user now converting to R - Help with Transpose
To: r-help@r-project.org
Received: Monday, September 28, 2009, 10:24 AM
I am just
Ah, but the offer of the permanent job with a foreign company is so enticing.
BTW I think he says that he is a computer science student. I doubt business
school students would be so cheap.
--- On Sat, 10/3/09, David Winsemius dwinsem...@comcast.net wrote:
From: David Winsemius
Define a matrix to hold the data and insert it into the loop?
Something like
mymat - matrix(rep(NA, 20), nrow=10)
for(i in 1:10){
a - i
b - i+1
mymat[i,] - c(a,b)
}
matplot(mymat)
--- On Mon, 10/5/09, RR99 redhwanza...@hotmail.com wrote:
From: RR99 redhwanza...@hotmail.com
I am playing around learning ggplot and cannot see how to suppress the x or y
axis values ( equivalent of xaxt in basic graphics)
It must be obvious but I'm not seeing it.
Problem
=
timedata - structure(list(month =
Subject: Re: [R] ggplot equivalent of par(xaxt)
To: John Kane jrkrid...@yahoo.ca
Cc: R R-help r-h...@stat.math.ethz.ch
Received: Tuesday, October 6, 2009, 2:57 PM
Hi,
2009/10/6 John Kane jrkrid...@yahoo.ca:
How do I suppress the numbers on the x-axis?
Try this,
p + opts(axis.text.x
(xaxt)
To: John Kane jrkrid...@yahoo.ca
Cc: R R-help r-h...@stat.math.ethz.ch
Received: Tuesday, October 6, 2009, 3:07 PM
body(theme_grey)
could help you find the name of a particular option (that's
what I did).
baptiste
2009/10/6 John Kane jrkrid...@yahoo.ca:
Lovely. I knew
I don't think I've seen an R version, probably because the technique is not
very good for displaying data.
Have a look at http://chartsgraphs.wordpress.com/tag/r-and-excel/ for an
alternative method of displaying the data using lattice.
--- On Fri, 10/9/09, zhijie zhang rusers...@gmail.com
I am attempting to graph 12 months of temperatures, delineate the months with a
vline and place the names of the months at the top of the graph.
So far I have gotten everything to work except the names, despite getting a
similar graph to work yesterday the day before yesterday with Baptise A's
?lines
?points
Something like :
x - 1:10
y1 - rnorm(10, 4, 3)
y2 - rnorm(5,5,2)
ymax - max(c(y1,y2))
ymin - min(c(y1,y2))
plot(x, y1, col='red',ylim = c(ymin,ymax))
lines(y2, col='green')
--- On Fri, 10/9/09, carol white wht_...@yahoo.com wrote:
From: carol white wht_...@yahoo.com
?mtext should help.
--- On Tue, 10/13/09, spidermonkeydp gbabo...@gmail.com wrote:
From: spidermonkeydp gbabo...@gmail.com
Subject: [R] Adding additional X-axis data to charts, e.g. N values
To: r-help@r-project.org
Received: Tuesday, October 13, 2009, 6:06 AM
Hello All,
Does
library(Hmisc) spss.get may do it but it's been some time since I used it.
--- On Sat, 10/10/09, Orvalho Augusto orvaq...@gmail.com wrote:
From: Orvalho Augusto orvaq...@gmail.com
Subject: [R] SPSS long variable names
To: r-help@r-project.org
Received: Saturday, October 10, 2009, 12:14 PM
?subset
?split
--- On Fri, 10/16/09, Joel Fürstenberg-Hägg joel_furstenberg_h...@hotmail.com
wrote:
From: Joel Fürstenberg-Hägg joel_furstenberg_h...@hotmail.com
Subject: [R] Division of data frame and deletion of values from column
To: r-help@r-project.org
Received: Friday, October 16,
Number of politicians' promises kept?
--- On Fri, 10/16/09, Patrick Burns pbu...@pburns.seanet.com wrote:
From: Patrick Burns pbu...@pburns.seanet.com
Subject: Re: [R] negative length vectors are not allowed in wilcox.exact()
and perm.test()
To: Ben Bolker bol...@ufl.edu
Cc:
library(reshape)
?rescaler
I think something along the lines of rescaler(data.frame, type=range) should
do what you want.
--- On Fri, 10/16/09, Noah Silverman n...@smartmediacorp.com wrote:
From: Noah Silverman n...@smartmediacorp.com
Subject: [R] Different way of scaling data
To: r
Oops replying to the wrong post but anyway
does this do what you want?
aa - c(3,6,3,5,8)
lbs - c('cat','goat', 'elephant', 'horse', 'whale')
dotchart(aa, pch=(16), col = 1:5, main=A Dotchart)
axis(side = 2, seq_along(aa), lbs, las=1)
--- On Thu, 10/15/09, Sean Carmody seancarm...@gmail.com
?TukeyHSD
--- On Fri, 10/16/09, Leslie J Seltzer lselt...@wisc.edu wrote:
From: Leslie J Seltzer lselt...@wisc.edu
Subject: [R] doing a Tukey HSD post-hoc
To: r-help@r-project.org
Received: Friday, October 16, 2009, 5:38 PM
Hi all
I have a large spreadsheet (Excel) file with many
Putting names on a ggplot
Can anyone suggest what I am doing wrong here. I am plotting
daily temperatures at Ottawa Ontario for 2008 broken down by
months, I seperate them by lines and want to put the names of the months
at the top of the chart ( with in the graphing area)
Everything is working
Subject: Re: [R] Putting names on a ggplot
To: John Kane jrkrid...@yahoo.ca
Cc: R R-help r-h...@stat.math.ethz.ch
Received: Saturday, October 17, 2009, 5:53 PM
hi,
On Sat, Oct 17, 2009 at 02:04:43PM -0700, John Kane wrote:
Putting names on a ggplot
p - p + geom_text(aes(x = namposts
--- On Sun, 10/18/09, m...@z107.de m...@z107.de wrote:
From: m...@z107.de m...@z107.de
Subject: Re: [R] Putting names on a ggplot
To: John Kane jrkrid...@yahoo.ca
Cc: R R-help r-h...@stat.math.ethz.ch
Received: Sunday, October 18, 2009, 6:05 PM
hello,
On Sun, Oct 18, 2009 at 08:29:19AM
--- On Tue, 10/20/09, hadley wickham h.wick...@gmail.com wrote:
From: hadley wickham h.wick...@gmail.com
Subject: Re: [R] Putting names on a ggplot
To: John Kane jrkrid...@yahoo.ca
Cc: m...@z107.de, R R-help r-h...@stat.math.ethz.ch
Received: Tuesday, October 20, 2009, 10:59 AM
On Sun
?rbind
df1 - data.frame(matrix(rep(0,9),nrow=3))
names(df1) - c(x1,x2,x3)
rbind(df,df1)
--- On Fri, 10/23/09, Ashta sewa...@gmail.com wrote:
From: Ashta sewa...@gmail.com
Subject: [R] Inserting rows
To: R help r-help@r-project.org
Received: Friday, October 23, 2009, 9:44 AM
Hi all,
I
dataframe xx
x1 x2 x3
1 2 5
2 4 1
5 6 0
1 1 2
data.frame(xx$x2,xx$x1,xx$x3)
# or
Awkward but works
--- On Fri, 10/23/09, Joel Fürstenberg-Hägg joel_furstenberg_h...@hotmail.com
wrote:
From: Joel Fürstenberg-Hägg joel_furstenberg_h...@hotmail.com
Subject: [R] Change positions
Perhaps subset the data first?
subset(x, x[,2] =0)
--- On Mon, 10/26/09, e-letter inp...@gmail.com wrote:
From: e-letter inp...@gmail.com
Subject: [R] exclude data for boxplot stats using mathematical operator
To: r-help@r-project.org
Received: Monday, October 26, 2009, 3:25 AM
Readers,
Why not just unlist the data.frame and specify the number of rows in a matrix
each time you need look at a different layout, assuming I understand the
question.
Example
===
aa - data.frame(1:100)
bb - unlist(aa)
(cc - matrix(bb,
PLEASE provide commented, minimal, self-contained, reproducible code.
particularly a sample data.set. At the moment it sounds like you have one
variable (Wavelength) with a length of 56 and Reflectance with a length of
5,000. What format(s) are the data in? Data.frames?
Clearly this is not
And
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--- On Thu, 10/29/09, premmad mtechp...@gmail.com wrote:
From: premmad mtechp...@gmail.com
Subject: [R] R crashes
To: r-help@r-project.org
--- On Fri, 10/30/09, Tony Greig tony.gr...@gmail.com wrote:
From: Tony Greig tony.gr...@gmail.com
Two questions:
1 - Say I have average speed and directions for tide and I
would like to
plot them on a polar plot, but with different colors so I
can indicate the
two directions. I'm
Do you mean to apply the same calculation to each element?
? apply
mydata - data.frame(aa = 1:5, bb= 11:15)
mp5 - function(x) x*5
mp5data - apply(mydata, 2, mp5)
mp5data
This is functionally equivelent to a double if loop.
mydata - data.frame(aa = 1:5, bb= 11:15)
newdata -
Duh, thought of that after I'd left for dinner :(
--- On Sat, 10/31/09, David Winsemius dwinsem...@comcast.net wrote:
From: David Winsemius dwinsem...@comcast.net
Subject: Re: [R] how to loop thru a matrix or data frame , and append
calculations to a new data frame?
To: John Kane jrkrid
I'm not quite sure I understood the second queston but does this work?
subset(temp, xx$v2==-9)
subset(temp, xx$v2!= -9)
--- On Sun, 11/8/09, Ashta sewa...@gmail.com wrote:
From: Ashta sewa...@gmail.com
Subject: [R] look up and Missing
To: r-h...@stat.math.ethz.ch
Received: Sunday, November
With xx as your sample data will this work? See ?addmargins
jj - table(xx)
addmargins(jj, 2)
# or for both margins
addmargins(jj, c(1,2))
or
apply(jj, 1, sum)
--- On Sun, 11/8/09, sylvain willart sylvain.will...@gmail.com wrote:
From: sylvain willart sylvain.will...@gmail.com
Subject:
I think that we probably need a sample database of your original data.
A few lines of the dataset would probably be enough as long as it was fairly
representative of the overall data set. See ?dput for a way of conveniently
supply a sample data set.
Otherwise off the top of my head, I would
Here's one way with aggregate()
library(car) # You probably will need to install it.
aggregate(DF[,3-4], by=list(years), mean,na.rm=TRUE)
recode(x, c(1,2)='A'; else='B')
DF$years - recode(DF$years, c(5,6,7)= '5-7')
DF
You may also want to have a look at the reshape and plyr packages.
---
I don't seem to be able to duplicate the problem. Using your read.table
command I get a data.frame (which is of course a type of list) and something
like sum(dat1[,1] gives me a numerical result.
What variable is giving you the not numerical error message
--- On Mon, 4/26/10, Laetitia Schmid
I suspect that you may have to construct the legend by hand (well, by explicit
text commands anyway)
Something like this seems to work and it should not be that difficult to write
a function to handle the text commands.
plot(1:10,10:1,lty=1,type='b', lwd=2,pch='a')
text(1.4,6, label=-a- ,
It depends on what kind of plot etc and which package you are using. The basic
plot routines are summarized in ?plot.default with many of the parameters
controlled by ?par
I think at the simplist something like this would work and you can add colour
plotting specs etc as you experiment.
Presumably, a scree plot?
Philip may find something useful here
http://www.statmethods.net/advstats/factor.html
--- On Sun, 5/2/10, Ista Zahn istaz...@gmail.com wrote:
From: Ista Zahn istaz...@gmail.com
Subject: Re: [R] Scree diagram,
To: Philip Wong tombfigh...@mysinamail.com
Cc:
I think that one of the packages, perhaps Hmisc or plotrix does this but you
can also do it just using text()
Example
plot(b~a,data=df, xlim=c(min(df$a)-5,max(df$a)+5), ylim=
c(min(df$b)-5,max(df$b)+5))
text( df$a+1,df$b, labels=df$year)
Alternatively you can do this in ggplot
I think that you are correct. R has the annoying habit of converting
character data to factors when you don't want it to while it is importing data.
This is because the in the option stringsAsFactors is set to TRUE for some
weird historical reasons.
Try the command str(insert name of data)
A small executable example would help here. We don't even know how you are
graphing this. There are several packages including lattice and ggplot as well
as the base graphs.
If you are doing this in base graphics have a look at ?text
--- On Mon, 5/3/10, Nish nisha.mukte...@gmail.com wrote:
?replace
Something like this should work
replace(df1, is.na(df1), 000/000)
--- On Tue, 5/4/10, Nevil Amos nevil.a...@gmail.com wrote:
From: Nevil Amos nevil.a...@gmail.com
Subject: [R] How to replace all NA values in a data.frame with another (
not 0) value
To: r-h...@stat.math.ethz.ch
Try this. My appologies for not giving the attribution but I forget who wrote
it.
my.values=10:15
x - barplot(my.values, ylim=c(0,11))
text(x, my.values, my.values, pos=3)
text(x, my.values, wibble, pos=3)
--- On Tue, 5/4/10, someone vonhof...@t-online.de wrote:
From:
Have a look at ?substring
--- On Tue, 5/4/10, Mohan L l.mohan...@gmail.com wrote:
From: Mohan L l.mohan...@gmail.com
Subject: [R] make a column from the row names
To: r-help@r-project.org
Received: Tuesday, May 4, 2010, 9:06 AM
Dear All,
avglog
01/11/09 02/11/09 03/11/09 04/11/09
--- On Tue, 5/4/10, Petr PIKAL petr.pi...@precheza.cz wrote:
From: Petr PIKAL petr.pi...@precheza.cz
Subject: Re: [R] / Operator not meaningful for factors
To: John Kane jrkrid...@yahoo.ca
Cc: r-help@r-project.org, vincent.deluard vincent.delu...@trimtabs.com
Received: Tuesday, May 4, 2010
For simply doing tables xtable has done some nice work for me.
--- On Fri, 5/7/10, Joris Meys jorism...@gmail.com wrote:
From: Joris Meys jorism...@gmail.com
Subject: Re: [R] What is the best way to have R output tables in an MS Word
format? (shaping R core)
To: Duncan Murdoch
Let me see. I open a Word document and type,
Dear Dr.Harrell,
I open a new LaTeX document and type something like:
\documentclass[10pt,a4paper]{letter}
\usepackage[latin1]{inputenc}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\address{your name and address}
\signature{your
?subset
--- On Wed, 5/12/10, Blue.Egg avonpfe...@gmail.com wrote:
From: Blue.Egg avonpfe...@gmail.com
Subject: [R] Removing points
To: r-help@r-project.org
Received: Wednesday, May 12, 2010, 8:33 AM
I have a some data, and imagine a column of how many
parasitic eggs found in
the stool
Hi Steve,
I think what you want to do is get a unique time-date from the first two
columns.
Try something like this: (changing the file name obviously.
mydate should give you a time and date format that you can add to the existing
data.frame.
mydata - read.table(C:/rdata/dates.junk.csv,
I don't think you can do this
precipitation!=NA)
have a look at ?is.na
--- On Tue, 5/18/10, stephen sefick ssef...@gmail.com wrote:
From: stephen sefick ssef...@gmail.com
Subject: [R] Function that is giving me a headache- any help appreciated
(automatic read )
To: r-help@r-project.org
This is not enough information to let us give a good example but perhaps ?lines
or ?points might help?
Example
aa - 1:5
bb - 1:5
cc - c(1.5,2.5,3.5,4.2,4.4)
plot(aa,bb)
lines(aa,cc,col='red')
points(aa,cc, col=blue)
--- On Sat, 5/22/10, khaz...@ceremade.dauphine.fr
The Prostatic_Neoplasm-miRNAs.DiseaseTargets.xls file seems to be an HTML
table and seems to open with no problem in OpenOffice.org Writer/Web. OOo 3.2.0
when opened from within OOOo.
At a guess it is some collection of PubMed references.
I don't know if that's any use but it's a nice table
Where does the table come from?
write.csv(t, file = t.csv)
looks like it would work
--- On Tue, 12/1/09, ggraves ggwra...@sfwmd.gov wrote:
From: ggraves ggra...@sfwmd.gov
Subject: [R] write.csv fails with $ operator invalid for atomic
To: r-help@r-project.org
Received: Tuesday, December
Just write the headers once and append as many times as needed?
You can append as many datasets as you want.
--- On Wed, 12/16/09, rkevinbur...@charter.net rkevinbur...@charter.net wrote:
From: rkevinbur...@charter.net rkevinbur...@charter.net
Subject: Re: [R] write.csv and header
To:
?sink perhaps?
--- On Sat, 12/19/09, Peng Yu pengyu...@gmail.com wrote:
From: Peng Yu pengyu...@gmail.com
Subject: [R] How to print to file?
To: r-h...@stat.math.ethz.ch
Received: Saturday, December 19, 2009, 7:12 AM
I don't find a function to print a
string to file. Would somebody let
?text for the first question ?
plot(xx$Eight, xx$Punctuation)
text(xx$Eight, xx$Punctuation, xx$Name)
You will need to play around with the values for Punctuation to get the names
to be beside the dots
--- On Thu, 12/24/09, Jose Narillos de Santos narillosdesan...@gmail.com
wrote:
From:
I'm not exactly an expert so this is not likely a good way to do it but if the
actual variable names are constant across the files why not just read in the
data and assign the names later?
see skip in ?read.table.
x - read.table(d:/junk1.txt, skip=2)
should read in the data.
You can
First of all there seems to be something wrong with your equation
rate_name[i] = (paste(`rate', i, ‘.csv`, sep = ‘’))
Try this
rate_name[i] - paste(rate,i,.csv, sep=)
I am not
--- On Sat, 12/26/09, Maithili Shiva maithili_sh...@yahoo.com wrote:
From: Maithili Shiva maithili_sh...@yahoo.com
An alternative approach (clumsy but probably not as clumsy as a loop) would be
to create a sixth column as a factor and aggregate on that. Simple-minded
example :
===
mydata - data.frame(matrix(rnorm(100),nrow=20))
mydata[,6] -
I think what you are encountering is a standard R default. R, by default, adds
4% to the axes. I suspect that this is to avoid graphing points right on the x
or x axis and thus obscuring them.
Have a look at ?par xaxs for more information and how to change the default.
--- On Mon,
Assuming the data set is called xx
subset (xx, xx$V1==AB)
or
xx[1,]
if you now AB is the first row of the data.
--- On Mon, 12/28/09, Nick Torenvliet nick.torenvl...@gmail.com wrote:
From: Nick Torenvliet nick.torenvl...@gmail.com
Subject: [R] Accessing members
To:
Could you just transpose the matrix?
Otherwise you can write a simple function that should work.
Try this
-(mat1 - matrix(c(1, 2, 3, NA, 10, 2, NA, 8, 9, NA),nrow=2))
gl - function(x)length(x[!is.na(x)]
apply(mat1, 1, gl)
Uh what do you want to do to it/them?
Here are a couple of R-type commands on a data.frame.
mydata - data.frame(vec1 = seq(19,109, by=10),
vec2 =seq(30,120, by=10))
mydata[,1]+mydata[,2]
apply(mydata, 2, mean)
--- On Thu, 12/31/09, donahc...@me.com donahc...@me.com wrote:
From:
?lines
?points
--- On Mon, 1/4/10, John Westbury jrwestb...@gmail.com wrote:
From: John Westbury jrwestb...@gmail.com
Subject: [R] how to plot multiple density functions in one graph
To: r-help@r-project.org
Received: Monday, January 4, 2010, 3:13 PM
Hello,
I am new to R and have two
Well, if nothing else, you have missing comma. :)
x01=y[,1]), x01=y[,1], x02=y[,2], x03=y[,3]
--
fn - function(x) {
y - t(x[,2])
data.frame( Croptype=x[1,1], Period =x[1,2],
name=colnames(x)[2],
x01=y[,1])x01=y[,1], x02=y[,2], x03=y[,3] }
---Problem
here
m -
I have the feeling that you can do this with ggplot2 but why?
You are likely to be much better off using a dotchart.
?dotchart
--- On Mon, 1/4/10, Elmer Wix elmer.cabekaziruronometu@gmail.com wrote:
From: Elmer Wix elmer.cabekaziruronometu@gmail.com
Subject: [R] Bar plots with
It looks like superpose.eb is someone's function and not in a package.
https://stat.ethz.ch/pipermail/r-help/2002-November/027299.html
--- On Thu, 6/3/10, Rosario Garcia Gil m.rosario.gar...@genfys.slu.se wrote:
From: Rosario Garcia Gil m.rosario.gar...@genfys.slu.se
Subject: [R] (no subject)
What does the text look like?
--- On Thu, 6/3/10, dhanush dhana...@gmail.com wrote:
From: dhanush dhana...@gmail.com
Subject: [R] import text file into R
To: r-help@r-project.org
Received: Thursday, June 3, 2010, 7:32 AM
can anyone tell me how to import a text file in R? the text
file
# A very quick example of how to draw an arrow on a graph.
plot(1:10)
text(2,5, Point 5 , cex=.8)
arrows(3,5, 4.5, 5)
--- On Thu, 6/3/10, Roslina Zakaria zrosl...@yahoo.com wrote:
From: Roslina Zakaria zrosl...@yahoo.com
Subject: [R] horizontal and vertical line with arrow in a plot
To:
The first thing we need to know is what errbar are you using?
There are at least two, on in the Hmisc package and one in sfsmisc.
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained,reproducible code.
I'm not sure what
?var perhaps
--- On Sat, 6/5/10, Adel ESSAFI adel.s...@imag.fr wrote:
From: Adel ESSAFI adel.s...@imag.fr
Subject: Re: [R] variation
To: r-help@r-project.org
Received: Saturday, June 5, 2010, 7:57 AM
2010/6/5 Jannis bt_jan...@yahoo.de
What exactly do you mean by variation? As I
m-matrix(seq(1,48),nrow=6,byrow=T)
as.vector(t(m))
gives me the correct result.
Any chance you may have already transformed m ?
--- On Sat, 6/5/10, steven mosher mosherste...@gmail.com wrote:
From: steven mosher mosherste...@gmail.com
Subject: Re: [R] Matrix to Vector
To: Henrique
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