Hello,
In my ongoing quest to develop a best model, I'm testing various forms
of SVM to see which is best for my application.
I have been using the SVM from the e1071 library without problem for
several weeks.
Now, I'm interested in RVM and LSSVM to see if I get better performance.
When
Howdy,
On Aug 19, 2009, at 2:54 PM, Noah Silverman wrote:
Hi Steve,
No custom kernel. (This is the exact same data that I call svm
with. svm works without a complaint.)
traindata is just a dataframe of numerical attributes
trainlabels is just a vector of labels. (good, bad)
Then I call
Hi,
On Aug 19, 2009, at 1:27 PM, Noah Silverman wrote:
Hello,
In my ongoing quest to develop a best model, I'm testing various
forms of SVM to see which is best for my application.
I have been using the SVM from the e1071 library without problem for
several weeks.
Now, I'm interested
Hi Steve,
No custom kernel. (This is the exact same data that I call svm with.
svm works without a complaint.)
traindata is just a dataframe of numerical attributes
trainlabels is just a vector of labels. (good, bad)
Then I call
model - rvm(x,y)
On 8/19/09 11:50 AM, Steve Lianoglou
Steve,
That makes sense, except that x is a data.frame with about 70 columns.
So I don't see how it would convert to a list.
-N
On 8/19/09 12:09 PM, Steve Lianoglou wrote:
Howdy,
On Aug 19, 2009, at 2:54 PM, Noah Silverman wrote:
Hi Steve,
No custom kernel. (This is the exact same data
Steve,
That makes sense, except that x is a data.frame with about 70
columns. So I don't see how it would convert to a list.
Yeah ... not sure if that's what happening (R class relationships/
testing is still a bit of a mystery to me), but see:
R df - data.frame(a=1:10,b=1:10)
R is(df)
On Aug 19, 2009, at 3:17 PM, Steve Lianoglou wrote:
Steve,
That makes sense, except that x is a data.frame with about 70
columns. So I don't see how it would convert to a list.
Yeah ... not sure if that's what happening (R class relationships/
testing is still a bit of a mystery to me),
Steve,
Not sure what to do with this.
I have a data.frame. Don't know how to convert it to a list.
Does anybody else have any input on this?
On 8/19/09 12:17 PM, Steve Lianoglou wrote:
Steve,
That makes sense, except that x is a data.frame with about 70
columns. So I don't see how it
On Aug 19, 2009, at 6:11 PM, Noah Silverman wrote:
Steve,
Not sure what to do with this.
I have a data.frame. Don't know how to convert it to a list.
A data.frame is a list.
Does anybody else have any input on this?
On 8/19/09 12:17 PM, Steve Lianoglou wrote:
Steve,
That makes
Thanks David,
Then, do you have any clue why RVM or LSSVM would be generating an error?
My original post was:
When running RVM or LSSVM on the exact same data as the SVM{e1071}, I
get an error that I don't understand:
Error in .local(x, ...) : kernel must inherit from class 'kernel'
Any
On Aug 19, 2009, at 6:30 PM, Noah Silverman wrote:
Thanks David,
Then, do you have any clue why RVM or LSSVM would be generating an
error?
No.
My original post was:
When running RVM or LSSVM on the exact same data as the SVM{e1071},
I get an error that I don't understand:
Error in
I think that the issue is that this version of rvm is only for
regression (and, if I understood correctly, you are passing class
labels).
Max
On Aug 19, 2009, at 6:36 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Aug 19, 2009, at 6:30 PM, Noah Silverman wrote:
Thanks David,
Ding! We have a winner :)
Thanks Max, that's exactly the problem. I don't know how I missed that.
I'm looking for different modeling functions to try for best predictive
results. An SVM isn't bad, but I'm looking for more. The RVM sounded
interesting, but I guess it won't work for my
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