?make.names perhaps.
On Fri, Sep 2, 2011 at 4:13 PM, Durant, James T. (ATSDR/DTEM/PRMSB)
h...@cdc.gov wrote:
Greetings -
I am working on some data that contain chemical names with air
concentrations, and I am creating a data frame with date/time and each
chemical having its own column.
sapply(a, `[`, 1)
On Wed, Aug 24, 2011 at 12:18 AM, Chee Chen chee.c...@yahoo.com wrote:
Dear All,
I would like to know, beside writing a function and then apply it to a list,
or using a for loop, whether there is a one-line command to do the following.
Suppose we have a list, each of whose
To open a website on the default browser:
system(open http://www.google.com;)
Gustavo.
On Tue, May 24, 2011 at 7:56 PM, jbrezmes jesus.brez...@gmail.com wrote:
I would like to be able to call external programs such as Java scripts (*.jar
files) or bring up the browser to a given direction.
This might be a bit quicker with larger vectors:
f - function(x, y) sum(x y)
vf - Vectorize(f, x)
vf(x, y)
On Thu, Apr 14, 2011 at 5:37 PM, Marc Schwartz marc_schwa...@me.com wrote:
On Apr 14, 2011, at 2:34 PM, Kevin Ummel wrote:
Take vector x and a subset y:
x=1:10
y=c(4,5,7,9)
For
Search for lavaan, sem, and OpenMx.
On Mon, Mar 21, 2011 at 12:34 AM, rvohen bingbingzhan...@126.com wrote:
thank you ! I will try it !
--
View this message in context:
http://r.789695.n4.nabble.com/confirmatory-factor-analysis-program-in-R-tp3386133p3392279.html
Sent from the R help
Your model is saturated.
I think lavaan calculates the number of degrees of freedom this way:
DF = n*(n + 1)/2 - t - n.fix*(n.fix + 1)/2
n = number of variables
t = number of free parameters
n.fix = number of fixed exogenous variables
So, if you fix the exogenous variables, as in mimic =
?URLencode
On Thu, Nov 25, 2010 at 3:53 PM, Tal Galili tal.gal...@gmail.com wrote:
Hello all,
I would like some R function that can translate a string to a URL encoding
(see here: http://www.w3schools.com/tags/ref_urlencode.asp)
Is it implemented? (I wasn't able to find any reference to it)
Perhaps something like this:
a$d - ifelse(duplicated(a$a), 0, 1)
On Tue, Nov 23, 2010 at 1:33 PM, Joel joda2...@student.uu.se wrote:
Is there any similar function in R to the first. in SAS?
What it dose is:
Lets say we have this table:
a b c
1 1 5
1 0 2
2 0 2
2 0 NA
2 9 2
Please consider this matrix:
x - structure(c(5, 4, 3, 2, 1, 6, 3, 2, 1, 0, 3, 2, 1, 0, 0, 2, 1,
1, 0, 0, 2, 0, 0, 0, 0), .Dim = c(5L, 5L))
For each pair of columns, I want to calculate the proportion of entries
different than 0 in column j (i j) that have lower values than the entries
in the
This function might be helpful:
bleh - function(a, b) {
where - list()
matches - 0
first - which(a == b[1])
for (i in first) {
seq.to.match - seq(i, length = length(b))
if (identical(a[seq.to.match], b)) {
matches - matches + 1
where[[matches]] - seq.to.match
}
}
Hello,
I've been unsuccessfully trying to reproduce a sem from Grace et al.
(2010) published in Ecological Monographs:
http://www.esajournals.org/doi/pdf/10.1890/09-0464.1
The model in question is presented in Figure 8, page 81. The errors
that I've been getting are:
1. Using a correlation
You can also try this:
x[,-(which(colSums(x) == 0))]
Cheers,
Gustavo.
On Wed, Jan 14, 2009 at 8:01 PM, Anthony Dick ad...@uchicago.edu wrote:
Hello-
I would like to remove the columns of a matrix that contain all zeros. For
example, from
x-matrix(c(1,5,3,2,1,4,0,0,0), ncol=3,nrow=3)
I
Sorry for the double post, but this is probably faster:
x[, colSums(x) != 0]
On Wed, Jan 14, 2009 at 8:22 PM, Gustavo Carvalho
gustavo.bi...@gmail.com wrote:
You can also try this:
x[,-(which(colSums(x) == 0))]
Cheers,
Gustavo.
On Wed, Jan 14, 2009 at 8:01 PM, Anthony Dick ad
Hello rafamoral,
Try this:
ifelse(is.na(x),0,x)
On Wed, Jan 14, 2009 at 8:32 PM, rafamoral rafa_moral2...@yahoo.com.br wrote:
I have a dataset which contains some missing values, and I need to replace
them with zeros. I tried using the following:
x - matrix(data=rep(c(1,2,3,NA),6), ncol=6,
Hello,
Something like this should work:
table(test$V1[!test$V2 %in% c(NM,QC)])
Cheers,
Gustavo.
On Wed, Dec 24, 2008 at 3:06 AM, Gundala Viswanath gunda...@gmail.com wrote:
Dear all,
I have the following data frame:
V1 V2
aaachr1
aaachr2
aaaNM
aaaQC
aaachr10
Hello,
You can probably extract a .tar.gz using 7zip on Windows.
Regards,
Gustavo.
On Mon, Dec 15, 2008 at 8:07 PM, Farrel Buchinsky fjb...@gmail.com wrote:
I saw a thread from September 24 in which Duncan Temple Lang told us:
- The package currently has no Rd files, but there is a brief
Take a look at ?any.
On Thu, Dec 11, 2008 at 3:11 PM, David B. Thompson, Ph.D., P.E.,
D.WRE, CFM [EMAIL PROTECTED] wrote:
OK, this should be trivial but I'm not finding it. I want to compress the
test,
if (i==7 | i==10 | i==30 | i==50) {}
into something like
if (i in c(7,10,30,50)) {}
Hello,
An alternative to round():
isTRUE(all.equal((2.3-1.3),1))
Regards,
Gustavo.
On Wed, Dec 10, 2008 at 3:12 PM, Stephan Kolassa [EMAIL PROTECTED] wrote:
Hi Emma,
unfortunately, rounding variables before taking the difference will not
solve your problem, because the *rounded* variables
Hello,
Anyone knows how can I do this in a cleaner way?
mynumber = 1001
as.numeric(unlist(strsplit(as.character(mynumber),)))
[1] 1 0 0 1
Thanks in advance,
Gustavo
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Hello,
You assigned 53 to c, not cc. Also, take a look at this:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-doesn_0027t-R-think-these-numbers-are-equal_003f
On Tue, Dec 9, 2008 at 9:36 PM, Renny Li [EMAIL PROTECTED] wrote:
Hi,
I am trying to compare two values using == operand, please
Thanks a lot!
On Fri, Dec 5, 2008 at 5:54 PM, Gabor Grothendieck
[EMAIL PROTECTED] wrote:
Try this:
dir()[!file.info(dir())$isdir]
On Fri, Dec 5, 2008 at 2:30 PM, Gustavo Carvalho
[EMAIL PROTECTED] wrote:
Is there a way to list only the files in a given directory without
passing pattern
Is there a way to list only the files in a given directory without
passing pattern=... to list.files()?
On Fri, Dec 5, 2008 at 5:10 PM, Kyle. [EMAIL PROTECTED] wrote:
Thanks, Barry. I'll use that in the future.
---Kyle.
On Fri, Dec 5, 2008 at 11:01 AM, Barry Rowlingson
[EMAIL PROTECTED]
If I understood your problem correctly, you are just missing a couple of things:
q = which(apply(p.unique,2,function(x)all(x==r)) == TRUE)
Also, you should probably change this line:
if(q0){c=p.unique[,q]};{c=c(0,0,0)}
To something like this:
if(length(q)0){c=p.unique[,q]};{c=c(0,0,0)}
Hello,
Take a look at this course:
http://www.r4all.group.shef.ac.uk/index.html
I don't think they teach tools for working with the genome, but it
might be helpful anyway.
On Thu, Nov 20, 2008 at 11:16 AM, Peter Saffrey [EMAIL PROTECTED] wrote:
(apologies if this is the wrong list)
I'm a
Take a look at vif in the package car.
On Wed, Nov 19, 2008 at 10:00 PM, Crystal McRae [EMAIL PROTECTED] wrote:
I am running a logistic regression model with a random effect using lmer. I
am uncertain how to check for collinearity between my parameters. I have
already run cor() and
xdg utils is probably not being recognized because you compiled it
from source. The R rpm is looking for the xdg utils package. I'm not
familiar with yum, but I think you can try to force the installation:
rpm -ivh --force (or something like that) /data/R-2.8.0-1.rh4.x86_64.rpm
On Tue, Nov 18,
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