Hi
I have a few problems with tail/head when applied to multiple time
series. I'm not sure as whether I did not understand the function or
whether it correspond to an unexpected behavior.
When head(a,n) is applied on data.frame or matrix, it returns a
data-frame or matrix with first n obs
a écrit :
Hi Mat,
You might be able to use the matrix method to get what you want.
head.matrix(EuStockMarkets)
-Ista
On Sat, Sep 4, 2010 at 1:15 PM, matmatthieu.stig...@gmail.com wrote:
Hi
I have a few problems with tail/head when applied to multiple time series.
I'm not sure as whether I
Raghu
Those packages are still not on CRAN. You can download the current
version from R-forge:
*|install.packages(blotter, repos=http://R-Forge.R-project.org;)
Mat
|*
Le 10. 07. 10 12:00, r-help-requ...@r-project.org a écrit :
Message: 137
Date: Sat, 10 Jul 2010 08:32:38 +0100
From
Barry, thanks a lot for checking for this!! Find below answers.
Le 13. 04. 11 18:26, Barry Rowlingson a écrit :
2011/4/13 Matthieu Stiglermatthieu.stig...@gmail.com:
Jim
Thanks for your feedback! The problem is that the people those responsible
for layout are us... We are doing the book in
Ok, I can replicate your problem, with following code:
dat - 1:10
barplot(dat, beside=TRUE,ylim=c(0,100));
par()$usr;
par(new=T);
plot(dat, ylim=c(0,100), type=l);
par()$usr;
So it looks like even if you specify yourself ylim, the resulting
effective ylim (usr[3:4] ) will be
Ajay
Please avoid cross-posting on two lists. Continue this thread only on
thes-ig-debian list.
You can't update packages from within R? Did you try to start R with
sudo permissions?:
sudo R
Hope this helps
Mat
Le 22. 01. 11 07:50, Ajay Ohri a écrit :
Dear List
I use synaptic
Hi
Well this is the output of str(dep) on a small example:
str(dep)
chr [1:8] ### ...
Browse[1] dep
[1] ###
[2] ### chunk number 1:
[3] ###
[4] #line
indeed this makes the trick! quite strange... is this a known bug/issue?
thanks!
Matthieu
Le 24. 01. 11 19:48, William Dunlap a écrit :
Put a space after the # in the line
#line 516
to avoid the problem. A similar problem also
appears in parse().
parse(text=#line 102\nlog(pi)\n)
Le 24. 01. 11 20:43, Duncan Murdoch a écrit :
On 11-01-24 12:07 PM, Matthieu Stigler wrote:
hi
I am seeing a strange behavior I can't understand... doing:
source(/tmp/RFile.r,echo=TRUE)
Error in rep.int(c(prompt.echo, continue.echo), c(leading,
length(dep) - :
invalid 'times' value
want a new data.frame, who show me only the newest entries according
to the No.
The solution look like this one:
No. Datelast change
1 1 2012-11-05 final
2 2 2013-01-17 final
can anyone help me?
thanks.
Mat
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2
A Albert1800
B Jack2000
C Mike 2200
How can i eliminate this double entries?
Thanks.
Mat?
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thx, works perfectly :-)
Mat
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thx, that worked perfekt, but is there any way to convert my Number 1 row
# 123
up as column description?
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.
1 2 3
1st round 1:22:30:0
2nd round 2:2 1:01:1
can you help me?
Thanks.
Mat
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: Mercedes_02352
Audi_03555
and now i want to filter this data.frame to
235
355
can you help me?
Thanks.
Mat
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111 final2013-01-12
is there any way to filter my data.frame to the latest data, perhabs max?
Thanks.
Mat
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can i do this.
Thanks.
Mat
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=.)
write.xls( Orders,pfad,colNames = TRUE,sheet = 1,from = 1,rowNames = FALSE )
if(dim(CO.PHB)[1]0){
write.table( CO.PHB,pfad,row.names=FALSE,sep= | )
}}
how should my code look like, if i want only an Export, when there is data
in the data.frame?
Thanks Mat
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i found a way :-)
data-merge(data,project,by.x=PJ_ID,by.y=PROJ_ID,all.x=TRUE)
perhaps this can help someone
Mat
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productive
Thanks.
Mat
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Value
A 33 Evo
B 1 Mer 80
C 1 Pold
thanks.
Mat
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thank you, this code works:
library(plyr)
join(dat1,dat2,by=c(cu.nr.,name),type=right)
but my dat2 frame has a lot of columns, which i don't want to match.
How can i say, that only the column value should be match to dat1 ?
Thank you.
Mat
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49396 1140
B49396 15013
perhabs anyone can help me.
Thank you
Mat
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. So the value of one column
has to have a own color in dependence of the Cat.
Perhabs anyone have an idea?
Thanks.
Mat
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if i can sort my list as follows, i can create the bar chart.
But how can i sort my list from:
[,1] [,2] [,3]
[,4]
abnr2 11425 11425 11555 11888
TIME 21 1
date value should stand under FIRST, the newer date under
SECOND.
Maybe anyone can help me, how i can do this.
Best regards. Mat
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thanks for the help up to here.
A little problem remains.
I have different ABNR, if i try it with another ABNR, the Column extend
for each ABNR, it should start with FIRST again.
dat1 - read.table(text=FS_ID ABNR
932733688812
11391 33688812
11392 33688812
11388 33688812
11390 33688812
THREEMAX
1 2 57 7
2 6 NA NA 6
3 5 7NA 7
4 1 NA NA 1
how can i do this?
thank you. Mat
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Hello togehter,
i have a litte problem. I have an output data.frame which look like this
one:
ID
1 10
2 11
3 12
Now I have another data.frame with more than one line for each ID:
IDGroupValue
1 10110
2 10220
3 103
this one, that i can convert into a data.frame
ID 1 2 3 4 5
110 10 20 30 40 50
211 0 0 60 70 0
312 0 0 0 80 0
Thank you
Mat
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this?
The solution look like this one:
1
A Marius Muller -
B Rockwood
C Microlog Services
D Firefox Services
Thank you.
Best regards. Mat.
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works perfect, thank you :-)
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hello togehter,
i have a little problem, i have frames like this two:
Cat Hours
A101 15
B103 10
Cat Hours
A103 16
B106 11
I need to convert this 2 data.frames into the following equal structure:
Cat Hours
A101
B
3 4700
4 3500
5 3800
Thanks.
Best regards. Mat
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, to create a line chart, with the years (Y10_11, etc.) in
the X-axis and the Categorie in the Y-axis. The lines should be created with
the numbers for each categorie. So in each plot there should be 6 lines in
dependence of the value for each year.
Thank you.
Best regards.
Mat
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regards. Mat
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Thanks first.
that doesn't look bad. But if have a equal ID in dat2, the days are no
longer correct.
the correct data.frame has to look like this one:
ID Name Management Training
1 1 Jack 13
2 2 John 10
3 3 Jill 04
not this one:
ID
thanks. Works perfectly
you made my day :-)
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with plotbase-t(plotbase).
Maybe you can help me.
Thanks Mat
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-10-0415
32013-10-0110
the result should be this one:
IDName First SecondThird
1 Andy10 15
2 John 7 10 15
3 Amy 10
maybe you can help me, to do this?
Thank you.
Mat
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get this result under my column for the Excel Export?
Now my Excel Export looks like this one.
PT_PROG
23
100
7
and now i want under this digets the sum of this column (130)?
Thanks for your help.
Mat
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help.
Mat
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, with the Numbers in my vector.
this one doens't work:
data_export_final-data_export[(data_export$KD_NR==Top10),]
Thank you.
Mat
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gsub() works perfectly, thank you very much.
Mat
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how to colour a complete row, like this task:
U3R - sh$Range(zellen_blue)
U3RF - U3R$Font()
U3RF[[Bold]] - TRUE
U3RF[[Size]] - 10
U3RF[[Color]] --10526881
but how can i color numbers accordung to her value?
Thanks.
Mat
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i tried it this way, but this won't help.
O3R - sh$PT_IST(zellen_other)
O3RF - O3R$Font()
O3RF[[Bold]] - TRUE
O3RF[[Size]] - 10
O3RF[[Color]] -5287936
perhabs you can help me, how i can differenz between the values of more and
less than 1,25?
Thanks.
Mat
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is generated from the data above and is ok.
The Excel sheet was generated every day. And the numbers can change from day
to day.
I know how to color the whole row, but i don't know how to color the number
Difference -- 1,15 according to her value, like: if1,2 - RED, if 1,2
- GREEN
Thanks.
Mat
i tried it this way. With this Code the Row Difference gets complete green.
But i want the color change to red according to a different value.
highlight_other-out.ex1[(out.ex1$AUFTR_NAME==Difference),]$LFD2
zellen_other-paste(paste(A,highlight_other,sep=),paste(S,highlight_other,sep=),sep=:)
#
1
How can i do this?
Thank you.
Mat
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Thank you all, a few ideas worked perfectly for me.
I take with(dat1,aggregate(B,by=list(A=A),length)) for my task.
Have a nice day.
Mat
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Hallo together,
i have a data.frame like this one.
A
13
2-2
31
and now i want to convert the negative number to 0.
A
13
20
31
How can i do this?
Thanks.
Mat
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works perfectly. Thank you :-)
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Hello together,
i want to round some numbers in my data.frame.
How can i round a number to values like 0.5; 1.0; 1.5; 2.0; etc.
It should look like this one
before
2.2 ; 2.3; 2.26; 1.11
after
2.0; 2.5; 2.5; 1.0
thanks.
Mat
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thx, works perfektly :-)
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ee
i tried it like this one:
out1-out[(out$No==no.ind),]
in no.ind i have the 2 numbers: c(2,3)
but this doesn't work.
Maybe anyone can help me.
Thank you.
Mat
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thanks together,
out1 - out[(out$No %in% no.ind),]
works perfectly :-)
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Hello together,
i have a little problem, to create a new column, in a data.frame.
I know i can calculate one column with as a example 2 like this:
ORDER$WEIGHT - ORDER$VALUE * 2
But how can i create the ORDER$WEIGHT with different numbers, like this one.
I have a data.frame like this one:
thanks a lot, works perfectly
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array or vector by himself, then the r tools use
the array or vector to calculate? I am very looking forward to your reply
thanks very much
sincerely
mat chueng
[[alternative HTML version deleted]]
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https
.
The formal job announcement is available at www.usajobs.gov - enter
FDA-09-07-109 in the search box. This announcement contains details
about the position, qualifications, and information about applying. If
you have any other questions, I would be happy to assist in anyway.
Thanks,
-Mat
is the best way to determine the two best teams to play
for the championship - a far from perfect scenario. Yet another debate
of the use of Super Crunching if I may borrow from Ian Ayres. Open to
any ideas/opinions.
Cheers,
-Mat
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL
) which looked quite well.
At least this seemed to work out all right on my Windows XP PC.
Hope this helps,
-Mat
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Mike Prager
Sent: Thursday, June 05, 2008 9:38 AM
To: [EMAIL PROTECTED]
Subject: Re: [R] Lattice
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