Dimitri Shvorob wrote:
df = structure(list(t = structure(c(1033963406.044, 1033974144.847,
+ 1033988418.836), class = c(POSIXt, POSIXct))), .Names = t, row.names
= c(NA,
+ 3L), class = data.frame)
df$min = trunc(df$t,units=mins)
does not work, Jeff; you will see that my original post
Dimitri Shvorob wrote:
.. One issue with the solution proposed by Jeff is that the transformed
column does not have the original's type:
x = structure(list(time = structure(c(1020232904.818, 1020232904.818
), class = c(POSIXt, POSIXct), tzone = ), price = c(321,
323.5), minute = c(1020232860,
On Dec 25, 2010, at 2:25 PM, Dimitri Shvorob wrote:
df = structure(list(t = structure(c(1033963406.044, 1033974144.847,
+ 1033988418.836), class = c(POSIXt, POSIXct))), .Names = t,
row.names
= c(NA,
+ 3L), class = data.frame)
df$min = trunc(df$t,units=mins)
does not work,
??? seems to
df = structure(list(t = structure(c(1033963406.044, 1033974144.847,
+ 1033988418.836), class = c(POSIXt, POSIXct))), .Names = t, row.names
= c(NA,
+ 3L), class = data.frame)
df$min = trunc(df$t,units=mins)
does not work, Jeff; you will see that my original post suggests familiarity
with
.. One issue with the solution proposed by Jeff is that the transformed
column does not have the original's type:
x = structure(list(time = structure(c(1020232904.818, 1020232904.818
), class = c(POSIXt, POSIXct), tzone = ), price = c(321,
323.5), minute = c(1020232860, 1020232860)), .Names =
Dimitri Shvorob wrote:
Nor would I call this much of an improvement in clarity... what about
min? You want to know the minimum?
LOL. (And apologies for the insensitivity). Thank you for help, Jeff. This
works, but I am still curious to see a solution based on trunc, if anyone
can find it.
df$dt - as.Date(df$t)
Thank you, David, but I need a *time* value. day was a confusing special
case; how about min?
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Dimitri Shvorob wrote:
df$dt - as.Date(df$t)
Thank you, David, but I need a *time* value. day was a confusing special
case; how about min?
Your original question was NOT clear on this point... it was not David's
fault your question was confusing, and you haven't even hinted at an
Nor would I call this much of an improvement in clarity... what about
min? You want to know the minimum?
LOL. (And apologies for the insensitivity). Thank you for help, Jeff. This
works, but I am still curious to see a solution based on trunc, if anyone
can find it.
--
View this message in
Can someone please fix this snippet? (i.e. append to the dataframe a column
containing truncated time value)?
df = structure(list(t = structure(c(1033963406.044, 1033974144.847,
1033988418.836), class = c(POSIXt, POSIXct))), .Names = t, row.names =
c(NA,
3L), class = data.frame)
# Try 1
On Nov 21, 2010, at 3:52 PM, Dimitri Shvorob wrote:
Can someone please fix this snippet? (i.e. append to the dataframe a
column
containing truncated time value)?
df = structure(list(t = structure(c(1033963406.044, 1033974144.847,
1033988418.836), class = c(POSIXt, POSIXct))), .Names = t,
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