I have :
raw - read.table(monthly.text, skip=3, sep=|,
col.names=c(junk, junk2,
wpi, g.wpi, wpi.primary, g.wpi.primary,
wpi.fuel, g.wpi.fuel, wpi.manuf, g.wpi.manuf,
cpi.iw, g.cpi.iw, cpi.unme, g.cpi.unme,
Jacques, provided that X and Y are colocated (i.e., have
exactly the same observation locations), you get the
cross variogram right; the definition of this cross
variogram is however:
gamma(h)= E[(X(s)-X(s+h))*(Y(s)-Y(s+h))]
also, where you select:
cv - v$gamma[1:14]
you may be better off using
Hi all, I've got some problems with irts objects, one of which could be a bug:
1) Read a table with several columns from Postgres and the first column is
Timestamp with timezone (this is OK). An extract is:
raincida$ts:
[2039] 25/03/2000 22:00:00 UTC 25/03/2000 23:00:00 UTC
[2041] 26/03/2000
There is no bug in R here. There was a change to DST in Spain at 2am on
2000-03-26, and they are *printed* as times in your locale, as documented.
Please read the posting guide and FAQ about what is a bug.
Also, please try not to confuse an object and its printed representation.
On Tue, 17 Aug
hi there
say that i have this table
x-table(adoc, oarb)
x
oarb
0 1
adoc
ab1 0
am5 1
ba 14 1
cc 271 3
ch 87 2
dz 362 6
fl
On Tue, 17 Aug 2004 [EMAIL PROTECTED] wrote:
say that i have this table
x-table(adoc, oarb)
x
oarb
0 1
adoc
ab1 0
am5 1
ba 14 1
cc 271 3
ch 87 2
First, many thanks to Frank Harrell for once again helping me out. This actually
relates to the next point, which is my contribution to the 'why don't social
scientists use R' discussion. I am a hybrid social scientist(child psychiatrist) who
trained on SPSS. Many of my difficulties in
I'm just curious, but how do social scientists, or anyone else for
that matter, learn SPSS, besides taking a class?
-roger
[EMAIL PROTECTED] wrote:
First, many thanks to Frank Harrell for once again helping me out.
This actually relates to the next point, which is my contribution
to the 'why
Shalini,
I think your hill equation is meant to just be an alternative
parameterization of the four parameter logistic (BTW, the hill
*coefficient* is a function of the slope parameter of the FPL, but I don't
believe hill equation is standard terminology). Note conc is the input
in this
Hi,
I am using R 1.9.1 on on i686 PC with SuSE Linux 9.0.
I have a data.frame, e.g.:
myData - data.frame( var1 = c( 1:4 ), var2 = c (5:8 ) )
If I add a new column by
myData$var3 - myData[ , var1 ] + myData[ , var2 ]
everything is fine, but if I omit the commas:
myData$var4 - myData[ var1
Arne Henningsen wrote:
Hi,
I am using R 1.9.1 on on i686 PC with SuSE Linux 9.0.
I have a data.frame, e.g.:
myData - data.frame( var1 = c( 1:4 ), var2 = c (5:8 ) )
If I add a new column by
myData$var3 - myData[ , var1 ] + myData[ , var2 ]
everything is fine, but if I omit the commas:
Hi all;
I've already send a similar e-mail to the list and Prof. Brian Ripley
answered me but my doubts remain unresolved. Thanks for the clarification,
but perhaps I wasn't clear enough in posting my questions.
I've got a postgres database which I read into R. The first column is
Timestamp
Arne Henningsen [EMAIL PROTECTED] writes:
Hi,
I am using R 1.9.1 on on i686 PC with SuSE Linux 9.0.
I have a data.frame, e.g.:
myData - data.frame( var1 = c( 1:4 ), var2 = c (5:8 ) )
If I add a new column by
myData$var3 - myData[ , var1 ] + myData[ , var2 ]
everything is
This is not a bug, and BTW data frames have names not colnames.
As I have said already today, don't confuse the printed repesentation of
an object with the object itself.
On Tue, 17 Aug 2004, Arne Henningsen wrote:
I am using R 1.9.1 on on i686 PC with SuSE Linux 9.0.
I have a data.frame,
R-help,
I have a data frame wich I subset like :
a - subset(df,df$column2 %in% c(factor1,factor2) df$column2==1)
But when I type levels(a$column2) I still get the same levels as in df (my original
data frame)
Why is that?
Is it right?
Luis
Luis Ridao Cruz
Fiskirannsóknarstovan
Nóatún 1
In your second model, log(conc) is negative for conc = 0.001.
This observation will generate NA for (log(conc)/xmid)^scal unless scal
is an integer or xmid is also negative. In the latter case,
(log(conc)/xmid)^scal will be NA for all but that last value unless scal
is an integer.
On Tue, 2004-08-17 at 09:01, Arne Henningsen wrote:
Hi,
I am using R 1.9.1 on on i686 PC with SuSE Linux 9.0.
I have a data.frame, e.g.:
myData - data.frame( var1 = c( 1:4 ), var2 = c (5:8 ) )
If I add a new column by
myData$var3 - myData[ , var1 ] + myData[ , var2 ]
On Tue, 2004-08-17 at 09:34, Marc Schwartz wrote:
Take a look at the details, value and coercion sections of
?.data.frame
This must be my week for typos. That should be:
?[.data.frame (in ESS)
or
?[.data.frame (otherwise)
Marc
__
[EMAIL
On Tue, 2004-08-17 at 09:30, Luis Rideau Cruz wrote:
R-help,
I have a data frame wich I subset like :
a - subset(df,df$column2 %in% c(factor1,factor2) df$column2==1)
But when I type levels(a$column2) I still get the same levels as in df (my
original data frame)
Why is that?
The
javier garcia - CEBAS rn001 at cebas.csic.es writes:
:
: Hi all;
: I've already send a similar e-mail to the list and Prof. Brian Ripley
: answered me but my doubts remain unresolved. Thanks for the clarification,
: but perhaps I wasn't clear enough in posting my questions.
:
: I've got a
Javier,
I recently had a problem with dates. This example might shed some light on
your problem.
x - ISOdate(rep(2000,2),rep(3,2),rep(26,2),hour=0)
x
[1] 2000-03-26 GMT 2000-03-26 GMT
unclass(x)
[1] 954028800 954028800
attr(,tzone)
[1] GMT
When one creates a date with ISOdate, the
A few comments:
First, your remarks are interesting and, I would say, mainly well founded. However, I
think they are in many respects irrelevant, although they do point to the much bigger
underlying issue, which Roger Peng also hinted at in his reply.
I think they are sensible because R IS
Ajay Shah ajayshah at mayin.org writes:
:
: I have :
:
: raw - read.table(monthly.text, skip=3, sep=|,
: col.names=c(junk, junk2,
: wpi, g.wpi, wpi.primary, g.wpi.primary,
: wpi.fuel, g.wpi.fuel, wpi.manuf, g.wpi.manuf,
:
Is there an easy way of converting an aov.summary into a matrix in which
the rows are the factor names and the columns are Df, Sum Sq, Mean Sq, F
value and Pr.
For example, convert
Df Sum Sq Mean Sq F value Pr(F)
block5 343.29 68.66 4.4467 0.015939 *
N1
On Tue, 17 Aug 2004, Moises Hassan wrote:
Is there an easy way of converting an aov.summary into a matrix in which
the rows are the factor names and the columns are Df, Sum Sq, Mean Sq, F
value and Pr.
You are confusing the printed representation with the object (which seems
today's
Krista Haanstra [EMAIL PROTECTED] writes:
As I am quitte an ignorant user of R, excuse me for any wrongfull usage of
all the terms.
My question relates to the statistics behind the survdiff function in the
package survival.
My textbook knowledge of the logrank test tells me that if I want to
Moises Hassan wrote:
Is there an easy way of converting an aov.summary into a matrix in which
the rows are the factor names and the columns are Df, Sum Sq, Mean Sq, F
value and Pr.
For example, convert
Df Sum Sq Mean Sq F value Pr(F)
block5 343.29 68.66 4.4467
On Tue, 17 Aug 2004, Arne Henningsen wrote:
Thank you for all your answers!
I agree with you that it is not a bug. My mistake was that I thought that a
data frame is similar to a matrix, but as ?data.frame says they ... share
many of the properties of matrices and of lists.
...
I think the
On Tuesday 17 August 2004 06:14, Roger D. Peng wrote:
I'm just curious, but how do social scientists, or anyone else for
that matter, learn SPSS, besides taking a class?
They sit down with a book, a computer, and data they desperately need to
analyze and start working. SPSS documentation and
On Tuesday 17 August 2004 09:20, Berton Gunter wrote:
A few comments:
It has been decades since I used SPSS. At that time, to really work with it
you edited a text file program that identified the data file and variable
columns you wanted to work with. You assembled the flow of work commands
I am working with a logistic-normal model (i.e, GLMM with random intercept
model) by Bayesian method. BUt I met some difficulities for programming by
R. Is there anyone have experience of this model or the R code I can refer
as example?
Thanks for your help.
Syl
Hi,
I have a time series plot to produce, yet I want the x-axis to be
labelled with dates
(stored on another array) and not with observation numbers. Can anyone
suggest me how?
Thanks.
Konrad
--- Konrad Banachewicz [EMAIL PROTECTED] wrote:
Hi,
I have a time series plot to produce, yet I want the x-axis to be
labelled with dates
(stored on another array) and not with observation numbers. Can
anyone
suggest me how?
Thanks.
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