Hello all. I have heard over and over that CART and its various tree-like
brethren are non-parametric techniques. When I read the chapter in
Chambers and Hastie on tree-based models it states that tree-based models
can be generalized (GTMs) in a manner similar to GLMs by specifying a
different
I am making a plot and am merely trying to increase the line thickness, or
width, of the box drawn around the legend. The help page on 'legend' was of
no use. Does anyone have any ideas?
[[alternative HTML version deleted]]
__
I cannot resist a very brief entry into this old and seemingly
immortal issue, but I will be very brief, I promise!
Amasco Miralisus suggests:
As I understood form R FAQ, there is disagreement among Statisticians
which SS to use
Hi
check out R-and-octave.txt on the contributed docs section of CRAN.
HTH
Robin
On 28 Aug 2006, at 17:50, Lord Tyranus wrote:
Hello wizards, I need to convert the following functions (prestd,
poststd, prepca) of matlab to R. Does Somebody knows how to do it. A
description of the
The short answer is that a Poisson distribution is a discrete
distribution: if that is appropriate to your data the rpart function (in
the package of that name) has a suitable option.
On Mon, 28 Aug 2006, Solomon Dobrowski wrote:
Hello all. I have heard over and over that CART and its various
ecatchpole a écrit :
Romain Francois wrote on 08/28/2006 04:23 PM:
=
Search for your R routines directly from Firefox!
http://addictedtor.free.fr/rsitesearch
=
When I try to search
Yuval Sapir wrote:
Hi all,
I am relatively new to R, so let me know if I missed something trivial.
I want to perform path-analysis with at least three levels of explaining
variables (i.e., A affects B that affects C). I perform multiple
regression for each set of variables, and get
Hello!
I would like to do Empirical Orthogonal functions and
Canonical correlation analysis on satellite data. My
matrices are going to be very big (more than 10,000
locations). Are there limitations in R regarding the
size of the matrix?
thanks a lot
regards
Isidora
Dear list,
I want to analyse some HG133Plus2.0 Affymetrix chips.
The first thing I intent to do, is just to perform a background correction
(mas, rma, gcrma,...) with the cel files.
Then I want to take a look at the files.
How can I do this ?
Gunther
Dear all,
After I work around, I found in my list of data with only one row which
need to remove or make it as matrix.
Here I write again my other toy example:
x - list(matrix(1:20, 5, 4),matrix(1:20, 5, 4),matrix(1:20, 5,
4),matrix(1:20, 5, 4),matrix(1:20, 5, 4))
y - list(c(1, -1, -1, 1,
Amasco,
In general it is dangerous to attempt to interpret a main effect that
is included in an interaction, regardless of wether or not the
interaction is significant. If you want to make a valid inference about
a main effect it is safest to do so after dropping any interaction that
contains the
In thinking about this some more Romain's idea of using
the browser to get this information can be done like this.
This solution only works with Internet Explorer:
library(RDCOMClient)
ie - COMCreate(InternetExplorer.Application)
ie$Navigate(about:blank)
width -
try the following:
# a
dff[sapply(dff, is.matrix)]
# b
lapply(dff, function(x) if(!is.matrix(x)) rbind(x) else x)
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35,
More than 10,000 locations but how many variables?
Like all computer programs there are limitations, but they are largely
imposed by your environment, so what OS and how much RAM do you have?
On Tue, 29 Aug 2006, isidora k wrote:
Hello!
I would like to do Empirical Orthogonal functions and
Dear all,
Dimitris, thanks for your great help and quick response.
Best, Muhammad Subianto
dff[sapply(dff, is.matrix)]
[[1]]
[,1] [,2] [,3] [,4] [,5]
[1,]16 11 161
[2,]49 14 191
[3,]5 10 15 201
[[2]]
[,1] [,2] [,3] [,4] [,5]
[1,]
I have got windows and 1Gb ram. my matrices are
monthly data for 10 years for sometimes more than
10,000 locations. I am going to perform the EOF on one
variable at a time and then the CCA on the principal
components that I will get from EOF. Do you think I
could do that in R?I could also find a
Hello,
I get the following message when I try to load a time series of 128 stock
returns.
Error in modwt(stock, wf = la8, n.levels = 8, boundary = periodic) :
wavelet transform exceeds sample size in modwt
I thought that MODWT had no restrictions on the sample size?
Any help?
--
That's a 10,000 x 120 matrix, if I understand you right. That is quite
modest. The key issue is to be able to do an SVD:
A - matrix(rnorm(1e4*120), 1e4, 120)
dim(A)
[1] 1 120
system.time(svd(A))
[1] 2.79 0.13 2.93 NA NA
on a similar machine to yours, using 50Mb.
It would be
Gunther Höning [EMAIL PROTECTED] writes:
Dear list,
I want to analyse some HG133Plus2.0 Affymetrix chips.
The first thing I intent to do, is just to perform a background correction
(mas, rma, gcrma,...) with the cel files.
Then I want to take a look at the files.
How can I do this ?
You
Suppose I have the following list:
a - strsplit(c(John;Smith, Jane;Doe, koda, gunner), ;)
I want to get to these two vectors without looping...
firstNames:c(John, Jane, koda, gunner)
lastNames:c(Jane, Doe, NA, NA)
Thanks
cn
[[alternative HTML version deleted]]
sapply(a, [, 1)
[1] John Jane koda gunner
sapply(a, [, 2)
[1] Smith Doe NA NA
---
Jacques VESLOT
CNRS UMR 8090
I.B.L (2ème étage)
1 rue du Professeur Calmette
B.P. 245
59019 Lille Cedex
Tel : 33 (0)3.20.87.10.44
Fax
Kind folks,
I have a data frame of mean values for 14 levels and 5 factors. I'd like to
use a coplot to illustrate how the mean values change.
Can anyone provide an example of how I can specify different ploting symbols
in this plot. I'd like to use either use a five different colors (col) for
Hello,
I follow the Bioconductor instruction (http://www.bioconductor.org/download
http://www.bioconductor.org/download ) to install Biocoductor, there have
some errors:
/usr/lib/R/bin/SHLIB: line 115: make: command not found
chmod: cannot access `/usr/local/lib/R/site-library/affyio/libs/*':
Ge, Weigong* [EMAIL PROTECTED] writes:
Hello,
I follow the Bioconductor instruction (http://www.bioconductor.org/download
http://www.bioconductor.org/download ) to install Biocoductor, there have
some errors:
Please post questions about Bioconductor to the bioconductor mailing
list:
Hi,
You don't say, but the errors make me think you are using Linux.
(Please specify your OS when you have problems). It sounds like
you are missing some of the Essential programs under Unix -
they really are essential.
I think you need to reread the R admin manual, as instructed
on the
Is there a function in R that does spectral clustering?
Thanks ../Murli
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R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Nair, Murlidharan T a écrit :
Is there a function in R that does spectral clustering?
Thanks ../Murli
** PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html **
Hi,
You would get a faster answer asking to RSiteSearch rather than this list.
Romain
R 2.3.1
I wrote a little script to do some cross correlations. The symbols are
in a text file like so:
symbols.txt
ibm
dd
csco
require(tseries)
symbols - scan(symbols.txt, what = 'character')
for(line in 1:(length(symbols)-1)) {
assign(symbols[line], get.hist.quote(instrument =
Hello, R experts,
If I understand Ted's anwser correctly, then I can not contrast the
mean yields between sections 1-8 and 9-11 under Trt but I can
contrast mean yields for sections 1-3 and 6-11 because there exists
significant interaction between two factors (Trt:section4,
Trt:section5).
The rpanel package builds on the tcltk package to provide simple
interactive controls for R functions, in particular to provide simple
forms of dynamic graphics. The intention is to make this form of
control particularly easy for R users to implement, with full
documentation. The necessary
Put the data into a list, not into individual variables. Something
like this (untested):
L - sapply(symbols[-length(symbols)],
get.hist.quote, start = 2005-01-09, quote = Close, simplify = FALSE)
mat - do.call(cbind, L)
cor.mat - cor(mat, use = complete)
symnum(cor.mat)
On 8/29/06,
Somebody pointed me to the right spot in the documentation, and kindly and
humorously
'suggested' to me to do the following:
My Apologies, everybody!
I should have read docs a bit better, actually...
...will do better next time!
luca
- Original Message -
From: [EMAIL PROTECTED]
To:
Dear R users,
I would like to adjust the x axis the way I wanted using
forestplot(labeltext, mean, lower, upper, align = NULL, xlab = , zero =
0, graphwidth = unit(2, inches), col = meta.colors(), xlog = FALSE). I
tried using xaxt=n and then redefine the axis using axis(1, at=c(0,0.5,1.0
Hi,
I am making a dendrogram with 180 terminal values. Whether I keep it
horizontal or vertical, it gives a 'squished' graph that refuses to be
stretched beyond the window size and I cannot read the labels.
(I'm using hclust and then plot to make the tree.)
Is there a way to stretch the graph in
Hi Folks,
I want to use key() to position the legend on top of the page in the following
example. Prefer not to use locator() par(mfrow = c(2,2)) plot(1:4,
title=Plot Number1) plot(rnorm(10), title=Plot Number2) plot(1:10,
title=Plot Number3) key(x,y, text=list(c(Alpha,Beta)),
Hi,
I would like to create a plot of y1,y2,y3,y4 against x for several subjects
such that y1 and y2 are plotted against x in one panel and y3 and y4 against x
in another panel. Thus if there are 3 subjects I should end up with 6 panels.
Is there a simple way of doing so (i.e. without calling
I'm using this syntax to create data subsets for plots:
subset=source==Both. Now I would like to create a subset defined by
two different variables like this: subset=source==Both
subset=site==home but this syntax is not correct. The documents in the
manual for subset seem to be creating
Dear R-list,
I would like to use the lattice library to show several groups on
the same graph. Here's my example :
## the data
f1 - factor(c(mod1,mod2,mod3),levels=c(mod1,mod2,mod3))
f1 - rep(f1,3)
f2 - factor(rep(c(g1,g2,g3),each=3),levels=c(g1,g2,g3))
df -
Hello!
I have found terrific demo or R package functionality at
http://had.co.nz/reshape/french-fries-demo.html
Author has told me off-list that he is using SnapzProX (on mac), and
ghostwriter (http://had.co.nz/ghostwriter/) to automate the typing.
Unfortunatelly, I do not have mac ;) Can
Jonathan Gheyssens
M.Sc Economie Appliquée
IEA - HEC Montréal
[EMAIL PROTECTED]
514-581-8009
514-678-5231
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
I would like to use the lattice library to show several groups on
the same graph. Here's my example :
## the data
f1 - factor(c(mod1,mod2,mod3),levels=c(mod1,mod2,mod3))
f1 - rep(f1,3)
f2 - factor(rep(c(g1,g2,g3),each=3),levels=c(g1,g2,g3))
df - data.frame(val=c(4,3,2,5,4,3,6,5,4),
Dear R People:
I am trying to split a character vector into a set of individual
letters:
Ideal:
x3 - c(dog)
d o g
I tried the following:
strsplit(x3)
Error in strsplit(x3) : argument split is missing, with no default
strsplit(x3,1)
[[1]]
[1] dog
I know that this is incredibly simple, but
On Tue, 29 Aug 2006, Erin Hodgess wrote:
Dear R People:
I am trying to split a character vector into a set of individual
letters:
Ideal:
x3 - c(dog)
d o g
I tried the following:
strsplit(x3)
Error in strsplit(x3) : argument split is missing, with no default
strsplit(x3,1)
[[1]]
[1]
Use '' as parameter to strsplit
x3 - 'dog'
strsplit(x3, '')
[[1]]
[1] d o g
On 8/29/06, Erin Hodgess [EMAIL PROTECTED] wrote:
Dear R People:
I am trying to split a character vector into a set of individual
letters:
Ideal:
x3 - c(dog)
d o g
I tried the following:
strsplit(x3)
On 8/29/06, Søren Højsgaard [EMAIL PROTECTED] wrote:
Hi,
I would like to create a plot of y1,y2,y3,y4 against x for several subjects
such that y1 and y2 are plotted against x in one panel and y3 and y4 against
x in another panel. Thus if there are 3 subjects I should end up with 6
panels.
Dear R users:
I want to model mosquito count data based on landcover attributes and
meteorological variables using a Poisson GLSM in the geoRglm package. I
have monthly mosquito counts over more than 20 years with repeated
observations from individual trap sites over time. I have used
Respected Sir/Madam,
I have a problem with apply function. I have to two matrices of dimension of
one column but n rows. I have to check whether one matrix is greater than
other by going thru each row (ie) using if condition to check one matrix
with another matrix.
I like to use apply()
Try this:
xyplot(val ~ x, data = df, type = p,
col = as.numeric(df$f1), pch = as.numeric(df$f2))
key1 - list(border = TRUE, colums = 2, text = list(levels(df$f1)),
points = list(pch = 1:nlevels(df$f1))
)
key2 - list(border = TRUE, colums = 2, text = list(levels(df$f2)),
I have not used this but wink is a free demo-maker for Windows
available at:
http://www.debugmode.com/wink/
Click the red on green arrow on that page to a (very short) demo.
On 8/29/06, Gregor Gorjanc [EMAIL PROTECTED] wrote:
Hello!
I have found terrific demo or R package functionality at
Gabor Grothendieck wrote:
I have not used this but wink is a free demo-maker for Windows
available at:
http://www.debugmode.com/wink/
Click the red on green arrow on that page to a (very short) demo.
Thanks! Do you perhaps also know equivalent of ghostwriter (link is
bellow) for
On 20 August 2006 at 15:29, Frank E Harrell Jr wrote:
| Manuel Castejón Limas wrote:
| Hello,
| I've just compiled Hmisc ok under dapper.
| I think you need to further install some packages.
| Have you installed libc6-dev?
| I would start installing the build-essential package.
| Best
Don't know. I would check whether the functionality is included in wink.
On 8/29/06, Gregor Gorjanc [EMAIL PROTECTED] wrote:
Gabor Grothendieck wrote:
I have not used this but wink is a free demo-maker for Windows
available at:
http://www.debugmode.com/wink/
Click the red on green
On 24 August 2006 at 11:35, Ryan Austin wrote:
| Hi Bruno,
|
| Your missing the Basic Linear Algebra Subroutines 3.0 package.
|
| apt-get install refblas3
|
| should fix the problem. (At least in Debian, should be the same for Ubuntu)
The 'empty' package r-base-dev depends on 'refblas3-dev |
Try xyplot.zoo in the zoo package (be sure you have
the latest zoo version). One caveat is that xyplot.zoo is
under development and could change. Here we use the
builtin data set anscombe as an example:
# display the anscombe data set
anscombe
library(lattice)
library(zoo)
# create zoo object
Note that before entering this you need:
library(lattice)
library(grid) # to access the viewport function
On 8/29/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
Try this:
xyplot(val ~ x, data = df, type = p,
col = as.numeric(df$f1), pch = as.numeric(df$f2))
key1 - list(border =
This is in regard to Dan Norlund's post from December 2003 (available at
https://stat.ethz.ch/pipermail/r-help/attachments/20031225/1bce02b8/attachment.pl
)
While I agree with Prof. Ripley's warning against fitting so few
observations per panel, this is not actually what causes the error.
Anusha anu1978 at hotmail.com writes:
Respected Sir/Madam,
I have a problem with apply function. I have to two matrices of dimension of
one column but n rows. I have to check whether one matrix is greater than
other by going thru each row (ie) using if condition to check one matrix
with
Dear R users,
I am using mAr package to fit a Vector autoregressive model to my data. But
here I want to put some predetermined values for some elements in
coefficient matrix that mAr.est going to estimate. For example if p=3 then I
want to put A3[1,3] = 0 and keep rest of the elements of
Hi all,
I have two time series data (say x and y). I am interested to
calculate the correlation between them and its confidence interval (or
to test no correlation). Function cor.test(x,y) does the test of no
correlation. But this test probably is wrong because of
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