You have already (incorrectly) filed this a bug report on *anova* and been
asked to read the R FAQ and discuss this with the package maintainer.
Please do as we ask: only package maintainers can change contributed
packages (here nlme).
On Tue, 14 Jun 2005, Nisha Mulakken wrote:
Hi,
I am
On Wed, 15 Jun 2005, Ajay Narottam Shah wrote:
I have a program which is doing a few thousand runs of lm(). Suppose
it is a simple model
y = a + bx1 + cx2 + e
I have the R object d where
d - summary(lm(y ~ x1 + x2))
I would like to obtain Var(x2) out of d. How might I do it?
I can,
Hi all,
I want to interpolate a matrix as function of its row and column
coordinates, i.e.
{u,v,w}=spline2d(x,y,z...)
Where u v are the new coordinates values and w the matrix extrapolated
Best regards
Naji
__
R-help@stat.math.ethz.ch mailing list
Hi,
yet another anova.mlm problem - it doesn't seem to end.
This time, I have a setup with a few within-subject factors and a
between-subject factor (SGROUP). Consider the most simple case with only one
within-factor (apo):
mlmfit0 - lm(data.n ~ 0 + SGROUP)
mlmfit1 - lm(data.n ~ 1 + SGROUP)
Are there functions available computing the gamma-correlation for ordinal
scaled variables and kappa-accuracy for nominal variables,
thanks, Mark
...
Swiss Federal Institute for Forest, Snow and Landscape Research
Hi all,
I'm trying to find a way to get xyplot to produce a second set of axes outside
the right hand side of the graph. This is my progress so far:
EE - equal.count(ethanol$E, number=9, overlap=1/4)
xyplot(NOx ~ C | EE, data = ethanol,
prepanel = function(x, y) prepanel.loess(x, y,
Hi all,
I want to draw a line with the values of x marked in X axis.
I tried with
x - c(0,6,12,18,24,30) #coordinates of points x
y - c(2,5,7,5,7,16) #coordinates of points y
plot(x,type=n,xlab=Months,ylab=Y
values,main=main,ylim=c(0,16),xlim=c(0,30))
lines(x,y)
The graph shows by default
Hi,
I run a script file by dropping it on a windows batch file that runs R
in --slave modus. In a subfunction there is the call to file.choose().
The problem is, that the dialog does show only folders but no files at
all. It's quite strange: a) without --slave modus the files are shown,
b) when I
try:
plot(x, y, type=l, xlab=Months,
xaxt=n, ylab=Y values)
axis(1, at=0:5*6)
Stefano
-Messaggio originale-
Da: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] conto di Massimiliano
Tripoli
Inviato: mercoledì 15 giugno 2005 10.35
A: r-help@stat.math.ethz.ch
Le 15.06.2005 10:35, Massimiliano Tripoli a écrit :
Hi all,
I want to draw a line with the values of x marked in X axis.
I tried with
x - c(0,6,12,18,24,30) #coordinates of points x
y - c(2,5,7,5,7,16) #coordinates of points y
plot(x,type=n,xlab=Months,ylab=Y
OS? R version? Locale?
This is a known problem with R 2.1.0 on Windows in some locales, solved
long ago in R-patched.
On Wed, 15 Jun 2005, Hans-Peter wrote:
Hi,
I run a script file by dropping it on a windows batch file that runs R
in --slave modus. In a subfunction there is the call to
hi,
i am using the RODBC package to read .xls files. now after i installed
the package and loaded the library and tried to read a file this is
the error i got.
channel-odbcConnect(D:/rstuff/1.xls)
Warning messages:
1: [RODBC] ERROR: state IM002, code 0, message [Microsoft][ODBC Driver
Manager]
Prof Brian Ripley [EMAIL PROTECTED] writes:
On Wed, 15 Jun 2005, Ajay Narottam Shah wrote:
I have a program which is doing a few thousand runs of lm(). Suppose
it is a simple model
y = a + bx1 + cx2 + e
I have the R object d where
d - summary(lm(y ~ x1 + x2))
I would like
Bela Bauer [EMAIL PROTECTED] writes:
Hi,
yet another anova.mlm problem - it doesn't seem to end.
This time, I have a setup with a few within-subject factors and a
between-subject factor (SGROUP). Consider the most simple case with only one
within-factor (apo):
mlmfit0 - lm(data.n ~ 0 +
Dear All,
Is it possible under WinXP to set the R binary path (...\R\bin)
as an environment variable during installation?
(rw2010.exe)
The problem is that I've written a program that needs to know the path
of Rterm.exe during installation.
At the moment the user can't choose the R installation
Hi,
I want to determine the confidence interval on the sum of two sigma's.
Is there an easy way to do this in R? I guess I have to use some sort of
chisquare convolution algorithm???
Thanx,
Roy
--
The information contained in this communication and any atta...{{dropped}}
On this day 6/15/2005 12:03 AM, Gabor Grothendieck wrote:
Is the code in your post intended to show what worked so others
will know what to do
Yes, I succes to remove and install gregmisc again like I have posted
before.
Regards,
Muhammad Subianto
or is that code intended to show what you
Hello!
I've tried to execute an R script that I used to use with older versions with
no problem. In the scrip ,I try to create a series of plots in png format,
and now there is an error (my actual verion is R2.0.1)
Error in title(main=main,sub=sub,xlab=xlab,ylab=ylab,...):
X11 font at size 14
2005/6/15, Prof Brian Ripley [EMAIL PROTECTED]:
OS? R version? Locale?
Win2000, SP4 - 2.1.0 -
LC_COLLATE=German_Switzerland.1252;
LC_CTYPE=German_Switzerland.1252;
LC_MONETARY=German_Switzerland.1252;
LC_NUMERIC=C;LC_TIME=German_Switzerland.1252
This is a known problem with R 2.1.0 on
Hi
I'm having difficulty following the advice in section 2.7 of R-exts.
In one of my packages, there is a function called mobius().
I want to refer to it in the Rd file as the Möbius function, and to
illustrate the
Möbius inversion formula (just to be explicit: this is Mobius but
with two
Hello Javier,
Please if you can provide more details about the script you are using, we
can help you out more effectively.
Thanks,
Carlos Ortega.
On 6/15/05, javier garcia [EMAIL PROTECTED] wrote:
Hello!
I've tried to execute an R script that I used to use with older versions
with
no
My new task (which I have not investigated yet) is to see if facilities
exist in R to turn the X11 device into an HTML document with an
html-map or into a PDF with hyperlinks.
To create an HTML imagemap, see B. Rowlingson's imagemap package at:
Vivek Subramanian wrote:
hi,
i am using the RODBC package to read .xls files. now after i installed
the package and loaded the library and tried to read a file this is
the error i got.
channel-odbcConnect(D:/rstuff/1.xls)
D:/rstuff/1.xls is not a DSN. Probably you are going to use
I have data in the form of (x,y) pairs and would like to find local
minima and maxima (typically the zeros of the 2nd derivative) of the y
values. I looked at numericDeriv, but I don't have an expression per
se. I looked at optim, also, but it looks like it will find only one
global max or
If you need work-around, than you can always save excel file in csv format
and than read that. See 'read.csv' or 'read.csv2'.
Jarek
\===
Jarek Tuszynski, PhD. o / \
Science Applications International
On Wed, 15 Jun 2005, Hans-Peter wrote:
2005/6/15, Prof Brian Ripley [EMAIL PROTECTED]:
OS? R version? Locale?
Win2000, SP4 - 2.1.0 -
LC_COLLATE=German_Switzerland.1252;
LC_CTYPE=German_Switzerland.1252;
LC_MONETARY=German_Switzerland.1252;
LC_NUMERIC=C;LC_TIME=German_Switzerland.1252
Sean Davis wrote:
I have data in the form of (x,y) pairs and would like to find local
minima and maxima (typically the zeros of the 2nd derivative) of the y
values. I looked at numericDeriv, but I don't have an expression per
se. I looked at optim, also, but it looks like it will find
It is unclear what you want to do, but it is clear that this is not the
appropriate list (see the posting guide) and that your subject line is
misleading.
Note that the path to R is normally entered in the registry during
installation, but this is optional as some users have a read-only
On Wed, 15 Jun 2005, javier garcia wrote:
I've tried to execute an R script that I used to use with older versions with
no problem. In the scrip ,I try to create a series of plots in png format,
and now there is an error (my actual verion is R2.0.1)
Error in
secretario academico FACEA wrote:
Dear all,
Is it possible to change the levels in a mosaic plot,
Change the levels? This depends on the data, not on the plot function, I
think...
the appearance of the level
What does apprearance mean? See ?mosaicplot which tells you how to
re-order
Robin Hankin [EMAIL PROTECTED] writes:
Hi
I'm having difficulty following the advice in section 2.7 of R-exts.
In one of my packages, there is a function called mobius().
I want to refer to it in the Rd file as the Möbius function, and to
illustrate the
Möbius inversion formula
Thanks you very much, Prof Ripley.
My actual version is 2.1.0 (I was confused).
The problem was exactly that one. I've installed the 100dpi fonts and now
there is no problem.
Thanks and best regards,
Javier
-
El Miércoles, 15 de Junio de 2005 14:28, Prof Brian Ripley escribió:
On Wed, 2005-06-15 at 10:16 +0200, Markus Schwarz wrote:
Are there functions available computing the gamma-correlation for ordinal
scaled variables and kappa-accuracy for nominal variables,
thanks, Mark
Mark,
Please use a meaningful subject.
1. For Gamma:
A. See the rcorr.cens()
Tuszynski, Jaroslaw W. JAROSLAW.W.TUSZYNSKI at saic.com writes:
If you need work-around, than you can always save excel file in csv format
and than read that. See 'read.csv' or 'read.csv2'.
Or use read.xls() from Greg's gdata package on CRAN. Gdata embeds Perl
code for reading xls files.
On Wed, 15 Jun 2005, Peter Dalgaard wrote:
Robin Hankin [EMAIL PROTECTED] writes:
Hi
I'm having difficulty following the advice in section 2.7 of R-exts.
In one of my packages, there is a function called mobius().
I want to refer to it in the Rd file as the Möbius function, and to
Dear R-helpers,
I have dataset (data.frame) like below,
x1 x2 x3 x4 x5 x6 x7 x8 x9 ... x1200
000110011
100110011
010110011
110110011
...
How
The example in the R doc
and the hints from Shusong Jin , Ingmar Visser and Reid Huntsinger
(thanks all three) refer to the case where the function does not have
arguments.
I'm still looking for a proper sequence of commands
to call C functions with arguemnts from R.
Imagine I want to
x - data.frame(matrix(c(1,0,1,0,1,1),nrow=3))
x[x==0] - 'no'
x[x==1] - 'yes'
x
X1 X2
1 yes no
2 no yes
3 yes yes
On Jun 15, 2005, at 9:58 AM, Muhammad Subianto wrote:
Dear R-helpers,
I have dataset (data.frame) like below,
x1 x2 x3 x4 x5 x6 x7 x8 x9 ... x1200
try this:
dat - data.frame(matrix(sample(0:1, 100 * 20, TRUE), 100, 20))
dat[] - lapply(dat, factor, levels = c(0, 1), labels = c(no,
yes))
dat
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic
Thanks, Uwe.
Actually, I didn't mean to make this complicated--simple vector x and
values at x in a vector y. Just wanted to determine the local minima
and maxima of y[x], but y is not continuous (but is a smooth function
of x). I will probably use hist or density to do it and then look at
On Wed, 2005-06-15 at 15:58 +0200, Muhammad Subianto wrote:
Dear R-helpers,
I have dataset (data.frame) like below,
x1 x2 x3 x4 x5 x6 x7 x8 x9 ... x1200
000110011
100110011
010110
Hi,
I would like to know:
1) if there is a way of getting an R-squared value for a bootstrap
crossvalidation.
2) how I can get the total residual standard error for a bootstraped model.
Thanks,
Caterina
__
R-help@stat.math.ethz.ch mailing list
Hi all,
for example:
X- rnorm(1000)
X0 - 0.899
I want to draw a density distribution plot with a arrow pointer
indicating the position of X0, meanwhile, giving out the p-value.
any functions?
Thanks very much.
__
R-help@stat.math.ethz.ch mailing
Greetings,
We want to fit lme/gls models with a compound symmetry variance
structure, but where the ICC takes different values across different
groups of clusters. (Specifically a two arm clustrered trial with different
ICC in each arm) Equivalent models can be fitted with heteroscedastic
Hi R-gurus,
In python one can do
import string
print string.letters
and get the characters in the local character set.
This feature is often useful in Python, and if I could find it in R
I could make good use of it.
In R both Sys.getlocale() and localeToCharset() can tell me which
charset
1. The function KalmanLike seems to change its inputs AND
PREVIOUSLY MADE copies of the inputs. Consider the following (using R
2.1.0 patched under Windows XP):
Fig2.1 - StructTS(x=Nile, type=level)
unlist(Fig2.1$model0[2:3])
a P
1120 286379470
tst2 -
This is one way not so good
RX-rnorm(100)
RX0-.899
Rplot(density(X))
Rabline(v=X0)
A better way
Rx-seq(-5,5,.01)
Rplot(x,dnorm(x))
Rplot(x,dnorm(x),type=l,col=2)
Rabline(v=X0,col=4)
R?text
Rtext(X0,.2,paste(P(XX0) =,signif(pnorm(X0),3)),pos=2)
Rabline(v=X0,col=4)
If you actually want arrows
Dear helpers in this forum,
This is a clarified version of my previous
questions in this forum. I really need your generous
help on this issue.
Suppose I have the following data set:
id x y
023 1 2
023 2 5
023 4 6
023 5 7
412 2 5
412 3 4
412 4 6
412 7 9
220 5 7
220 4 8
220 9
Hi!
How can I suppress the output of the function nnet in the library(nnet) ?
I get the following output :
nn = nnet(x, y, size=5, maxit=40, linout=TRUE);
# weights: 16
initial value 33.511291
iter 10 value 5.792440
iter 20 value 5.279584
iter 30 value 4.800890
iter 40 value 4.593410
Dear all,
Sean Davis, Dimitris Rizopoulos and Marc Schwartz, thanks for your great
help. It works perfectly. Thanks a lot.
All the best,
Muhammad Subianto
On this day 6/15/2005 4:06 PM, Sean Davis wrote:
x - data.frame(matrix(c(1,0,1,0,1,1),nrow=3))
x[x==0] - 'no'
x[x==1] - 'yes'
gg - function(y) {
ggg - function() {
cat(current frame is, sys.nframe(), \n)
cat(parents are, sys.parents(), \n)
print(sys.function(0)) # ggg
print(sys.function(2)) # gg
}
if(y 0) gg(y-1) else ggg()
}
gg(3)
I did several simulation sessions and the result turned out to be a
surprise. After some investigation, I found that different R sessions
of the program used the same seed. Simply, in R210, if I start R and
type rnorm(1), I always get the same random number. This is
contradictary to what is in the
On Wed, 15 Jun 2005, Spencer Graves wrote:
1. The function KalmanLike seems to change its inputs AND
PREVIOUSLY MADE copies of the inputs.
The strange thing is that it changes its inputs. It would be expected that
this also changed previously made copies. The copies will just be
Thorstensen Nicolas wrote:
Hi!
How can I suppress the output of the function nnet in the library(nnet) ?
?nnet suggests adding trace=FALSE to the arguments.
In other cases if functions dont have this sort of option then on a
Unix box you can wrap your function calls in sink(/dev/null)
On Wed, 15 Jun 2005, Jason Liao wrote:
I did several simulation sessions and the result turned out to be a
surprise. After some investigation, I found that different R sessions
of the program used the same seed. Simply, in R210, if I start R and
type rnorm(1), I always get the same random
Hi, Robin:
Have you considered using moebius? In my elementary German class,
I was taught that oe was an acceptable alternative to the umlaut.
(This may not be relevant, but Google just gave me 788,000 hits for
moebius and 750,000 for mobius.) Perhaps one of our German
On Wed, 15 Jun 2005, Thomas Lumley wrote:
On Wed, 15 Jun 2005, Spencer Graves wrote:
1. The function KalmanLike seems to change its inputs AND
PREVIOUSLY MADE copies of the inputs.
The strange thing is that it changes its inputs. It would be expected that
this also changed
Thank you, Prof. Ripley. Yes, it turned out that different R sessions
(batch mode) loaded the same work space. Inserting
rm(list=ls(all=TRUE))
on top of the code solves the problem.
--- Prof Brian Ripley [EMAIL PROTECTED] wrote:
On Wed, 15 Jun 2005, Jason Liao wrote:
I did several
Hi, Thomas:
Thanks much. I modified the R code for KalmanLike as you
suggested, and the problem went away.
Next question: Should KalmanLike work the way it does without your
suggested modification? If not, how do we get your proposal transmitted
to the appropriate
Prof Brian Ripley [EMAIL PROTECTED] writes:
UTF-8 for latex does not work well (as yet, at least: there is now a
utf8 encoding that allows at least the first plane (Latin-1) to work).
So it would be much better to use Latin-1 for the file and mark it
with \encoding{latin1} and mark
Greetings fellow humans,
I am attempting to export a text file after using the MatchIt package to match
control with treatment subjects. I attempted to write.table and used the
following syntax:
write.table(social,shaka.txt,sep= ,quote=FALSE,row.names=FALSE,col.names=
FALSE)
But received
could you set trace = FALSE in the nnet().
On 6/15/05, Thorstensen Nicolas [EMAIL PROTECTED] wrote:
Hi!
How can I suppress the output of the function nnet in the library(nnet) ?
I get the following output :
nn = nnet(x, y, size=5, maxit=40, linout=TRUE);
# weights: 16
initial
Caterina Barillari wrote:
Hi,
I would like to know:
1) if there is a way of getting an R-squared value for a bootstrap
crossvalidation.
2) how I can get the total residual standard error for a bootstraped model.
Thanks,
Caterina
Install the Design and Hmisc packages and look at
p = data.frame(high=c(5,2), settle=c(3,4))
p
high settle
15 3
22 4
What is the most abbreviated way to apply:
if (p$high p$settle) p$high = p$settle
I want to modify p to become:
p
high settle
15 3
24 4
__
On Wed, 15 Jun 2005, Spencer Graves wrote:
Thanks much. I modified the R code for KalmanLike as you
suggested, and the problem went away.
Next question: Should KalmanLike work the way it does without your
suggested modification? If not, how do we get your proposal
Dear R-helpers,
To get curves for a pseudo cohort other than the one centered at the mean of
the covariates, I have been trying to use the newdata argument to survfit
with no success. Here is my model statement, the newdata and the ensuing
error. What am I doing wrong?
summary(fit)
Call:
On Wed, 15 Jun 2005, Omar Lakkis wrote:
p = data.frame(high=c(5,2), settle=c(3,4))
p
high settle
15 3
22 4
What is the most abbreviated way to apply:
if (p$high p$settle) p$high = p$settle
I want to modify p to become:
p
high settle
15 3
24 4
On Wed, 2005-06-15 at 13:59 -0400, Omar Lakkis wrote:
p = data.frame(high=c(5,2), settle=c(3,4))
p
high settle
15 3
22 4
What is the most abbreviated way to apply:
if (p$high p$settle) p$high = p$settle
I want to modify p to become:
p
high settle
15
Spencer Graves spencer.graves at pdf.com writes:
(This may not be relevant, but Google just gave me 788,000 hits for
moebius and 750,000 for mobius.) Perhaps one of our German
contributors could tell us which they prefer.
As you asked for it: The former is correct, and the second is a
On Wed, 2005-06-15 at 19:33 +0100, Prof Brian Ripley wrote:
On Wed, 15 Jun 2005, Omar Lakkis wrote:
p = data.frame(high=c(5,2), settle=c(3,4))
p
high settle
15 3
22 4
What is the most abbreviated way to apply:
if (p$high p$settle) p$high = p$settle
I want
Greetings,
I would like to plot three lines on the same figure, and I am lost. There is
an answer to a similar thread
but I tried matplot and it is beyond me. An
example of the data follows:
YearEM IM BM
19839.1 16.8-7.7
198412.018.0-6.0
198513.6
Apologies for cross posting
**Reserve the Dates**
SALFORD SYSTEMS DATA MINING 2006 CONFERENCES
San Diego, California: March 29 - March 31, 2006
Sydney, Australia: June 7 - June 8, 2006
The conference will offer prominent keynote speakers, including Jerome
Friedman, coupled with informative
assuming that your matrix is named x, try
matplot(x,type=l)
Ales Ziberna
P.S.: see ?matplot for help to matplot. That it all it took me!
- Original Message -
From: Mihai Nica [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Sent: Wednesday, June 15, 2005 8:50 PM
Subject: [R] Multiple
Have you considered the distr package?
Consider the following:
library(distr)
C1234 - Chisq(df=1, ncp=2)+Chisq(df=3, ncp=4)
# = Chisq(df=1+3, ncp=2+4)
q(C1234)(c(.025, .975))
[1] 1.823846 23.435932
qchisq(c(.025, .975), 4, 6)
[1] 1.823846 23.435932
C12345 -
On Wed, 2005-06-15 at 13:50 -0500, Mihai Nica wrote:
Greetings,
I would like to plot three lines on the same figure, and I am lost. There is
an answer to a similar thread but I tried matplot and it is beyond me. An
example of the data follows:
Year EM IM BM
1983 9.1
You appear to have a coding for prior.f in newdata rather than the factor
itself.
It's a bit hard to be sure when we don't have data8 to compare with.
On Wed, 15 Jun 2005, Hanke, Alex wrote:
Dear R-helpers,
To get curves for a pseudo cohort other than the one centered at the mean of
the
As this is a proper name, is not what is `right' what the person concerned
prefers (if known)?
Guessing on their behalf is not unambiguous: even if you know someone is,
say, German, their surname may not be or vice versa.
People have even written to me to `correct' the spelling of `Box and
Hi!, I made a plot with two variables representing the first two axis of a
principle component analysis. My question is:
How can I superimpose on such plot an ellipse that represent the 95% interval of
confidence of scores?
Best regards,
Paula
--
Lic. Paula Gonzalez
División Antropología
Here is an example. It assumes the data is in a
data frame, with all variables numeric.
tst - data.frame(yr=1981:1990,y1=rnorm(10), y2=5+rnorm(10), y3=rnorm(10)-3)
plot(tst$yr, tst$y1, ylim=range(tst[,-1]),type='l')
lines(tst$yr,tst$y2,col=2)
lines(tst$yr,tst$y3,col=3)
-Don
At 1:50 PM
You could do something like
ids - unique(mydata$id)
ans - vector(length=length(ids), mode=list)
for (i in ids) {
g - which(mydata$id == i)
ans[[i]] - (length(g) - 1)*cov(mydata$x[g], mydata$y[g])
}
ans
but cov() returns NA for length 1 vectors, so you'd want an if (length(g) ==
1) ans[i] - 0
Hi,
I am using Partek for LDA analysis. For a binary
response variable, it generates 2 discriminant
functions, one for each of the 2 levels of the
response variable. And I can simply calculate 2
discriminant scores (say d1 and d2) for each sampples
using the 2 discriminant functions, then I can
Note that p1 and p2 depend only on d1 - d2. Have a look at a book like
Ripley's Pattern Recognition and Neural Networks or Anderson's
multivariate statistics book for further information.
Reid Huntsinger
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of
Hi, there:
I have a dataset like the following:
1412|WINDOW|SHATTER|TORN|SOFT|TOP|WATER|RAIN|LAB|AI|BOLL|CAMP|0
1413|PARK|IV|STRUCK|PARK|PUSH|COD|POLICI|CIA|TB|SIC|0
2412|ACCID|REAREND|MULTI|EH|IV|MIDDL|FAN|DUAL|LOSS|CALM|1
2414|IV|REAREND|CD|COG|LAB|ADVERS|1
On 15 Jun 2005, at 23:05, [EMAIL PROTECTED] wrote:
Hi!, I made a plot with two variables representing the first two axis
of a
principle component analysis. My question is:
How can I superimpose on such plot an ellipse that represent the 95%
interval of
confidence of scores?
You can't,
Hi !
how can I do a k-fold crossvalidation with neural networks?
and how can I load matlab data files into R?
thx in advance!
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
I would compile a table of all the words in the dataset (maybe you have it
already), then create a list where each component is an integer vector of
indices of words. That is, replace words by their positions in the table.
From that sparse form you could create binary features to use with
The data structure I described is a sparse (binary) matrix, and I should
have said you could use the SparseM or Matrix package's sparse matrix
classes and methods to do what I suggested below. There are linear algebra
routines available for them but for other things I'm not sure.
Reid Huntsinger
On 6/15/05, Marc Schwartz [EMAIL PROTECTED] wrote:
On Wed, 2005-06-15 at 19:33 +0100, Prof Brian Ripley wrote:
On Wed, 15 Jun 2005, Omar Lakkis wrote:
p = data.frame(high=c(5,2), settle=c(3,4))
p
high settle
15 3
22 4
What is the most abbreviated way to
A simple workaround would be to call KalmanLike this way:
KalmanLike(y, mod[], nit)
as [] makes a copy.
On 6/15/05, Spencer Graves [EMAIL PROTECTED] wrote:
Hi, Thomas:
Thanks much. I modified the R code for KalmanLike as you
suggested, and the problem went away.
One thing to be careful of is that we likely intend to
represent the columns of the data frame as factors in which
case we still want the levels to be No and Yes even if a
column only consists of one level (i.e. all No or all Yes).
Note that one solution specifically provided for that.
On
1. See ?turnpoints in package pastecs.
2. do it yourself with rapply in the zoo package:
library(zoo)
f - function(x) x[2] max(x[-2])
rapply(zoo(rank(x, ties = first)), 3, function(x) f(x) - f(-x))
Note that if a run is an extrema then the last member of a
run of maxima and the
On 6/15/05, Dirk Eddelbuettel [EMAIL PROTECTED] wrote:
Spencer Graves spencer.graves at pdf.com writes:
(This may not be relevant, but Google just gave me 788,000 hits for
moebius and 750,000 for mobius.) Perhaps one of our German
contributors could tell us which they prefer.
As you
On 6/15/05, Barry Rowlingson [EMAIL PROTECTED] wrote:
Thorstensen Nicolas wrote:
Hi!
How can I suppress the output of the function nnet in the library(nnet) ?
?nnet suggests adding trace=FALSE to the arguments.
In other cases if functions dont have this sort of option then on a
I think Lic. Paula Gonzalez is after one ellipse representing
Hotelling's T^2 with the major axis of the ellipse oriented
along PC1 and minor axis oriented along PC2.
douglas
On Jun 15, 2005, at 5:27 PM, Jari Oksanen wrote:
On 15 Jun 2005, at 23:05, [EMAIL PROTECTED] wrote:
Hi!, I made
On 6/15/05, ronggui [EMAIL PROTECTED] wrote:
gg - function(y) {
ggg - function() {
cat(current frame is, sys.nframe(), \n)
cat(parents are, sys.parents(), \n)
print(sys.function(0)) # ggg
print(sys.function(2)) # gg
}
On 6/15/05, Mihai Nica [EMAIL PROTECTED] wrote:
Greetings,
I would like to plot three lines on the same figure, and I am lost. There is
an answer to a similar thread but I tried matplot and it is beyond me. An
example of the data follows:
YearEM IM BM
19839.1 16.8
Hi, Gabor: Great. Thanks. spencer graves
Gabor Grothendieck wrote:
A simple workaround would be to call KalmanLike this way:
KalmanLike(y, mod[], nit)
as [] makes a copy.
On 6/15/05, Spencer Graves [EMAIL PROTECTED] wrote:
Hi, Thomas:
Thanks much. I modified the R code
Greetings,
Can anyone suggest me if we can vectorize the following problem
effectively?
I have two datasets, one dataset is portfolio of stocks returns on a
historical basis and another dataset consist of a bunch of factors (again on
a historical basis). I intend to compute a rolling
Thanks.
A small arrow may be more nice-looking than a long cutting line.
and, another question,
how to get the p-value of the position of X0?
If the whole distribution is not as regular as norm, chi-square but a
strange one, how could I get the X0's p-value?
any functions?
Thanks very much.
On
Hi there,
I am a master student in Denmark, and apply R to analyze the drug data.
I use the function 'lda' to obtain a linear discriminant object, and
then wish to use 'plot.lda' to do the plot on this object like below.
drug.lda - lda(Inhibition ~ NET_CHARGE + PKA_1 + MW + MLOGP,
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