For the example df below this also works:
library(lattice); library(zoo)
xyplot(zoo(df[1:4], df$x), type = p)
On Sun, Sep 6, 2009 at 12:51 AM, David Winsemiusdwinsem...@comcast.net wrote:
I'm not exactly sure what structure df has. Here's my effort to duplicate
it:
df -
On Sat, Sep 5, 2009 at 10:43 PM, Bryan Hansonhan...@depauw.edu wrote:
Thanks David, your way of constructing df is much more compact than what I
was using, so I've incorporated it. I also had my rows and columns
transposed relative to how xyplot wanted them (though I had tested for that,
On Sep 6, 2009, at 12:51 AM, David Winsemius wrote:
I'm not exactly sure what structure df has. Here's my effort to
duplicate it:
df - data.frame(y=matrix(rnorm(24), nrow=6), x=1:6)
df
y.1y.2y.3y.4 x
1 0.1734636 0.2348417 -1.2375648 -1.3246439 1
2
Hello R Folks...
I have a list with the following structure:
str(df)
List of 3
$ y: num [1:4, 1:1242] -0.005379 0.029874 -0.023274 0.000655 -0.004537
..
$ x: num [1:1242] 501 503 505 507 509 ...
$ names: Factor w/ 4 levels PC Loading 1,..: 1 2 3 4
I want to plot each row of df$y
I'm not exactly sure what structure df has. Here's my effort to
duplicate it:
df - data.frame(y=matrix(rnorm(24), nrow=6), x=1:6)
df
y.1y.2y.3y.4 x
1 0.1734636 0.2348417 -1.2375648 -1.3246439 1
2 1.9551669 -1.1027262 -0.7307332 0.3953752 2
3 -0.7645778
Thanks David, your way of constructing df is much more compact than what I
was using, so I've incorporated it. I also had my rows and columns
transposed relative to how xyplot wanted them (though I had tested for that,
other problems interfered).
In my case, I may have varying numbers of y
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