How to make Rdll.lib is in readme.packages, the basic documentation for
making packages from sources pointed at from the rw-FAQ.
It seems to be the force-Rdll.lib target in that makefile.
You might also want to note the comments about paths with spaces in, in
that basic documentation, and that
Liaw, Andy [EMAIL PROTECTED] writes:
Reid: It isn't a memory problem. For vectors of length 6e5, I killed the R
process after more than 5 hours on an Opteron 248. The R process was taking
up about 114MB of RAM, out of 8GB in the box. I'm rather surprised that
such seemingly simple
Hello,
I had been thinking for years, without having ever checked (shame on
me), that indexing a named vector by a factor 'f' produced the same
results as indexing it by 'as.character(f)'. I was wrong, as the
following example shows:
(m - c(a=1,b=2))
(f - factor(c(1,2),labels=c('b','a')))
Dear R-friends,
in plotting x and y, conditioning on z, I am trying to find a way to
make the standard errors appearing together with the loess in the
trellis plot.
I have tried the following code without success.
x - x
y - y
z.two.groups - equal.count(z, number=2, overlap=.1)
xyplot(x~y |
My suggestion is that you look at the code for panel.loess, and then ask
yourself what made you think this could possibly work.
- what happens to arguments in ... ?
- does panel.loess call loess?
- does loess accept a se=TRUE argument? Does loess.smooth?
You need to write your own panel and
It may be educational to read ?factor before you use a factor for some
operation (such as subscripting), I guess. In part, it says:
Value:
'factor' returns an object of class 'factor' which has a set of
numeric codes the length of 'x' with a 'levels' attribute of
mode
It may be educational to read ?factor before you use a factor for some
operation (such as subscripting), I guess. In part, it says:
Value:
'factor' returns an object of class 'factor' which has a set of
numeric codes the length of 'x' with a 'levels' attribute of
mode 'character'.
Dear all,
I'm running into problem in R-1.9.0 that hasn't happened with R-1.8.x
If I make a plot with xyplot(), and use the menu to either save to a metafile or copy
to clipboard as a metafile to export to eg
Powerpoint, I can just copy a blank then. This does not occur with the classical
Note that if f is a factor with Date labels, e.g.
f - factor(c(2000-02-02,2000-02-03))
then as.Date has a factor method whose effect is such that (as of R 1.9.1):
as.Date(f)
*is* the same as as.Date(as.character(f)) . (Presumably this makes
it easier to use as.Date with read.table.)
On Saturday 08 May 2004 08:45, Patrick Giraudoux wrote:
Dear all,
I'm running into problem in R-1.9.0 that hasn't happened with
R-1.8.x
If I make a plot with xyplot(), and use the menu to either save to a
metafile or copy to clipboard as a metafile to export to eg
Powerpoint, I can just
I don't know if this workaround suffers the same problem or not
since I have not tried it but you could try using the xfig device
for your graphics and then using xfig2dev to convert that file
to .cgm format (which is also vector based) and then in Word use:
Insert | Picture
or if a
pallier [EMAIL PROTECTED] writes:
Given a named vector 'm' and a factor 'f' whose levels match (e.g.
when 'm' is the result of a 'tapply' command using the factor f as
INDEX), my intuition is that m[f] means m[as.character(f)]
It's not like we haven't visited this before. As I recall it, the
OK. Deepayan sent me the copy of a chat on another list between John Fox, Duncan
Murdoch and Paul Murrell. The bug in the gui.exe
looks like being reported with an example to turn it before he has been definetely
fixed. Just try:
trellis.device(win.metafile, file=test.emf)
data(iris)
Dear Sir/Madam
Hello
I'm Ph.D student of psychometric at the university of
Tehran.I use R version 1.8.1. I want to upgrade the R
into higher version.I downloaded the latest version
R-1.9.0.tgz. Unfortunately I could not to upgrade
the R. Could you tell me how I can to upgrade the
R,please?
Best
Dear Sir/Madam
Hello
I'm Ph.D student of psychometric at the university of
Tehran.I use R version 1.8.1. I want to upgrade the R
into higher version.I downloaded the latest version
R-1.9.0.tgz. Unfortunately I could not to upgrade
the R. Could you tell me how I can to upgrade the
R,please?
Best
Hi there!
This is my second message in two weeks. I am regretting to get ride of my
R-1.4.1! In fact, since I upgraded to R-1.8.1 (directly from R-1.4.1) and
then to R-1.9.0 I am experiencing diffulties I never faced before. Professor
Ripley and Dr. Murdoch had helped with the Fatal Error.
Alain Yamakana wrote:
Hi there!
This is my second message in two weeks. I am regretting to get ride of my
R-1.4.1! In fact, since I upgraded to R-1.8.1 (directly from R-1.4.1) and
then to R-1.9.0 I am experiencing diffulties I never faced before. Professor
Ripley and Dr. Murdoch had helped with
Asghar Minaei wrote:
Dear Sir/Madam
Hello
I'm Ph.D student of psychometric at the university of
Tehran.I use R version 1.8.1. I want to upgrade the R
into higher version.I downloaded the latest version
R-1.9.0.tgz. Unfortunately I could not to upgrade
the R. Could you tell me how I can to upgrade
I'm using 1.9.0 on Windoze 2k and I created a numeric matrix and used
colnames() to give it some column names, but if I try to select a
column using matrixname$validname I get a null return but if I use
matrixname[,4] it works fine. Looking at the help I think this is
because a matrix is not a
You can access a column of a dataframe using $ but not a matrix.
That's just how it is. You can access a column of a matrix
via its column name using, for example
m - matrix(1:12, 4, 3)
colnames(m) - c(a, b, c)
m[, b]
[1] 5 6 7 8
-roger
chris1 wrote:
I'm using 1.9.0 on Windoze 2k and I
Hello everybody,
I would like to calculate a wavelet transformation of EEG data
(preferably a Morlet transformation) and plot the results as a
time-frequency power spectrum (using R 1.9.0 on Mac OS X). I have
checked Rwave and the explanations in the book by R. Carmona et al.,
but couldn't
chris1 [EMAIL PROTECTED] writes:
I'm using 1.9.0 on Windoze 2k and I created a numeric matrix and used
colnames() to give it some column names, but if I try to select a
column using matrixname$validname I get a null return but if I use
matrixname[,4] it works fine. Looking at the help I
I've downloaded and installed R 1.9.0 under OS X 10.3.3. I then
removed my previous R 1.8.0 installation by following the
instructions in the readme file, e.g.,
1. drag the StartR icon into the Trash;
2) go inside your Home directory and search for the Library folder.
Inside the Library
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Alain
Yamakana
Sent: den 8 maj 2004 17:22
To: [EMAIL PROTECTED]
Subject: [R] as.double.default()
Hi there!
This is my second message in two weeks. I am regretting to
get ride of my R-1.4.1!
Hello list !
I have a huge data.frame with several variables observed on about 3000
persons. For every person (row) there is variable called GROUP which indices
the group the person belongs to. There is also another variable AV for each
person. Now i want to create a new variable which holds
predict(lm(AV~as.factor(GROUP)))
Felix Eschenburg Atropin75 at t-online.de writes:
:
: Hello list !
:
: I have a huge data.frame with several variables observed on about 3000
: persons. For every person (row) there is variable called GROUP which indices
: the group the person belongs to.
as.data.frame(matrixname)$validname
chris1 chris1 at psyctc.org writes:
:
: I'm using 1.9.0 on Windoze 2k and I created a numeric matrix and used
: colnames() to give it some column names, but if I try to select a
: column using matrixname$validname I get a null return but if I use
:
hello,
I am working with some data which i would like to find the
best fit model for them.
First, this data are in a matrix. Each of the columns are
treatments and the raws are repetions for the each tratment.
So, i've already maden one chart with all the boxplot
graphic, for each treatment.
Oops...the error was my own.
I had been typing
sudo ln -s /Library/Frameworks/R.framework/Resources/bin/R usr/local/bin/R
instead of
sudo ln -s /Library/Frameworks/R.framework/Resources/bin/R /usr/local/bin/R
which makes all the difference in the world.
Brian
sudo ln -s
Dear Sir/Madam
Hello
I'm Ph.D student of psychometric at the university of
Tehran.I use R version 1.8.1. I want to upgrade the R
into higher version.I downloaded the latest version
R-1.9.0.tgz. Unfortunately I could not to upgrade
the R. Could you tell me how I can to upgrade the
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