Hi,
how can I extract the t-values after running a pairwise.t.test? The
output just list the p-values.
Many thanks for your help.
Cheers
Guido
Guido J. Parra
School of Tropical Environment Studies and Geography
James Cook University
Townsville
Queensland
On Fri, 5 Aug 2005 Julia Reid wrote:
Subject: [R] GAP pointer
I am trying to do a simple segregation analysis using the GAP package. I
have the documentation for pointer but I desperately need an example so
that I can see how to format the datfile and the jobfile. For each
individual, I
Hi
I am trying to use this function. Can anyone show me how I would input
the following example?
Chi-Squared = (40-30)^2 + (20-30)^2 + (30-30)^2
30 30 30
= 3.333 + 3.333 + 0 = 6.666 (p value = 0.036)
I want to be able to use different
Le mail envoye a [EMAIL PROTECTED] le lundi 08 août contient un virus
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PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Hallo
My output lists more than p-values
ttt-t.test(rnorm(10), rnorm(10), paired=T)
ttt
Paired t-test
data: rnorm(10) and rnorm(10)
t = 1.7508, df = 9, p-value = 0.1139
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-0.1750263
I think the questioner was interested in pairwise.t.test. See
?pairwise.t.test. From looking at the source, pairwise.t.test calls t.test
if sd's are not pooled, or calculates its own t.val if sds are pooled. It
looks very easy to hack to return the t values instead of the p values.
Simon.
At
Guido Parra Vergara [EMAIL PROTECTED] writes:
Hi,
how can I extract the t-values after running a pairwise.t.test? The
output just list the p-values.
Many thanks for your help.
It's not a very complicated function. Why not just modify it to your
needs?
--
O__ Peter Dalgaard
Stephen Choularton [EMAIL PROTECTED] writes:
Hi
I am trying to use this function. Can anyone show me how I would input
the following example?
Chi-Squared = (40-30)^2 + (20-30)^2 + (30-30)^2
30 30 30
= 3.333 + 3.333 + 0 = 6.666 (p
Hi,
I was a user of the searchable Mail Archives which you have
linked from somewhere on your homepage.
http://maths.newcastle.edu.au/~rking/R/
This link is out of order. I know there is a search at GMANE
and MARC, but the results were not that nice.
Is it possible to recreate this searchable
Hi,
I am not familiar with changing R functions. I
can see in the code that t-values get calculated
as t. val, however when I modified the code to
include t.val under ans and then run the modified
function I get Object t.val not found. How do
I properly modify the function to list t. val in
Hi Everybody,
I am interested in estimating nested logit with latent classes at the
lower level.
I have seen the codes for conditional logit and latent class analysis
but I havent found anything about nested logit all the more nested
logit with latent classes.
Could you help me with
Hi all,
When I tried to install package randomForest, it gave out the following
error message:
install.packages(randomForest, dependencies = TRUE)
trying URL
'http://www.lmbe.seu.edu.cn/CRAN/src/contrib/randomForest_4.5-12.tar.gz'
Content type 'application/x-gzip' length 82217 bytes
opened
Xiao Jianfeng wrote:
Hi all,
When I tried to install package randomForest, it gave out the following
error message:
install.packages(randomForest, dependencies = TRUE)
trying URL
'http://www.lmbe.seu.edu.cn/CRAN/src/contrib/randomForest_4.5-12.tar.gz'
Content type
Hallo
I am not sure but this could be what you want. You has to change
function compare.levels not only add t.val in ans. If you want t-
values AND p-values together in one table it probably is not so
simple.
my.pairded.t.test - function (x, g, p.adjust.method =
p.adjust.methods, pool.sd =
The site by Robert King is now working again. I admit that I had
problems accessing it too few times last week. By adding the phrase
site:https://stat.ethz.ch/pipermail/r-help/; in my google search, I got
something that resembled that output but it did specify from which
archive and month the
On Mon, 8 Aug 2005, Uwe Ligges wrote:
Xiao Jianfeng wrote:
Hi all,
When I tried to install package randomForest, it gave out the following
error message:
install.packages(randomForest, dependencies = TRUE)
trying URL
Hi Everyone
May I request for a small help while performing the regression analysis.
I would like to know is there any possibility of conducting the
regression for different data subsets (in the same data file),
classified on the basis of grouping variable. The alternative for
this is running
hi all
are we able to combine column vectors of different lengths such that the
result appears in matrix form?
e.g.
a=1
b=1:3
d=1:4
then
z=CBIND(a,b,d)
1 1 1
2 2
3 3
4
i stil want the following!
z[,1]=1
z[,2]=1:3
z[,3]=1:5
i made up the name of this function. we could use cbind
hi all
assume that one is doing a simulation. in each iteration one produces a
vector of results. this vectors length might change for each different
iteration. how can one construct a matrix that contains all of the
interation results in a matrix where each of the columns are the outputs
from
Clark Allan wrote:
hi all
assume that one is doing a simulation. in each iteration one produces a
vector of results. this vectors length might change for each different
iteration. how can one construct a matrix that contains all of the
interation results in a matrix where each of the
Clark Allan wrote:
hi all
are we able to combine column vectors of different lengths such that the
result appears in matrix form?
e.g.
a=1
b=1:3
d=1:4
then
z=CBIND(a,b,d)
1 1 1
2 2
3 3
4
i stil want the following!
z[,1]=1
z[,2]=1:3
z[,3]=1:5
i made up
Clark Allan wrote:
hi all
are we able to combine column vectors of different lengths such that the
result appears in matrix form?
e.g.
a=1
b=1:3
d=1:4
then
z=CBIND(a,b,d)
1 1 1
2 2
3 3
4
i stil want the following!
z[,1]=1
z[,2]=1:3
z[,3]=1:5
i made
Dear list,
I would like to create histograms for up to three groups, with
distincive colour/pattern, in a trellis panel. However, I have not
been able to find a way to do this. histogram does not seem to have a
group argument.
Please help.
/Fredrik
On 8/8/05, Clark Allan [EMAIL PROTECTED] wrote:
hi all
are we able to combine column vectors of different lengths such that the
result appears in matrix form?
e.g.
a=1
b=1:3
d=1:4
then
z=CBIND(a,b,d)
1 1 1
2 2
3 3
4
i stil want the following!
z[,1]=1
On 8/8/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 8/8/05, Clark Allan [EMAIL PROTECTED] wrote:
hi all
are we able to combine column vectors of different lengths such that the
result appears in matrix form?
e.g.
a=1
b=1:3
d=1:4
then
z=CBIND(a,b,d)
1 1 1
you could use function lmList() from the nlme package, i.e.,
dat - data.frame(y = rnorm(120), x = runif(120, -3, 3), g = rep(1:3,
each = 40))
library(nlme)
m - lmList(y ~ x | g, data = dat)
m
summary(m)
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
On 8/8/05, Krishna [EMAIL PROTECTED] wrote:
Hi Everyone
May I request for a small help while performing the regression analysis.
I would like to know is there any possibility of conducting the
regression for different data subsets (in the same data file),
classified on the basis of
Hi Gary,
I have found this, but it is not exactly what I am looking for.
What I need is the groups to be inside of a single panel, not in
different panels.
Kind of like an histogram version of the xyplot(Y ~ X1,
groups=X2,panel=panel.superpose) command. (I hope this is correct).
/Fredrik
On
Prof Brian Ripley wrote:
On Mon, 8 Aug 2005, Uwe Ligges wrote:
Xiao Jianfeng wrote:
Hi all,
When I tried to install package randomForest, it gave out the following
error message:
install.packages(randomForest, dependencies = TRUE)
trying URL
Hi everybody,
I'd like to know if there's an easy way for extracting
outliers record from a dataset, in order to perform
further analysis on them.
Thanks
Alessandro
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Date: Thu, 4 Aug 2005 19:36:35 +0200
From: Cristian [EMAIL PROTECTED]
Subject: [R] linkage disequilibrium
To: r-help@stat.math.ethz.ch
Message-ID: [EMAIL PROTECTED]
Content-Type: text/plain; charset=ISO-8859-1
I'm using the package Genetics, and I'm interested in the computation of D'
Hi Alessandro,
On Mon, 8 Aug 2005, alessandro carletti wrote:
Hi everybody,
I'd like to know if there's an easy way for extracting
outliers record from a dataset, in order to perform
further analysis on them.
The answer is no. The reasons are not technical. There are some quite
easy outlier
Perhaps what Alessandro is after is simpler than that: Making a plot of data in
a data frame, being able to click on 'suspicious points', getting the
corresponding rows of a data out in a new data frame (for further inspection)
while keeping the 'good points' in the plot (and perhaps redoing
Hi,
if Soren is right, why not take a look on the identify help page?
Christian
On Mon, 8 Aug 2005, Søren Højsgaard wrote:
Perhaps what Alessandro is after is simpler than that: Making a plot of data
in a data frame, being able to click on 'suspicious points', getting the
corresponding
Hi,
I would like to get the coefficient of polynomial expansion. For example,
(1+ x)^2 = 1 + 2x + x^2, and the coefficients are 1, 2 and 1.
(1 + x + x^2)^3 = 1 + 3*x + 6*x^2 + 7*x^3 + 6*x^4 + 3*x^5 + x^6, and
the coefficients are 1, 3, 6, 7, 6, 3, and 1.
I know that we can use polynom library.
From: Prof Brian Ripley
On Mon, 8 Aug 2005, Uwe Ligges wrote:
Xiao Jianfeng wrote:
Hi all,
When I tried to install package randomForest, it gave out
the following
error message:
install.packages(randomForest, dependencies = TRUE)
trying URL
Dear R-helpers,
I'm trying to get xyplot to plot 2 y-axes. I looked at the examples
and googled around. This is how far I got so far.
test-data.frame(a=rnorm(100),b=rnorm(100)*10,ind=rep(1:10,10),con=rep
(1:10,rep(10,10)))
xyplot(a+b~con|ind,data=test,allow.multiple=T)
This however puts a+b
Liaw, Andy wrote:
Thanks for catching that! It must have slipped when I was going back and
forth between C and Fortran...
Update should appear on CRAN this week, I hope.
Best,
Andy
Thanks for your quick replay.
I just want you to know that I have tried R 2.1.0 on my pc running
Debian
Hi all,
In heatmap's documentation, it mentions that the output value is
actually an invisible list...how would one access this list?
Thanks,
Jake
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
On 8/8/05, Peter Yang [EMAIL PROTECTED] wrote:
Hi,
I would like to get the coefficient of polynomial expansion. For example,
(1+ x)^2 = 1 + 2x + x^2, and the coefficients are 1, 2 and 1.
(1 + x + x^2)^3 = 1 + 3*x + 6*x^2 + 7*x^3 + 6*x^4 + 3*x^5 + x^6, and
the coefficients are 1, 3, 6, 7,
1) If the output at each iteration gives a fixed number of elements,
then you can pre-define the matrix. For example
mat - matrix( NA, nr=6, nc=500 )
for(i in 1:500 ){
x - rnorm(13)
mat[ , i] - summary(x)
}
2) If the length of the output varies at each iteration, then it is
On 8/8/05 9:45 AM, Jacob Michaelson [EMAIL PROTECTED] wrote:
Hi all,
In heatmap's documentation, it mentions that the output value is
actually an invisible list...how would one access this list?
Mylist - heatmap()
__
R-help@stat.math.ethz.ch
Hi,
I'd like to perform Dufrene-Legendre Indicator Species Analysis for
a multivariate regression tree. However I have problems with arguments
of duleg(veg,class,numitr=1000)function. How to obtain a vector of
numeric class memberships for samples, or a classification object
returned from
I have a matrix r and a scalar d, and I would like to apply the
following functions to each of its elements:
1. if r 0, no change
2. if 0 = r d, replace element by zero
3. if d = r, replace element by r-d
I wrote a small function for this
m - function(b) {sapply(b, function(bb) {
if (bb
Peter == Peter Yang [EMAIL PROTECTED]
on Mon, 8 Aug 2005 09:11:47 -0400 writes:
Peter Hi, I would like to get the coefficient of polynomial
Peter expansion. For example,
Peter (1+ x)^2 = 1 + 2x + x^2, and the coefficients are 1,
Peter 2 and 1. (1 + x + x^2)^3 = 1 + 3*x +
On Mon, 8 Aug 2005, Tamas K Papp wrote:
I have a matrix r and a scalar d, and I would like to apply the
following functions to each of its elements:
1. if r 0, no change
2. if 0 = r d, replace element by zero
3. if d = r, replace element by r-d
I wrote a small function for this
m -
Jake == Jake Michaelson [EMAIL PROTECTED]
on Fri, 05 Aug 2005 14:39:49 -0600 writes:
Jake Thanks for the help -- this morning someone (on the
Jake Ubuntu boards) was kind enough to point this out to
Jake me. Now if there were only a decent Linux front
Jake end/gui for R...
Spencer,
Thank you for referring me to your other email on Exact goodness-of-fit
test. However, I'm not entirely sure if what you mentioned is the same
for my case. I'm not a statistician and it would help me if you could
explain what you meant in a little more detail. Perhaps I need to
On Mon, Aug 08, 2005 at 04:07:10PM +0100, Prof Brian Ripley wrote:
On Mon, 8 Aug 2005, Tamas K Papp wrote:
m - function(b) {sapply(b, function(bb) {
if (bb 0) {bb} else {if (bbd) {bb-d} else 0}
})}
Why use sapply?
r[] - ifelse(r = d, r-d, ifelse(r = 0, 0, r))
is one more
Hi!
OK, I'm trying to select some useful outliers from
my dataset: I defined 11 treshold values (1 for each
level of a variable (sampling site) as follows:
tresholds-function(x)
{
tapply(x,mm$NAME,FUN=mean ,simplify = T, na.rm=T)-med
tapply(x,mm$NAME,FUN=sd ,simplify = T,
na.rm=T)-standev
I use Mac OS X at home and Linux at work, so the R Aqua GUI has spoiled
me. I have not seen its equal so far (on Windows or Linux). The most
important thing to me is how easily accessible the help and
documentation is. I like how when I begin typing a function, the form
and arguments to the
Hello,
I plot with filled.contour and have this problem.
There is an area that I want to cover with angled
shading lines to represent NA in my data.
Very much appreciate help.
Thanks,
Mark
pal - palette(gray(seq(1.,0.,len=8)))
filled.contour(fvec,qvec,etsarray,
hello,
I work since a few time on R and i wanted to know how to obtain the Wald chi
square value when you make a binary logistic regression. In fact, i have the z
value and the signification but is there a script to see what is the value of
Wald chi square. You can see my model below,
Best
Hello,
The set of messages below reports a successful build of 2.0.0 on AIX 5.2
using GCC 3.3.2
I've been trying for a while now to build 2.1.0 and 2.1.1 and have been
unsuccessful. I've tried:
- GCC 3.3.2 and 4.0.1
- default AIX make and GNU make
- 32-bit and 64-bit builds
A typical configure
Hi,
I have a dataset which has around 138 variables and 30,000 cases. I am
trying to calculate a mahalanobis distance matrix for them and my
procedure is like this:
Suppose my data is stored in mymatrix
S-cov(mymatrix) # this is fine
D-sapply(1:nrow(mymatrix), function(i) mahalanobis(mymatrix,
I have a data frame with three columns, type (a factor with two
values: Monolithic and Compositional), size (numeric), and states
(numeric). I want to create a plot where size goes on the x-axis and
states goes on the y-axis. In this plot, I want two lines, one where
the type is Monolithic and
[EMAIL PROTECTED] a écrit :
hello,
I work since a few time on R and i wanted to know how to obtain the Wald chi
square value when you make a binary logistic regression. In fact, i have the z
value and the signification but is there a script to see what is the value of
Wald chi square. You
Once I had a situation where the reason was that the variables were
scaled to extremely different magnitudes. 1e-25 is a *very* small number
but still there is some probability that it may help to look up standard
deviations and to multiply the
variable with the smallest st.dev. with 1e20 or
th,ks for your help,
i don't have this package on my R, do you know an other package that have this
test...thanks
Selon Renaud Lancelot [EMAIL PROTECTED]:
[EMAIL PROTECTED] a écrit :
hello,
I work since a few time on R and i wanted to know how to obtain the Wald
chi
square value
Dear R Users ,
Suppose that we want to regress a certain autoregressive model using SVM. We
have our data and also some fixed kernels in libSVM behinde e1071 in front. The
question: Where can we insert our certain autoregressive model ? During
creating data frame ? Or perhaps we can make
trellis.device()
xyplot(states ~ size, groups=type, data=tmp,
panel = panel.superpose,
panel.groups =panel.linejoin, auto.key=TRUE)
Jamieson Cobleigh wrote:
I have a data frame with three columns, type (a factor with two
values: Monolithic and Compositional),
I think the problem might be caused two variables are very correlated.
Should I check the cov matrix and try to delete some?
But i am just not quite sure of your reply. Could you detail it with some steps?
thanks,
weiwei
On 8/8/05, Christian Hennig [EMAIL PROTECTED] wrote:
Once I had a
More ideas:
You can also perform an Eigenvalue decomposition of the covariance
matrix and see along which
directions the singularity occurs and how strong it is.
Consequences could be: rescaling (or omission) of variables that are
strong in these
directions, taking principal components, or linear
Sorry, our emails crossed...
On Mon, 8 Aug 2005, Weiwei Shi wrote:
I think the problem might be caused two variables are very correlated.
Should I check the cov matrix and try to delete some?
In this case, taking principal components should do the job.
Variable deletion may help as well - I
I have a huge matrix on which I need to do a simple (elementwise)
transformation. Two of these matrices cannot fit in the memory, so I cannot
do this in R.
I thought of writing some C code to do this and calling it using .C with
DUP=FALSE. All I need is a simple for loop that replaces elements
Hi,
having a matrix where rows=n and cols=m, I calculated the spearman
correlation values of the matrix, this generated a square matrix m x m.
Dose anyone knows how can I create a plot similar to this
http://bio.ifom-firc.it/User/finoc/ask.png ( produced with hierarchical
cluster explorer)
On Mon, 8 Aug 2005, Jake Michaelson wrote:
I use Mac OS X at home and Linux at work, so the R Aqua GUI has spoiled
me. I have not seen its equal so far (on Windows or Linux). The most
important thing to me is how easily accessible the help and
documentation is. I like how when I begin
Is this a research question? If not, I'd like to know why you think
the Wald test is better.
Are you famililiar with Bates and Watts (1988) Nonlinear Regression
Analysis and Its Applications (Wiley), and with the concepts of
intrinsic and parameter effects nonlinearity?
General Notes :
a) Please try to give a simple example
b) Please avoid the rightwards assignment (i.e. -). Eventhough it is
perfectly legal to use it, it is confusing especially when you are
posting to a mailing list.
1) Here is a reproducible example
set.seed(1) # for
Hi all,
Apologies if this has been raised before ... R's tapply is very fast, but if
X has names in this example, there seems to be a huge slow down: under 1
second compared to 151 seconds. The following timings are repeatable and
are timed properly on a single user machine :
X = 1:10
Dear all,
Anybody knows about the difference amongst various spline smoothers,
specifically in R, 'bs' (by default a cubic spline), 'ns', smooth.spline with
roughness penalty along with many other smoothers? I've consulted serveral
books like 'S-plus Guide to Statistics' by Mathsoft, Ripley
Hi to all,
I am new in R , and I would like to ask how to plot the survival function, and
the associated baseline hazard in the case of parametric survival estimation
models(SURVIVAL PACKAGE). plot.survfit works only with cox models.
A lot of thanks
D.Lalountas
Dear R-listers:
I am trying to work with a big (262 Mb) file but apparently reach a
memory limit using R on a MacOSX as well as on a unix machine.
This is the script:
type=list(a=0,b=0,c=0)
tmp - scan(file=coastal_gebco_sandS_blend.txt, what=type,
sep=\t, quote=\, dec=., skip=1,
The URL that you sent is not working. Can you please check ?
If you mean 2 dimensional hierarchical clustering as often used in
microarrays, then see help(heatmap). There was a discussion last week
about using red-green for heatmap. See
http://tolstoy.newcastle.edu.au/R/help/05/08/9714.html
Or
suppose I have the following data
x-c(rep(.1,5),rep(.2,6),rep(.4,10),rep(.5,20))
y-c(rep(.5,3),rep(.6,8),rep(1.2,8),rep(2.5,18),rep(3,4))
If I plot(x,y) in R, I will only get seven distinct
points. What I want to do is to use different symbols
to show the frequency at each point.
e.g. if the
From Note section of help(read.delim) :
'read.table' is not the right tool for reading large matrices,
especially those with many columns: it is designed to read _data
frames_ which may have columns of very different classes. Use
'scan' instead.
So I am not sure why you used
You might consider one of these approaches instead:
plot(jitter(x), jitter(y))
or
pdf(file=c:/AlphaExample.pdf, version = 1.4)
plot(x, y, col = rgb(1, 0, 0, .2), pch = 16)
dev.off()
Kerry Bush wrote:
suppose I have the following data
x-c(rep(.1,5),rep(.2,6),rep(.4,10),rep(.5,20))
Tamas K Papp [EMAIL PROTECTED] writes:
I have a huge matrix on which I need to do a simple (elementwise)
transformation. Two of these matrices cannot fit in the memory, so I cannot
do this in R.
I thought of writing some C code to do this and calling it using .C with
DUP=FALSE. All I
... and it is likely that even if you did have enough memory (several times
the size of the data are generally needed) it would take a very long time.
If you do have enough memory and the data are all of one type -- numeric
here -- you're better off treating it as a matrix rather than converting
On Mon, 8 Aug 2005, Peter Dalgaard wrote:
Tamas K Papp [EMAIL PROTECTED] writes:
I have a huge matrix on which I need to do a simple (elementwise)
transformation. Two of these matrices cannot fit in the memory, so I cannot
do this in R.
I thought of writing some C code to do this and
Group by which variable ? If you mean the joint distribution of 'x' and
'y' then something along the following lines
x - rep( c(0.1, 0.2, 0.4, 0.5), c(5, 6, 10, 20) )
y - rep( c(0.5, 0.6, 1.2, 2.5, 3.0), c(3, 8, 8, 18, 4) )
new - factor( paste(x, y, sep=_) )
tb - table(new)
Thank you.
But I only need three classes of freqnencies (in
another words, only three kinds of symbols) for 1-5,
5-10 and above 10, not to use different symbols for
different frequencies. Otherwise, clearly R will run
out of available symbols and the plot is also hard to
view.
Thank you anyway.
On Mon, 2005-08-08 at 11:57 -0700, Kerry Bush wrote:
suppose I have the following data
x-c(rep(.1,5),rep(.2,6),rep(.4,10),rep(.5,20))
y-c(rep(.5,3),rep(.6,8),rep(1.2,8),rep(2.5,18),rep(3,4))
If I plot(x,y) in R, I will only get seven distinct
points. What I want to do is to use different
Please use a current version of R!
This was fixed long ago, and you will find it in the NEWS file:
split() now handles vectors with names internally and so is
almost as fast as on vectors without names (and maybe 100x
faster than before).
On Mon, 8 Aug 2005, Matthew
Hi,
I had a logit regression, but don't really know how to
handle the Warning message: non-integer #successes in
a binomial glm! in: eval(expr, envir, enclos)
problem. I had the same logit regression without
weights and it worked out without the warning, but I
figured it makes more sense to add
Quick question: how can I reverse the order of the rows in a matrix?
i.e. make the last row first and the first row last, etc.?
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PLEASE do read the posting guide!
Dear R users,
Does anybody know if there is an R function (package) to fit a two-terms
exponential model like y = a*exp(bx) + c*exp(dx) where y is dependent
variable and x is independent variable. MATLAB has a Curve Fitting Toolbox
to implement this fitting, but I don't know if there is an R
Hello All;
I need to run a multiple regression analysis and use Akaike's Information
Criterion for model selection. I understand that this command will give the
AIC value for specified models:
AIC(object, ..., k = 2)
with ... meaning any other optional models for which I would like AIC
sapply(nrow(matrix):1, function(x) matrix[x,])
On Mon, 8 Aug 2005, Jake wrote:
Quick question: how can I reverse the order of the rows in a matrix?
i.e. make the last row first and the first row last, etc.?
__
R-help@stat.math.ethz.ch mailing
Thanks to those who provided the one-liner answers! They worked
quite well.
I'm quite sure that 95% of the questions posted on this mailing list
could be answered with a quick...read the manual, stupid..., but
I'm very grateful to those who take the time to write one-liners. I
know
Remove the '6' from the code that contains 'cut'. I am not sure how it
crept into my code. Then you should have the following mapping
Freqpch code
1-5 1
6-102
11- 3
I am more concerned about viewers getting confused with many symbols
than running
How about simply
mat - mat[ nrow(mat):1, ]
Regards, Adai
On Mon, 2005-08-08 at 19:44 -0400, Jean Eid wrote:
sapply(nrow(matrix):1, function(x) matrix[x,])
On Mon, 8 Aug 2005, Jake wrote:
Quick question: how can I reverse the order of the rows in a matrix?
i.e. make the
Are you looking for possibly stepAIC from the package MASS ?
Regards, Adai
On Mon, 2005-08-08 at 16:39 -0600, Martin Kardos wrote:
Hello All;
I need to run a multiple regression analysis and use Akaike's Information
Criterion for model selection. I understand that this command will give
The last time I used it, the function step() was using
AIC as model selection criteria as the default. It is
in the base package so you don't have to refer to
other fancy functions.
--- Adaikalavan Ramasamy [EMAIL PROTECTED]
wrote:
Are you looking for possibly stepAIC from the
package MASS ?
On Mon, Aug 08, 2005 at 03:17:44PM -0400, Chuck Cleland wrote:
You might consider one of these approaches instead:
plot(jitter(x), jitter(y))
or
pdf(file=c:/AlphaExample.pdf, version = 1.4)
plot(x, y, col = rgb(1, 0, 0, .2), pch = 16)
dev.off()
sunflowerplot() is also useful for
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