some_df[1, ] is actually a data frame: see ?[.data.frame. It's hard to
see what else it could be, as columns of a data frame are of arbitrary
classes.
When you apply matrix() to a data frame it gets dropped to a list.
On Sat, 4 Jun 2005, Andy Bunn wrote:
Adam:
Providing a reproducible
On Sat, 4 Jun 2005, Laetitia Mestdagh wrote:
I am trying to fit a glm with a distribution free family, link = log and
variance = constant*mu. I guess I have to use the quasi family but the
choices of variance are restricted to constant or mu or mu^2..., I don't
know the way to choose the
Hello again,
First, thanks for the help that got the latest plotrix package finished.
I had been planning to write something about packages since Scott
Waichler offered the gantt.chart function. Then Ben Bolker (who helped
me to write the axis.break function) asked if I would be willing to
On 6/5/05, Jim Lemon [EMAIL PROTECTED] wrote:
There are now about 500 packages on CRAN. Some are focused, covering a
particular area well, easy for the prospective user to discover their
potential usefulness, while others are less so.
CRAN Task Views
Thanks for posting this; I think you raise good points, but they're more
appropriate for R-devel, so I've posted my reply there.
Duncan Murdoch
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R-help@stat.math.ethz.ch mailing list
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PLEASE do read the
Dear all,
I have a set of data that is 2 columns wide and 35,000 rows long (see
extract below). The first column contains codes for tetrads (2km x 2km
squares within NW England) and the second column has the names of moss
species present within each tetrad. I wish to convert this into a matrix
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
You are able to store such a huge matrix in R, if you ask for it...
Furthermore, table command might help you:
Help page for table says:
Cross Tabulation and Table Creation
Description:
'table' uses the cross-classifying factors to build a
On 5 Jun 2005, at 16:47, Duncan Murdoch wrote:
Thanks for posting this; I think you raise good points, but they're
more appropriate for R-devel, so I've posted my reply there.
There are diverse opinions about netiquette. One of the most basic, in
my opinion, is this: if someone posts starts
some_df[1, ] is actually a data frame: see ?[.data.frame. It's hard to
see what else it could be, as columns of a data frame are of arbitrary
classes.
I see, I was confusing class and mode. However, since a list can be a ts
object as in this example:
R w - list(rnorm(10), rnorm(10))
R x -
On 6/5/05, Andy Bunn [EMAIL PROTECTED] wrote:
some_df[1, ] is actually a data frame: see ?[.data.frame. It's hard to
see what else it could be, as columns of a data frame are of arbitrary
classes.
I see, I was confusing class and mode. However, since a list can be a ts
object as in this
Dear List members,
Thank you so much for your insights.
On Sat, 4 Jun 2005 09:39:33 +0100 (BST),
Prof Brian Ripley [EMAIL PROTECTED] wrote:
[...]
I think it is more likely you want to wait for the Tk interaction and
then return the results, that is use a `modal' widget. If so, take a
look
Dear all
I think my problem is not complicated but I'm having difficulties to solve it.
v is a vector: v=c(p1 , p2 , p3 , p4), and f is a function: f : v - w , where
w=c(p1 , p2*(1-p1) , p3*(1-p2)*(1-p1) , p4*(1-p3)*(1-p2)*(1-p1))
I write the function f as:
jose silva wrote:
Dear all
Its very difficult to read your post due to all the blank lines, so I
cannot really
read it very well, but what about writing your function as (not tried)
fun - function(x) c(x[1],
or if that doesn't work look into
?mapply
But you should really look into
On 6/5/05, jose silva [EMAIL PROTECTED] wrote:
Dear all
I think my problem is not complicated but I'm having difficulties to solve it.
v is a vector: v=c(p1 , p2 , p3 , p4), and f is a function: f : v - w , where
w=c(p1 , p2*(1-p1) , p3*(1-p2)*(1-p1) ,
Kjetil and Gabor:
thank you both so much for for yor help
silva [EMAIL PROTECTED] wrote:
Dear all
I think my problem is not complicated but I'm having difficulties to solve
it.
v is a vector: v=c(p1 , p2 , p3 , p4), and f is a function: f : v - w ,
where
w=c(p1 , p2*(1-p1) ,
Hello,
I am guessing this is not a difficult question. But at the same time, I
haven't had much luck figuring this issue out from the R documentation and
help pages.
How can I create superscript text in the labels of a plot? The parameter
along my y-axis is volume and my desire is for the
On 6/5/05, Jim BRINDLE [EMAIL PROTECTED] wrote:
Hello,
I am guessing this is not a difficult question. But at the same time, I
haven't had much luck figuring this issue out from the R documentation and
help pages.
How can I create superscript text in the labels of a plot? The parameter
Why doesn't nls() produce any kind of R-squared value? In the absence
of such information, how are we supposed to compare one fit to another
when the y-axis scale changes?
sm - nls(y ~ SSfpl(x, miny, maxy, midx, grad))
summary(sm)
Formula: y ~ SSfpl(x, miny, maxy, midx, grad)
Parameters:
On 6/5/05, James Salsman [EMAIL PROTECTED] wrote:
Why doesn't nls() produce any kind of R-squared value? In the absence
of such information, how are we supposed to compare one fit to another
when the y-axis scale changes?
sm - nls(y ~ SSfpl(x, miny, maxy, midx, grad))
summary(sm)
Hello,
I am unable to get the greater-than-or-equal-to symbol (?) in a legend.
I am able to get pi, squares, sqrt, but not this particular symbol. Can
anyone tell me what I am doing wrong?
legend(locator(n=1), legend = c(Observed, expression(Area 5* m^2),
expression(Area = 5*m^2)),
On 6/5/05, Krista Chin [EMAIL PROTECTED] wrote:
Hello,
I am unable to get the greater-than-or-equal-to symbol (?) in a legend.
I am able to get pi, squares, sqrt, but not this particular symbol. Can
anyone tell me what I am doing wrong?
legend(locator(n=1), legend = c(Observed,
Hello everybody,
Could I consult you a question?
I always use R old version 1.9.1 . Because I can not add my library
into the new version 2.0.0 by the same method as old version.
* I have read the webpage http://www.stats.ox.ac.uk/pub/Rtools
* Download the tools.zip
Gabor explained, how are we supposed to compare one fit to another
but not Why doesn't nls() produce any kind of R-squared value. For
that, I requested 'RSiteSearch(R-squared from nls)'. The
seventh hit was a summary of an earlier discussion on this issue
Hi, every one,
I have translated An Introduction to R into simplified Chinese and
traditional Chinese. You can browse them from these two URL:
simplified Chinese:
http://www.biosino.org/pages/newhtm/r/schtml/index.html#Top
traditional Chinese: http://www.biosino.org/pages/newhtm/r/tchtml/
I
On 6/5/05, Ivy_Li [EMAIL PROTECTED] wrote:
Hello everybody,
Could I consult you a question?
I always use R old version 1.9.1 . Because I can not add my library
into the new version 2.0.0 by the same method as old version.
Getting the latest version of R is strongly recommended.
Hello all,
Sorry if this is an FAQ. I have been trying to search the archives
without success.
I have a dataset (ChiPs microarray) where the experiment to experiment
variability is very high
but where within an experiment, the data nearly always goes in the
right (hypothesis confirming)
Hi, Ivy_Li:
I also had trouble adding libraries under recent versions of R. The
new versions of R ask you to select a local CRAN mirror. Unfortunately,
I was using XEmacs, which failed to pass on the request to select a
local CRAN mirror and instead locked up. I started using RGui
I want to th current folder is the specific folder when R start.It is
very boring to modify the current directory manually. How can I do it?
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PLEASE do read the posting
On 6 June 2005 at 10:58, luan_sheng wrote:
| I want to th current folder is the specific folder when R start.It is
| very boring to modify the current directory manually. How can I do it?
The first answer to
RSiteSearch(change directory)
tells you about setwd() and getwd().
There
Guohui,
Great effort for translating this document into Chinese. I will
certainly read through and send some feedback to you.
Best
Yuandan
Guohui Ding wrote:
Hi, every one,
I have translated An Introduction to R into simplified Chinese and
traditional Chinese. You can browse them from
Hi all,
I'm trying to debug some fortran 95 code that I'm bringing in
with a dyn.load().
I'm compiling a number of files using g95 on intel linux w/ R 2.1.0.
The .so file loads without complaint, but when I try to call it I get a
seg fault. I was hoping I could get a core dump in order to get
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