On Mon, 13 Jun 2005, Chris Bergstresser wrote:
Hi all --
I'm seeing the following commands reliably produce a crash in RGui,
version 2.0.1, for both my home and office machine:
rm(list = ls(all = TRUE));
load(dataset.R);
library(wle);
data.wle = wle.lm(abortion ~ year * lib.con +
Hi dear Rers,
I am using SSOAP package to access SOAP service at NCBI.
I followed the example code in SSOAP but failed.
z - .SOAP(http://www.ncbi.nlm.nih.gov/entrez/eutils/soap/soap_adapter.cgi;,
method=run_eInfo, db=pubmed, action = I(einfo))
Error: protect(): protection stack overflow
Peter == Peter Alspach [EMAIL PROTECTED]
on Tue, 14 Jun 2005 14:11:47 +1200 writes:
Peter Ben
Peter Others have pointed out plotmath. However, for some
Peter superscripts (including 2) it may be easier to use
Peter the appropriate escape sequence (at in Windows):
Chuck Cleland [EMAIL PROTECTED] writes:
See ?plotmath.
plot(1:10, 1:10, ylab=expression(BA (m^{2}/ha)))
Ick... The parser will think that BA is a function and m^2/ha its
argument. This probably has consequences for the spacing.
Try expression(BA * (m^2/ha))
--
O__ Peter Dalgaard
Dear R-Users,
I wish to create a new family object based on the Binomial family. The only
difference will be with the link function. Thus instead if using the 'logit(u)'
link function, i plan to use '-log(i-u)'.
So far, i have tried to write the function following that of the Binomial and
On Tue, 14 Jun 2005, Hu Chen wrote:
Hi dear Rers,
I am using SSOAP package to access SOAP service at NCBI.
I followed the example code in SSOAP but failed.
z -
.SOAP(http://www.ncbi.nlm.nih.gov/entrez/eutils/soap/soap_adapter.cgi;,
method=run_eInfo, db=pubmed, action = I(einfo))
Error:
Hi I have tried to unsubscribe from this list now three times, I desperately
need to unsubscribe from this list from this address because the list is choking
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How can ordinary polynomial coefficients be calculated
from an orthogonal polynomial fit?
I'm trying to do something like find a,b,c,d from
lm(billions ~ a+b*decade+c*decade^2+d*decade^3)
but that gives: Error in eval(expr, envir, enclos) :
Object a not found
decade - c(1950, 1960, 1970,
[EMAIL PROTECTED] writes:
Hi I have tried to unsubscribe from this list now three times, I desperately
need to unsubscribe from this list from this address because the list is
choking
this mailbox.
Below are the various suggested ways of unsubscribing
To subscribe or unsubscribe via
Laurent 14 juin 12:02 afficher les options
De : Laurent [EMAIL PROTECTED] - Rechercher les messages de cet
auteur
Date : Tue, 14 Jun 2005 03:02:37 -0700
Local : Mar 14 juin 2005 12:02
Objet : bs() function of the splines package
Répondre | Répondre à l'auteur | Transférer |
You can also use switch() instead of ifelse(), which makes the code a
bit easier to read. The downside to this is that switch does not take
vectorised input and thus you need a loop. For example
# data
dbh - c(30,29,15,14,30,29)
form - factor(c(tree, tree, liana, liana, palm, palm))
df -
On Tue, 14 Jun 2005, James Salsman wrote:
How can ordinary polynomial coefficients be calculated
from an orthogonal polynomial fit?
Why would you want to do that? predict() is perfectly happy with an
orthogonal polynomial fit and the `ordinary polynomial coefficients' are
rather badly
On Tue, 14 Jun 2005, Martin Maechler wrote:
Peter == Peter Alspach [EMAIL PROTECTED]
on Tue, 14 Jun 2005 14:11:47 +1200 writes:
Peter Ben
Peter Others have pointed out plotmath. However, for some
Peter superscripts (including 2) it may be easier to use
Peter the
Dear all,
I have a problem to update package gregmisc.
After I update,
update.packages(ask='graphics')
trying URL
'http://cran.at.r-project.org/bin/windows/contrib/2.1/gregmisc_2.0.8.zip'
Content type 'application/zip' length 2465 bytes
opened URL
downloaded 2465 bytes
package 'gregmisc'
On 6/14/05, Muhammad Subianto [EMAIL PROTECTED] wrote:
Dear all,
I have a problem to update package gregmisc.
After I update,
update.packages(ask='graphics')
trying URL
'http://cran.at.r-project.org/bin/windows/contrib/2.1/gregmisc_2.0.8.zip'
Content type 'application/zip' length 2465
Hello,
I'm implementing a function using non uniform B-Splines. Looking at the
code of the bs() function, I realized that if the intercept was set to
FALSE, the behavior of the function was the following (df is the number
of degrees of freedom that I believe can be interpreted as the number
of
Thanks.
I do like this,
remove.packages(gregmisc, .libPaths()[1])
remove.packages(gtools, .libPaths()[1])
install.packages(gregmisc, .libPaths()[1])
update.packages()
update.packages()
install.packages(gtools, .libPaths()[1])
update.packages()
update.packages()
PD Peter Dalgaard [EMAIL PROTECTED]
on 14 Jun 2005 12:06:53 +0200 writes:
PD [EMAIL PROTECTED] writes:
Hi I have tried to unsubscribe from this list now three
times, I desperately need to unsubscribe from this list
from this address because the list is choking this
You can test this suggestion by asking for a password reminder from the
https site. If you do get an email that says what your password is, then
you are still subscribed.
I actually asked the website to send me a password reminder to an
account that is not subscribed. Although it says that A
Does anyone know a way to do the following:
Save a large number of R objects to a file (like load() does) but then
read back only a small named subset of them . As far as I can see,
load() reads back everything.
The context is:
I have an application which will generate a large number of large
I have a program which is doing a few thousand runs of lm(). Suppose
it is a simple model
y = a + bx1 + cx2 + e
I have the R object d where
d - summary(lm(y ~ x1 + x2))
I would like to obtain Var(x2) out of d. How might I do it?
I can, of course, always do sd(x2). But it would be much
Thank you very much! All methods are very useful.
Paulo M. Brando
Instituto de Pesquisa Ambiental da Amazonia (IPAM)
Santarem, PA, Brasil.
Av. Rui Barbosa, 136.
Fone: + 55 93 522 55 38
www.ipam.org.br
E-mail: [EMAIL PROTECTED]
-Mensagem
Richard Mott wrote:
Does anyone know a way to do the following:
Save a large number of R objects to a file (like load() does) but then
read back only a small named subset of them . As far as I can see,
load() reads back everything.
Save them to individual files when you generate them?
I would suggest saving each object to an individual file with
some sort of systematic file name. That way, you can implement a
rudimentary key-value database and load only the objects you
want. You might be interested in the 'serialize()' and
'unserialize()' functions for this purpose.
If
Prof Brian Ripley wrote:
On Tue, 14 Jun 2005, James Salsman wrote:
How can ordinary polynomial coefficients be calculated
from an orthogonal polynomial fit?
Why would you want to do that? predict() is perfectly happy with an
orthogonal polynomial fit and the `ordinary polynomial
I think this is covered in the FAQ:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#Models
-roger
James Salsman wrote:
How can ordinary polynomial coefficients be calculated
from an orthogonal polynomial fit?
I'm trying to do something like find a,b,c,d from
lm(billions ~
Hello,
Given a vector of characters, or factors, denoting the date in
the following way: 28/03/2000, is there a method of
1) Computing the earliest of these dates;
2) Using this as a base, then converting all the other dates into merely
the number of days after this minimum date
Many
Use POSIX. To convert:
my.dates - strptime(your.characters, format='%d/%m/%Y')
once you have that, you can use 'min' to find the minimum.
'difftime' will give you the differences.
Jim
__
James HoltmanWhat is the problem you
try this:
x - c(28/03/2000, 27/08/2001, 29/05/2002, 15/12/2003)
y - as.Date(x, %d/%m/%Y)
y - min(y)
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
it seems R has no function to sort the data.frame according to some
variable(s),though we can do these by order() and indexing.but why not make
sort() the a generic function,making it can sort vector and other type of
objects?
maybe this is a silly suggestion,but i think it is quite usefull.
On Tue, 14 Jun 2005, Frank E Harrell Jr wrote:
Prof Brian Ripley wrote:
On Tue, 14 Jun 2005, James Salsman wrote:
How can ordinary polynomial coefficients be calculated
from an orthogonal polynomial fit?
Why would you want to do that? predict() is perfectly happy with an
orthogonal
take a look at this function by Kevin Wright
RSiteSearch(sort.data.frame)
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/16/336899
Fax: +32/16/337015
Web:
Dear helpers,
I am a beginner user of R and probably I am not using properly the
function gls() of the library nlme.
I estimated a model with AR(1) residuals but apparently the fitted and
the predicted values arent constructed considering the autocorrelation
of the residuals.
It seems that
On Tue, 14 Jun 2005, Barry Rowlingson wrote:
Richard Mott wrote:
Does anyone know a way to do the following:
Save a large number of R objects to a file (like load() does) but then
read back only a small named subset of them . As far as I can see,
load() reads back everything.
Save them
On Tue, 14 Jun 2005, Abatih E. wrote:
Dear R-Users, I wish to create a new family object based on the Binomial
family. The only difference will be with the link function. Thus instead
if using the 'logit(u)' link function, i plan to use '-log(i-u)'. So
far, i have tried to write the
Hi R users,
I am currently using c(...,recursive=TRUE) to handle list-structured
objects.
This allows to represent something like:
l1 = list(level1=1,level2=list(sub1=1,sub2=2))
as:
(l1names = names(c(l1,recursive=TRUE)))
[1] level1 level2.sub1 level2.sub2
Then, one can use:
(l1names
On Mon, 13 Jun 2005, Kerry Bush wrote:
Suppose I fit the following model:
library(gam)
fit - gam(y~x1+x2+s(x3),family=binomial)
and then I use
fitf$coef
x1x2 s(x3)
4.1947460 2.7967200 0.0788252
are the coefficients for x1 and x2 the estimated
coefficients?
What I really want now are the 95% confidence intervals that I
mistakenly thought that linesHyperb.lm() would provide:
pm - lm(billions ~ I(decade) + I(decade^2) + I(decade^3))
library(sfsmisc)
linesHyperb.lm(pm)
Error in names-.default(`*tmp*`, value = c(I(decade),
I(decade^2), :
Thanks everyone for help on this. It looks like the solution is a
zillion files.
Richard
--
Richard Mott | Wellcome Trust Centre
tel 01865 287588 | for Human Genetics
fax 01865 287697 | Roosevelt Drive, Oxford OX3 7BN
Hi,
I've just started using R and RSPerl. I have some code as follows:
R::initR(--no-save);
R::call(t.test, ([EMAIL PROTECTED], [EMAIL PROTECTED]));
where @array1 and @array2 are both 1-dimensional arrays in Perl having 54675
elements each. On execution the output is as follows:
Calling R
This has nothing to do with RSPerl, instead it has to do what kind of
object you obtain and how these are print():ed. Typing the name of an
object, say, 'res', at R prompt and pressing ENTER;
res
is equivalent as typing
print(res)
This is for convenience to the user. Basically, this is
Dimitris,
wouldn't this be more precise ---
sapply(jj,function(x) which(x$b[1]==4))
[[1]]
[1] 1
[[2]]
numeric(0)
[[3]]
[1] 1
John
Dimitris wrote ---
maybe something like this:
jj - list(list(a = 1, b = 4:7), list(a = 5, b = 3:6), list(a = 10, b
= 4:5))
###
jj[sapply(jj,
I would like to call C routines from Fortran as suggested in section 5.6 of
the Writing R extensions documentation.
I'm familiar with Fortran but not with C.
I understand the example provided in Fortran:
subroutine testit()
double precision normrnd, x
call rndstart()
x = normrnd()
call dblepr(X
Hello. I am having the worst time converting x-axis date ticks to real
dates. I have tried several suggestions in online help tips and books to
no avail.
For example, the x-axis has 0, 50, 100, etc, and I want it to have
6/17/03, 8/6/03 etc. See attached (sample).
Can anybody help me with
On Tue, 14 Jun 2005, Prof Brian Ripley wrote:
If your file system does not like 15000 files you can always
save in a DBMS.
Or, switch to a better/more appropriate file system:
http://en.wikipedia.org/wiki/Comparison_of_file_systems
ReiserFS would allow you to store up to about 1.2 million
Dear all,
Is it possible to change the levels in a mosaic plot, the appearance of
the level or the levels size?
For instance:
A C E
B D
Thanks for your help
Adrián
__
Using R 2.1.0 on Windows
2 questions:
1. Is there a way to parse the output from kmeans within R?
2. If the answer to 1. is convoluted or impossible, how do you save the
output from kmeans in a plain text file for further processing outside R?
Example:
ktx-kmeans(x,12, nstart = 200)
I would
help(kmeans) describes the return value: a list with a) the complete
classification b) the cluster centers c) the within-cluster sums of squares
b) the cluster sizes. Thankfully, you don't need any parsing.
Reid Huntsinger
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL
Hello all,
This may be aimed for r-devel, but I encountered this as an R-user
and not an R-developer so I start here (having said that, please
direct me to R-devel if you think this is appropriate. I am not cross-
posting, as I believe this is bad netiquette).
I am a recent, but extremely
try this example:
x.1 - strptime(6/17/03,'%m/%d/%y')
x.1
[1] 2003-06-17
plot(0:250, xaxt='n')
dates - x.1 + c(0,50,100,150,200,250) * 86400 # 'dates' is in seconds,
so add the appropriate number of days
dates
[1] 2003-06-17 00:00:00 EDT 2003-08-06 00:00:00 EDT 2003-09-25
00:00:00 EDT
(My apologies if this is a repeated posting. I couldn't find any trace
of my previous attempt in the archive.)
I'm having trouble with forecast() in the dse2 package. It works fine
for me on a model without a trend, but gives me NaN output for the
forecast values when using a model with a
i just write one for myself,but the result is different from the spss's.
i anyone can send me a copy of function calc the lamda coefficient?(i know i
should google first,but right now i can surf the internet.)
lamda
function(table){
obs1.y-sum(apply(table,1,max))
Dear R-users,
I would like to ask whether it's possible (for sure it would be), to
plot each rows (or columns) in different graphs and in the same figure
region without using the function par and then struggling around with
axes and labels etc.
Luckily, I would always have rows + columns = even
Dear R-users,
I have a set of 12000 image samples. I can divide this set into two
categories: training and testing. I need to classify the test set into
a two qualitative outputs: true or false for some characteristic.
To do the classification I'm using the packages SVM in e1071 library
and
==
BioC2005
Where Software and Biology Connect
==
http://bioconductor.org/meeting05/
About BioC2005
==
This conference will highlight current developments within and beyond
Bioconductor, a world-wide open
Hi All,
I am working with three time varying covariates in a coxph model. I cannot
seem to figure out how to use survfit and the newdata argument to provide
estimated survival curves for two scenarios of one covariate while holding
the other two at the mean value.
Is it possible to display how
Hi All,
I'd like to plot something like
http://www.nawcwpns.navy.mil/~weather/mugu/mesodata/analysis.html
Looking through the galleries at
http://addictedtor.free.fr/graphiques/allgraph.php
http://r-spatial.sourceforge.net/gallery/
http://fawn.unibw-hamburg.de/cgi-bin/Rwiki.pl?GraphGallery
Scott
This works for me:
arma.pred.without.trend$forecast[[1]][,1]
[1] 106.0038 105.9789 105.9605 105.9396 105.9224 105.9052 105.8926 105.8849
[9] 105.8812 105.8880 105.9043 105.9240 105.9579 105.9878 105.9901 106.0095
[17] 106.0555 106.0782 106.0644 106.0427 106.0297 106.0072 106.0126
You need to use R-patched, nowadays 2.1.1 beta, not the released R 2.1.0.
As far as I know it is fixed there.
On Tue, 14 Jun 2005, Constantinos Antoniou wrote:
Hello all,
This may be aimed for r-devel, but I encountered this as an R-user
and not an R-developer so I start here (having said
Shame nobody has included this function in their package! Would be
useful to have as a standard function!
Sander.
Dimitris Rizopoulos wrote:
take a look at this function by Kevin Wright
RSiteSearch(sort.data.frame)
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Dear R-helpers,
Can you help me to see why code 1 gives error
while code 2 runs fine? The only difference in
the data is the distribution of age categories.
I am attaching the session after the code.
Many thanks.
XL
library(survival)
library(rpart)
# code 1
n - 20
age - rep(1:3, c(2, 3,
Hello,
I try to install udunits and RNetCDF packages
With the first one
after R CMD INSTALL udunits_1.2.tar.gz the script
looks for the library, does not find and says
to edit udunits_1.0/udunits/src/Makevars.in
with links to an include file and location of the
library. When I put the correct path
On Tue, 2005-06-14 at 20:00 +0200, Camarda, Carlo Giovanni wrote:
Dear R-users,
I would like to ask whether it's possible (for sure it would be), to
plot each rows (or columns) in different graphs and in the same figure
region without using the function par and then struggling around with
Thank you. I am compiling it now...
Costas
On 14 2005, at 10:13 , Prof Brian Ripley wrote:
You need to use R-patched, nowadays 2.1.1 beta, not the released R
2.1.0.
As far as I know it is fixed there.
On Tue, 14 Jun 2005, Constantinos Antoniou wrote:
Hello all,
This may be aimed
Dear helpers in this forum,
I have the following question:
Suppose I have the following data set:
id x y
023 1 2
023 2 5
023 4 6
023 5 7
412 2 5
412 3 4
412 4 6
412 7 9
220 5 7
220 4 8
220 9 8
..
and i want to calculate sum_{i=1}^k
sum_{j=1}^{n_i}x_{ij}*y_{ij}
is there a simple way to do
Hello,
This is not a problem with R, the calculated results are mathematically
correct. This a matrix stability problem. Because of measuring errors, my
matrix solution is a bit off.
Here is what my equations look like:
A11 x11+A12 x12 +A13 x13 = b1
A21 x21+A22 x21 +A23 x23 = b2
A31 x31+A32
On 6/14/05, Richard Hillary [EMAIL PROTECTED] wrote:
Hello,
Given a vector of characters, or factors, denoting the date in
the following way: 28/03/2000, is there a method of
1) Computing the earliest of these dates;
2) Using this as a base, then converting all the other dates into
On 6/14/05, Bernard L. Dillard [EMAIL PROTECTED] wrote:
Hello. I am having the worst time converting x-axis date ticks to real
dates. I have tried several suggestions in online help tips and books to
no avail.
For example, the x-axis has 0, 50, 100, etc, and I want it to have
6/17/03,
On 6/14/05, Camarda, Carlo Giovanni [EMAIL PROTECTED] wrote:
Dear R-users,
I would like to ask whether it's possible (for sure it would be), to
plot each rows (or columns) in different graphs and in the same figure
region without using the function par and then struggling around with
axes and
On 6/14/05, Ajay Narottam Shah [EMAIL PROTECTED] wrote:
I have a program which is doing a few thousand runs of lm(). Suppose
it is a simple model
y = a + bx1 + cx2 + e
I have the R object d where
d - summary(lm(y ~ x1 + x2))
I would like to obtain Var(x2) out of d. How might I do it?
On 6/14/05, Richard Mott [EMAIL PROTECTED] wrote:
Does anyone know a way to do the following:
Save a large number of R objects to a file (like load() does) but then
read back only a small named subset of them . As far as I can see,
load() reads back everything.
The context is:
I have
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Anderson de Rezende
Rocha
Sent: Tuesday, June 14, 2005 11:01 AM
To: r-help@stat.math.ethz.ch
Subject: [R] How to fix false positve rates?
Dear R-users,
I have a set of 12000 image samples. I can divide
I have a Lattice plot in which I want to adjust the number of tick
marks used, and I want to have the drawn grid reflect that change.
Here is what I'm doing:
bwplot(var1 ~ var2, data=df, scales=list(tick.number=10),
panel=function(...) {
panel.grid(h=0,v=-1,...);
It looks to me like the x measurements are normalized to sum to 1. So
whatever measurement error there is gets spread around, so to speak.
It would help if you could explain the setting a little more fully? Why is
it, for example, that you know the A values from experiment to experiment
(they do
Milos Zarkovic [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
I believe that FFT is not appropriate. However Lomb-Scargle periodogram
could be used.
This may interest you:
(Preprint of submitted paper)
Detecting periodic patterns in unevenly spaced gene expression time series
using
If you look at the code of panel.grid, you'll see why it doesn't work -- it
does not use any of the scale parameters. Moreover the Help page for
panel.grid explicitly warns that the h,v=-1 specification may not work, so
no promises have been broken.
I'm not sure how bwplot handles grids, since
On 6/14/05, Kerry Bush [EMAIL PROTECTED] wrote:
Dear helpers in this forum,
I have the following question:
Suppose I have the following data set:
id x y
023 1 2
023 2 5
023 4 6
023 5 7
412 2 5
412 3 4
412 4 6
412 7 9
220 5 7
220 4 8
220 9 8
..
and i want to calculate
Hi,
I am working with R version 2.1.0, and I seem to have run into what looks
like a bug. I get the same error message when I run R on Windows as well as
when I run it on Linux.
When I call anova to do a LR test from inside a function, I get an error.
The same call works outside of a
Hello R-USERS,
I think some people didn't understand my question. What I want is to
use the training set to minimize the FALSE POSITIVE RATE.
I think it is possible. I sacrifice ACCURACY to have less FALSE
POSITIVES. I don't want a classifier result with 5% of FPR and, for
example, 93% of
Dear Gilles,
You can try this.
Save the fortran file as 1.f
Save the C file as 2.c
Then
R CMD SHLIB 1.f 2.c
You should obtain a file named 1.so.
Then start you R program, then
dyn.load('/where/is/your/1.so')
.Fortran(testit)
You should obtain a random number which is normally distributed.
Prof Brian Ripley wrote:
On Tue, 14 Jun 2005, Frank E Harrell Jr wrote:
Prof Brian Ripley wrote:
On Tue, 14 Jun 2005, James Salsman wrote:
How can ordinary polynomial coefficients be calculated
from an orthogonal polynomial fit?
Why would you want to do that? predict() is perfectly
Prof Brian Ripley wrote:
On Mon, 13 Jun 2005, Chris Bergstresser wrote:
I'm seeing the following commands reliably produce a crash in RGui,
version 2.0.1, for both my home and office machine:
rm(list = ls(all = TRUE));
load(dataset.R);
library(wle);
data.wle = wle.lm(abortion ~ year
I have a program which is doing a few thousand runs of lm(). Suppose
it is a simple model
y = a + bx1 + cx2 + e
I have the R object d where
d - summary(lm(y ~ x1 + x2))
I would like to obtain Var(x2) out of d. How might I do it?
I can, of course, always do sd(x2). But it
On 6/14/05, Ajay Narottam Shah [EMAIL PROTECTED] wrote:
I have a program which is doing a few thousand runs of lm(). Suppose
it is a simple model
y = a + bx1 + cx2 + e
I have the R object d where
d - summary(lm(y ~ x1 + x2))
I would like to obtain Var(x2) out of d. How
On 6/14/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 6/14/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 6/14/05, Camarda, Carlo Giovanni [EMAIL PROTECTED] wrote:
Dear R-users,
I would like to ask whether it's possible (for sure it would be), to
plot each rows (or columns) in
Dear all R-users,
I am a new user of R and I am trying to build a discrete choice model (with
more than two alternatives A, B, C and D) using logistic regression. I have
data that describes the observed choice probabilities and some background
information. An example below describes the data:
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