I finally got around to posting my list of R gripes on a blog at
http://ivo-welch.blogspot.com/2012/04/r-annoyances-and-gripes.html .
I did put in some time, but I do not expect anyone to read it. it was
more for myself. still, if you are curious, I would love to hear
where I got it wrong and
Ivo:
The primary source of your problems appears to be:
Unfortunately, for a generic programming language, R still lacks some sugar.
R is **not** a generic programming language, nor was it ever meant to
be one. Have you read Chambers's et al books? R was designed as a
language for data analysis
All of this is syntactic sugar. Just because a language does not have
the sintax that you are used (e.g, Perl) does not make it bad/hard to
use. What is the problem if I have to type a couple of extra lines:
f - function(x) list(a = seq_along(x), b=x*3)
result - f(1)
r1 - result$a
r2 - result$b
what is the problem you are trying to solve?
elegance, ease, and readability in my programs.
R has morphed from a data manipulation, graphics, and stats program
into my mainstay programming language. most of this has been a huge
gain. the addition of the parallel package was another recent big
Dear R wizards: is there a clean way to assign to elements in a list?
what I would like to do, in pseudo R+perl notation is
f - function(a,b) list(a+b,a-b)
(c,d) - f(1,2)
and have c be assigned 1+2 and d be assigned 1-2. right now, I use the clunky
x - f(1,2)
c - x[[1]]
d - x[[2]]
You don't need temporary variable x
c-f(1,2)[[1]]
d-f(1,2)[[2]]
Weidong Gu
On Fri, Mar 30, 2012 at 6:40 PM, ivo welch ivo...@gmail.com wrote:
Dear R wizards: is there a clean way to assign to elements in a list?
what I would like to do, in pseudo R+perl notation is
f - function(a,b)
On 2012-03-30 15:40, ivo welch wrote:
Dear R wizards: is there a clean way to assign to elements in a list?
what I would like to do, in pseudo R+perl notation is
f- function(a,b) list(a+b,a-b)
(c,d)- f(1,2)
and have c be assigned 1+2 and d be assigned 1-2. right now, I use the clunky
On Fri, Mar 30, 2012 at 6:40 PM, ivo welch ivo...@gmail.com wrote:
Dear R wizards: is there a clean way to assign to elements in a list?
what I would like to do, in pseudo R+perl notation is
f - function(a,b) list(a+b,a-b)
(c,d) - f(1,2)
and have c be assigned 1+2 and d be assigned 1-2.
You can also take a look at
http://stackoverflow.com/questions/7519790/assign-multiple-new-variables-in-a-single-line-in-r
which has some additional solutions.
On Fri, Mar 30, 2012 at 4:49 PM, Peter Ehlers ehl...@ucalgary.ca wrote:
On 2012-03-30 15:40, ivo welch wrote:
Dear R wizards: is
thanks, everyone. I should have been clearer (as always). I used the
numbers as an example only. I am aware that I can put numbers into
vectors and get nice R syntax. my problem is that I usually want to
return multiple and/or mixed objects, such as multiple data frames. I
should have given
An idiom like this would also work.
f - function(a,b) list( data.frame(a+rnorm(20), b), loess( a ~ b) )
lapply(seq_along(out - f(1:20, 1:20)), function(i) assign(c(c,
d)[i], out[[i]], envir = .GlobalEnv))
It is not elegant if you are doing this regularly, but, I think,
functions typically
,,,But assigning to the global environment is a bad idea. You're just
asking for trouble -- overwriting without warning something that's
already there.
May I suggest a rule of thumb: When things are difficult or clumsy to
do in R, don't do them.
Of course this is not inviolable, but the OP's
I agree that global side effects are a bad idea, but ivo started this by
pointing out that it is straightforward to do this in Perl. It might be worth
considering adding this capability to R.
---
Jeff Newmiller
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