Hi,
It might be that R can't find Matlab; then you have to specify option
'matlab', see help(Matlab). Try also a different port. Try to add a
line setVerbose(matlab, -2) to get more detailed output what is going
on;
matlab - Matlab(host=localhost, port=9998)
setVerbose(matlab, -2)
if
Hello,
I am trying to use R to carry out loglinear analysis. So far, starting from a
previous post in this list
(http://finzi.psych.upenn.edu/R/Rhelp02a/archive/33698.html), I have been
able to use loglm() to generate likelihood ratio.
I now try to find a function that generates all the
I believe the split function should work in this case.
From the help file:
split(x, f, drop = FALSE, ...)
split(x, f, drop = FALSE, ...) - value
unsplit(value, f, drop = FALSE)
Arguments
|x| vector or data frame containing values to be divided into groups.
|f| a “factor” in the
Hi,
I would like to plot a map of US counties using different colors. map()
seems to be the function to use, e.g.
library(maps); map('usa'); map('county', 'colorado', add=T,fill = T,
col=c(1:5))
plots Colorado counties using colours 1 to 5.
However, I want each color to represent a certain
Try:
plot(x, y, bty = n, xaxs = i, yaxs = i)
Actually I think there may be a bug here since the axes do not intersect.
On 12/27/06, Knut Krueger [EMAIL PROTECTED] wrote:
Dear R-Group,
the first example is working as expected, but I need the plot without
the box,
normally no problem, but I
What do you think is `slightly inconsistent behavior' here? (You seem to
be quite consistent in not telling us such relevant facts, including your
OS and version of R!)
If you think that the memory usage of R should be monotone in the size of
the problem, your expectations are unfounded.
Given the lines after Description: have been wrapped during e-mail
transfer and are in one line in your DESCRIPTION file, here are two guesses:
- You have some additional library added that contains a broken
installation of some base package?
- You have declared some non-existing default
Dear Gabor,
sorry for not posting the code. below I have a piece of code that generates
a multivariate zoo data (3 columns) and graphs it using the axis
commands to generate the labels. This does not work. However, if one
extracts one column the labelling works using the same commands!
I cannot
Hi,
how to suppress a loading required package:... message?
Kind regards
Jaci
--
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
On 12/27/06, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Hi,
how to suppress a loading required package:... message?
require(package, quiet=TRUE)
jab
--
John Bollinger, CFA, CMT
www.BollingerBands.com
If you advance far enough, you arrive at the beginning.
I am writting some functions that return an array of coefficients
along with confidence intetervals for each coefficient. My intent is
to eventually typeset the coefficients and intervals into a table (or
tables) in a document. I would like to use existing tools such as the
'latex' function in
To do it with plot.zoo one has to create a custom panel.
Another approach is to use xyplot.zoo since that supports custom scales
directly. Note that the ?xyplot.zoo examples contain code that is along the
lines of the xyplot.zoo solution.
Here are examples of both approaches:
library(zoo)
#
If this is time series data try
library(zoo)
example(plot.zoo)
example(xyplot.zoo)
to see if any of those fit your requirements.
On 12/27/06, BBands [EMAIL PROTECTED] wrote:
Dear helpeRs,
Is there a better method of producing stacked charts than
par(mfrow(3,1)), plot(x), plot(y), plot(z)?
John,
On 27 December 2006 at 08:36, BBands wrote:
| Dear helpeRs,
|
| Is there a better method of producing stacked charts than
| par(mfrow(3,1)), plot(x), plot(y), plot(z)? What I would like to do is
| produce a chart of several panes stacked vertically with no space
| between them so they
since dr. bivand seems to be away, i will try to help a little :-)
i did not work with the database that comes with maps, but with shapefiles from
http://www.census.gov/geo/www/cob/co2000.html#shp. you need to merge the
dataframe that you have with the shapefile.
do you have access to gis
On 27 December 2006 at 08:52, BBands wrote:
| On 12/27/06, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
| Hi,
|
| how to suppress a loading required package:... message?
|
| require(package, quiet=TRUE)
Some packages insist on talking even when they are asked to be quiet, in
which case I have
Or try:
invisible(capture.output(library(Hmisc)))
On 12/27/06, Dirk Eddelbuettel [EMAIL PROTECTED] wrote:
On 27 December 2006 at 08:52, BBands wrote:
| On 12/27/06, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
| Hi,
|
| how to suppress a loading required package:... message?
|
|
On 12/27/06, Dirk Eddelbuettel [EMAIL PROTECTED] wrote:
Do you remember the bollingerBands example we worked on a few years ago and
that is still at Romain's incredible R Graph Gallery at
http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=65
It uses layout, you can also use
Hi John,
I cannot see the attached file but if you read the vignette of the zoo package
there is an example with Lucent stock price (High Low Open Close) doing what
you want.
the command plot(z) (z being the zoo multivariate object) produces the graph
that
you want I guess. Also there are some
Dirk Eddelbuettel wrote:
On 27 December 2006 at 08:52, BBands wrote:
| On 12/27/06, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
| Hi,
|
| how to suppress a loading required package:... message?
|
| require(package, quiet=TRUE)
Some packages insist on talking even when they are asked
Hi everyone:
I'm trying to compose a string dynamicly for the parameter input of
some function. For example:
In package MASS, function lda() require to input the name of predictor
variable. Let's say the 16th column is the predictor variable. Then we call
the function like this:
Dear All,
I am trying to automate series of dendrograms for
binary data in R as well as calculate the Consensus
Fork Index (Colless' index). I'll appreciate any
assistance with regards to this.
Thank you and best regards,
Taiwo
__
Hi everyone:
I wrote a R program which has loops. When I run the program, it
crashed. I would like to identify in which loop the pragram crashed, how
can I debug ? I'm new to R, could somebody please give me a general idea
about debugging in R.(I'm a C/C++ programmer and have
Hi,
I have 2 questions.
First - is it possible to use the offset term in a glmmPQL formula rather
than transforming the variables in the dataset beforehand?
Second - how do you compare the output/fit of 2 models produced through
glmmPQL if you can't use the Anova(model1, model2,
I am working with a non-parametic smoothing operation using a
Generalized Additive Model. It is a bivariate data set. I know how to
do the smooth, and out comes a nice smooth curve.
Now I want to find the value of the smoothed curve for several values
of x (the abscissa). This can be done
On Wednesday 27 December 2006 06:00, [EMAIL PROTECTED] wrote:
jingjiangyan
I agree, you can use 'assign'. To be more explicit, you could use the
following function.
jingjiangyan -
function(formula, data)
{
m - match.call()
%,% - function(x,y)paste(x,y,sep=)
d.nm - as.character(m$data)
Try:
lda(iris[-5], iris[,5])
On 12/26/06, Feng Qiu [EMAIL PROTECTED] wrote:
Hi everyone:
I'm trying to compose a string dynamicly for the parameter input of
some function. For example:
In package MASS, function lda() require to input the name of predictor
variable. Let's say the
Geoffrey == Geoffrey Zhu [EMAIL PROTECTED]
on Tue, 26 Dec 2006 10:05:55 -0600 writes:
Geoffrey I meant x[i] - x[i-1] + y[i-1] and Y[i] - y[i-1] + x[i] below.
Geoffrey The mailing list software just keep adding 3D's. Sorry.
It's not the mailing list software - not per se at least.
Thank you Gabor. This is very helpful.
AA.
- Original Message
From: Gabor Grothendieck [EMAIL PROTECTED]
To: ahmad ajakh [EMAIL PROTECTED]
Cc: r-help@stat.math.ethz.ch
Sent: Wednesday, December 27, 2006 12:08:41 PM
Subject: Re: [R] plotting time series with zoo pckg
To do it with
Thomas L Jones wrote:
I am working with a non-parametic smoothing operation using a
Generalized Additive Model. It is a bivariate data set. I know how to
do the smooth, and out comes a nice smooth curve.
Now I want to find the value of the smoothed curve for several values
of x (the
The following example shows how to get/display the county names:
library(maps)
# Get County Data
m - map('county', 'colorado', plot=FALSE)
names(m)
m$names # State,County names
# The names appear to be in alphabetical order by state, e.g.:
m$names[1:3]
[1] colorado,adamscolorado,alamosa
I want to be able to search my saved R script files on my hard drive.
Thankfully the files are all saved with the .R filename extension which
means that filetype:R in the Google Desktop Search (GDS) box limits the
search to those files. Unfortunately if I put any other term in the search
box (for
If you're on Windows switch to
http://www.copernic.com/en/products/desktop-search/index.html ,
last time I looked it was quite a lot better than Google Desktop Search.
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Farrel
Buchinsky
Sent: Wednesday,
I would like to make one histogram combining two value vectors. One vector has
more than 50 entries and the other only has 16. Both vectors contain dates in
the POSIXct format. I need to be able to highlight the 16 entries from the
smaller data set.
Is it possible to do this with the hist
Go to the gooogle desktop preferences page and install
Larry's Any Text File Indexer 1.00 by Larry Gadea (Index any file extension
specified as plaintext)
then tell it to search the .R and other extensions as plaintext.
Google will then index all indicated files on your harddisk and will
find
Wonderful. I did it and it works perfectly. Thanks a lot.
Richard M. Heiberger [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Go to the gooogle desktop preferences page and install
Larry's Any Text File Indexer 1.00 by Larry Gadea (Index any file
extension specified as plaintext)
Thank you for your advice. I have read quite a bit about Copernic Desktop
Search. Nevertheless, I chose not to download yet another indexing program.
I am very happy with Google Desktop Search and particularly how well it
integrates with many other features. Therefore, when I saw the reply to
If you look at the help for the tkBrush function in the TeachingDemos package,
the examples show the definition of a function called colhist. That function
may do what you want.
Hope this helps,
-Original Message-
From: [EMAIL PROTECTED] on behalf of sloan jones
Sent: Wed 12/27/2006
hello all,
I wonder if anyone could give me a hint on which statistical technique
I should use and how to carry it out in R in my case. Thanks in
advance.
My data is composed of two columns, the same numerical variable
(continuous) from actual measurement and model prediction. My
objective is to
Hi.
From what you tell me you manage to start Matlab in the background by calling:
Matlab$startServer()
but that R fails to connect to Matlab by:
matlab - Matlab(host=localhost, port=9998)
if (!open(matlab))
throw(Matlab server is not running: waited 30 seconds.)
Sorry for not being
Hi,
a follow up after realizing that you might not have started the Matlab
application to listen on port 9998. Try:
Matlab$startServer(port=9998)
and then
matlab - Matlab(host=localhost, port=9998)
if (!open(matlab)) throw(Matlab server is not running: waited 30 seconds.)
Does this help?
Generally, you can create formula from string:
lda(formula(paste(names(iris)[5],~.)),iris)
On 12/28/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
Try:
lda(iris[-5], iris[,5])
On 12/26/06, Feng Qiu [EMAIL PROTECTED] wrote:
Hi everyone:
I'm trying to compose a string dynamicly
Frank,
On 27 December 2006 at 12:30, Frank E Harrell Jr wrote:
| Dirk Eddelbuettel wrote:
| On 27 December 2006 at 08:52, BBands wrote:
| | On 12/27/06, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
| | how to suppress a loading required package:... message?
| |
| | require(package,
Hello all,
Can somebody point me to references or provide some code on dealing with
this date issue. Basically, I have two vectors of values that represent
dates. I want to convert these values into a date format and subtract the
differences to show elapsed time in days. More specifically,
Try this:
x - 'Date1 Date2
+ 032398061585
+ 032398061585
+ 111694101994
+ 111694101994
+ 062695021595
+ 051898111597
+ 072495040195
+ 072495040195'
data.in - read.table(textConnection(x), header=TRUE,
colClasses=c('character', 'character'))
data.in$Date1 -
Try:
as.date(Date1)-as.date(Date2)
On 12/28/06, Brian Edward [EMAIL PROTECTED] wrote:
Hello all,
Can somebody point me to references or provide some code on dealing with
this date issue. Basically, I have two vectors of values that represent
dates. I want to convert these values into a
See the documentation for
as.Date
Something like (untested):
as.Date(Date1, '%m%d%y) - as.Date(Date2,%m%d%y)
That's assuming Date1 and Date2 have already been loaded into R, and
are character vectors. They would have to be character vectors in
order to display the leading zero, as in
Dirk Eddelbuettel wrote:
Frank,
On 27 December 2006 at 12:30, Frank E Harrell Jr wrote:
| Dirk Eddelbuettel wrote:
| On 27 December 2006 at 08:52, BBands wrote:
| | On 12/27/06, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
| | how to suppress a loading required package:... message?
|
In your colLab function, you are assigning the label colors using the
mycols 4-element vector, which you generated using the rainbow()
function. So, to pick colors using the values in vector c, normalize c
and then try the colorRamp function.
I don't know how to use that function, myself,
All -
I'm creating some plots in R that I would like to overlay on images that
are created outside of R.
I've used image before to plot image-like data within R, and have added
vector plots on top of them, but I can't find a way to read in an external
bitmap file into R and use that.
How about fitted statistics of the model ?
Justin BEM
Elève Ingénieur Statisticien Economiste
BP 294 Yaoundé.
Tél (00237)9597295.
- Message d'origine
De : Xu Yuan [EMAIL PROTECTED]
À : r-help@stat.math.ethz.ch
Envoyé le : Jeudi, 28 Décembre 2006, 1h14mn 35s
Objet : [R] how to test
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