Regarding : ... I don't know
what the 4th to last page would be called (could add another ante-, or
in R just use tail(book,4))...
According to wordsmith.org (sign up it's free, note I have no affiliation to
that site) the word is preantepenultimate.
Check it out:
Philippe,
replies inline
On Sat, Feb 22, 2014 at 12:29 AM, Philippe Grosjean
phgrosj...@sciviews.org wrote:
Greg,
I really like that TeachingDemos::SnowsPenultimateNormalityTest()...
If you like that function then you may appreciate
Greg,
For some authors the 4th page from the back should be the first page.
Not so for you, however.
Clint
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTERNET: cl...@math.utah.edu
Department of Ecology VOICE: (360)
Hello,
Inline
Em 21-02-2014 23:13, Rolf Turner escreveu:
On 22/02/14 11:04, Rui Barradas wrote:
Hello,
Not answering directly to your question, if the sample size is a
documented problem with shapiro.test and you want a normality test, why
don't you use ?ks.test?
m - mean(HP_TrinityK25$V2)
Second.
Rui Barradas
Em 21-02-2014 23:44, Rolf Turner escreveu:
On 22/02/14 11:53, Greg Snow wrote:
SNIP
Why are you testing your data for normality? For large sample sizes
the normality tests often give a meaningful answer to a meaningless
question (for small samples they give a
Dear R users,
Please help with with this maybe basic question. I am trying to see if my
data is normal but is a large file and the test does not work.
I keep getting the message : Error in shapiro.test(x = HP_TrinityK25$V2)
: sample size must be between 3 and 5000
thanks!
Hello,
Not answering directly to your question, if the sample size is a
documented problem with shapiro.test and you want a normality test, why
don't you use ?ks.test?
m - mean(HP_TrinityK25$V2)
s - sd(HP_TrinityK25$V2)
ks.test(HP_TrinityK25$V2, pnorm, m, s)
Hope this helps,
Rui Barradas
Rui,
Note this quote from the last paragraph of the Details section of ?ks.test:
If a single-sample test is used, the parameters specified in '...'
must be pre-specified and not estimated from the data.
Which is the exact opposite of your example.
Gonzalo,
Why are you testing your data
On 22/02/14 11:04, Rui Barradas wrote:
Hello,
Not answering directly to your question, if the sample size is a
documented problem with shapiro.test and you want a normality test, why
don't you use ?ks.test?
m - mean(HP_TrinityK25$V2)
s - sd(HP_TrinityK25$V2)
ks.test(HP_TrinityK25$V2, pnorm,
On 22/02/14 11:53, Greg Snow wrote:
SNIP
Why are you testing your data for normality? For large sample sizes
the normality tests often give a meaningful answer to a meaningless
question (for small samples they give a meaningless answer to a
meaningful question).
SNIP
Fortune!!!
cheers,
Second!!
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
H. Gilbert Welch
On Fri, Feb 21, 2014 at 3:44 PM, Rolf Turner r.tur...@auckland.ac.nz wrote:
On 22/02/14 11:53, Greg
Greg,
I really like that TeachingDemos::SnowsPenultimateNormalityTest()… even the
tortuous way to always return a p-value == 0:
# the following function works for current implementations of R
# to my knowledge, eventually it may need to be expanded
is.rational - function(x){
rep( TRUE,
Hey,
today I wanted to use the shapiro.test() on data containing 3
numerical values per group.
It is the first time that an NA was given back for some of the groups.
In the follwing an example of code and output is shown:
shapiro.test(c(0.000637806, 0.00175561, 0.001196708))
See
?shapiro.test
...the number of non-missing values must be between 3 and 5000.
By the way, how reasonable testing normality of 3 values?
Best
ozgur
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View this message in context:
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Sent from the R help mailing list archive
Actually, your sample size is 3. Sorry for that.
Ozgur
--
View this message in context:
http://r.789695.n4.nabble.com/shapiro-test-tp4634513p4634525.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
On Jun 26, 2012, at 16:43 , r...@uni-potsdam.de wrote:
Hey,
today I wanted to use the shapiro.test() on data containing 3 numerical
values per group.
It is the first time that an NA was given back for some of the groups.
In the follwing an example of code and output is shown:
Hi,
David Winsemius schrieb:
snip
This would imply that ozon is a list or dataframe.
snip
And you tried to give the whole list to a function that only wants a
vector.
And whenever you suspect that your data types clash, try str() to find
out just what kind of thing your data is. Here:
...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Stefan Scheurer
Sent: Wednesday, May 26, 2010 1:37 PM
To: r-help@r-project.org
Subject: [R] shapiro.test
Hi,
I am not so sure about an error note I got
Hi,
I am not so sure about an error note I got when using shapiro.test.
I imported some data into R by wrinting it into a .txt file via
tab1-read.table(etctxt,header=T)
attach(tab1)
The following object(s) are masked _by_ .GlobalEnv :
ozon
ozon$V1 [1] 2.5 3.0 5.6 4.7 6.5
On May 26, 2010, at 3:36 PM, Stefan Scheurer wrote:
Hi,
I am not so sure about an error note I got when using shapiro.test.
I imported some data into R by wrinting it into a .txt file via
tab1-read.table(etctxt,header=T)
attach(tab1)
The following object(s) are masked _by_
Hi, I need help to perform a Shapiro.test on a data frame, I know that
this test works only with vector but I guess there most be a way to
permor it on a data frame instead of vactor by vector (i.e. I've got 40
variables to analyze and its kinda annoying to do it one by one)
Thanks to anyone that
Try this:
x - data.frame(A = runif(10), B = rnorm(10))
lapply(x, shapiro.test)
On Mon, Jun 22, 2009 at 3:15 PM, Gonzalo Quiroga
quirogagonz...@gmail.comwrote:
Hi, I need help to perform a Shapiro.test on a data frame, I know that
this test works only with vector but I guess there most be a
On Monday 22 June 2009, Gonzalo Quiroga wrote:
Hi, I need help to perform a Shapiro.test on a data frame, I know that
this test works only with vector but I guess there most be a way to
permor it on a data frame instead of vactor by vector (i.e. I've got 40
variables to analyze and its kinda
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