Hi r-help,
When I was building my package whin on Mac OS X using
R CMD build --binary whin
the following error occured:
$ R CMD build --binary whin
* checking for file 'spss/DESCRIPTION' ... OK
* preparing 'spss':
* checking DESCRIPTION meta-information ... ERROR
hi,
I am using the R connect to mysql by RODBC, windows XP. when I use sqlQuery()
to select blob columns from table, the result is binary type. but what i put
into the blob column is character. and when using Perl, it is ok.
i change the column data type to longtext. but this time, the
Hello,
in using vector() we can create a vector and fill in like this
v - vector()
v - c(v,2)
v - c(v,c(5,10,23))
but I wanna know if it's possible to do the same with the list I don't fond how?
Can you help me?
Thanks.
On Wed, 2007-07-18 at 03:52 +, Jose wrote:
The thing that I don't understand in the gR page is why there are so many
different packages and why they are not very integrated:
You have to understand the gR project for that. It started from a number
of completely separate pieces of software
'c' also works with lists:
a=list(1,2,3)
b=list(1,2,3)
c(a,b)
[[1]]
[1] 1
[[2]]
[1] 2
[[3]]
[1] 3
[[4]]
[1] 1
[[5]]
[1] 2
[[6]]
[1] 3
On 7/18/07, elyakhlifi mustapha [EMAIL PROTECTED] wrote:
Hello,
in using vector() we can create a vector and fill in like this
v - vector()
v -
On Tue, 17 Jul 2007, Marc Schwartz wrote:
Try the sqlQuery() syntax with a semi-colon at the end of it:
sqlQuery(essai, select * from S_TYP_COLLEGES;)
Oracle requires the semi-colon at the end of the SQL statement.
Over ODBC? I've never heard of that, and others have used RODBC to
Oracle
hello,
I have a longitudinal data:
idn mort30 newinfec
1 0 1
1 0 1
1 0 1
1 0 1
2 1 1
2 1 1
2 1 1
3 0
hi meeryana,
may be this time nobnody is responding. but dont worry you will get a lot
of help eventually, so always post a copy to the mailing list.
The reason is there are a lot many newbies, although i am also not so old
enough, who have even the simplest questions but are hesitant to ask.
sigalit mangut-leiba wrote:
hello,
I have a longitudinal data:
idn mort30 newinfec
1 0 1
1 0 1
1 0 1
1 0 1
2 1 1
2 1 1
2 1
Dear R-help users,
i used R to costruct the Delaunay triangulation with delaunayn function:
vertex=delaunayn(3d_coord, option=QJ)
of geometry package.
3d_coord is a matrix that contain 3d coordinates (x,y,z) of 160 points in
the 3d space.
I understand that not all of this point are used by
Dimitri
If you try
order(c(b,a,c))
[1] 2 1 3
or
sort(c(b,a,c))
[1] a b c
You will see that sort() and order() DO respect character order.
Your problem could be that your data frame variable is not a character but a
factor (the default for read.table, for example)
Check the class of the
Hello again,
I'm trying to purge the indexes in i.delete from frame and end up with more
rows!? Please be so kind and let me know where I screw this up ...
Joh
i.delete
[1] 40 45 165 212 253 270 280 287 301 352 421 433 463 467
487
[16] 517 537 542 573 594 596 612
Gagnon,Francois [SteFoy] wrote:
Hi,
I try to compute circular means for a matrix with NAs, but the function
circ.mean return only means for lines with complete values and do not
accept na.omit=T or na.rm=T, or na.action=na.omit, or na.fail=T.
Also, I try to use polar.plot of the
Problem: I have a Set of samples each with a list of observed species
(presence only).
Data is stored in a excel spreadsheet and the columns (spl) have
different numbers of observations (spcs).
Now I want to organize the data in a species by sample matrix with
presence/absence style in R.
data
I have seen that the hist() function plots an histogram of the frequency but I
cannot find the value of the object hist that contains theese values... how
is possible to get out them?
thank you very mutch
best regards
Manuele
--
Manuele Pesenti
[EMAIL PROTECTED]
Try
xx = hist(yy,plot=FALSE) ## plot=FALSE if you don't want to plot it
and then xx$counts
HIH
Stefano
On Wed, Jul 18, 2007 at 12:34:42PM +0200, Manuele Pesenti wrote:
ManueleI have seen that the hist() function plots an histogram of the
frequency but I
Manuelecannot find the value of the
On Wed, 2007-07-18 at 11:40 +0200, Johannes Graumann wrote:
Hello again,
I'm trying to purge the indexes in i.delete from frame and end up with more
rows!? Please be so kind and let me know where I screw this up ...
I think you'll have to explain why you think there are more rows after
using
Patrick Zimmermann wrote:
Problem: I have a Set of samples each with a list of observed species
(presence only).
Data is stored in a excel spreadsheet and the columns (spl) have
different numbers of observations (spcs).
Now I want to organize the data in a species by sample matrix with
I have an R script that spawns output in the form of an HTML page. This
is done by the R2HTML package.
Now I want to run the same script using Rcmd BATCH. However, it seems
that it is not possible to use R2HTML in this case.
My script ends with this error message:
#
Dear all,
I would like to know how can I retrieve a data.frame without the columns that
have a partial match name. Let´s say that I have a data.frame with 200 columns
and 100 of them have the name StartX, with X being the unique part for each
column name. I want to delete all columns that
Hi,
DATA_OK - DATA[,-match(Start, names(DATA))]
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O
On 18/07/07, João Fadista [EMAIL PROTECTED] wrote:
Dear all,
I would like to know how can I retrieve a data.frame without the columns that
have a partial match name.
DATA_OK - DATA[-grep(^Start, names(DATA)),]
On 7/18/07, João Fadista [EMAIL PROTECTED] wrote:
Dear all,
I would like to know how can I retrieve a data.frame without the columns that
have a partial match name. Let´s say that I have a data.frame with 200
columns and 100 of them have the name
On Wed, 2007-07-18 at 08:04 +0100, Prof Brian Ripley wrote:
On Tue, 17 Jul 2007, Marc Schwartz wrote:
Try the sqlQuery() syntax with a semi-colon at the end of it:
sqlQuery(essai, select * from S_TYP_COLLEGES;)
Oracle requires the semi-colon at the end of the SQL statement.
Over
Hi
I am working on R 2.5.0 on window. I am trying to provide a Hyper-link to
the user as a result, I have tried using gtkLinkButton to exercise the
facility, however, i am not able to perform the required task, i.e. when I
clicked on the LinkButton actually nothing happened.
I have gone through
hello,
I have programmed this function to calculate the Neuman-Keuls test but I have a
problem the function return an empty list and I don't know why.
summary(fm1)
E - sqrt((summary(fm1)[[1]][Residuals,Mean Sq])/length(LR))
lst - list()
lst1 - list()
lst2 - list()
NK - function (x) {
if
I think you can still read as a table, just use argument fill=TRUE.
Reading from Excel in general: you can save data as 'csv' or tab-delimited
file and then use read.csv or read.delim, respectively, or use one of the
packages listed in the following post (for some reason lines breaks are
messed
On 7/18/07, d. sarthi maheshwari [EMAIL PROTECTED] wrote:
Hi
I am working on R 2.5.0 on window. I am trying to provide a Hyper-link to
the user as a result, I have tried using gtkLinkButton to exercise the
facility, however, i am not able to perform the required task, i.e. when I
clicked on
Hi All,
I have a n x m matrix. The n rows are individuals, the m columns are variables.
The matrix is in itself a collection of 1s (if a variable is observed for an
individual), and 0s (is there is no observation).
Something like:
[,1] [,2] [,3] [,4] [,5] [,6]
[1,]1011
you could also have a look at function lca() from package `e1071' that
performs a latent class analysis, e.g.,
fit1 - lca(data, 2)
fit1
fit2 - lca(data, 3)
fit2
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic
Dimitris Rizopoulos wrote:
you could also have a look at function lca() from package `e1071' that
performs a latent class analysis, e.g.,
fit1 - lca(data, 2)
I tried but I got:
lca(data, 2)
Error in matrix(0, 2^nvar, nvar) : matrix: invalid 'nrow' value (too large or
NA)
In addition:
I believe I have seen that error message from
Oracle when I tried to query a table for which I
did not have select privileges (and when I knew
for certain that the table existed). Ask your
database administrator about the table, and make
sure that you do have that privilege.
What I am
Hi there,
I am relatively new user of R. I need to generate random number following
Gamma distribution with mean 14 und st.dev 3. I read the help-text but I can
not understand it well.
Regards,
Azizi
[[alternative HTML version deleted]]
__
I am trying to get the forall symbol (upside down A) as part of the
label of a lattice plot. Is there an easy way to do this?
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hi all.
I'd like know what is the format file saved by Leica
Microsystems TCS SP2-AOBS equipped with a SP2-FCS2 Leica Microsystems
workstation its datas. Cause it save in *.fcs extention file but
ins't flow cytometry standart format file...
Tahnks Horacio.
Dear R users,
Imagine please an optimization problem:
minimize sum S1+S2
Subject to : y - x = a + S1
x - y = a + S2
and we want to add two more constraints:
y - x = b - S3
x - y = b - S4
where a is a small
It appears that HSAURtable only works on two dimensional tables. Is this
correct?
For example, here is HairEyeColor:
, , Sex = Male
Eye
HairBrown Blue Hazel Green
Black32 1110 3
Brown38 502515
Red 10 10 7 7
Blond 3 30
Hello Hadi,
See ?rgamma
The Gamma distribution usually takes two parameters, shape and scale,
not the mean and st. deviation. If you have data, you can estimate
those parameters using MLE methods, which are nicely provided in MASS:
library(MASS)
fitdistr(yourdata,Gamma)
Once you have your
Dear useRs,
Lately I noticed a strange warning in the summary of a lm-object. Any
idea what this warning is about? I'm using R 2.5.1 on Win XP pro.
x - rnorm(100)
y - rnorm(100)
summary(lm(y~x))
Call:
lm(formula = y ~ x)
Residuals:
Min 1Q Median 3Q Max
-1,77809
At 12:32 17/07/2007, Johannes Graumann wrote:
Does anybody have any insight into how to make this faster?
I am not an expert on R programming by any means but I notice you are
growing your new data frame row by row. I believe it is normally
recommended to allocate enough space to start with.
I
Hello,
Could someone please let me know the procedure for determining the 'best'
solution with regards to the number of clusters using the Fanny algorithm
for computing fuzzy clusters? The function requires a specification of the
number of clusters a priori, but I am interested in determining what
2007/7/16, Bernardo Rangel Tura [EMAIL PROTECTED]:
On Fri, 2007-07-13 at 16:06 -0300, Horacio Castellini wrote:
Hi all.
How do I extract date from fcs format file with R. I.e I'd like
make statistical analysis using R-program, but I don't know if there
are R-packets for fcs format file,
FYI, Here is a tip that Gabor Grothendieck sent to the r-com help-list.
Thought others might find it helpful.
http://mailman.csd.univie.ac.at/pipermail/rcom-l/2007-July/001717.html
Subject: Re: [Rcom-l] running Excel/Visual Basic macro from within R[input]
[input] [input]
I am trying to save an R data.frame as an Excel sheet.
I do NOT want the column names saved into row 1.
I set colnames=F.
However, it still seems that the colnames are saved into row 1.
Is this a bug? Or am I coding incorrectly and.or misunderstanding this feature?
#example code:
sheet =
I think that you are on to something there Don.
I just tried accessing a table from our Oracle server, which I do know
exists, but for which I do not have access permissions.
Using the following query in the Oracle Instant Client:
select table_name from all_tables;
I can get a list of all
Hi everybody,
consider please an optimization problem:
minimize sum S1+S2
Subject to : y - x = A + S1
x - y = A + S2
and we want to add two more constraints:
y - x = B - S3
x - y = B - S4
where A is
As Jim points out, building up a data frame by rbinding in a loop can be
a slow way to do things in R.
Here's an example of how you can easily read data frames into a list:
# Create 3 files
invisible(lapply(1:3, function(i)
write.csv(file=paste(tmp,i,.csv,sep=),
Quick question about the configuration files relative to RMySQL (I've
tried to get feedback directly from the author David James, but his
email address was non-responsive):
Documentation at http://cran.r-project.org/doc/packages/RMySQL.pdf on
page 3 indicates that for windows machines the only
Hi,
I am also a quite new user of R and would like to ask you for help:
I have a data frame where all columns are numeric variables. My aim is
to convert one columnt in factors.
Example:
MD
0.2
0.1
0.8
0.3
0.7
0.6
0.01
0.2
0.5
1
1
I want to make classes:
0-0.2 A
0.21-0.4 B
0.41-0.6 C
. and
Michael
Assume your data frame is called data and your variable is called
V1. Converting this to a factor is:
data$V1 - factor(data$V1)
Creating the classes can be done using ifelse(). Something like
data$class - ifelse(data$V1 .21, A, ifelse(data$V1 .41, B, C))
Harold
-Original
Hi useR,
I am trying to find how to schedule an automatic run of R periodically, I
have written some scripts to extract data which are updated monthly on
another server, my os is xp. The goal is that my script will run at a
scheduled time every month and record the results to some directories.
Have a look at the recode function in the car package
library(car)
?recode
should give you what you need.
--- Ing. Michal Kneifl, Ph.D. [EMAIL PROTECTED]
wrote:
Hi,
I am also a quite new user of R and would like to
ask you for help:
I have a data frame where all columns are numeric
Hi,
I am new to programming and R. I am reading the manual and R books by Dalgaard
and Veranzo to help answer my questions but I am unable to figure out the
following:
I have a data file that contains 1080 data points. Here's a snippet of the file:
[241] 0.3603704000 0.1640741000
Tobias,
Adding the first constraints yields:
S1 + S2 = -2A
Similarly adding the second set of constraints:
S3 + S4 = 2B
If A and B are positive (which you didn't specify) then
The minimum of S1+S2 is -2A, and the maximum of S3+S4 is 2B.
Thus, the minimum of S1+S2-S3-S4 is -2(A+B).
Ravi.
maybe:
x = c(.2, .1, .8, .3, .7, .6, .01, .2, .5, 1, 1)
breaks = seq(0, 1, .2)
LETTERS[1:(length(breaks)-1)][cut(x, breaks)]
b
On Jul 18, 2007, at 1:50 PM, Doran, Harold wrote:
Michael
Assume your data frame is called data and your variable is called
V1. Converting this to a factor is:
On Wed, 2007-07-18 at 19:36 +0200, Ing. Michal Kneifl, Ph.D. wrote:
Hi,
I am also a quite new user of R and would like to ask you for help:
I have a data frame where all columns are numeric variables. My aim is
to convert one columnt in factors.
Example:
MD
0.2
0.1
0.8
0.3
0.7
0.6
Tobias,
Just a clarification/correction to my solution: it makes no difference
whether A and B are positive or negative. The minimum of S1+S2-S3-S4 is
always -2(A+B).
Ravi.
---
Ravi Varadhan, Ph.D.
Assistant
You can use 'cut':
x
MD
1 0.20
2 0.10
3 0.80
4 0.30
5 0.70
6 0.60
7 0.01
8 0.20
9 0.50
10 1.00
11 1.00
cut(x$MD, breaks=seq(0,1,.2), include.lowest=TRUE, labels=LETTERS[1:5])
[1] A A D B D C A A C E E
Levels: A B C D E
On 7/18/07, Ing. Michal Kneifl, Ph.D. [EMAIL PROTECTED]
Quoting Johannes Graumann [EMAIL PROTECTED]:
Hello again,
I'm trying to purge the indexes in i.delete from frame and end up with more
rows!? Please be so kind and let me know where I screw this up ...
Joh
i.delete
[1] 40 45 165 212 253 270 280 287 301 352 421 433 463
On Wed, 2007-07-18 at 12:53 -0500, Marc Schwartz wrote:
On Wed, 2007-07-18 at 19:36 +0200, Ing. Michal Kneifl, Ph.D. wrote:
Hi,
I am also a quite new user of R and would like to ask you for help:
I have a data frame where all columns are numeric variables. My aim is
to convert one
Quoting Manuele Pesenti [EMAIL PROTECTED]:
I have seen that the hist() function plots an histogram of the
frequency but I
cannot find the value of the object hist that contains theese values... how
is possible to get out them?
thank you very mutch
best regards
Manuele
if you
Is it really possible that nobody can help me with this? Is r-help too
overwhelmed now? Any help appreciated - Jon
On 7/16/07, Dr Carbon [EMAIL PROTECTED] wrote:
Please preemptively excuse my ignorance.
I'm trying to fit a cubic smoothing spline to a time series according to a
method
Just create a batch file, say myproc.bat with the line
C:/pathtoR/bin/R CMD BATCH myscript.R
and use the Windows task scheduler to schedule your job.
(Drag your batch file into C:/WINDOWS/Tasks, change its name if you
like, and right click to Properties to schedule it and set other
attributes.)
This should create your files for you:
x - 1:1080 # test data
# create a vector of 30 consecutive values for spliting the data
breaks - rep(1:ceiling(length(x) / 30), each=30)[1:length(x)]
# now partition the data into 30 values and write them
fileNo - 1 # initialize the file number
On 7/18/07, d. sarthi maheshwari [EMAIL PROTECTED] wrote:
Hi
I am working on R 2.5.0 on window. I am trying to provide a Hyper-link to
the user as a result, I have tried using gtkLinkButton to exercise the
facility, however, i am not able to perform the required task, i.e. when I
clicked on
Hello,
I have a question about Simon Wood's gam function.
Suppose I have a simple model
n-100
x - runif(n, 0, 1);
y-x*x
data-data.frame(x,y)
ct-gam(y~ s(x,k = 5))
how could I estimate first derivative of the smooth. From what I understand, i
could get coefficients of the fit from
ct2-gam(y~
I want to generate a lattice plot of a multiple linear regression. I'm
using the code:
xyplot(y ~ x1 + x2 | status, data=datam,
xlab=Peak separation,ylab=G/W,main=G/W vs Fuzzy peak
separation: Threshold=1.8,
groups=Fuzzy.gw.t.score1.8,
subset=(status %in%
Proper calendar dates in R are great for plotting and calculating.
However for the non-wonks among us, they can be very frustrating.
I have recently discussed the pains that people in my lab have had
with dates in R. Especially the frustration of bringing date data into R
from Excel, which we
Create a .bat file with the commands to execute R BATCH and then
create a scheduled task that will run at the desired time to call the
batch file.
On 7/18/07, Am Stat [EMAIL PROTECTED] wrote:
Hi useR,
I am trying to find how to schedule an automatic run of R periodically, I
have written some
Hello!
I need to perform maximum likelihood estimation on R, but I am not sure
which command to use. I searched on google, and found an example using the
function mlogl, but I couldn't find the package on R. Is there such
function? Or how should i perform my mle?
Thank you very much.
--
View
See the Other Applications section of the R News 4/1 help desk
article on dates.
On 7/18/07, Mr Natural [EMAIL PROTECTED] wrote:
Proper calendar dates in R are great for plotting and calculating.
However for the non-wonks among us, they can be very frustrating.
I have recently discussed the
Dear list,
I am interested in fitting a Generalized Additive Mixed Model with
spatially correlated errors to a large, spatially indexed, data set
(~4000 observations).
My initial analysis was a Generalized Additive Model that included a two
dimensional smooth term to model spatially
Hi Elyakhlifi,
I'm not a statistics expert and so can't intuit what your code is
doing easily. I also can't just run the code as supplied, as it uses
variables and data structures you haven't specified.
From a coding perspective, there are several issues though that will
almost certainly make a
On Wed, Jul 18, 2007 at 08:08:50AM -0700, rach.s wrote:
Hello!
I need to perform maximum likelihood estimation on R, but I am not sure
which command to use. I searched on google, and found an example using the
function mlogl, but I couldn't find the package on R. Is there such
function?
On 7/18/07, Alan S Barnett [EMAIL PROTECTED] wrote:
I want to generate a lattice plot of a multiple linear regression. I'm
using the code:
xyplot(y ~ x1 + x2 | status, data=datam,
xlab=Peak separation,ylab=G/W,main=G/W vs Fuzzy peak
separation: Threshold=1.8,
Hi,
I have a file fileFoo.R, say that contains these two lines, invoking
function foo that is specified in foo_details.R:
source(foo_details.R)
foo(parameter1)
I want to specify and pass parameter1 in my command line when invoking R
in linux: R --no-save fileFoo.R.
How can I do that?
On Wed, 2007-07-18 at 12:14 -0700, Mr Natural wrote:
Proper calendar dates in R are great for plotting and calculating.
However for the non-wonks among us, they can be very frustrating.
I have recently discussed the pains that people in my lab have had
with dates in R. Especially the
Look at the commandArgs function to see if that does what you want.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
(801) 408-8111
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of
Aydemir, Zava
If you create plots and use odfWeave to create an odf text document, the
default for figures is png bitmap graphics. The only way I've found to
insert eps graphics is to first create the eps graphic using the
postscript driver and then use odfInsertPlot. I've tried to use
getImageDefs and
Hi netters,
I'm using the 64-bit R-2.5.0 on a x86-64 cpu, with an RAM of 2 GB. The
operating system is SUSE 10.
The system information is:
-uname -a
Linux someone 2.6.13-15.15-smp #1 SMP Mon Feb 26 14:11:33 UTC 2007 x86_64
x86_64 x86_64 GNU/Linux
I used heatmap to process a matrix of the
...just a follow up to reading time series data from CSV files. If you've
got data like Gavin's (only with the dates in the first column)
Date,Data
01/01/2007,1
02/01/2007,2
03/01/2007,3
04/01/2007,4
...
then you can use read.zoo() in package zoo:
x - read.zoo(mydata.csv, sep = ,,
I am working on a nlme model that has multiple fixed effects (linear and
nonlinear) with a nonlinear (asymptotic) random effect.
asymporig-function(x,th1,th2)th1*(1-exp(-exp(th2)*x))
asymporigb-function(x,th1b,th2b)th1b*(1-exp(-exp(th2b)*x))
Hello R users:
I would like to produce a world map with countries colored according to whether
they fall into one of 7 eco-climatic zones. For simplicity, each country is
allocated to exactly 1 eco-climatic zone. For this purpose I have looked at the
map and mapdata packages, which contain world
HI:
I'm still struggling with datasets, the more I read
about it the more confussed I get. This is the
scenario... In R console|Edit|Data Editor, I can find
all the datasets available with the different
packages, So to create a new dataset in the R console
I use the following commands to create an
Are you paging? That might explain the long run times. How much space
are your other objects taking up? The matrix by itself should only
require about 13MB if it is numeric. I would guess it is some of the
other objects that you have in your working space. Put some gc() in
your loop to see
Hi All,
I want to test an H0 hypothesis about the proportions of observed counts
in k classes. I know that I can do this with the chisq.test.
However, besides of the overall acceptance or rejection of the H0, I
would like to know which of the k classes cause(s) rejection and I would
like to know
Where are you trying to copy data from? I would assume that with that
script you are typing all the data in by hand. Why don't you put it
in a text file and use read.table? By default, R will save your
workspace on exit and then reload it on startup. Is this enough to
save your data? You can
Horacio Castellini [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi all.
I'd like know what is the format file saved by Leica
Microsystems TCS SP2-AOBS equipped with a SP2-FCS2 Leica Microsystems
workstation its datas. Cause it save in *.fcs extention file but
ins't
On 7/18/07, Tanja Srebotnjak [EMAIL PROTECTED] wrote:
Hello R users:
I would like to produce a world map with countries colored according to
whether
they fall into one of 7 eco-climatic zones. For simplicity, each country is
allocated to exactly 1 eco-climatic zone. For this purpose I have
Hi,
I'm trying to use R to get eigenvalues and eigenvectors of a matrix
whose elements are of the form (2 * lambda), -(lambda + mu), etc. I'd
like R to treat this matrix as a numeric matrix without treating lambda
and mu as variable names but rather as some sort of atomic quantities
(and
Hello All,
I have a simple question based on how things are labeled on my heat map;
particularly, there is this annoying X that appears before the numeric
value of all the labels of my columns.
Let's say I have the following silly data, stored in temp.txt
1905191019501992
Dear Community,
I am very new to the world of Linux and R and I have stumbled upon a problem
that I cannot seem to resolve on my own. Here is the relevant background:
I am working on a 64-bit Linux Fedora Core 6 OS. I using R version 2.5.1. I
have 3.8 Gb of RAM and 1.9 Gb of swap. As I see it,
Hell all.
I¡¯m trying to estimate mixed logit model using MSLE.
In order to see that mixed logit model works better than simple logit model (
the logit model with fixed coefficient)
I simulated a dataset with random coefficients and tried to fit the data with
both mixed logit and simple
Hi.
I'm looking for an efficient way of writing a function(x,mat1,mat2).
n-4
m-4
r-3
x - array(sample(1:1000)/10^4,rep.int(n,m))
mat1 - matrix(sample(1:1000)/10^4,n,n)
mat2 - matrix(sample(1:1000)/10^4,n,n)
It needs to work for *any* itegers n, r=m with output (in horrible gory
detail)
I have 2 questions about the Biplot function:
Both of the questions refer to the following type of graph, which is a biplot of
a principal component analysis:
biplot(prcomp(dataset))
1. Does anyone know how to change the appearance of data points on the biplot?
As it is currently, for
The dist object for the rows of the matrix will be 16000x16000, which if
there are any copies will easily suck up all of your RAM.
A more pertinent question is what use would a heatmap of that size be?
How do you plan to visualize 16000 rows? In a pdf? You certainly
couldn't publish such a
Hi
I'm quite new to this area a bit but I'm wondering if there is any
implementation of multi-objective optimization using evolutionary approach
available in R? Any point to reference would be really appreciated. Thank you.
- adschai
__
Hi,
You may specify a different default.file in the dbConnect() call
to point to a non-default configuration file; dbConnect() simply passes this
filename to the MySQL API, which does the appropriate thing (in particular
you may want to double check the MySQL documentation regarding
using this
read.table is doing that, not heatmap.2. Use
read.table(temp.txt, header = TRUE, check.names = FALSE)
On 7/18/07, Suzanne Matthews [EMAIL PROTECTED] wrote:
Hello All,
I have a simple question based on how things are labeled on my heat map;
particularly, there is this annoying X that
Hi Tobias,
Could you please explain the role of x and y - are
they somehow related to S1,S2,S3,S4? Are they
constant? Are they additional variable?
What was your original problem (without the slack
variables)?
Regards,
Moshe.
--- Tobias Schlottmann [EMAIL PROTECTED]
wrote:
Hi everybody,
Hi Suzanne,
My solution (which I am sure is not the best) would
be:
heat - read.table('temp.txt')
heat
X1905 X1910 X1950 X1992 X2011 X2020
Gnat 0.08 0.29 0.29 0.37 0.39 0.43
Snake 0.16 0.34 0.32 0.40 0.41 0.53
Bat0.40 0.54 0.52 0.60 0.60 0.63
Cat0.16 0.27 0.29
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