Hello David,
Let me try again, I don't think this was the best post ever I've made :-)
Hopefully this is clearer, or otherwise I may break this up into
three separate simple queries as this may be too long.
== is not an assignment operator in R, so the answer is that it
would do neither. -
On Apr 26, 2009, at 7:48 AM, Esmail wrote:
Hello David,
Let me try again, I don't think this was the best post ever I've
made :-)
Hopefully this is clearer, or otherwise I may break this up into
three separate simple queries as this may be too long.
== is not an assignment operator in
David Winsemius wrote:
Yes. As I said before I am going to refrain from posting speculation
until you provide valid R code
that will create an object that can be the subject of operations.
The code I have provided works, here is a run that may prove helpful:
POP_SIZE = 6
LEN = 8
On Apr 26, 2009, at 9:43 AM, Esmail wrote:
David Winsemius wrote:
Yes. As I said before I am going to refrain from posting
speculation until you provide valid R code
that will create an object that can be the subject of operations.
The code I have provided works, here is a run that may
I want to (1) create a deep copy of pop,
I have already said *I* do not know how to create a deep copy in R.
Creating a deep copy is easy, because all copies are deep copies.
You need to try very hard to create a reference in R.
Hadley
--
http://had.co.nz/
My understanding of the OP's request was for some sort of copy which
did change when entries in the original were changed; the sort of
behavior that might be seen in a spreadsheet that had a copy by
reference.
On Apr 26, 2009, at 11:28 AM, hadley wickham wrote:
I want to (1) create a
David,
Good news! It seems that R has deep copy by default. I ran this simplified
test and it seems I can change 'pop' without changing the saved version.
POP_SIZE = 4
LEN = 8
pop=create_pop_2(POP_SIZE, LEN)
cat('printing original pop\n')
print(pop)
keep_pop = pop
pop[1,1] = 99
cat('printing
hadley wickham wrote:
I want to (1) create a deep copy of pop,
I have already said *I* do not know how to create a deep copy in R.
Creating a deep copy is easy, because all copies are deep copies.
You need to try very hard to create a reference in R.
Hi Hadley
Right you are .. I discovered
In that case, you would want a shallow copy, and you'd need to jump
through a lot of hoops to do that in R.
Hadley
On Sun, Apr 26, 2009 at 10:35 AM, David Winsemius
dwinsem...@comcast.net wrote:
My understanding of the OP's request was for some sort of copy which did
change when entries in the
David Winsemius
dwinsem...@comcast.net wrote:
My understanding of the OP's request was for some sort of copy which did
change when entries in the original were changed; the sort of behavior that
might be seen in a spreadsheet that had a copy by reference.
You misunderstood (my phrasing
Hello all,
I have the following function call to create a matrix of POP_SIZE rows
and fill it with bit strings of size LEN:
pop=create_pop_2(POP_SIZE, LEN)
I have 3 questions:
(1) If I did
keep_pop[1:POP_SIZE] == pop[1:POP_SIZE]
to keep a copy of the original data structure
On Apr 26, 2009, at 12:28 AM, Esmail wrote:
Hello all,
I have the following function call to create a matrix of POP_SIZE rows
and fill it with bit strings of size LEN:
pop=create_pop_2(POP_SIZE, LEN)
Are you construction a vector or a matrix? What are the dimensions of
your matrix?
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