Re: [R] grid.table and expression in table body?
Hi - I can't get this figured out ...
Thanks for any hint.
Joh
load(/tmp/AbsoluteTable.Rdata)
absolutetable
library(gridExtra)
grid.table(absoluteTable)#Works
grid.table(absoluteTable,parse=TRUE)
Error in parse(text = d[ii]) : unexpected symbol in Survey Scans
sessionInfo()
R version 2.11.1 (2010-05-31)
x86_64-pc-linux-gnu
locale:
[1] LC_CTYPE=en_US.UTF-8 LC_NUMERIC=C
[3] LC_TIME=en_US.UTF-8LC_COLLATE=en_US.UTF-8
[5] LC_MONETARY=C LC_MESSAGES=en_US.UTF-8
[7] LC_PAPER=en_US.UTF-8 LC_NAME=C
[9] LC_ADDRESS=C LC_TELEPHONE=C
[11] LC_MEASUREMENT=en_US.UTF-8 LC_IDENTIFICATION=C
attached base packages:
[1] grid stats graphics grDevices utils datasets methods
[8] base
other attached packages:
[1] gridExtra_0.7
loaded via a namespace (and not attached):
[1] tools_2.11.1
On Monday 09 August 2010 12:02:03 baptiste auguie wrote:
I just uploaded version 0.7 on googlecode. I had inadvertently messed
up the previous attempt (uploaded an older version from another
computer). Fingers crossed it should build on r-forge in the next few
days.
baptiste
On 6 August 2010 17:11, Johannes Graumann johannes_graum...@web.de wrote:
I updated the package from r-forge, but despite the fact that
grid.table does not complain about the parse option if given, your
example below is not being printed as a parsed expression.
How can I check the actual version of the installed/loaded gridExtra
package?
Thanks, Joh
On Wednesday 04 August 2010 16:47:12 you wrote:
I added a parse argument to grid.table so that when switched to TRUE
(default FALSE) all the text strings are interpreted as expressions
(inspired by ggplot2::geom_text),
d - data.frame(alpha, beta)
grid.table(d, parse=T)
you'll need revision 258 of gridExtra for this to work (googlecode now,
r-forge in the following days, CRAN in the next stable version).
HTH,
baptiste
On Aug 4, 2010, at 9:56 AM, Johannes Graumann wrote:
Hi Baptiste,
This is, I fear a bit beyond my level of competency ... What I want to
be able to do is things like put 2.2%*%10^{-16} in a table cell,
who's name I can already set to p[Wilcoxon] ...
Joh
On Wednesday 04 August 2010 09:15:43 you wrote:
Hi,
I don't know the answer to your question (how to make a data.frame
with expressions), but if you have a list of expressions you could
try the following,
http://code.google.com/p/gridextra/wiki/testExpressions
I'm open to suggestions for your original query (what is the best way
to do it – parse each string and coerce it as an expression?)
HTH,
baptiste
On Aug 4, 2010, at 12:05 AM, Johannes Graumann wrote:
Hi,
Is there any way to get an expression into a data.frame, such that
grid.table from gridExtra will plot it evaluated in the table
body? The docu does it for the header, but is the body possible?
Thanks, Joh
__
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http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code.
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and provide commented, minimal, self-contained, reproducible code.
Re: [R] grid.table and expression in table body?
On 17 August 2010 18:38, Johannes Graumann johannes_graum...@web.de wrote:
Hi - I can't get this figured out ...
Thanks for any hint.
The parse=TRUE argument means that all the table content will be
parsed and interpreted as expression. In your content you have invalid
expressions (e.g. text with spaces), which cause the error. You could
try to reformat the labels,
# replace the spaces
m = gsub( ,~,as.matrix(absoluteTable))
# wrap the sign in
m = gsub(,\\,m)
library(gridExtra)
grid.table(data.frame(m),parse=T)
but I don't see the point of using parse in your example (there is not
plotmath expression to render).
Of course, I welcome any suggestion to create a matrix of valid
expressions, I have no clue how to deal with these.
baptiste
Joh
load(/tmp/AbsoluteTable.Rdata)
absolutetable
library(gridExtra)
grid.table(absoluteTable)#Works
grid.table(absoluteTable,parse=TRUE)
Error in parse(text = d[ii]) : unexpected symbol in Survey Scans
sessionInfo()
R version 2.11.1 (2010-05-31)
x86_64-pc-linux-gnu
locale:
[1] LC_CTYPE=en_US.UTF-8 LC_NUMERIC=C
[3] LC_TIME=en_US.UTF-8 LC_COLLATE=en_US.UTF-8
[5] LC_MONETARY=C LC_MESSAGES=en_US.UTF-8
[7] LC_PAPER=en_US.UTF-8 LC_NAME=C
[9] LC_ADDRESS=C LC_TELEPHONE=C
[11] LC_MEASUREMENT=en_US.UTF-8 LC_IDENTIFICATION=C
attached base packages:
[1] grid stats graphics grDevices utils datasets methods
[8] base
other attached packages:
[1] gridExtra_0.7
loaded via a namespace (and not attached):
[1] tools_2.11.1
On Monday 09 August 2010 12:02:03 baptiste auguie wrote:
I just uploaded version 0.7 on googlecode. I had inadvertently messed
up the previous attempt (uploaded an older version from another
computer). Fingers crossed it should build on r-forge in the next few
days.
baptiste
On 6 August 2010 17:11, Johannes Graumann johannes_graum...@web.de wrote:
I updated the package from r-forge, but despite the fact that
grid.table does not complain about the parse option if given, your
example below is not being printed as a parsed expression.
How can I check the actual version of the installed/loaded gridExtra
package?
Thanks, Joh
On Wednesday 04 August 2010 16:47:12 you wrote:
I added a parse argument to grid.table so that when switched to TRUE
(default FALSE) all the text strings are interpreted as expressions
(inspired by ggplot2::geom_text),
d - data.frame(alpha, beta)
grid.table(d, parse=T)
you'll need revision 258 of gridExtra for this to work (googlecode now,
r-forge in the following days, CRAN in the next stable version).
HTH,
baptiste
On Aug 4, 2010, at 9:56 AM, Johannes Graumann wrote:
Hi Baptiste,
This is, I fear a bit beyond my level of competency ... What I want to
be able to do is things like put 2.2%*%10^{-16} in a table cell,
who's name I can already set to p[Wilcoxon] ...
Joh
On Wednesday 04 August 2010 09:15:43 you wrote:
Hi,
I don't know the answer to your question (how to make a data.frame
with expressions), but if you have a list of expressions you could
try the following,
http://code.google.com/p/gridextra/wiki/testExpressions
I'm open to suggestions for your original query (what is the best way
to do it – parse each string and coerce it as an expression?)
HTH,
baptiste
On Aug 4, 2010, at 12:05 AM, Johannes Graumann wrote:
Hi,
Is there any way to get an expression into a data.frame, such that
grid.table from gridExtra will plot it evaluated in the table
body? The docu does it for the header, but is the body possible?
Thanks, Joh
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] grid.table and expression in table body?
Try this,
source(http://gridextra.googlecode.com/svn/trunk/inst/test/expressions.r;)
library(grid)
e = expression(p[Wilcoxon], *2.2%*%10^{-16})
grid.expr(e)
HTH,
baptiste
On Aug 4, 2010, at 9:56 AM, Johannes Graumann wrote:
Hi Baptiste,
This is, I fear a bit beyond my level of competency ... What I want to be
able
to do is things like put 2.2%*%10^{-16} in a table cell, who's name I can
already set to p[Wilcoxon] ...
Joh
On Wednesday 04 August 2010 09:15:43 you wrote:
Hi,
I don't know the answer to your question (how to make a data.frame with
expressions), but if you have a list of expressions you could try the
following,
http://code.google.com/p/gridextra/wiki/testExpressions
I'm open to suggestions for your original query (what is the best way to do
it – parse each string and coerce it as an expression?)
HTH,
baptiste
On Aug 4, 2010, at 12:05 AM, Johannes Graumann wrote:
Hi,
Is there any way to get an expression into a data.frame, such that
grid.table from gridExtra will plot it evaluated in the table body?
The docu does it for the header, but is the body possible?
Thanks, Joh
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] grid.table and expression in table body?
I added a parse argument to grid.table so that when switched to TRUE (default
FALSE) all the text strings are interpreted as expressions (inspired by
ggplot2::geom_text),
d - data.frame(alpha, beta)
grid.table(d, parse=T)
you'll need revision 258 of gridExtra for this to work (googlecode now, r-forge
in the following days, CRAN in the next stable version).
HTH,
baptiste
On Aug 4, 2010, at 9:56 AM, Johannes Graumann wrote:
Hi Baptiste,
This is, I fear a bit beyond my level of competency ... What I want to be
able
to do is things like put 2.2%*%10^{-16} in a table cell, who's name I can
already set to p[Wilcoxon] ...
Joh
On Wednesday 04 August 2010 09:15:43 you wrote:
Hi,
I don't know the answer to your question (how to make a data.frame with
expressions), but if you have a list of expressions you could try the
following,
http://code.google.com/p/gridextra/wiki/testExpressions
I'm open to suggestions for your original query (what is the best way to do
it – parse each string and coerce it as an expression?)
HTH,
baptiste
On Aug 4, 2010, at 12:05 AM, Johannes Graumann wrote:
Hi,
Is there any way to get an expression into a data.frame, such that
grid.table from gridExtra will plot it evaluated in the table body?
The docu does it for the header, but is the body possible?
Thanks, Joh
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] grid.table and expression in table body?
Great! I will give it a try ASAP!
Thanks!
Joh
On Wednesday 04 August 2010 16:47:12 baptiste Auguié wrote:
I added a parse argument to grid.table so that when switched to TRUE
(default FALSE) all the text strings are interpreted as expressions
(inspired by ggplot2::geom_text),
d - data.frame(alpha, beta)
grid.table(d, parse=T)
you'll need revision 258 of gridExtra for this to work (googlecode now,
r-forge in the following days, CRAN in the next stable version).
HTH,
baptiste
On Aug 4, 2010, at 9:56 AM, Johannes Graumann wrote:
Hi Baptiste,
This is, I fear a bit beyond my level of competency ... What I want to be
able to do is things like put 2.2%*%10^{-16} in a table cell, who's
name I can already set to p[Wilcoxon] ...
Joh
On Wednesday 04 August 2010 09:15:43 you wrote:
Hi,
I don't know the answer to your question (how to make a data.frame with
expressions), but if you have a list of expressions you could try the
following,
http://code.google.com/p/gridextra/wiki/testExpressions
I'm open to suggestions for your original query (what is the best way to
do it – parse each string and coerce it as an expression?)
HTH,
baptiste
On Aug 4, 2010, at 12:05 AM, Johannes Graumann wrote:
Hi,
Is there any way to get an expression into a data.frame, such that
grid.table from gridExtra will plot it evaluated in the table body?
The docu does it for the header, but is the body possible?
Thanks, Joh
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
minimal, self-contained, reproducible code.
signature.asc
Description: This is a digitally signed message part.
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] grid.table and expression in table body?
Hi, Is there any way to get an expression into a data.frame, such that grid.table from gridExtra will plot it evaluated in the table body? The docu does it for the header, but is the body possible? Thanks, Joh __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
