d = as.POSIXlt(c(2005-07-01, 2005-07-02, 2005-07-03, 2005-07-04,
2005-07-05))
d$mon and d$year will get you part way there.
That is assuming your dates are formated -mm-dd. strptime() might
also be useful.
Richard van Wingerden wrote:
Hi,
Given a frame with calendar date's:
Cal == Cal Stats [EMAIL PROTECTED]
on Mon, 12 Dec 2005 10:25:38 -0800 (PST) writes:
Cal Hi.., is there a function in R to fit bivariate splines
Cal ? I came across 'polymars' (POLSPLINE) and 'mars'
Cal (mda) packages. Are these the one to use or are there
Cal other specific
D = as.POSIXlt(c(2005-07-01, 2005-07-02,
2005-07-03, 2005-07-04, 2005-07-05))
(Years = 1900+D$year)
[1] 2005 2005 2005 2005 2005
(Months = D$mon+1)
[1] 7 7 7 7 7
weekdays(D)
[1] Friday Saturday Sunday Monday Tuesday
# you better check this one carefully !!!
(Weeknumbers =
Dear list:
A datafile was sent to me that is very large (92890 x 1620) and is *very*
sparse. Instead of leaving the entries with missing data blank, each cell with
missing data contains a dot (.)
The data are binary in almost all columns, with only a few columns containing
whole numbers,
Hi, I am plotting a distribution of (ordered) values as a barplot. I
would like to label groups of bars together to highlight aspects of the
distribution. The label for the group should be the range of values in
those bars.
As this is hard to describe, here is an example;
x - rlnorm(50)*2
Is this what you want...
op-par(xpd=TRUE)
segments(0,-1,20,-1,col=2)
text(10,-1,Interval,pos=1)
Cheers,
Hans Gardfjell
Dept. of Ecology and Environmental science
Umeå University, Sweden
Dan Bolser wrote:
Hi, I am plotting a distribution of (ordered) values as a barplot. I
would like to
Hello everyone
I have estimated the partial correlations of a matrix (n=160, vars=7) with
command pcor.shrink (library corpcor) and then i want to estimate their
respective confidence intervals. So i have tried to use the command
pcor.confint(pcor,kappa,alpha) from library GeneNT. My problem
Hello,
I have a problem that I am trying to solve and I am not sure how to
do it in R.
Suppose, that 16 numbers are choosen at random from 0 to 9, what's
the probability that their average will be between 4 and 6. I typed
the following code:
set.seed(100)
sample(0:9, 16, replace =TRUE)
Please disregard this message and don't post it to the web. I found
the answer.
Thanks
Davia S. Cox
517-575-8031 cell
[EMAIL PROTECTED]
Human potential, though not always apparent, is there waiting to be
discovered and invited forth. -William W. Purkey
On Dec 13, 2005, at 6:20 AM, Davia
Hi all,
I am using a 'tricked' Cox Hazard regression model for discrete choice
habitat modelling.
However, I'm having a hard time understanding the meaning of the first
line the following part of the summary() output:
Rsquare= 0.307 (max possible= 0.475 )
Likelihood ratio test= 91.8 on 12 df,
Tobias, thanks to you and others, who made the same suggestion. This is
exactly what I was looking for, Sys.sleep(0.1) does the job much more quietly
than my previous solution ...
Regards, Ulrike
-- Original Message ---
From: Tobias Verbeke [EMAIL PROTECTED]
To: Ulrike
2005/12/12, Michael Dewey [EMAIL PROTECTED]:
There are occasional comments on this list about how difficult it is to
read the digest format.
[snip]
Any other comments welcome of course.
I use google mail with a R-Label. In this way, all my R-Mails are
available in the R-Label-view and are
dear R users,
I need some help for multivariate analysis.
I have 2 anaesthetic treatment groups (20 patients/group) where I
register heart frequency and pressure for 60 min (repeated measures
every 5 minutes). I would like to perform a test to check if treatments
are different in controlling
I'm trying to write a function that takes a vector of length n and then
takes the first value of the vector i.e j=1 and forms a new vector of
length n (i.e replicate the first value n times). This function will
then calculate the absoulte difference of the original vector and the
new vector
On 12/13/05 6:20 AM, Davia Cox [EMAIL PROTECTED] wrote:
Hello,
I have a problem that I am trying to solve and I am not sure how to
do it in R.
Suppose, that 16 numbers are choosen at random from 0 to 9, what's
the probability that their average will be between 4 and 6. I typed
the
Davia Cox wrote:
Hello,
I have a problem that I am trying to solve and I am not sure how to
do it in R.
Suppose, that 16 numbers are choosen at random from 0 to 9, what's
the probability that their average will be between 4 and 6. I typed
the following code:
set.seed(100)
Please, I´d like to store this sample matrix as a new object. How can I
do this ?
pulse - c(67, 67, 68, 68, 68, 69, 69, 69, 69, 69, 70, 70, 70, 70, 71,
71, 72, 72, 73, 74)
m - NULL
x - 0
for (i in 1:5)
{
x - sample(pulse,3)
m - mean(x)
cat(x,m,\n)
}
Thanks,
Mauricio
Hi,
First, thank you. It 'almost' works: I can convert a matrix to a
'zoo' object, but it can not convert it to a 'ts'.
The sitruation is this: I load a set of samples with
h_types - list (0, 0, character(0), character(0), 0, 0, 0, 0, 0)
h_names - list (time, flow, type, dir,
Is there any function available in R for computing the incomplete Beta
function?
I'll appreciate any suggestion
--
Albert Sorribas
Grup de Bioestadística i Biomatematica
Departament de Ciències Mèdiques Bàsiques
Universitat de Lledia
tel: +34 973 702 406
FAX: +34 973 702 426
Home page:
Your variable mat is not a matrix; its a data frame. Check it with:
class(mat)
Here is an example:
x - cbind(A = 1:4, B = 5:8)
tt - c(1, 3:4, 6)
library(zoo)
x.zoo - zoo(x, tt)
x.ts - as.ts(x.zoo)
On 12/13/05, Alvaro Saurin [EMAIL PROTECTED] wrote:
Hi,
First, thank you. It 'almost'
Dear R-Users,
I'm searching for somebody who can support me or even likes to
collaborate with
me in setting up an R-package for constrained maximim log-likelihood
parameter
estimation.
For example fitting the parameters of a MA(1)-APARCH(1,1) model for a
time series
of 17'000 points (e.g.
Hi all,
I'm trying to superimpose a rchisq density line over a histogram with
something like:
hist(alnlength)
lines(density(rchisq(length(alnlength), 4)),col=red)
But the rchisq line won't appear anywhere,
Anyone knows what I am missing here?
Thanks in advance,
Albert.
Does anyone have an idea of how to make a chart in R like the
ones here that use a graphic:
http://bigpicture.typepad.com/comments/images/slide1.gif
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
Please, I´d like to store this sample matrix as a new object. How can I
do this ?
pulse - c(67, 67, 68, 68, 68, 69, 69, 69, 69, 69, 70, 70, 70, 70, 71,
71, 72, 72, 73, 74)
m - NULL
x - 0
for (i in 1:5)
{
x - sample(pulse,3)
m - mean(x)
cat(x,m,\n)
}
Thanks,
Mauricio
I should have also noted in this email how I have allocated memory and
an error that appears.
I'm using Windows, so as in FAQ 2.2 I did
C:\Program Files\R\R-2.2.0\bin\Rgui.exe --sdi --max-mem-size=2Gb
# Check memory size in R
example(memory.size)
mmry.s memory.size()
[1] 11894064
mmry.s
dear R users,
I need some help for multivariate analysis.
I have 2 anaesthetic treatment groups (20 patients/group) where I
register heart frequency and pressure for 60 min (repeated measures
every 5 minutes). I would like to perform a test to check if treatments
are different in controlling
From: Martin Maechler
Cal == Cal Stats [EMAIL PROTECTED]
on Mon, 12 Dec 2005 10:25:38 -0800 (PST) writes:
Cal Hi.., is there a function in R to fit bivariate splines
Cal ? I came across 'polymars' (POLSPLINE) and 'mars'
Cal (mda) packages. Are these the one to use or
One thing to check: Are the data in the same range as chisq with 4 df?
Andy
From: Albert Vilella
Hi all,
I'm trying to superimpose a rchisq density line over a histogram with
something like:
hist(alnlength)
lines(density(rchisq(length(alnlength), 4)),col=red)
But the rchisq line
On 13-Dec-05 Uwe Ligges wrote:
Davia Cox wrote:
[...]
My question is in order to run a true random sample,
We have to disappoint you: Your computer cannot generate
true random samples.
At least on Linux (and probably most Unix) systems,
/dev/random must be a pretty good approximation
Hello
In an article in J. Computational and Graphical Statistics, v 13, p.
36-47, Ben and Yohai propose quantile quantile plots for deviance
residuals of generalized linear models, Normal quantile plots of these
residuals are unsatisfactory, but B and Y propose a QQ plot of the
deviance
try
hist(alnlength, prob = TRUE)
moreover I think that you do not need to sample from the Chi-squared
to draw its density; you could use
dchisq(seq(...), 4))
instead.
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Le 13.12.2005 14:23, Albert Vilella a écrit :
Hi all,
I'm trying to superimpose a rchisq density line over a histogram with
something like:
hist(alnlength)
lines(density(rchisq(length(alnlength), 4)),col=red)
But the rchisq line won't appear anywhere,
Anyone knows what I am missing here?
That can be done very easy using a program that can deal with layers,
for example the Gimp.
Just make one layer containing the barplot and one layer containing the
background image. Then you can do all kind of nice things.
Directly in R, I don't have a clue, but it wouldn't surprise me
if
On Tue, 13 Dec 2005, Albert Sorribas wrote:
Is there any function available in R for computing the incomplete Beta
function?
pbeta(). The incomplete Beta function is the cdf of the Beta
distribution
-thomas
I'll appreciate any suggestion
--
Albert Sorribas
Grup de
On Tue, 13 Dec 2005, May, Roel wrote:
Hi all,
I am using a 'tricked' Cox Hazard regression model for discrete choice
habitat modelling.
However, I'm having a hard time understanding the meaning of the first
line the following part of the summary() output:
Rsquare= 0.307 (max possible=
hello,
has anyone come across the following rather mysterious problem:
when pasting large bits of code (100 and more lines) into the R console with
the central mouse button (under linux), only part of the code is pasted, and
the text interrupts somewhere arbitrarily. It does not happen when
You mean writing to a file?
Maybe you should read the R Data Import/Export Manual
http://cran.r-project.org/doc/manuals/R-data.html
or as pdf
http://cran.r-project.org/doc/manuals/R-data.pdf
You might also want to read the manual pages of these
two commands:
help('dump')
help('write.table')
On 13-Dec-05 Albert Vilella wrote:
Hi all,
I'm trying to superimpose a rchisq density line over a histogram with
something like:
hist(alnlength)
lines(density(rchisq(length(alnlength), 4)),col=red)
But the rchisq line won't appear anywhere,
Anyone knows what I am missing here?
On Tue, 13 Dec 2005 [EMAIL PROTECTED] wrote:
On 13-Dec-05 Uwe Ligges wrote:
Davia Cox wrote:
[...]
My question is in order to run a true random sample,
We have to disappoint you: Your computer cannot generate
true random samples.
At least on Linux (and probably most Unix) systems,
On 13-Dec-05 Albert Vilella wrote:
Hi all,
I'm trying to superimpose a rchisq density line over a histogram with
something like:
hist(alnlength)
lines(density(rchisq(length(alnlength), 4)),col=red)
But the rchisq line won't appear anywhere,
Anyone knows what I am missing here?
Hi,
I'm looking for a way to bind specific model parameters to a constant
(in my case: 0) before fitting the model. I'm fitting multinomial
logistic regression models (via glm()).
Assuming a model with a categorial response variable c {c1,c2,c3}
that is a matrix like
c2:b2 b2.1 b2.2
This certainly did the trick,
Thanks Ted, Sean, Romain, Dimitris, Lian and Andy,
alnlength-rchisq(1000,4)
x-0.25*(0:100)
hist(alnlength,breaks=0.25*(0:100))
lines(x,1000*dchisq(x,4)*0.25)
And apologies for my newbieness in the posting,
Albert.
I am curious whether anybody has or is developing this capability within
R. I have not found any software yet that has this capability and I am
not sure whether it is too new a method and nobody is actually using it,
or if there are other means to get the same analysis that I do not know
of. Any
Hi Mauricio,
Although you question is not clear, I'm supposing that you want to save
as a new object (matrix) whatever is printed out from cat(x,m,\n).
If this is the case, then your result is a matrix with 5 rows and 4
columns. For each row, the first 3 values are x and the last value is m.
I've enconuntered this problem with the last cran version of geoR:
library(geoR)
day - rep(1:2, each=5)
coords - matrix(rep(runif(10),2), 10, 2)
data - rnorm(10)
data[1] - NA
as.geodata(cbind(coords, data, day), realisations=4)
as.geodata: 1 points removed due to NA in the data
Errore in
On 13-Dec-05 Thomas Lumley wrote:
On Tue, 13 Dec 2005, Albert Sorribas wrote:
Is there any function available in R for computing the incomplete Beta
function?
pbeta(). The incomplete Beta function is the cdf of the Beta
distribution
But don't forget to multiply by beta(,):
On 13 Dec 2005, at 13:08, Gabor Grothendieck wrote:
Your variable mat is not a matrix; its a data frame. Check it with:
class(mat)
Here is an example:
x - cbind(A = 1:4, B = 5:8)
tt - c(1, 3:4, 6)
library(zoo)
x.zoo - zoo(x, tt)
x.ts - as.ts(x.zoo)
Fixed, but anyway it fails:
On 12/12/05, Leo Gürtler [EMAIL PROTECTED] wrote:
Dear list members,
the following hlm was constructed:
hlm - groupedData(laut ~ design | grpzugeh, data = imp.not.I)
the grouped data object is located at and can be downloaded:
www.anicca-vijja.de/lg/hlm_example.Rdata
The following
Please provide a reproducible example. Note that dput(x) will output
an R object in a way that can be copied and pasted into another session.
On 12/13/05, Alvaro Saurin [EMAIL PROTECTED] wrote:
On 13 Dec 2005, at 13:08, Gabor Grothendieck wrote:
Your variable mat is not a matrix; its a data
I'm trying to use garchFit from fSeries, with Student or Skewed Student
conditionnal distribution. Let's say that eps (vector) is my series of daily
log-returns:
data(EuStockMarkets)
eps = diff(log(EuStockMarkets[,CAC]))
library(fSeries)
g = garchFit(series = eps, formula.var = ~garch(2,2),
On 13-Dec-05 Prof Brian Ripley wrote:
On Tue, 13 Dec 2005 [EMAIL PROTECTED] wrote:
On 13-Dec-05 Uwe Ligges wrote:
Davia Cox wrote:
[...]
My question is in order to run a true random sample,
We have to disappoint you: Your computer cannot generate
true random samples.
At least on Linux
On Tue, 13 Dec 2005, Oarabile Molaodi wrote:
I'm trying to write a function that takes a vector of length n and then
takes the first value of the vector i.e j=1 and forms a new vector of
length n (i.e replicate the first value n times). This function will
then calculate the absoulte
Le 13.12.2005 14:32, Gabor Grothendieck a écrit :
Does anyone have an idea of how to make a chart in R like the
ones here that use a graphic:
http://bigpicture.typepad.com/comments/images/slide1.gif
Hi Gabor,
Here's a first draft.
The following code will produce a pdf (i only found
I think I have found the error. It appears when there are two entries
with the same time. Using as input file:
- CUT
# Output format for PCKs:
# TIME FLOW P [+-] SEQ TS X RTT SIZE
#
123.125683 0 P + 967 123.125683 13394 0.798205 1472
123.241137 0 P + 968 123.241137 12680
Thomas Lumley [EMAIL PROTECTED] writes:
On Tue, 13 Dec 2005, Albert Sorribas wrote:
Is there any function available in R for computing the incomplete Beta
function?
pbeta(). The incomplete Beta function is the cdf of the Beta
distribution
..except for the normalizing constant, I
I am using R in a Microsoft Windows environment.
I have a dataset called mp1b. I have a variable called h.
h can take a value from -1 to 5.
If h 1, I want to create a new dataset called mp2 that is the same as mp1b:
mp2-mp1b
If h 0, I want to set create a
Sebastian Leuzinger wrote:
hello,
has anyone come across the following rather mysterious problem:
when pasting large bits of code (100 and more lines) into the R console with
the central mouse button (under linux), only part of the code is pasted, and
the text interrupts somewhere
On Tue, 13 Dec 2005 [EMAIL PROTECTED] wrote:
On 13-Dec-05 Thomas Lumley wrote:
On Tue, 13 Dec 2005, Albert Sorribas wrote:
Is there any function available in R for computing the incomplete Beta
function?
pbeta(). The incomplete Beta function is the cdf of the Beta
distribution
But
Does this do what you want:
IED - function(risk){
tmp - outer(risk,risk,-)
tmp - abs(tmp)
return(tmp[lower.tri(tmp)])
}
--
Gregory L. Snow Ph.D.
Statistical Data Center, IHC
[EMAIL PROTECTED]
(801) 408-8111
-Original Message-
From: [EMAIL PROTECTED]
On Tue, 2005-12-13 at 15:50 +0100, Sebastian Leuzinger wrote:
hello,
has anyone come across the following rather mysterious problem:
when pasting large bits of code (100 and more lines) into the R console with
the central mouse button (under linux), only part of the code is pasted, and
Hi,
ok, I know I should be using a later version than 1.7.1 (64 bit) but
it's not in my power.
So here is the problem:
In my R script I declare a data.frame that consists of 40 vectors, each
having 125 numeric elements. This is no problem as long as I run the
sript in interactive mode, but
On Tue, 2005-12-13 at 10:53 +, Dan Bolser wrote:
Hi, I am plotting a distribution of (ordered) values as a barplot. I
would like to label groups of bars together to highlight aspects of the
distribution. The label for the group should be the range of values in
those bars.
As this is
Yes, this is the definition of a time series and therefore of a zoo object.
A time series is a mathematical function, i.e. it assigns a single element
of the range to each element of the domain. This data does not describe
a time series.
Also it has no underlying regularity as the warning message
Hi,
I am trying to fit a Weibull PH model with a gaussian frailty term
(kidney data). Is the following approach correct?
1. Fit the model using survReg with the frailty term added in.
Kidn1-survreg(formula = Surv(rtime, event)~
age+sex+gn+an+pkn+frailty.gaussian(patient), data=kidney,
Hi,
I'm trying to draw a 2D plot using multiple tints of red. The
(simplified) setup is the following: || year | x | y ||
My idea is that each year is plotted with a different tint of red.
Older year (lightest) - Later year (darkest). I've managed to plot
this with different scales of grays
On 13-Dec-05 Prof Brian Ripley wrote:
On Tue, 13 Dec 2005 [EMAIL PROTECTED] wrote:
On 13-Dec-05 Thomas Lumley wrote:
On Tue, 13 Dec 2005, Albert Sorribas wrote:
Is there any function available in R for computing the incomplete
Beta
function?
pbeta(). The incomplete Beta function is
Hi,
I'm pretty new to R and I've been having some problems filtering data
in matrices.
I have the following initial dataset:
|| year | name | varA ||
I have multiple values for varA for the same year and the same name.
Having this as the input I would like to obtain the following:
|| year |
I realized that I may not have answered the question you were asking and that
no one else has responded. I can across a similar problem and may have an
answer to your question now. If you have both the wavelet coefficients and the
scaling coefficients then create a fake sequence of the same
?ifelse ; it's clear that you can use it in your case.
Where cluster_q is comming from ( I suppose is the column name you want
to filter by!)?
What if you use the simpler syntax :
if(h1)
mp2-mp1
else
mp2-subset(mp1b,cluster_q==h)
?
THT
t c wrote:
I am using R in a Microsoft Windows
Hello,
I am not sure if I am interfacing with C correctly and _safely_
or if there is a better way esp. with regards to terminating
the returned array.
I am trying to fill an int array with values whose actual size
is determined in the C function and is always maximally as large
as
In thinking about this some more, the trick I discussed is
probably not the best way to do it since its possible that
in the future zoo will completely disallow illegal zoo objects.
I think a better way might be to construct it like this:
aggregate(zoo(z.data), round(z.time, 1), tail, 1)
where
I use lmer to fit a mixed effect model.It give some warnings.what does this
warnings mean? and what should I do?
(fm2.mlm - lmer(qd ~ edu + jiankang + peixun +hunyin + cadcj + age + age2 +
sex + dangyuan + Comp.1 + Comp.2+trust.cz1 +(trust.cz1|commid), data =
individual,na.action =
Le 13.12.2005 19:34, Sérgio Nunes a écrit :
Hi,
I'm trying to draw a 2D plot using multiple tints of red. The
(simplified) setup is the following: || year | x | y ||
My idea is that each year is plotted with a different tint of red.
Older year (lightest) - Later year (darkest). I've managed to
I'm trying to draw a 2D plot using multiple tints of red. The
(simplified) setup is the following: || year | x | y ||
You might find this function useful:
map_colour_gradient - function(x, low=red,
mid=white,high=black, midpoint = 0) {
x - as.numeric(x)
low.rgb - col2rgb(low,
It would be nice to have a date stamp on an object.
In S/Splus this was always available, because objects were files.
I have looked around, but I presume this information is not available.
Trevor Hastie
Le 13.12.2005 21:40, Romain Francois a écrit :
Le 13.12.2005 19:34, Sérgio Nunes a écrit :
Hi,
I'm trying to draw a 2D plot using multiple tints of red. The
(simplified) setup is the following: || year | x | y ||
My idea is that each year is plotted with a different tint of red.
Older
t c wrote:
I am using R in a Microsoft Windows environment.
I have a dataset called “mp1b”. I have a variable called h.
h can take a value from -1 to 5.
If h 1, I want to create a new dataset called mp2 that is the same as mp1b:
“mp2-mp1b”
If h 0, I want
Jörg Schaber wrote:
Hi,
ok, I know I should be using a later version than 1.7.1 (64 bit) but
it's not in my power.
So here is the problem:
In my R script I declare a data.frame that consists of 40 vectors, each
having 125 numeric elements. This is no problem as long as I run the
Sérgio Nunes snunes at gmail.com writes:
Hi,
I'm trying to draw a 2D plot using multiple tints of red. The
(simplified) setup is the following: || year | x | y ||
My idea is that each year is plotted with a different tint of red.
Older year (lightest) - Later year (darkest).
how
On Tue, 13 Dec 2005, Ido M. Tamir wrote:
Hello,
I am not sure if I am interfacing with C correctly and _safely_
or if there is a better way esp. with regards to terminating
the returned array.
You need to pass the length to the C routine and check you do not
overwrite it. (As in the parts
On Dec 12, 2005, at 6:50 PM, David James wrote:
Prof Brian Ripley wrote:
On Mon, 12 Dec 2005, Sean Davis wrote:
On 12/12/05 9:21 AM, bogdan romocea [EMAIL PROTECTED] wrote:
Sean Davis wrote:
but you will have to create the table by hand
There's no need for manual steps. To take
Braesch Lucas wrote:
I'm trying to use garchFit from fSeries, with Student or Skewed Student
conditionnal distribution. Let's say that eps (vector) is my series of daily
log-returns:
data(EuStockMarkets)
eps = diff(log(EuStockMarkets[,CAC]))
library(fSeries)
g = garchFit(series = eps,
aggregate(x$varA, by=list(x$year, x$name), mean)
On 12/13/05, Sérgio Nunes [EMAIL PROTECTED] wrote:
Hi,
I'm pretty new to R and I've been having some problems filtering data
in matrices.
I have the following initial dataset:
|| year | name | varA ||
I have multiple values for varA for
Hey,
Can anyone answer this question. I am working with really large datasets and
most of the programs I have been running take quite some time.
I heard that R may be faster in Unix. I sthis true and if so can anyone
reccomend which system and requirements may allow things to go
Melanie Edwards wrote:
I am curious whether anybody has or is developing this capability within
R. I have not found any software yet that has this capability and I am
not sure whether it is too new a method and nobody is actually using it,
googling around I found that this (PVA) is a variant
Gabor Grothendieck wrote:
Yes, this is the definition of a time series and therefore of a zoo object.
A time series is a mathematical function, i.e. it assigns a single element
of the range to each element of the domain. This data does not describe
a time series.
Since nobody else has
Please read the posting guide and repost. Your question is too vague to
respond to sensibly.
Speed in R depends on two things: How you program and what sort of system
resources R has available (especially memory). OS's can certainly make a
difference, but this is a 2nd order effect, I think.
--
Hi again,
the previous answers were great. I was able to do what was planned.
Now, I would like to do the following to a matrix:
|| year | event | team | total ||
where I can have multiple event per team, but each team only has
a year and a total. Thus, this table has multiple lines for the
Dear Fabio
PLease download the latest geoR from:
www.est.ufpr.br/geoR
and let me know in case the problem persists
P.J.
On Tue, 13 Dec 2005, Antonio, Fabio Di Narzo wrote:
Date: Tue, 13 Dec 2005 17:18:14 +0100
From: Antonio, Fabio Di Narzo [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc:
Dear all
First time posting in this list. This is my question: I have three
vectors (x, y, z) containing random numbers from three different
distributions (normal, random, exponential). I want to sort the vectors
so the pairwise correlation coefficient between them is 0.5. How can I
do this. I
Have you tried ?intervals and ?intervals.lme? The following is
an example under ?intervals.lme:
fm1 - lme(distance ~ age, Orthodont, random = ~ age | Subject)
intervals(fm1)
Also, have you checked Pinheiro and Bates (2000) Mixed-Effects Models in
S and S-Plus (Springer)?
unique(x[,-2])
Sérgio Nunes a écrit :
Hi again,
the previous answers were great. I was able to do what was planned.
Now, I would like to do the following to a matrix:
|| year | event | team | total ||
where I can have multiple event per team, but each team only has
a year and a total. Thus,
___
Hi,
I'm writing up the online help for a package I'm developing (in-house
only, sorry), and I've come across an odd glitch when trying to nest a
list inside the arguments section of the .Rd file. I was just
I've just tried to install the tseries package (which seems to include quite
a bit) and got the following results:
package 'dynlm' successfully unpacked and MD5 sums checked
package 'leaps' successfully unpacked and MD5 sums checked
package 'chron' successfully unpacked and MD5 sums checked
Hi,
help on 'mahalanobis' (in the stats package in Rv2.2.0) now says:
Description:
Returns the Mahalanobis distance of all rows in 'x' and the vector
mu='center' with respect to Sigma='cov'. This is (for vector 'x')
defined as
D^2 = (x - mu)' Sigma^{-1} (x -
Dear group,
I tried to run a Repeated Mesures Anova for Mixed effects model and I got
a warnning after entering the model specification saying: Reached total
allocation of 254Mb: see help(memory.size).
here is part of the log:
***
___
Ah, I think I've solved it. Apparently \describe needs to have a newline
before it, or things get funny. Thus
\arguments{
\item{item1}{ This is item 1. }
\item{itemlist}{ Here is a list.
On Tue, 13 Dec 2005, Jeff D. Hamann wrote:
I've just tried to install the tseries package (which seems to include quite
a bit) and got the following results:
package 'dynlm' successfully unpacked and MD5 sums checked
package 'leaps' successfully unpacked and MD5 sums checked
package 'chron'
On Tue, 13 Dec 2005, Sérgio Nunes wrote:
Hi,
I'm trying to draw a 2D plot using multiple tints of red. The
(simplified) setup is the following: || year | x | y ||
My idea is that each year is plotted with a different tint of red.
Older year (lightest) - Later year (darkest). I've managed
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