Given a long zoo matrix, the goal is to sweep out a statistic from the
entire length of the
sequences.
longzoomatrix-zoo(matrix(rnorm(720),ncol=6),as.yearmon(outer(1900,seq(0,length=120)/12,+)))
cnames-c(12345,23456,34567,45678,56789,67890)
colnames(longzoomatrix)-cnames
longzoomatrix[1:24,]
On Wed, Aug 11, 2010 at 12:22 PM, steven mosher mosherste...@gmail.com wrote:
Given a long zoo matrix, the goal is to sweep out a statistic from the
entire length of the
sequences.
longzoomatrix-zoo(matrix(rnorm(720),ncol=6),as.yearmon(outer(1900,seq(0,length=120)/12,+)))
The colMeans comes closest,
for a single series the assume you have 100 years of monthly data.
The mean you want to scale by is the mean for a restricted period in the
center
of the series.. say 1950-1960
for this period you have the average jan (1950-1960) average feb, ect.
your final series
On Wed, Aug 11, 2010 at 2:38 PM, steven mosher mosherste...@gmail.com wrote:
The colMeans comes closest,
for a single series the assume you have 100 years of monthly data.
The mean you want to scale by is the mean for a restricted period in the
center
of the series.. say 1950-1960
for this
On Wed, Aug 11, 2010 at 2:44 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Wed, Aug 11, 2010 at 2:38 PM, steven mosher mosherste...@gmail.com wrote:
The colMeans comes closest,
for a single series the assume you have 100 years of monthly data.
The mean you want to scale by is the
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