I have a program that creates a Png file using Rgooglemap with an extent
(lonmin,lonmax,latmin,latmax)
I also have a contour plot of the same location, same extent, same sized
(height/width) png file.
I'm looking for a way to make the contour semi transparent and overlay it on
the google map (
I've read a number of examples on doing a multiple bar plot, but cant seem
to grasp
how they work or how to get my data into the proper form.
I have two variable holding the same factor
The variables were created using a cut command, The following simulates that
A - 1:100
B - 1:100
A[30:60] -
if your data for the rest of the file looks like this then read.fwf will
work.
depending which vars you want to pull)
widths= c(18,32,41)
E-CBIL-28-raw-cel-1435145228.cel1
would pull 3 vars, E-CBIL-28-raw-cel-; 1435145228.cel;1
widths -c(32,41)
E-CBIL-28-raw-cel-1435145228.cel;1
you
Thanks for the pointer,
After looking at the many folders of R code I have I decided it was time to
start working in an IDE and also getting my stuff under version control (
for my own sanity)
I'll have a look at Geany.. for version control.. not so sure.
On Wed, Oct 27, 2010 at 12:14 PM, Liviu
Ok I downloaded it and showed you how to get your data out. How to read it
into a raster brick,
how to plot the data, how to get the mean rainfall of every day.lots more
you can do.
there is a bad bit of data in the last time step.
check my blog.
In the future what you should do is write code
I'm doing some test processing of a cvs file that appears to use a different
locale
from my machine.
I get the following warning:
input string 1 is invalid in this locale
My locale is US. Is this simply a matter of changing my locale to 'all;
locales?
I don't know what locale the string is
Thanks david.
Matevz, maybe I can help explain by doing a very simple and brute force
approach
as opposed to the way david did it. But you should learn his methods.
I will just do a subset of your problem and if you understand how it works
then you should
be able to get something done and
differing number of rows: 22928, 10«
What am I doing wrong?
Thnks, m
*From:* steven mosher [mailto:mosherste...@gmail.com]
*Sent:* Tuesday, November 02, 2010 8:45 PM
*To:* David Winsemius
*Cc:* Matevž PavliÄ; Gaj Vidmar; r-h...@stat.math.ethz.ch
*Subject:* Re: [R] spliting first 10
Line should be:
first=second=third=fourth=fifth=sixth=seventh=eighth=ninth=tenth-vector(length=nrow(
sent))
sorry cut and past error
On Tue, Nov 2, 2010 at 3:32 PM, steven mosher mosherste...@gmail.comwrote:
That's easy you are confusing the dummy code I sent.
Do this:
lit-read.csv
just merge the data.frames back together.
use merge or cbind()
cbind will be easier
DF1 - data.frame(x,y,z)
DF2 -data.frame(DF1$x) # copy a column
then you added columns to DF2
just put them back together
DF3 -cbind(DF2,DF1$y,DF$z)
if you spend more time with R you will be able to do things
R 2.12 is not functioning for me On the MAC what the most painless way of
reverting
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
I would use RCurl.
if you have, for example, the url of an ftp site you can merely do a
getURL() and the contents will be returned. That call will return data that
can be coerced into a data.frame that will look like a directory structure
listing the file names.
If you need code just ask, but
using RCurl
getFtpList - function(ftp){
# the structure returned is dependent on the ftp site as there are
# various formats for directory listings dependent upon the server
# and the OS. you will need to play with this.
# have a look at the ftp with your browser first and
AM, Baoqiang Cao bqcaom...@gmail.com wrote:
Thanks Steven!
It is excellent code indeed!
On Tue, Nov 30, 2010 at 11:26 AM, steven mosher mosherste...@gmail.com
wrote:
I would use RCurl.
if you have, for example, the url of an ftp site you can merely do a
getURL() and the contents
[ ,1],Time=dir[ ,2],stringsAsFactors=FALSE)
closeAllConnections()
return(out)
}
On Tue, Nov 30, 2010 at 9:56 AM, Baoqiang Cao bqcaom...@gmail.com wrote:
Thanks Steven!
It is excellent code indeed!
On Tue, Nov 30, 2010 at 11:26 AM, steven mosher mosherste...@gmail.com
wrote:
I would use
) {
#download.file failed
}
#no error message though
2)
Henrique Dallazuanna and Steven Mosher both suggested using RCurl,
here is an example code from Henrique for checking if a file exists on
a server:
library(RCurl)
h = basicHeaderGatherer()
Lines - getURI(http://www.pdb.org/pdb/files/2J0S.1001
Given a matrix of MxN
want to take the means of rows in the following fashion
m-matrix(seq(1,80),ncol=20, nrow=4)
result-matrix(NA,nrow=4,ncol=20/5)
result[,1]-apply(m[,1:5],1,mean)
result[,2]-apply(m[,6:10],1,mean)
result[,3]-apply(m[,11:15],1,mean)
result[,4]-apply(m[,16:20],1,mean)
, mean), ncol=ncol(m)/ncol(m2), byrow=TRUE)
result
--
Patrick Rogers
Dept. of Political Science
University of California, San Diego
On Jul 15, 2010, at 2:39 AM, steven mosher wrote:
Given a matrix of MxN
want to take the means of rows in the following fashion
m-matrix(seq(1,80),ncol=20
# build a sample data frame illustrating the problem
ids-c(rep(1234,5),rep(5436,3),rep(7864,4))
years-c(seq(1990,1994,by=1),seq(1991,1993,by=1),seq(1990,1993,by=1))
data-seq(14,25,by=1)
data[6]-NA
DF-data.frame(Id=ids,Year=years,Data=data)
DF
Id Year Data
1 1234 1990 14
2 1234 1991
ha. that was a stupid mistake. Thanks.
On Fri, Jul 30, 2010 at 11:46 AM, David Winsemius dwinsem...@comcast.netwrote:
On Jul 30, 2010, at 2:41 PM, steven mosher wrote:
# build a sample data frame illustrating the problem
ids-c(rep(1234,5),rep(5436,3),rep(7864,4))
years-c(seq(1990,1994
, at 2:41 PM, steven mosher wrote:
# build a sample data frame illustrating the problem
ids-c(rep(1234,5),rep(5436,3),rep(7864,4))
years-c(seq(1990,1994,by=1),seq(1991,1993,by=1),seq(1990,1993,by=1))
data-seq(14,25,by=1)
data[6]-NA
DF-data.frame(Id=ids,Year=years,Data=data)
DF
Id Year Data
very slick Thx.
On Fri, Jul 30, 2010 at 12:44 PM, Wu Gong w...@mtmail.mtsu.edu wrote:
Hi,
R has a buildin function ?rowsum
rowsum(DF$Data,DF$Id,na.rm=T)
-
A R learner.
--
View this message in context:
http://r.789695.n4.nabble.com/Summing-by-index-tp2308332p2308411.html
Sent
Given a data frame, or it could be a matrix if I choose to.
The data consists of an ID, a year, and data for all 12 months.
Missing values are a factor AND missing years.
Id-c(rep(67543,4),rep(12345,3),rep(89765,5))
Years-c(seq(1989,1992,by =1),1991,1993,1994,seq(1991,1995,by=1))
at 4:49 PM, steven mosher mosherste...@gmail.com
wrote:
Given a data frame, or it could be a matrix if I choose to.
The data consists of an ID, a year, and data for all 12 months.
Missing values are a factor AND missing years.
Id-c(rep(67543,4),rep(12345,3),rep(89765,5))
Years-c(seq
Jun 1990NA 21.0NA
Jul 1990NA 21.0NA
Aug 1990NA 21.0NA
Sep 1990NANANA
Oct 1990NANANA
Nov 1990NANANA
Dec 1990NANANA
Jan 1991 54.0NA 12.0
Feb 1991 27.0NA 6.0
...
On Sat, Aug 7, 2010 at 5:09 PM, steven mosher
and those
7000
get averaged and combined in different ways
On Sat, Aug 7, 2010 at 8:45 PM, Gabor Grothendieck
ggrothendi...@gmail.comwrote:
On Sat, Aug 7, 2010 at 9:18 PM, steven mosher mosherste...@gmail.com
wrote:
Very Slick.
Gabor this is a Huge speed up for me. Thanks. ha, Now I want
AM, steven mosher mosherste...@gmail.com
wrote:
In the real data the months are all complete, but the years can be
missing.
So years can be missing up front, in the middle, at the end. but if a
year
is present than every month has a value or NA.
To create regular R ts I had to plow
this is the change from months to the (1)...
On Sun, Aug 8, 2010 at 8:55 AM, Gabor Grothendieck
ggrothendi...@gmail.comwrote:
On Sun, Aug 8, 2010 at 11:21 AM, steven mosher mosherste...@gmail.com
wrote:
Ok,
I'm a bit confused by what you mean by regularly spaced
After I do the do.call I do get
Assuming a data frame or matrix with two columns representing variable that
you want to aggregate over.
you want to calculate column means, by year, for each Id
example-data.frame(id=c(rep(12345,5),rep(54321,6),rep(45678,7)),Year=rep(seq(1900,1902,by=1),6),
x=seq(1,18,by=1),y=seq(18,1,by=-1))
That works.
Thanks
On Mon, Aug 9, 2010 at 7:55 AM, Henrique Dallazuanna www...@gmail.comwrote:
Try this:
aggregate(example[c('x', 'y')], example[c('id', 'Year')], 'mean')
On Mon, Aug 9, 2010 at 11:46 AM, steven mosher mosherste...@gmail.comwrote:
Assuming a data frame or matrix with two
rc-list(c(
123,321,234,543,654,768,986,987,246,284),c(Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec))
# the matrix has rownames that are used as identifiers and columns
# of time. 1 years worth of data. Thats the native format
test-matrix(seq(1,120, by=1), nrow=10,dimnames=rc)
test
Jan
Given a long zoo matrix, the goal is to sweep out a statistic from the
entire length of the
sequences.
longzoomatrix-zoo(matrix(rnorm(720),ncol=6),as.yearmon(outer(1900,seq(0,length=120)/12,+)))
cnames-c(12345,23456,34567,45678,56789,67890)
colnames(longzoomatrix)-cnames
longzoomatrix[1:24,]
, 2010 at 11:21 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Wed, Aug 11, 2010 at 12:22 PM, steven mosher mosherste...@gmail.com
wrote:
Given a long zoo matrix, the goal is to sweep out a statistic from the
entire length of the
sequences.
longzoomatrix-zoo(matrix(rnorm(720
Stupid question, but its been a long night.
If I have a long vector how can I turn it into a list of the same length
x-rep(seq(1,100,by=1),each=10)
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Thx, I see my problem. more sleep required
On Sat, Aug 14, 2010 at 9:25 AM, Romain Francois romain.franc...@dbmail.com
wrote:
Le 14/08/10 18:22, steven mosher a écrit :
Stupid question, but its been a long night.
If I have a long vector how can I turn it into a list of the same length
In the particular application I have I save test.Rdata to a sub directory
dir-Example
dir.create(dir)
test-data.frame(a=c(1,2,3),b=c(3,4,5)
full-file.path(dir,test.Rdata,fsep=.Platform$file.sep)
save(test,file=full)
load(full)
returns NULL
it works fine when the object is saved to the working
, Aug 14, 2010 at 5:14 PM, steven mosher mosherste...@gmail.com
wrote:
In the particular application I have I save test.Rdata to a sub
directory
dir-Example
dir.create(dir)
test-data.frame(a=c(1,2,3),b=c(3,4,5)
full-file.path(dir,test.Rdata,fsep=.Platform$file.sep)
save(test,file=full
you can report
the results of sessionInfo()
Cheers,
Josh
On Sat, Aug 14, 2010 at 5:14 PM, steven mosher mosherste...@gmail.com
wrote:
In the particular application I have I save test.Rdata to a sub
directory
dir-Example
dir.create(dir)
test-data.frame(a=c(1,2,3),b=c(3,4,5)
full
On Sun, Aug 15, 2010 at 12:06 AM, steven mosher mosherste...@gmail.com
wrote:
Did you exit R and then return?
fname-test.Rdata
full-file.path(Example,fname,fsep=.Platform$file.sep)
full
[1] Example/test.Rdata
load(full)
test
NULL
sessionInfo()
R version 2.11.1 (2010-05-31
, at 3:06 AM, steven mosher wrote:
Did you exit R and then return?
fname-test.Rdata
full-file.path(Example,fname,fsep=.Platform$file.sep)
full
[1] Example/test.Rdata
load(full)
test
NULL
I am unable to reproduce the problem (after correcting two different
syntactic errors in the initial
A quick question
x - as.yearmon(2000 + seq(0, 23)/12)
x
[1] Jan 2000 Feb 2000 Mar 2000 Apr 2000 May 2000 Jun 2000 Jul
2000 Aug 2000 Sep 2000 Oct 2000 Nov 2000 Dec 2000 Jan 2001
[14] Feb 2001 Mar 2001 Apr 2001 May 2001 Jun 2001 Jul 2001 Aug
2001 Sep 2001 Oct 2001 Nov 2001 Dec 2001
j-matrix(nrow=10,ncol=10)
k-matrix(seq(1:50), ncol=10)
row.names(k) - seq(2,10,by=2)
j
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,] NA NA NA NA NA NA NA NA NANA
[2,] NA NA NA NA NA NA NA NA NANA
[3,] NA NA NA NA NA
35 40 4550
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of steven mosher
Sent: Sunday, 5 September 2010 5:10 PM
To: r-help
Subject: [R] merging two maxtrices
j-matrix(nrow=10,ncol=10)
k-matrix(seq(1:50), ncol
NA NA NA NA NA NANA
105 10 15 20 25 30 35 40 4550
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of steven mosher
Sent: Sunday, 5 September 2010 5:10 PM
To: r-help
Subject: [R] merging
not sure how you wanted sampling of x
R-142
color-rep(0,142)
for(i in 1:R){
y-sample(x,142,replace=FALSE)
onebit- as.numeric(3471 %in% y)
twobit-as.numeric(6720 %in% y)*2
fourbit-as.numeric(6263 %in% y)*4
colorbit-onebit+twobit+fourbit+1
color[i]-colorbit
}
On Tue, Sep 14, 2010 at
Wongsang,
Just to be clear R.utils is different than utils
As Henrik notes gunzip has been in R.utils ( see http://cran.r-project.org/)
for some time. It works
like a champ. R.utils is a great package.
On Wed, Sep 15, 2010 at 9:30 AM, Wonsang You y...@ifn-magdeburg.de wrote:
Dear Henrik,
...@phatrasecurities.com
*From:* steven mosher [mailto:mosherste...@gmail.com]
*Sent:* Thursday, September 16, 2010 2:29 AM
*To:* Suphajak Ngamlak
*Subject:* Re: [R] Get File Names in Folder, Read Files, Update, and Write
Import-C:/A0810.RSK
Table-read.table(file= Import, sep = ,, head=TRUE
you are welcome. Henrik's package is an great piece of work. It is worth
the time to read through the whole thing and see how you can improve your
programs by using other features as well.
On Thu, Sep 16, 2010 at 2:16 AM, Wonsang You y...@ifn-magdeburg.de wrote:
Dear Henrik and Steven,
Thank
v-c(1,2,3,4,5,6,7,8,97,6,5,4,NA,NA)
b-zoo(v)
b
1 2 3 4 5 6 7 8 9 10 11 12 13 14
1 2 3 4 5 6 7 8 97 6 5 4 NA NA
b[is.na(b)]-0
b
1 2 3 4 5 6 7 8 9 10 11 12 13 14
1 2 3 4 5 6 7 8 97 6 5 4 0 0
is.zoo(b)
[1] TRUE
On Mon, Sep 20, 2010 at 2:37 AM, skan
I'm accessing around 95 tar files on an FTP server ranging in size between
10 and 40MB a piece.
while certainly can click on them and download them outside of R, I'd like
to have my script do it.
Retrieving the ftp directory with RCurl works fine (about 90% of the time)
but downloading the
pills.
i did note, however, some odd behavior with tryCatch, where statements
after the finally={} were executed. Not sure if that deserves a bug report.
On Tue, Sep 21, 2010 at 2:33 AM, Barry Rowlingson
b.rowling...@lancaster.ac.uk wrote:
On Tue, Sep 21, 2010 at 9:39 AM, steven mosher
The package R.utils has a function to get absolutepath
On Sun, Sep 26, 2010 at 1:00 AM, Sebastian Gibb li...@sebastiangibb.dewrote:
Hello,
I get a value which stores a relative file name. (I get it from another
function, which I don't want to change.)
e.g.
fileName - ../data/2010-08.csv;
in the package R.utils
getAbsolutePath()
or you can do a file.list(.. full.names=TRUE,
recursive=TRUE,pattern=(.R))
the rest will require grep and pulling the file name and directory path
apart
If its not evident just ask and I'll write something for you.
basically you want a call
I know its no consolation, but I have a similar issue with R on a MAC, also
ploting
out large numbers of raster layers. sometimes the problem lingers even
after I clear the workspace, do gc() etc. Almost as if R wont ask for
processor resources.
weird.
On Wed, Oct 6, 2010 at 12:06 PM, Bastien
Thanks,
haven't used valgrind in years, this should be fun.
Steve
On Wed, Oct 6, 2010 at 1:55 PM, Ben Bolker bbol...@gmail.com wrote:
steven mosher moshersteven at gmail.com writes:
I know its no consolation, but I have a similar issue with R on a MAC,
also
ploting
out large
Given a csv file from this location
Airports-http://www.ourairports.com/data/airports.csv;
download.file(Airports,basename(Airports))
airports -read.csv(airports.csv,encoding=UTF-8)
airports[1,]
id ident type name latitude_deg longitude_deg
elevation_ft continent
at 1:33 PM, steven mosher mosherste...@gmail.com
wrote:
Given a csv file from this location
Airports-http://www.ourairports.com/data/airports.csv;
download.file(Airports,basename(Airports))
airports -read.csv(airports.csv,encoding=UTF-8)
airports[1,]
id ident type
Hmm,
RCurl might have something on this.
otherwise pull you can figure out their scheme and just construct the url
from scratch.
when you finish filling in the form, look at the url they construct. do it a
few times
and you can just emulate that. I've done that in the past without problems.
Is there a simple way to calculate the maximum for a row or column of a
matrix when there are NA,s present.
# given a matrix that has any number of NA per row
m-matrix(c(seq(1,9)),nrow=3)
m
[,1] [,2] [,3]
[1,]147
[2,]258
[3,]369
m[3,1]=NA
m[1,]=NA
m
a large number of these -Inf..
I Was looking at maxtrixStats package but it still beta
On Sat, Apr 17, 2010 at 10:01 PM, David Winsemius dwinsem...@comcast.netwrote:
On Apr 18, 2010, at 12:16 AM, steven mosher wrote:
Is there a simple way to calculate the maximum for a row or column of a
matrix
= TRUE)))
[1] NA 8 9
See ?ifelse, ?all and ?max for more information.
HTH,
Jorge
On Sun, Apr 18, 2010 at 12:16 AM, steven mosher wrote:
Is there a simple way to calculate the maximum for a row or column of a
matrix when there are NA,s present.
# given a matrix that has any number of NA
improvements.
On Sun, Apr 18, 2010 at 2:47 AM, Henrik Bengtsson h...@stat.berkeley.eduwrote:
On Sun, Apr 18, 2010 at 7:26 AM, steven mosher mosherste...@gmail.com
wrote:
Ya I got that result but fixing it was a mystery. especially since I will
eventually want to subtract the row max from the row Min
I have a 43MB dataframe ( 5 variables) and I'm trying to summarize subsets
of the data.
I've RTFM ( not very clear) and looked at a variety of samples but cant seem
to figure out
how to make these functions work.
A sample of what I want to do would be this:
ids-seq(1,50)
)
--
On Sun, Apr 25, 2010 at 9:29 AM, steven mosher mosherste...@gmail.comwrote:
I have a 43MB dataframe ( 5 variables) and I'm trying to summarize subsets
of the data.
I've RTFM ( not very clear) and looked at a variety of samples but cant
')
DF$years - recode(DF$years, c(5,6,7)= '5-7')
DF
You may also want to have a look at the reshape and plyr packages.
--- On Sun, 4/25/10, steven mosher mosherste...@gmail.com wrote:
From: steven mosher mosherste...@gmail.com
Subject: [R] Noobie question on aggregate tapply
Having some difficulties with understanding how tapply works and getting
return values I expect
Data: dataframe. DF DF$Id $D $Year...
Id D Year Jan Feb Mar Apr May Jun Jul Aug Sep Oct
Nov Dec
11264402000 1 1980 NA NA NA NA NA 212 203 209 228 237 NA
I've tried both mean and colMean.
I did success with one attempt using mean, however if only have 1 year and
its a NA
then I get NaN ( which I can replace). I'll keep trying.
On Mon, Apr 26, 2010 at 12:26 AM, Petr PIKAL petr.pi...@precheza.cz wrote:
Hi
r-help-boun...@r-project.org napsal
That fails:
The manual says:
tapply(X, INDEX, FUN = NULL, ..., simplify = TRUE)
ArgumentsXan atomic object, typically a vector.INDEXlist of factors, each of
same length as X. The elements are coerced to factors by
as.factorhttp://127.0.0.1:31214/library/base/help/as.factor
.
my error says:
230
8 1.33 1989 232 233 238 239 231 NaN 215 NaN NaN NaN NaN 238
Replace the NaNs with NAs and that should do it
HTH,
Dennis
On Sun, Apr 25, 2010 at 9:52 PM, steven mosher mosherste...@gmail.comwrote:
Having some difficulties with understanding how tapply works and getting
return
PIKAL petr.pi...@precheza.cz wrote:
Hi
steven mosher mosherste...@gmail.com napsal dne 26.04.2010 10:21:37:
That fails:
The manual says:
tapply(X, INDEX, FUN = NULL, ..., simplify = TRUE)
Arguments
X
an atomic object, typically a vector.
INDEX
list of factors, each
Thanks dennis.
Is there a book on R u could recommend.
On Mon, Apr 26, 2010 at 7:12 PM, Dennis Murphy djmu...@gmail.com wrote:
Hi:
On Mon, Apr 26, 2010 at 8:01 AM, steven mosher
mosherste...@gmail.comwrote:
Thanks,
I was trying to stick with the base package and figure out
, drop=FALSE])
str(df[,1:15])
Regards
Petr
Thanks.
On Mon, Apr 26, 2010 at 2:43 AM, Petr PIKAL petr.pi...@precheza.cz
wrote:
Hi
steven mosher mosherste...@gmail.com napsal dne 26.04.2010 10:21:37:
That fails:
The manual says:
tapply(X, INDEX, FUN
I was talking with another guy on the list about this very topic.
A simple example would help.
first a sample C struct, and then how one would do the equivalent in R.
In the end i suppose one want to do a an 'array' of these structs, or list
of the structs.
On Sat, May 1, 2010 at 8:04 AM, Ted
Azua brave...@gmail.com wrote:
On May 1, 2010, at 6:48 PM, steven mosher wrote:
I was talking with another guy on the list about this very topic.
A simple example would help.
first a sample C struct, and then how one would do the equivalent in R.
In the end i suppose one want to do
:
On May 1, 2010, at 6:48 PM, steven mosher wrote:
I was talking with another guy on the list about this very topic.
A simple example would help.
first a sample C struct, and then how one would do the equivalent in
R.
In the end i suppose one want to do a an 'array' of these structs
Winsemius dwinsem...@comcast.netwrote:
On May 1, 2010, at 3:14 PM, steven mosher wrote:
maybe I can illustrate the problem by showing how a c programmer might
think
about the problem and the kinds of mistakes 'we' ( I) make when trying to
do
this in R
cstruct-function(int, bool){
+
+ myint
]
[1] 130
TADA!
On Sat, May 1, 2010 at 12:42 PM, David Winsemius dwinsem...@comcast.netwrote:
On May 1, 2010, at 3:14 PM, steven mosher wrote:
maybe I can illustrate the problem by showing how a c programmer might
think
about the problem and the kinds of mistakes 'we' ( I) make when trying
thanks ted..
being new the R thsi has been a huge help, espececially on the
Myint=myint thing... I assummed the name was just implicit.
On Sat, May 1, 2010 at 1:19 PM, Ted Harding ted.hard...@manchester.ac.ukwrote:
See below.
On 01-May-10 19:14:08, steven mosher wrote:
maybe I can
The situation arises where I open a file to write a data.frame to it. with
write.table.
multiple lines are written to the file and the file is kept in Append=TRUE
mode.
If one sets the col.names to the names of the variables being written, you
have output
that looks like this...
name1 name2
On Mon, May 3, 2010 at 5:19 PM, steven mosher mosherste...@gmail.com
wrote:
The situation arises where I open a file to write a data.frame to it.
with
write.table.
multiple lines are written to the file and the file is kept in
Append=TRUE
mode.
If one sets the col.names to the names
thanks.. worked
On Mon, May 3, 2010 at 3:24 PM, Ted Harding ted.hard...@manchester.ac.ukwrote:
On 03-May-10 21:19:34, steven mosher wrote:
The situation arises where I open a file to write a data.frame
to it. with write.table.
multiple lines are written to the file and the file is kept
Error in La.svd(x, nu, nv) : error code 1 from Lapack routine dgesdd
what resources are there to track down errors like this
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Given a text like
I want to be able to extract a matched regular expression from a piece of
text.
this apparently works, but is pretty ugly
# some html
test-/trtrth88958/ththAbcdsef/thth67.8S/thth68.9\nW/thth26m/th
# a pattern to extract 5 digits
pattern-[0-9]{5}
# regexpr returns a start
and we ask for
the contents of the first component using [[1]].
# 1 - sub
sub(.*(\\d{5}).*, \\1, test)
# 2 - strapply - see http://gsubfn.googlecode.com
library(gsubfn)
strapply(test, \\d{5}, c)[[1]]
On Wed, May 5, 2010 at 5:13 PM, steven mosher mosherste...@gmail.com
wrote:
Given a text
://gsubfn.googlecode.com
library(gsubfn)
strapply(test, \\d{5}, c)[[1]]
On Wed, May 5, 2010 at 5:13 PM, steven mosher mosherste...@gmail.com
wrote:
Given a text like
I want to be able to extract a matched regular expression from a piece of
text.
this apparently works, but is pretty ugly
/ththAbcdsef/thth67.8S/thth68.9\nW/thth26m/th
sub(.*(\\d{5}).*, \\1, test)
[1] 88958
R.version.string
[1] R version 2.10.1 (2009-12-14)
I also got the above in R 2.11.0 patched as well.
On Wed, May 5, 2010 at 5:55 PM, steven mosher mosherste...@gmail.com
wrote:
test
[1]
/trtrth88958
) Service Pack 2
On Wed, May 5, 2010 at 6:20 PM, steven mosher mosherste...@gmail.com
wrote:
Hmm.
I have R11 just downloaded fresh.
I'll reload a new session..and revert. I will note that I've had trouble
with \\d
which is why I was using [0-9]
MAC here.
On Wed, May 5, 2010 at 3:00 PM
Given a valid ftp address, is there a package that will allow me to get a
listing of the files/directory structure
on that site? RCurl looks to have this ability are there others?
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R-help@r-project.org
I'm looking for a function or package that will allow me to get a list of
the files at an ftp site.
RCurl looks promising. Are there other packages that have similar
functionality
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R-help@r-project.org
Given a matrix of m*n, I want to reorder it as a vector, using a row major
transpose.
so:
m-matrix(seq(1,48),nrow=6,byrow=T)
m
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
[1,]12345678
[2,]9 10 11 12 13 14 15 16
[3,] 17 18 19 20 21
32 33 34 35 36 37 38 39 40 41 42 43 44 45
[46] 46 47 48
On Sat, Jun 5, 2010 at 11:17 AM, Henrique Dallazuanna www...@gmail.comwrote:
Try this:
as.vector(t(m))
On Sat, Jun 5, 2010 at 3:12 PM, steven mosher mosherste...@gmail.comwrote:
Given a matrix of m*n, I want to reorder it as a vector
I bet that is what I did.
On Sat, Jun 5, 2010 at 11:54 AM, John Kane jrkrid...@yahoo.ca wrote:
m-matrix(seq(1,48),nrow=6,byrow=T)
as.vector(t(m))
gives me the correct result.
Any chance you may have already transformed m ?
--- On Sat, 6/5/10, steven mosher mosherste...@gmail.com wrote
# create a matrix with some random NAs in it
m-matrix(NA,nrow=15,ncol=14)
m[,3:14]-52
m[13,9]-NA
m[4:7,8]-NA
m[1:2,5]-NA
m[,2]-rep(1800:1804, by=3)
y-order(m[,2])
m-m[y,]
m[,1]-rep(1:3,by=5)
m
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13]
[,14]
[1,]1
, 2010 at 6:16 PM, Erik Iverson er...@ccbr.umn.edu wrote:
Hello,
steven mosher wrote:
# create a matrix with some random NAs in it
m-matrix(NA,nrow=15,ncol=14)
m[,3:14]-52
m[13,9]-NA
m[4:7,8]-NA
m[1:2,5]-NA
m[,2]-rep(1800:1804, by=3)
y-order(m[,2])
m-m[y,]
m[,1]-rep(1:3,by=5
Hi Gabor,
Not sure where to report this, but
Mac 10.5.8
R: 11.1
When you examine the zoo vignette and hit the back button, you get a hang.
I havent tested with other vignettes and cant imagine that is is specific to
yours
FWIW.
Did I mention that zoo is great. Thx for your work on it.
On
The following dataframe will illustrate the problem
DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep(NA,10),x4=seq(20,29,by=1))
DF$x3[5]-50
# we have a data frame. we are interested in the columns x2,x3,x4 which
contain sparse
# values and many NA.
DF
name x1 x2
Thanks, the dataframe, is indeed clever at preserving its dimensions.
I'll try your solution with the real data
On Tue, Jun 22, 2010 at 12:23 M, Petr PIKAL petr.pi...@precheza.cz wrote:
Hi
r-help-boun...@r-project.org napsal dne 22.06.2010 08:28:04:
The following dataframe will illustrate
Hmm
DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep(NA,10),x4=seq(20,29,by=1))
DF$x3[5]-50
mask-apply(sample,2,%in%, target)
DF
name x1 x2 x3 x4
1 1 A 10 NA 20
2 1 A 11 NA 21
3 2 A 12 NA 22
4 2 A 13 NA 23
5 3 A 14 50 24
6 3 A 15 NA
Thanks for the solution
On Tue, Jun 22, 2010 at 1:02 AM, Peter Ehlers ehl...@ucalgary.ca wrote:
On 2010-06-22 1:45, steven mosher wrote:
Hmm
DF-data.frame(name=rep(1:5,each=2),x1=rep(A,10),x2=seq(10,19,by=1),x3=rep(NA,10),x4=seq(20,29,by=1))
DF$x3[5]-50
mask-apply(sample,2
Thomas,
How popular is R inside of NOAA?
On Thu, Jul 1, 2010 at 11:25 AM, Thomas Adams thomas.ad...@noaa.gov wrote:
OK
My Grandfather, who was a farmer, was outstanding in his field
Cheers
Murray M Cooper, PhD wrote:
For what its worth!
A good friend who also happens to be
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