Hi David,
The variable names of mma are sp, dentro, variable and value - area is
not a variable in that data frame.
Hadley
On Sun, Nov 22, 2009 at 9:48 PM, David Douterlungne
daviddou...@hotmail.com wrote:
Dear R Users,
Reshape seems to be very useful for data-manipulation, but I am
Hi Michael,
I'm having trouble figuring out how to format Date variables when used as
axis labels in graphs.
The particular case here is an attempt to re-create Nightingale's coxcomb
graph with ggplot2,
where I'd like the months to be labeled as Mar 1885, Apr 1885, using a
date format
of
Yes I tried all the basic ones like box plot, pie chart, etc but the data
representation isnt that clear.
Given that you have neither provided your data, nor explained what you
are trying to uncover from it, what sort of advice do you expect to
get?
Hadley
--
http://had.co.nz/
so there are many such posts and dept with varied duties and times resp
Regards
Our Thoughts have the Power to Change our Destiny.
Sunita
On Wed, Nov 18, 2009 at 9:15 PM, hadley wickham h.wick...@gmail.com wrote:
Yes I tried all the basic ones like box plot, pie chart, etc
Hi all,
Is there a method for escaping strings to be used regular expressions?
i.e. if I have a user supplied string that I'd like to use as a fixed
component is there a method that will turn (e.g.) .$^ into
\\.\\$\\^ ?
Thanks,
Hadley
--
http://had.co.nz/
), fixed = TRUE)
On Fri, Nov 13, 2009 at 11:33 AM, Hadley Wickham had...@rice.edu wrote:
Hi all,
Is there a method for escaping strings to be used regular expressions?
i.e. if I have a user supplied string that I'd like to use as a fixed
component is there a method that will turn (e.g
On Fri, Nov 13, 2009 at 9:53 AM, Peng Yu pengyu...@gmail.com wrote:
library(some_library_name)
Try
help(package = some_library_name)
Hadley
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aggregate(dat$value, list(dat$x, dat$y), mean)
Group.1 Group.2 x
1 1 1 15
2 1 2 30
newdat -aggregate(dat$value, list(dat$x, dat$y), mean)
names(newdat) - c(x,y,bquote(mean(value)) )
That bquote isn't necessary because you're already working with strings.
c(x = 1, y
See the above example. Is there a way to make 'drop=FALSE' as global
default, so that when I say 'tmp[,1]', R will treat it as
'tmp[,1,drop=FALSE]'?
The following code won't change the defaults, but it would at least
let you know when you're making the mistake:
trace_all - function(fs,
If you don't want to preserve factor levels when subsetting use
characters. There are very few other differences in behavior.
Hadley
On Tuesday, November 10, 2009, baptiste auguie
baptiste.aug...@googlemail.com wrote:
Dear list,
subset has a 'drop' argument that I had often mistaken for the
:
Is this what you want:
x - ' one two three '
y -
sub(.*?([^[:space:]]+)[[:space:]]+([^[:space:]]+)[[:space:]]+([ehrt]{5}).*,
+ \\1 \\2 \\3, x, perl=TRUE)
unlist(strsplit(y, ' '))
[1] one two three
On Sun, Nov 8, 2009 at 1:51 PM, Hadley Wickham had...@rice.edu
Have a look at ?split
Hadley
On Mon, Nov 9, 2009 at 10:41 AM, agm. amur...@vt.edu wrote:
Hello,
I'm trying to run a loop that will subset my data into specific sets by
regions and by race/ethnicity. I'm trying to do this fairly compactly, and
I cannot get this to work.
A simple version
Hi all,
Is there a tool in base R to extract matched expressions from a
regular expression? i.e. given the regular expression (.*?) (.*?)
([ehtr]{5}) is there a way to extract the character vector c(one,
two, three) from the string one two three ?
Thanks,
Hadley
--
http://had.co.nz/
If readShapePoly() (deprecated - use readShapeSpatial() instead) says that
the data are not polygons, then they are not. If you want to fill
administrative boundaries polygons, you need polygons, not lines. The source
you are using is based on OpenStreetMaps, so more likely to be lines, and as
Hi Paul,
You might want to try the gray colour scale - scale_fill_grey()
Unfortunately grid (the underlying graphics library that ggplot2 uses)
does not currently support patterns.
Hadley
On Wed, Nov 4, 2009 at 4:17 AM, Paul Chatfield p.s.chatfi...@rdg.ac.uk wrote:
Am trying to produce a
If you package depends on another package, it will be automatically installed.
Hadley
On Mon, Nov 2, 2009 at 12:56 PM, Jonathan Greenberg
greenb...@ucdavis.edu wrote:
R-helpers:
I'm working on an r-package that I want to make as easy-to-use as possible
for a novice R-user, which includes
On Wed, Oct 28, 2009 at 8:19 PM, Bill Gillespie bi...@metrumrg.com wrote:
I currently use lattice functions to produce multiple pages of plots using
the layout argument to specify the number of rows and columns of panels,
e.g.,
xyplot(price ~ carat | clarity, diamonds, layout = c(2, 2))
Do you have write permission in C:\Program Files\R\R-2.9.2\library? It
could be that the installer just tried to create the QRMlib subdir, and
failed, and that's why it doesn't exist.
One possible reason for failure is that your virus checker prevented
the R installer from creating a new
I can reproduce it with for example
x=c(-9.23, -9.56, -1.40)
But adding a single positive number, even .001, fixes it, while
adding a similar negative number introduces a new error message, so it
really looks like a bug in ggplot2 when all the values are negative.
Report it to the
Hi John,
Could you please provide a small reproducible example?
Thanks,
Hadley
Sent from my iPhone
On 26/10/2009, at 6:50 PM, Jonathan Bleyhl jonathan_ble...@affymetrix.com
wrote:
I'm trying to plot values based on a date and then overlay a
histogram also
by date. The problem is that
Hi Bryan,
Thanks for the reproducible example. The problem is actually in your
code, not mine ;) You probably want: y = min(res, na.rm = TRUE) - 0.1
* diff(range(res, na.rm = TRUE))
Hadley
(drop = TRUE solves a difference problem - it controls whether or not
to remove bins with zero count)
What are the values of
length((Ht_cm[type=='SD'][from_treeline=='above'])[1])
I suspect the error is in the subsetting - the following seems more plausible:
Ht_cm[type=='SD' from_treeline=='above']
Hadley
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http://had.co.nz/
__
On Sun, Oct 18, 2009 at 10:29 AM, John Kane jrkrid...@yahoo.ca wrote:
Thanks Stefan, the annotate approach works beautifully. I had not got that
far in Hadley's book apparently :(
I'm not convinced though that the explaination
you shouldn't use aes in this case since nampost,
temprange,
To answer one of your other questions: ggplot (and lattice) is/are
very powerful, but base graphics are (a) easier to get your head around
and (b) easier to adjust if you don't like the defaults. Changing things
just a little bit in ggplot can be difficult (as an example, the answer to
your
Is there a way to have some points solid and some points hollow? I have two
classes of points and there are so many points, that it's hard to see just
the difference in shapes. I'd like to have one of the classes be hollow in
addition to being a different shape. Any help would be grand.
Just a note: this technique is called memoisation.
Hadley
On Wed, Oct 14, 2009 at 3:42 PM, Benilton Carvalho bcarv...@jhsph.edu wrote:
Thank you very much, Martin. :)
b
On Oct 14, 2009, at 5:23 PM, Martin Morgan wrote:
Steve Lianoglou wrote:
Very clever, that looks to do the trick!
I
On Tue, Oct 13, 2009 at 6:57 AM, Ista Zahn istaz...@gmail.com wrote:
I'm sure there's a really cool way to do this with plyr, although I
don't know if my particular plyr version is much better. Anyway here
it is:
cmbine - read.csv(textConnection('names, mass, classes
apple,0.50,1
Can I use (a) the logo and/or (b) the slogan for the KCL R workshops?
I think it is quite clear from my website that this is neither about
the Springer book series nor about an R user conference.
No, sorry, the logo/name should be used exclusively for the Springer series
and the R User
Neither a1 nor 2:100 are lists, so it would seem that sapply would be more
appropriate.
The difference between lapply and sapply is the output, not the input.
Hadley
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It is much easier to do you data preparation before plotting.
Cummul - ddply(subset(DF, precipitation!=NA), gauge_name,
function(x){
x$Cummul - cumsum(x$precipitation)
x
})
With a little less typing:
Cummul - ddply(subset(DF, precipitation!=NA), gauge_name, transform,
Please provide a reproducible example. I've had problems with
multcompLetters in the past, because I was giving it slightly
incorrect input.
Hadley
On Tue, Oct 6, 2009 at 7:41 AM, goz garbage.collec...@hotmail.fr wrote:
hello,
i try to use the multcomp letters, but i have problems with my
Whether or not what follows is to be recommended I don't know, but it
seems to work,
p - ggplot(diamonds, aes(carat, ..density..)) +
geom_histogram(binwidth = 0.2)
x = quote(cut)
facets = facet_grid(as.formula(bquote(.~.(x
p + facets
That's what I'd recommend. You can also just do
The point Duncan was making was
What other value would you expect it to have after incrementing from 1 to
200 and stopping?
Well, depending on the scoping rules of the language you are used to,
you might expect i at the top-level to remain undefined.
Hadley
--
http://had.co.nz/
On Fri, Oct 2, 2009 at 4:24 AM, jim holtman jholt...@gmail.com wrote:
try this:
x - read.table(textConnection(x1 x2 x3
+ A 1 1.5
+ B 2 0.9
+ B 3 2.7
+ C 7 1.8
+ D 7 1.3), header=TRUE)
closeAllConnections()
do.call(rbind, lapply(split(seq(nrow(x)), x$x1),
On Wed, Sep 30, 2009 at 2:32 PM, Ista Zahn istaz...@gmail.com wrote:
An extremely verbose, but (in my view) easy to understand approach is:
data.f - data; data.f[which(data = 10)] - levs[1]; data.f[which(data
10)] - levs[2]; data.f - factor(data.f)
All those which()s are unnecessary. And
On Tue, Sep 29, 2009 at 6:58 AM, xavier.char...@free.fr wrote:
Apologies for the misunderstanding. I can come up with a solution that might
suit your needs:
library(plyr)
out - ddply(test, .(nr), function(x) data.frame(date=x$date,
index=rank(-as.integer(x$date
out[is.na(out$nr) |
Have you used persp or trans3d before? Here is a little piece of data that I
am want to convert to 2d. I can plot (x,z) or (z,y). I know there is a better
way to convert it to 2d. I did it long time back in my 3d geometry class.
http://en.wikipedia.org/wiki/3D_projection ?
Hadley
--
or with l_ply (plyr package)
l_ply(data.frame(a=1:3, b=2:4), function(x) print(deparse(substitute(x
The best way to do this is to supply both the object you want to
iterate over, and its names. Unfortunately it's slightly difficult to
create a data structure of the correct form to do this
many thanks for your answer and for the enormous work you put into plyr, a
really powerful package.
For now, I will solve my problem with a variable label attribute, I usually
attach to columns in data frames. I asked the list, because I thought, I am
overlooking something trivial, since
On Mon, Sep 28, 2009 at 9:01 AM, Gary Lewis gary.m.le...@gmail.com wrote:
Hi - Many organizations now make their data available as XML via a
REST web service architecture. Is there any R package or facility to
access this type of data directly (eg, to make the HTTP GET request
and have the
On Fri, Sep 25, 2009 at 7:55 AM, baptiste auguie
baptiste.aug...@googlemail.com wrote:
Thank you Paul, I was convinced I tried this option but I obviously didn't!
In ?packGrob, the user is warned that packing grobs can be slow. In
order to quantify this, I made the following comparison of 3
wtf - factor(x, levels(c(levels(wtf), NA), exclude=NULL)
xtabs (~ wtf, exclude=NULL, na.action=na.pass)
Also see addNA.
Hadley
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PLEASE do read
Well, the title says all for this one.
Not really. What do you mean by crash? What do you mean by used together?
Hadley
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PLEASE do read the
On Mon, Sep 21, 2009 at 3:04 PM, A Singh aditi.si...@bristol.ac.uk wrote:
Dear R users,
I am trying to read in a file with 105 columns, and when trying to attach
it, get an error as follows:
vc1-read.table(P:\\R\\Everything-I.txt, header=T, sep= , dec=.,
na.strings=NA, strip.white=T)
From: hadley wickham h.wick...@gmail.com
Don't use attach?
Obvously good advice but why?
Philosophically, it's better to be explicit than implicit, and the
extremely non-local effects of attach can make debugging difficult.
Hadley
--
http://had.co.nz
Here is a simpler mockup which shows the issue:
x = data.frame(rbind(c(1,2,3),c(1,2,3)))
xnames = c(a, b, c)
names(x) = xnames
for(i in 1:length(x))
{
# Create a varying string expression
expr = paste(y = x$, xnames[i], [1], sep=)
# evaluate expression
eval(parse(text=print(expr)))
On Tue, Sep 15, 2009 at 9:48 AM, ivo welch ivo...@gmail.com wrote:
dear R wizards: here is the strange question for the day. It seems to me
that nrow() is very slow. Let me explain what I mean:
ds= data.frame( NA, x=rnorm(1) ) ## a sample data set
system.time( { for (i in 1:1)
PS: Any speed suggestions are appreciated. This is experimenting time for
me.
You might want to check out the plyr package - it incorporates
everything I know about making these sorts of operations fast. The
next version will do even better.
Hadley
--
http://had.co.nz/
I think this is just because you picked short strings. If the factor
is mapping the string to a native integer type, the strings would have
to be larger for you to notice:
object.size(sample(c(a pretty long string, another pretty long string),
1000, replace=TRUE))
8184 bytes
its 32-bit representation. This seems like it might be too
conservative for me, since it implies that R allocated exactly as much
memory for the lists as there were numbers in the list (e.g. typically
in an interpreter like this you'd be allocating on order-of-two
boundaries, i.e. sizeof(obj)
Is there a place to find a list of the legal values for the coord_trans
parameters. I spent a bunch of time searching the ggplot2 docs and r-help
for same without success. I also made an attempt at looking at the code in R
which also failed.
In the book, or with apropos(^Trans, ignore = F)
On Sat, Sep 12, 2009 at 1:34 PM, Stephan Kolassa stephan.kola...@gmx.de wrote:
Dear guRus,
I am starting to work with the ggplot2 package and have two very dumb
questions:
1) deterministic position_jitter - the jittering is stochastic; is there any
way to get a deterministic jittering? For
What's the difference between a line and a thin bar?
Hadley
On Tue, Sep 8, 2009 at 12:17 PM, rafamoralrafa_moral2...@yahoo.com.br wrote:
I'm sorry, but I think I was misunderstood. What I need is something like
this:
http://img525.imageshack.us/img525/2818/imagemyu.jpg
Lines instead of
On Mon, Sep 7, 2009 at 8:36 AM, Petr PIKALpetr.pi...@precheza.cz wrote:
Dear all
Colleague of mine ask me if R is capable of Andrews plot like
andrewsplot(x) in Matlab.
Quick search did not reveal anything but before I start to write any
routine I would like to ask this ingenious audience
Hi Michael,
You could use aes(y = 1000 * myyvar) and coord_trans(trans_y = inverse)
Hadley
On Sun, Sep 6, 2009 at 6:30 AM, Michael Kubovykub...@virginia.edu wrote:
Hi Stephen,
Because coord_trans() does all the work of plotting the original values on
the tranformed scale. See ?coord_trans.
Hi Gene,
Yes, ggplot2 has replaced ggplot.
Hadley
On Fri, Sep 4, 2009 at 12:58 PM, Gene Leynesgleyne...@gmail.com wrote:
This must be explained somewhere, but I've been searching for a couple of
hours and not found it.
What happened to ggplot? It appears to be missing on CRAN, except in
Would like some tips on how to avoid loops as I know they are slow in R
They are not slow. They are slower than vectorised equivalents, but
not slower than apply and friends.
Hadley
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On Sun, Aug 30, 2009 at 5:08 PM, Noah Silvermann...@smartmediacorp.com wrote:
Hi,
I need a bit of guidance with the sapply function. I've read the help page,
but am still a bit unsure how to use it.
I have a large data frame with about 100 columns and 30,000 rows. One of
the columns is
An opening curly brace should never go on its own line;
I tend to do this:
f - function()
{
if (TRUE)
{
cat(TRUE!!\n)
} else {
cat(FALSE!!\n)
}
}
(I don't usually put one-liners in if/else blocks; here I would have
used ifelse)
I haven't seen many others
But in interactive use the R parser is constrained to work a line at a
time (unless it could predict what you were going to type next ;)
Hadley
On Sat, Aug 29, 2009 at 5:05 PM, John Sorkinjsor...@grecc.umaryland.edu wrote:
For my money, and perspective as one who has written a compiler, this
Perhaps most of you have already seen this?
http://google-styleguide.googlecode.com/svn/trunk/google-r-style.html
Comments/Critiques?
I made my own version that reflects my personal biases:
http://had.co.nz/stat405/resources/r-style-guide.html
Hadley
--
http://had.co.nz/
I made my own version that reflects my personal biases:
http://had.co.nz/stat405/resources/r-style-guide.html
I see you repeated (or independently invented?) the bad rule about closing
braces. They should usually go on their own line, but not when followed by
an else clause.
That was an
It's ok to try to persuade people coding randomly, but otherwise it is
waste of time to get into arguing over if-else or bracketing - we all
have our own favorite.
I totally agree. The main purpose of my style guide is so that my
students write code that I can easily read, understand and
An opening curly brace should never go on its own line and should always be
followed by a new line; a closing curly brace should always go on its own
line.
It seems to me that the opening an dosing curly brace should go on their own
lines to allow the reader to immediately know what is
On Thu, Aug 27, 2009 at 6:37 PM, Richardson,
Patrickpatrick.richard...@vai.org wrote:
I have a dataset that I'm trying to rearrange for a repeated measures
analysis:
It looks like:
patient basefev1 fev11h fev12h fev13h fev14h fev15h fev16h fev17h fev18h drug
201 2.46 2.68 2.76
On Wed, Aug 26, 2009 at 11:31 AM,
miller_2555nabble.30.miller_2...@spamgourmet.com wrote:
miller_2555 wrote:
I'm trying to convert a data.frame to a series of strings (row-wise).
There was a very good discussion awhile back (2002) entitled [R] string
concatenate across rows of a matrix??
Hi Benoit,
You could turn the standard errors off with se = F. Then they'll be
removed from the legend as well.
Hadley
On Tue, Aug 18, 2009 at 7:43 AM, Benoit
Boulinguiezbenoit.boulingu...@ensc-rennes.fr wrote:
Sorry I forgot the code that goes with
**CODE
desorb_plot-ggplot() +
CRAN (and crantastic) updates this week
New packages
Updated packages
New reviews
---
This email provided as a service for the R community by
http://crantastic.org.
Like it? Hate it? Please let us know: crana...@gmail.com.
* SensoMineR, by padmanabhan.vijayan
http://crantastic.org/reviews/25
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http://crantastic.org/reviews/24
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Like it? Hate it? Please let us know: crana...@gmail.com.
On Mon, Aug 24, 2009 at 4:18 PM, Hadley
You might find the article Computing Thousands of Test Statistics
Simultaneously in R in
http://stat-computing.org/newsletter/issues/scgn-18-1.pdf helpful.
Hadley
On Sun, Aug 23, 2009 at 7:55 PM, big permiebigper...@gmail.com wrote:
Dear R users,
I have a matrix a and a classification vector
On Tue, Aug 18, 2009 at 11:10 PM, Chris Friedlcfrieda...@gmail.com wrote:
Still struggling with this. A further example using a slightly different
organisation of the data. The factors A and B are included in the
dataframe in an attempt to get ggplot to generate a legend automatically.
x -
That's on the to do list :(
Hadley
On Tue, Aug 11, 2009 at 10:00 PM, Ben Bolkerbol...@ufl.edu wrote:
Thanks. I can get it to work for facet_grid (which will do for my current
purposes) but am curious about whether there's a way to do the same
for facet_wrap (which doesn't have a labeller
You might also want to have a look at the plyr package,
http://had.co.nz/plyr. This package is an attempt to
standardise and make consistent the various common uses of apply and friends.
Hadley
On Tue, Aug 11, 2009 at 3:09 PM, Peng Yupengyu...@gmail.com wrote:
Hi,
There are quiet a few
Have a look at the code and examples of label_value and label_both.
They should suggest how to write your own labeller to do what you
want.
Hadey
On Tue, Aug 11, 2009 at 1:44 PM, Ben Bolkerbol...@ufl.edu wrote:
just a quick question (to which I suspect the answer is no):
does anyone know if,
Hi all,
On October 19, I'll be offering a one data ggplot2 course in
conjunction with the ISMI Manufacturing Week. The course is open to
all and you can attend in person (Austin TX) or over the web. More
information available from http://lookingatdata.com/ismi-2009/
Regards,
Hadley
--
On Mon, Aug 3, 2009 at 5:23 PM, dav...@rhotrading.com wrote:
I'm having trouble reshaping a data.frame from long to wide.
(I think that's the right terminology; feel free to educate me.)
I've looked at the reshape function and package and plyr package,
but I can't quite figure out how to do
Hi Benoit,
Unfortunately there's currently no way to do that - the legend
automatically corresponds to the geom in the plot.
Hadley
On Thu, Jul 23, 2009 at 11:30 AM, Benoit
Boulinguiezbenoit.boulingu...@ensc-rennes.fr wrote:
Hi all,
I've this ggplot2 graph
On Fri, Jul 24, 2009 at 9:08 AM, Steve
Lianogloumailinglist.honey...@gmail.com wrote:
Hi,
On Jul 24, 2009, at 8:49 AM, n...@aleblanc.cotse.net
n...@aleblanc.cotse.net wrote:
Hi,
can anyone tell me what a roclet is exactly?
Is this terminology specific to R, or is it used in other
Have a look at the meifly package, which also includes tools for
visualising the resulting models.
Hadley
On Wed, Jul 22, 2009 at 7:28 AM, Thomas A. Groentagr...@gmail.com wrote:
Hi,
I would like to have a script/function (or write one) that can calculate the
linear models for all possible
Ups, I just realized that we have the possibility of using
grid.remove(..., redraw = FALSE) which is more or less what I was looking for.
But I'm still wondering if its possible to remove a viewport from
a viewport tree:
I've talked with Paul about this (for the general case of modifying
Drawing grid graphics always takes long, I would write the images to png's
and make the animation. If you use Linux I can suggest some nice tools to do
this. This movie is also much more compatible with all kinds of machines. It
might be that you can get your grid animation working on your own
On Tue, Jul 21, 2009 at 7:39 PM, Gene Leynesgleyne...@gmail.com wrote:
# Just when I thought I had the basic stuff mastered
# This has been quite perplexing, thanks for any help
## Here's the example:
db1=data.frame(
olditems=c('soup','','','','nuts'),
prices=c(4.45, 3.25, 4.42,
Hi Damien,
This is because of a small bug. You can work around it by explicitly
using the force function - dlply(d, V1, force). The default will be
fixed in the next version.
Regards,
Hadley
On Tue, Jul 21, 2009 at 11:18 AM, Damien Mooredamienlmo...@gmail.com wrote:
I'm running R 2.9.1 on
On Fri, Jul 17, 2009 at 3:39 AM, Alex Brownfisht...@compsoc.man.ac.uk wrote:
Sure thing, an example.:
ggplot
(data.frame(name=letters[1:3],value=c(1,4,9),type=c(fun,fun,not
fun)),aes(x=name,y=value,fill=type,label=paste(value is ,value))) +
geom_bar() + coord_flip() + geom_text(hjust=0)
for educational purposes I wonder if it is possible to simulate
different data sets (or specifically residuals) for a linear regression.
I would like to show my students residuals with different means,
variances and distributions (normal, but also not normal) in the plots
created with the
/Cordialement
Benoit Boulinguiez
-Message d'origine-
De : hadley wickham [mailto:h.wick...@gmail.com]
Envoyé : mercredi 15 juillet 2009 14:52
À : Benoit Boulinguiez
Cc : r-help@r-project.org
Objet : Re: [R] ggplot2: geom_errorbarh()
In ggplot2, you'll want to use size.
Hadley
On Wed
Could you please give a reproducible example?
Thanks,
Hadley
On Thu, Jul 16, 2009 at 5:41 PM, Alex Browna...@transitive.com wrote:
Hi there,
I'm trying to find out the command to stop clipping to plot region in
ggplot.
I have a bar chart (axis flipped) with labels on the bars,
-Message d'origine-
De : hadley wickham [mailto:h.wick...@gmail.com]
Envoyé : dimanche 12 juillet 2009 11:04
À : Benoit Boulinguiez
Cc : r-help@r-project.org
Objet : Re: [R] ggplot2: geom_errorbarh()
Hi Benoit,
What do you expect width to do? You are already setting the left and right
Hi Benoit,
What do you expect width to do? You are already setting the left and
right extents with xmin and xmax.
Hadley
On Thu, Jul 9, 2009 at 10:37 AM, Benoit
Boulinguiezbenoit.boulingu...@ensc-rennes.fr wrote:
Hi all,
quick question: is the optional command width effective in the
a curve from a formula.
I'm looking for the equivalent of curve() in ggplot2, Hadley Wickham
mentions geom_curve, but as far as I've seen in the help it doesn't exist.
My need is to plot a regular scatter plot of experimental data (easy to do
actually) and then add the fitting model according
Hi megh,
Unfortunately there's a known bug which prevents you from setting the
y axis title in this way. Instead you can do :
qplot(...) + scale_y_continuous()
I think I've figured out a work around and it will be fixed in a future release.
Hadley
On Mon, Jul 13, 2009 at 2:15 AM,
In this simple example, it took less than half a second to generate the
result. That is on a 2.93 Ghz MacBook Pro.
So, for your data, the code would look something like this:
system.time(DF.new - do.call(rbind,
lapply(split(patch_summary,
On Mon, Jul 13, 2009 at 5:55 AM, Weiwei Shihelprh...@gmail.com wrote:
Hi, there:
Assume I have a dataframe with rownames like A with rownames like a to e,
A
[,1] [,2]
a 1 6
b 2 7
c 3 8
d 4 9
e 5 10
when I use A[1,], I lost the rowname for it, like below.
On Mon, Jul 6, 2009 at 12:12 AM, nykn...@nyk.ch wrote:
Thanks for your reply! This is what I was looking for!
I'm using
nas1 - apply(data_matrix,1,function(x)sum(is.na(x))/nrow(data_matrix))
nas2 - apply(data_matrix,2,function(x)sum(is.na(x))/ncol(data_matrix))
You can simplify this a
On Mon, Jul 6, 2009 at 8:22 PM, Mark Knechtmarkkne...@gmail.com wrote:
Hi,
In the examples from the ReShape package there is a simple example
of using melt followed by cast that produces a smallish amount of
output about the chicks database. Here's the code:
library(reshape)
2) Related to the above, how do I tell what packages are currently
loaded at any given time so that I don't waste time loading things
that are already loaded? search() tells me what's available, but
what's loaded? The best I can find so far goes like this:
Loading something a second time
Also make sure to check roxygen (from roxygen.org) - it makes package
documentation much much easier. Ironically, the documentation for
roxygen currently leaves something to be desired but I think Peter and
Manuel are working on it.
Hadley
On Sat, Jul 4, 2009 at 3:59 PM, Jason
I think the root cause of a number of my coding problems in R right
now is my lack of skills in reading and grabbing portions of the data
out of arrays. I'm new at this. (And not a programmer) I need to find
some good examples to read and test on that subject. If I could locate
which column
Hi Malcolm,
You need to tell geom_boxplot not to use stat_boxplot:
geom_boxplot(aes(lower=y_q1, upper=y_q3, middle=y_med, ymin=y_min,
ymax=y_max), stat = identity)
Hadley
On Mon, Jul 6, 2009 at 6:55 AM, Malcolm Ryanmalco...@cse.unsw.edu.au wrote:
Is there anyway in ggplot2 to set the
On Sat, Jul 4, 2009 at 7:56 PM, Mark Kimpelmwkim...@gmail.com wrote:
I am using grep to locate colnames to automate a report build and have
run into a problem when a colname is not found. The use of integer(0)
in a conditional statement seems to be a no no as it has length 0.
Below is a
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