[R] Custom Sort Character and Numeric
Im trying to do a custom sort in this order:
1) Numeric digit furthest right;
2) Alphabetical second furthest to the right;
3) Alphabetical the rest of the string beginning with the first character;
The example code I'm using is an array that follows:
/myArray - c('AFP9','AFR9','TLQP7','AFS9','AFR8','AFP8','AFS7','TLQS8')/
The output I desire is:
/myArray
[1] AFS7 AFP8 AFR8 AFP9 AFR9 AFS9 TLQP7 TLQS8 /
What I'm thinking is writing a function that will order it by analyzing it
from right to left. Ideally there would be a way to look at the individual
strings like the formula in Excel =RIGHT(cell, 1) and drop the furthest
right then do the same thing to the next character. I've been looking into
custom sort for R and haven't found much. Any idea what this function would
look like? Possibly a while loop? Each string would have a length of at
least 3, possibly longer. Thank you in advance.
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Re: [R] Custom Sort Character and Numeric
Try this, but I get a different order especially based on the last digit
myArray - c('AFP9','AFR9','TLQP7','AFS9','AFR8','AFP8','AFS7','TLQS8')
# create a sort key
key - sub(^(.*)(.)(.)$, \\3\\2\\1, myArray)
key
[1] 9PAF 9RAF 7PTLQ 9SAF 8RAF 8PAF 7SAF 8STLQ
# sort, but don't get your output
myArray[order(key)]
[1] TLQP7 AFS7 AFP8 AFR8 TLQS8 AFP9 AFR9 AFS9
On Sun, Oct 16, 2011 at 4:47 AM, swonder03 ramey.ste...@gmail.com wrote:
Im trying to do a custom sort in this order:
1) Numeric digit furthest right;
2) Alphabetical second furthest to the right;
3) Alphabetical the rest of the string beginning with the first character;
The example code I'm using is an array that follows:
/myArray - c('AFP9','AFR9','TLQP7','AFS9','AFR8','AFP8','AFS7','TLQS8')/
The output I desire is:
/myArray
[1] AFS7 AFP8 AFR8 AFP9 AFR9 AFS9 TLQP7 TLQS8 /
What I'm thinking is writing a function that will order it by analyzing it
from right to left. Ideally there would be a way to look at the individual
strings like the formula in Excel =RIGHT(cell, 1) and drop the furthest
right then do the same thing to the next character. I've been looking into
custom sort for R and haven't found much. Any idea what this function would
look like? Possibly a while loop? Each string would have a length of at
least 3, possibly longer. Thank you in advance.
--
View this message in context:
http://r.789695.n4.nabble.com/Custom-Sort-Character-and-Numeric-tp3909058p3909058.html
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Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
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Re: [R] Custom Sort Character and Numeric
Here is another solution that gets the order you posted:
myArray - c('AFP9','AFR9','TLQP7','AFS9','AFR8','AFP8','AFS7','TLQS8')
# create a sort key
key - sub(^(.*)(.)(.)$, \\3\\2\\1, myArray)
key
[1] 9PAF 9RAF 7PTLQ 9SAF 8RAF 8PAF 7SAF 8STLQ
# sort, but don't get your output
myArray[order(key)]
[1] TLQP7 AFS7 AFP8 AFR8 TLQS8 AFP9 AFR9 AFS9
# to get your output, new key
newKey - sub(^(.*)(.)(.)$, \\1\\3\\2, myArray)
newKey
[1] AF9P AF9R TLQ7P AF9S AF8R AF8P AF7S TLQ8S
myArray[order(newKey)]
[1] AFS7 AFP8 AFR8 AFP9 AFR9 AFS9 TLQP7 TLQS8
On Sun, Oct 16, 2011 at 4:47 AM, swonder03 ramey.ste...@gmail.com wrote:
Im trying to do a custom sort in this order:
1) Numeric digit furthest right;
2) Alphabetical second furthest to the right;
3) Alphabetical the rest of the string beginning with the first character;
The example code I'm using is an array that follows:
/myArray - c('AFP9','AFR9','TLQP7','AFS9','AFR8','AFP8','AFS7','TLQS8')/
The output I desire is:
/myArray
[1] AFS7 AFP8 AFR8 AFP9 AFR9 AFS9 TLQP7 TLQS8 /
What I'm thinking is writing a function that will order it by analyzing it
from right to left. Ideally there would be a way to look at the individual
strings like the formula in Excel =RIGHT(cell, 1) and drop the furthest
right then do the same thing to the next character. I've been looking into
custom sort for R and haven't found much. Any idea what this function would
look like? Possibly a while loop? Each string would have a length of at
least 3, possibly longer. Thank you in advance.
--
View this message in context:
http://r.789695.n4.nabble.com/Custom-Sort-Character-and-Numeric-tp3909058p3909058.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
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[R] Custom Sort on a Table object
Greetings - I've got the following table (the result of a two-way table operation): f m 0 to 5 11.328000 6.900901 15 to 24 6.100570 5.190058 25 to 34 9.428707 6.567280 35 to 4410.462158 7.513270 45 to 54 7.621988 5.692905 5 to 14 6.502741 6.119663 55 to 64 5.884737 4.319905 65 to 74 5.075606 4.267810 75 to 84 4.702020 3.602362 85 and over 4.75 3.877551 Which I'd like to sort so that the column of rownames (which represent age bands) and their corresponding f and m values appear in logical order. I've tried a bunch of things; merging with a separate df bearing Age Bands paired with a sequence number, stripping out row vectors and rbind-ing a new df, etc., all to no avail. It seems to be very difficult to spin a table object into a data frame without being stuck with the tables rownames! I haven't yet tried writing to an external file and then reading it back (so as to get R to forget that it's a Table object), and then merging on the group bands to pull in a sequence vector upon which to do an order(). Seems like it should be easier. Many thanks, Galen [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Custom Sort on a Table object
Here is a one way. tab fm 0 to 5 11.328000 6.900901 15 to 24 6.100570 5.190058 25 to 34 9.428707 6.567280 35 to 4410.462158 7.513270 45 to 54 7.621988 5.692905 5 to 14 6.502741 6.119663 55 to 64 5.884737 4.319905 65 to 74 5.075606 4.267810 75 to 84 4.702020 3.602362 85 and_over 4.75 3.877551 lowAge - as.numeric(sapply(strsplit(rownames(tab), ), [, 1)) (tab - tab[order(lowAge), ]) fm 0 to 5 11.328000 6.900901 5 to 14 6.502741 6.119663 15 to 24 6.100570 5.190058 25 to 34 9.428707 6.567280 35 to 4410.462158 7.513270 45 to 54 7.621988 5.692905 55 to 64 5.884737 4.319905 65 to 74 5.075606 4.267810 75 to 84 4.702020 3.602362 85 and over 4.75 3.877551 -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Galen Moore Sent: Tuesday, 7 June 2011 1:23 PM To: r-help@r-project.org Subject: [R] Custom Sort on a Table object Greetings - I've got the following table (the result of a two-way table operation): f m 0 to 5 11.328000 6.900901 15 to 24 6.100570 5.190058 25 to 34 9.428707 6.567280 35 to 4410.462158 7.513270 45 to 54 7.621988 5.692905 5 to 14 6.502741 6.119663 55 to 64 5.884737 4.319905 65 to 74 5.075606 4.267810 75 to 84 4.702020 3.602362 85 and over 4.75 3.877551 Which I'd like to sort so that the column of rownames (which represent age bands) and their corresponding f and m values appear in logical order. I've tried a bunch of things; merging with a separate df bearing Age Bands paired with a sequence number, stripping out row vectors and rbind-ing a new df, etc., all to no avail. It seems to be very difficult to spin a table object into a data frame without being stuck with the tables rownames! I haven't yet tried writing to an external file and then reading it back (so as to get R to forget that it's a Table object), and then merging on the group bands to pull in a sequence vector upon which to do an order(). Seems like it should be easier. Many thanks, Galen [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] custom sort?
Steve Jaffe wrote: hmm, that is what I was afraid of. I considered that but thought to myself, surely there must be an easier way. I wonder why this feature isn't available. It's there in scripting languages, like perl, but also in hardcore languages like C++ where std::sort and sorted containers allow the user to provide a comparison function (even for builtin types like int). It's hard to believe that you have to jump through more hoops to do a custom sort in R than in C++ ... You put a class on the vector... there has been some discussion on sorting here some time ago; r folks do not seem to accept the idea of sorting as a generic task, with the sorting algorithm a separate thing from the comparison operator and the type of the elements to be sorted. (hence you can't sort arbitrary lists, for example.) you may want to lookup the archives. vQ __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] custom sort?
Duncan Murdoch wrote:
On 28/05/2009 6:06 PM, Steve Jaffe wrote:
hmm, that is what I was afraid of. I considered that but thought to
myself,
surely there must be an easier way. I wonder why this feature isn't
available. It's there in scripting languages, like perl, but also in
hardcore languages like C++ where std::sort and sorted containers
allow
the user to provide a comparison function (even for builtin types
like int).
It's hard to believe that you have to jump through more hoops to do a
custom
sort in R than in C++ ...
You put a class on the vector...
Each of the things I described to you would take about a line of code,
plus the logic of the comparisons. So the hoops R makes you jump
through amount to 2-4 extra lines of code. C++ is probably going to
take at least that much.
it's not just about the amount of code. defining a comparator is
conceptually different from defining a class to sort, e.g., regular
numbers or strings. passing an additional comparator argument to a
sorting routine is more convenient and readable than wrapping an object
into a dummy class for the mere purpose of sorting it.
You put a class on the vector (e.g. using class(x) - myvector), then
define a conversion to numeric (e.g. xtfrm.myvector) or actual
comparison methods (you'll need ==.myvector, .myvector, and
is.na.myvector).
x = 3:1
class(x) = 'foo'
'==.foo' = function(...) FALSE
'.foo' = function(...) FALSE
sort(x)
# 1 2 3
'==.foo' = function(...) TRUE
'.foo' = function(...) TRUE
sort(x)
# 1 2 3
'==.foo' = function(...) TRUE
'.foo' = function(...) FALSE
sort(x)
# 1 2 3
'==.foo' = function(...) FALSE
'.foo' = function(...) TRUE
sort(x)
# 1 2 3
hmm, doesn't seem to work. it also won't do for the case when lists
('generic vectors') are to be sorted:
x = structure(list(1,2,3), class='foo')
sort(x)
# Error in switch(ties.method, average = , min = , max =
.Internal(rank(x[!nas], :
# unimplemented type 'list' in 'greater'
vQ
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Re: [R] custom sort?
Stavros Macrakis wrote:
I agree that it is surprising that R doesn't provide a sort function with a
comparison function as argument. Perhaps that is partly because calling out
to a function for each comparison is relatively expensive; R prefers vector
operations.
That said, many useful custom sorts are easy to define by reordering,
possibly using the 'order' function, e.g.
rr - function (v) v[order( v %% 10 , v 500, - v ) ]
# sort first by last digit (ascending), then by whether 500, then by
magnitude (descending)
duncan's suggestion (then define a conversion to numeric) and your
suggestion (using the 'order' function) can be combined to what could
be considered a form of the schwartzian tranform, e.g.:
stsort = function(x, transform, ...)
x[order(transform(x), ...)]
stsort(1:3, `-`)
# 3 2 1
stsort(c('foo', 'f', 'fo'), nchar)
# f fo foo
...
vQ
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[R] custom sort?
Sounds simple but haven't been able to find it in docs: is it possible to sort a vector using a user-defined comparison function? Seems it must be, but sort doesn't seem to provide that option, nor does order sfaics -- View this message in context: http://www.nabble.com/custom-sort--tp23770565p23770565.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] custom sort?
On 28/05/2009 5:34 PM, Steve Jaffe wrote: Sounds simple but haven't been able to find it in docs: is it possible to sort a vector using a user-defined comparison function? Seems it must be, but sort doesn't seem to provide that option, nor does order sfaics You put a class on the vector (e.g. using class(x) - myvector), then define a conversion to numeric (e.g. xtfrm.myvector) or actual comparison methods (you'll need ==.myvector, .myvector, and is.na.myvector). Duncan Murdoch __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] custom sort?
hmm, that is what I was afraid of. I considered that but thought to myself, surely there must be an easier way. I wonder why this feature isn't available. It's there in scripting languages, like perl, but also in hardcore languages like C++ where std::sort and sorted containers allow the user to provide a comparison function (even for builtin types like int). It's hard to believe that you have to jump through more hoops to do a custom sort in R than in C++ ... You put a class on the vector... -- View this message in context: http://www.nabble.com/custom-sort--tp23770565p23770964.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] custom sort?
I agree that it is surprising that R doesn't provide a sort function with a comparison function as argument. Perhaps that is partly because calling out to a function for each comparison is relatively expensive; R prefers vector operations. That said, many useful custom sorts are easy to define by reordering, possibly using the 'order' function, e.g. rr - function (v) v[order( v %% 10 , v 500, - v ) ] # sort first by last digit (ascending), then by whether 500, then by magnitude (descending) set.seed(2009) rr(sample(1000,30)) [1] 840 670 580 140 100 10 991 901 881 561 231 71 722 662 432 222 32 473 53 [20] 24 645 796 86 697 607 567 397 257 77 818 568 428 198 619 569 479 439 299 Hope this helps, -s On Thu, May 28, 2009 at 6:06 PM, Steve Jaffe sja...@riskspan.com wrote: hmm, that is what I was afraid of. I considered that but thought to myself, surely there must be an easier way. I wonder why this feature isn't available. It's there in scripting languages, like perl, but also in hardcore languages like C++ where std::sort and sorted containers allow the user to provide a comparison function (even for builtin types like int). It's hard to believe that you have to jump through more hoops to do a custom sort in R than in C++ ... You put a class on the vector... -- View this message in context: http://www.nabble.com/custom-sort--tp23770565p23770964.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] custom sort?
On 28/05/2009 6:06 PM, Steve Jaffe wrote: hmm, that is what I was afraid of. I considered that but thought to myself, surely there must be an easier way. I wonder why this feature isn't available. It's there in scripting languages, like perl, but also in hardcore languages like C++ where std::sort and sorted containers allow the user to provide a comparison function (even for builtin types like int). It's hard to believe that you have to jump through more hoops to do a custom sort in R than in C++ ... You put a class on the vector... Each of the things I described to you would take about a line of code, plus the logic of the comparisons. So the hoops R makes you jump through amount to 2-4 extra lines of code. C++ is probably going to take at least that much. Duncan Murdoch __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] custom sort?
I couldn't get your suggested method to work: `==.foo` - function(a,b) unclass(a)==unclass(b) `.foo` - function(a,b) unclass(a) unclass(b) # invert comparison is.na.foo - function(a)is.na(unclass(a)) sort(structure(sample(5),class=foo)) #- 1:5 -- not reversed What am I missing? -s On Thu, May 28, 2009 at 5:48 PM, Duncan Murdoch murd...@stats.uwo.cawrote: On 28/05/2009 5:34 PM, Steve Jaffe wrote: Sounds simple but haven't been able to find it in docs: is it possible to sort a vector using a user-defined comparison function? Seems it must be, but sort doesn't seem to provide that option, nor does order sfaics You put a class on the vector (e.g. using class(x) - myvector), then define a conversion to numeric (e.g. xtfrm.myvector) or actual comparison methods (you'll need ==.myvector, .myvector, and is.na.myvector). Duncan Murdoch __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] custom sort?
On 28/05/2009 8:17 PM, Stavros Macrakis wrote: I couldn't get your suggested method to work: `==.foo` - function(a,b) unclass(a)==unclass(b) `.foo` - function(a,b) unclass(a) unclass(b) # invert comparison is.na.foo - function(a)is.na(unclass(a)) sort(structure(sample(5),class=foo)) #- 1:5 -- not reversed What am I missing? I'm not sure: I've never actually used that, I was basing it on the docs. Looks like it's not as simple as I thought. Sorry for the misinformation. Duncan Murdoch -s On Thu, May 28, 2009 at 5:48 PM, Duncan Murdoch murd...@stats.uwo.cawrote: On 28/05/2009 5:34 PM, Steve Jaffe wrote: Sounds simple but haven't been able to find it in docs: is it possible to sort a vector using a user-defined comparison function? Seems it must be, but sort doesn't seem to provide that option, nor does order sfaics You put a class on the vector (e.g. using class(x) - myvector), then define a conversion to numeric (e.g. xtfrm.myvector) or actual comparison methods (you'll need ==.myvector, .myvector, and is.na.myvector). Duncan Murdoch __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
