At 22:36 23.07.2007 +, D L McArthur wrote:
James MacDonald jmacdon at med.umich.edu writes:
Hi all,
Most of the analyses I do are short little once-and-done type things
that are
easily encapsulated in a .Rnw
file. However, I sometimes end up with projects that take an extended
amount
Dear All,
To check if an url exists, I can use try(). This works, as I expected, if I
do it directly, as in the first part of the following example, but I could
not find a way to do it from within a function, as in the second part.
Where could I find information on how to do this?
Thanks,
Heinz
Thank you, Duncan, especially for the hint concerning inherits.
Heinz
At 08:02 26.05.2007 -0400, Duncan Murdoch wrote:
On 26/05/2007 7:13 AM, Heinz Tuechler wrote:
Dear All,
To check if an url exists, I can use try(). This works, as I expected, if I
do it directly, as in the first part
At 09:41 28.02.2007 +1030, Geoff Russell wrote:
There is a warning in the documentation for ?factor (R version 2.3.0)
as follows:
The interpretation of a factor depends on both the codes and the
'levels' attribute. Be careful only to compare factors with the
same set of levels (in the same
Dear All,
is there a convenient way to combine Surv objects?
Imagine two Surv objects as in the following example.
Is it possible to combine them into one _Surv_ object?
I tried rbind(), cbind(), c(), merge(), but none of these function does,
what I would like.
So I drafted a method for
Dear All,
Trying to combine two data frames with identical structure by rbind() or
merge() I cannot find a way to preserve the class of a Surv object (see
example).
Reading the help page for rbind, I an uncertain if I could expect that a
Surf oject retains it's class, but I would wish it did.
What could be the reason, to respond not only to the list? I did not see an
advantage, to receive a response twice, once directly, once by the list.
Is it wrong, to assume that someone who writes to the list, does also
receive all the postings on the list?
Heinz
At 08:09 08.08.2006 -0500, Mike
At 21:04 02.08.2006 +0100, Prof Brian Ripley wrote:
On Wed, 2 Aug 2006, Christian Hennig wrote:
Thank you Brian!
I'm updating my fpc package at the moment and will add some new
functions.
I learned that there should be print and summary methods for the key
functions.
for
Dear All,
is there a possibility to provide a default for the first argument in an
assignment function?
I could not find out if and how. You see in the example below that not
explicitly stating the first argument leads to errors.
Thanks,
Heinz Tüchler
### example of assignment function
Dear All,
applying some function within a with() function I wanted to use also
sapply() and get() to form a data.frame, but did not succede.
Below is a simplified example.
It is possible to use sapply() within a with() function, it is also
possible to use get() within a with() function, but when
Thank you, Thomas!
It helps a lot to know that something is impossible and that I have to look
for a different kind of solution.
Heinz
At 07:33 03.08.2006 -0700, Thomas Lumley wrote:
On Thu, 3 Aug 2006, Heinz Tuechler wrote:
Dear All,
applying some function within a with() function I wanted
Dear All!
If I pass an object to an assignment function I cannot get it's name by
deparse(substitute(argument)), but I get *tmp* and I found no way to get
the original name, in the example below it should be va1.
Is there a way?
Thanks,
Heinz
## example
'fu1-' - function(var, value) {
you, Gabor for your response. My example was very reduced, just to
show the point, but in the way I would like to use it, probably your
solution may be difficult to apply. Seems, I have to accept that I cannot
solve it.
Thanks again,
Heinz
On 7/27/06, Heinz Tuechler [EMAIL PROTECTED] wrote:
Dear
At 20:39 14.07.2006 -0500, Frank E Harrell Jr wrote:
Heinz Tuechler wrote:
At 11:02 13.07.2006 -0500, Frank E Harrell Jr wrote:
Heinz Tuechler wrote:
At 08:11 13.07.2006 -0500, Frank E Harrell Jr wrote:
Heinz Tuechler wrote:
At 13:14 12.07.2006 -0500, Marc Schwartz (via MN) wrote:
On Wed
At 11:02 13.07.2006 -0500, Frank E Harrell Jr wrote:
Heinz Tuechler wrote:
At 08:11 13.07.2006 -0500, Frank E Harrell Jr wrote:
Heinz Tuechler wrote:
At 13:14 12.07.2006 -0500, Marc Schwartz (via MN) wrote:
On Wed, 2006-07-12 at 17:41 +0100, Jol, Arne wrote:
Dear R,
I import data from spss
At 13:14 12.07.2006 -0500, Marc Schwartz (via MN) wrote:
On Wed, 2006-07-12 at 17:41 +0100, Jol, Arne wrote:
Dear R,
I import data from spss into a R data.frame. On this rawdata I do some
data processing (selection of observations, normalization, recoding of
variables etc..). The result is
At 08:11 13.07.2006 -0500, Frank E Harrell Jr wrote:
Heinz Tuechler wrote:
At 13:14 12.07.2006 -0500, Marc Schwartz (via MN) wrote:
On Wed, 2006-07-12 at 17:41 +0100, Jol, Arne wrote:
Dear R,
I import data from spss into a R data.frame. On this rawdata I do some
data processing (selection
At 12:36 13.07.2006 -0400, Richard M. Heiberger wrote:
Further I do not see a simple method to label numerical
variables. I often encounter discrete, but still metric data, as e.g. risk
scores. Usually it would be nice to use them in their original coding,
which may include zero or decimal
From the help page of Surv:
Although unusual, the event indicator can be omitted, in which case all
subjects are assumed to have an event.
That means, you can use coxph that way, _but_ it depends on your model.
Do you really want to model the time on study regardless of the kind of event?
Maybe you find that thread helpful:
http://tolstoy.newcastle.edu.au/R/help/00b/1426.html
Heinz
At 12:59 11.07.2006 +0200, [EMAIL PROTECTED] wrote:
How can I model coxph() in combination with competing risks
i.e. I have two events and for event the object will leave the data set.
So :
Dear All,
Is there a better way to include NA's of a factor in the output of table()
than using as.character()?
Admittedly, I do not understand the help page for table concerning the
exclude argument applied to factors. I tried in different ways, but could
not get NA to be included in the table,
rue du Professeur Calmette
B.P. 245
59019 Lille Cedex
Tel : 33 (0)3.20.87.10.44
Fax : 33 (0)3.20.87.10.31
http://www-good.ibl.fr
---
Heinz Tuechler a écrit :
Dear All,
Is there a better way to include NA's of a factor
Dear All,
as shown in the example, unique() deletes names of vector elements.
Is this intended?
Of course, one can use indexing by !duplicated() instead.
Greetings,
Heinz
## unique deletes names
v1 - c(a=1, b=2, c=3, e=2, a=4)
unique(v1) # names deleted
v1[!duplicated(v1)] # names preserved
Thank you, Richard. As soon as I find time I will carefully look at your
solution and your book.
Heinz
At 10:01 05.06.2006 -0400, Richard M. Heiberger wrote:
Aha! Thank you for the more detailed example.
My solution for that situation is an attribute position and function
as.position(). I use
Quoting Heinz Tuechler [EMAIL PROTECTED]:
At 14:12 03.06.2006 +0200, Martin Maechler wrote:
Heinz == Heinz Tuechler [EMAIL PROTECTED]
on Tue, 23 May 2006 01:17:21 +0100 writes:
Heinz Dear All, after searching on CRAN I got the
Heinz impression that there is no standard way in R
Richard, Martin,
the example is not ideal, I see. I was strating from the question, how to
represent a metric categorical variable.
By metric categorical variable I intend a variable, which has only few
distinct values and an inherent metric. An example would be a risk score,
which classifies
At 14:12 03.06.2006 +0200, Martin Maechler wrote:
Heinz == Heinz Tuechler [EMAIL PROTECTED]
on Tue, 23 May 2006 01:17:21 +0100 writes:
Heinz Dear All, after searching on CRAN I got the
Heinz impression that there is no standard way in R to
Heinz label values of a numerical
, Marc Schwartz wrote:
On Thu, 2006-05-25 at 00:43 +0100, Heinz Tuechler wrote:
Thank you for your answer, Gabor. I will see, if I understood it.
Heinz
At 11:31 24.05.2006 -0400, Gabor Grothendieck wrote:
You could create your own child class with its own [ method.
[.myfactor - function(x
see: [R] How to access results of survival analysis Xiaochun Li (06 May 2006)
At 15:03 24.05.2006 +0200, David Hajage wrote:
Hello R users !
Here a survfit object :
library(survival)
essai - aml[aml$x == Maintained,]
calc - survfit(Surv(essai$time, 1 - essai$status))
calc
Call:
Dear All!
For descriptive purposes I would like to add attributes to objects. These
attributes should be kept, even if by indexing only part of the object is
used.
I noted that some attributes like levels and class of a factor exist also
after indexing, while others, like comment or label vanish.
) - attr
x
}
gx - structure(fx, class = c(myfactor, class(fx)))
attributes(gx[1])
On 5/24/06, Heinz Tuechler [EMAIL PROTECTED] wrote:
Dear All!
For descriptive purposes I would like to add attributes to objects. These
attributes should be kept, even if by indexing only part of the object
Dear All,
after searching on CRAN I got the impression that there is no standard way
in R to label values of a numerical variable.
Since this would be useful for me I intend to create such an attribute, at
the moment for my personal use.
Still I would like to choose a name which does not conflict
Dear All,
often I encounter variables, which have only few distinct values and an
inherent metric. An example would be a risk score, which classifies
patients in several groups like low, intermediate, high, extreme with
corresponding risk estimates of 0, 1, 2, 5.5.
In some cases, like tables and
At 12:55 07.05.2006 +0100, Prof Brian Ripley wrote:
On Sun, 7 May 2006, Heinz Tuechler wrote:
Hello Xiaochun Li!
Thank you for submitting the function. At the time I had that problem I
solved it in a somewhat different way.
I changed a few lines in the print.survfit method. I introduced
Hello Xiaochun Li!
Thank you for submitting the function. At the time I had that problem I
solved it in a somewhat different way.
I changed a few lines in the print.survfit method. I introduced a parameter
ret.res=FALSE set to false to preserve the normal behaviour of print.
The second last line
Dear All,
there seems to be some strange influence of the Design package on
data.frame. If I build a data.frame containing a Surv object without
loading the package Design, the data frame is usable to coxph. If instead I
just load Design and build a data.frame afterwards, the naming of the Surv
At 11:13 16.03.2006 -0800, Thomas Lumley wrote:
On Thu, 16 Mar 2006, Heinz Tuechler wrote:
Dear All,
there seems to be some strange influence of the Design package on
data.frame. If I build a data.frame containing a Surv object without
loading the package Design, the data frame is usable
Dear All,
a Surv object I put in a data frame behaves somehow unexpected (see example).
If I do a Cox regression on the original Surv object it works. If I put it
in a data.frame and do the regression on the data frame it does not work.
Seemingly it has to do with the class attribute, because if
At 09:23 15.03.2006 -0800, Thomas Lumley wrote:
On Wed, 15 Mar 2006, Heinz Tuechler wrote:
Dear All,
a Surv object I put in a data frame behaves somehow unexpected (see
example).
If I do a Cox regression on the original Surv object it works. If I put it
in a data.frame and do the regression
At 11:59 15.03.2006 -0600, Robert Baer wrote:
This does work:
coxph(survobj~group, data=df.test[[1]]) # this works like your original
To get insight compare:
str(survobj)
str(df.test)
str(df.test[[1]])
Thank you for your answer. It seems to me that your solution only works, as
long as the
be defined in the posting guide.
This way, every reader/expert can decide on a personal level to split the
list by filtering the messages accordingly.
Heinz Tuechler
John Maindonald email: [EMAIL PROTECTED]
phone : +61 2 (6125)3473fax : +61 2(6125)5549
Mathematical Sciences Institute
At 13:11 03.01.2006 -0500, Peter Flom wrote:
Ben Fairbank [EMAIL PROTECTED] 1/3/2006 12:42 pm wrote
One implicit point in Kjetil's message is the difficulty of learning
enough of R to make its use a natural and desired first choice
alternative, which I see as the point at which real progress
Dear All,
Does someone have, or know of survexp ratetables for european contries,
especially Austria and Germany?
I know only about slopop in the package relsurv.
Thanks in advance
Heinz Tüchler
__
R-help@stat.math.ethz.ch mailing list
At 16:30 15.12.2005 +0100, Robert Chung wrote:
Heinz Tuechler wrote:
Dear All,
Does someone have, or know of survexp ratetables for european contries,
especially Austria and Germany?
I know only about slopop in the package relsurv.
I'm not sure I understand what you're asking for; slopop
At 07:56 09.09.2005 +0200, TEMPL Matthias wrote:
RSiteSearch(read spss data)
--
library(foreign)
?read.spss
Best,
Matthias
or spss.get in Hmisc
Heinz
-Ursprüngliche Nachricht-
Von: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Im Auftrag von ERICK YEGON
Gesendet: Freitag, 09.
At 12:09 09.09.2005 +0200, Martin Maechler wrote:
Heinz == Heinz Tuechler [EMAIL PROTECTED]
on Fri, 09 Sep 2005 01:58:29 +0200 writes:
Heinz Dear All,
Heinz it seems to me that the function read.spss of package
Heinz foreign changed its behaviour regarding factors. I
Heinz
Dear Thomas,
Thanks a lot for your extensive answer.
Heinz
At 08:53 09.09.2005 -0700, Thomas Lumley wrote:
On Fri, 9 Sep 2005, Heinz Tuechler wrote:
Dear Martin,
Thank you for your answer. As I said, I appreciate this change. The
documentation does not explain precisely, how variables
Dear All,
it seems to me that the function read.spss of package foreign changed its
behaviour regarding factors. I noted that in version 0.8-8 variables with
value labels in SPSS were transformed in factors with the labels in
alphabetic order.
In version 0.8-10 they seem to be ordered preserving
At 19:02 28.08.2005 -0700, Thomas Lumley wrote:
On Sun, 28 Aug 2005, Heinz Tuechler wrote:
Thanks to Peter Dalgaard and Frank Harrell for your answers. Fortunately I
don't have an urgent need for this test, but it may be in the future.
Still I would be grateful if someone could comment on my
Dear All,
is there a stratified version of the Wilcoxon test (also known as van
Elteren test) available in R?
I could find it in the survdiff function of the survival package for
censored data. I think, it should be possible to use this function creating
a dummy censoring indicator and setting it
test.
Thanks,
Heinz Tüchler
At 15:18 28.08.2005 -0500, Frank E Harrell Jr wrote:
Peter Dalgaard wrote:
Heinz Tuechler [EMAIL PROTECTED] writes:
Dear All,
is there a stratified version of the Wilcoxon test (also known as van
Elteren test) available in R?
I could find it in the survdiff
Dear All,
where can I find information about how to write an assigment form of a
function?
For curiosity I tried to write a different form of the levels()-function,
since the original method for factor deletes all other attributes of a factor.
Of course, the simple method would be to use instead
/336899
Fax: +32/16/337015
Web: http://www.med.kuleuven.be/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
- Original Message -
From: Heinz Tuechler [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Sent: Wednesday, August 10, 2005 2:24 PM
Subject: [R] how to write
where I read
what.
Heinz Tüchler
Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and A Guide for the Unwilling S User)
Heinz Tuechler wrote:
Dear All,
where can I find information about how to write an assigment form of a
function?
For curiosity I
2004-04-12 Ostern
Can I get this table without 1, 2, 3 ?
Thanks in advance
Heinz Tuechler
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
At 16:05 02.08.2005 +0200, Romain Francois wrote:
Le 02.08.2005 15:45, Heinz Tuechler a écrit :
Dear All,
is there a simple way to print a data.frame without its row.names?
example:
datum - as.Date(c(2004-01-01, 2004-01-06, 2004-04-12))
content - c('Neujahr', 'Hl 3 K.', 'Ostern')
df1
Thanks to all of you for your help.
As far as I see, the solution of Peter Dalgaard works exactly as I want.
All other solutions have limitations.
Heinz
At 19:19 02.08.2005 +0200, Peter Dalgaard wrote:
Martin Maechler [EMAIL PROTECTED] writes:
Heinz == Heinz Tuechler [EMAIL PROTECTED
Dear All,
it seems to me that levels() deletes other attributes. See the following
example:
## example with levels
f1 - factor(c('level c','level b','level a','level c'), ordered=TRUE)
attr(f1, 'testattribute') - 'teststring'
attributes(f1)
levels(f1) - c('L-A', 'L-B', 'L-C')
attributes(f1)
If
At 09:29 18.07.2005 -0500, Frank E Harrell Jr wrote:
Heinz Tuechler wrote:
Dear All,
it seems to me that levels() deletes other attributes. See the following
example:
## example with levels
f1 - factor(c('level c','level b','level a','level c'), ordered=TRUE)
attr(f1, 'testattribute
At 16:53 18.07.2005 +0200, Heinz Tuechler wrote:
At 09:29 18.07.2005 -0500, Frank E Harrell Jr wrote:
Heinz Tuechler wrote:
Dear All,
it seems to me that levels() deletes other attributes. See the following
example:
## example with levels
f1 - factor(c('level c','level b','level a','level
Dear All,
Assume I have a data.frame that contains also factors and I would like to
get another data.frame containing the factors as numeric vectors, to apply
functions like sapply(..., median) on them.
I read the warning concerning as.numeric or unclass, but in my case this
makes sense, because
At 07:15 02.04.2005 -0500, Gabor Grothendieck wrote:
Try this:
data.matrix(df.f12)
Perfect! This is exactly what I needed.
Many thanks,
Heinz Tüchler
On Apr 2, 2005 6:01 AM, Heinz Tuechler [EMAIL PROTECTED] wrote:
Dear All,
Assume I have a data.frame that contains also factors and I would
At 14:26 02.04.2005 +0100, Prof Brian Ripley wrote:
On Sat, 2 Apr 2005, Heinz Tuechler wrote:
Dear All,
Assume I have a data.frame that contains also factors and I would like to
get another data.frame containing the factors as numeric vectors, to apply
functions like sapply(..., median
At 16:13 29.03.2005 -0800, Thomas Lumley wrote:
On Wed, 30 Mar 2005, Heinz Tuechler wrote:
Dear all,
Last December there was a thread regarding the famous FAQ 7.21 How can I
turn a string into a variable? and asking what people want to do with
these strings.
My, certainly trivial
At 09:32 30.03.2005 +0200, Heinz Tuechler wrote:
At 16:13 29.03.2005 -0800, Thomas Lumley wrote:
On Wed, 30 Mar 2005, Heinz Tuechler wrote:
Dear all,
Last December there was a thread regarding the famous FAQ 7.21 How can I
turn a string into a variable? and asking what people want to do
Dear all,
Last December there was a thread regarding the famous FAQ 7.21 How can I
turn a string into a variable? and asking what people want to do with
these strings.
My, certainly trivial application would be as follows:
Assume I have a data.frame containing besides others also the columns f1,
Hello,
still I have difficulties with variable names in functions. I know the
famous example form help for deparse/substitute but I will give a simpler
one to explain my problem.
I know from Reid Huntsinger (Tue, 8 Feb 2005 12:39:32 -0500) that:
Semantically, R is pass-by-value, so you don't
for the example.
Still I am looking for a more general solution, but it is not urgent.
Heinz Tüchler
Heinz Tuechler wrote:
Hello,
still I have difficulties with variable names in functions. I know the
famous example form help for deparse/substitute but I will give a simpler
one to explain my problem.
I
At 11:51 17.02.2005 +0100, Peter Dalgaard wrote:
Heinz Tuechler [EMAIL PROTECTED] writes:
mytable1-function(x,y){table(x,y)}
mytable1(charly, delta)
y
x 1 2
1 2 1
2 3 4
If I define the function in the following way, it does what I wish, namely
it returns output equivalent
At 08:32 17.02.2005 -0800, Berton Gunter wrote:
I thought Thomas L. was clear, but apparently not...
** Do not pass character string names as arguments to functions. ** Pass the
objects (or expressions) which can consist of lists of vectors, dataframes,
etc. instead.
If you need the names
Hello,
Using Update Packages from CRAN in R Version 2.0.1 Patched (2005-01-15)
under Windows 98, I found it tricky to save the downloaded files.
Even if I answer N to the question, if the downloaded files should be
deleted, they are deleted after R is quitted. I understood that I have to
copy
Thank you for the hint regarding the destdir parameter of update.packages.
Heinz Tüchler
At 12:15 15.02.2005 +0100, Uwe Ligges wrote:
Heinz Tuechler wrote:
Hello,
Using Update Packages from CRAN in R Version 2.0.1 Patched (2005-01-15)
under Windows 98, I found it tricky to save
Hello,
applying a function to a list of variables I face the following problem:
Let's say I want to compute tables for several variables. I could write a
command for every single table, like
bravo-c(1,1,2,3,5,5,5,);charly-c(7,7,4,4,2,1)
table(bravo); table(charly)
table(bravo); table(charly)
for a list of variables.
In any case, thanks,
Heinz
From: Heinz Tuechler
Hello,
applying a function to a list of variables I face the
following problem:
Let's say I want to compute tables for several variables. I
could write a
command for every single table, like
bravo-c(1,1,2,3,5,5,5
to produce this named list by some function from a simple list without
retyping each name.
Thanks again,
Heinz
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Heinz Tuechler
Sent: Tuesday, February 08, 2005 8:45 AM
To: r-help@stat.math.ethz.ch
Subject
a temporary workaround, but it seems to work.
Thanks,
Heinz Tüchler
At 19:09 05.02.2005 +0100, Uwe Ligges wrote:
Heinz Tuechler wrote:
At 15:19 05.02.2005 +0100, Uwe Ligges wrote:
Heinz Tuechler wrote:
Hello,
it seems that the main results of survival analysis with package survival
are shown
Message -
From: Heinz Tuechler [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Sent: Friday, February 04, 2005 11:17 PM
Subject: [R] How to access results of survival analysis
Hello,
it seems that the main results of survival analysis with package survival
are shown only as side effects
At 15:19 05.02.2005 +0100, Uwe Ligges wrote:
Heinz Tuechler wrote:
Hello,
it seems that the main results of survival analysis with package survival
are shown only as side effects of the print method.
If I compute e.g. a Kaplan-Meier estimate by
km.survdur-survfit(s.survdur)
then I
Hello,
it seems that the main results of survival analysis with package survival
are shown only as side effects of the print method.
If I compute e.g. a Kaplan-Meier estimate by
km.survdur-survfit(s.survdur)
then I can simply print the results by
km.survdur
Call: survfit(formula =
At 10:30 06.12.2004 -0500, Duncan Murdoch wrote:
But we still have users using Win9x versions, which use a more
DOS-like method of setting the path. At some point we'll drop support
for them, but I don't want to do it sooner than necessary.
Duncan Murdoch
Thank you for supporting Win9x! I
2004 16:54:53 +0100
To: Duncan Murdoch [EMAIL PROTECTED]
From: Heinz Tuechler [EMAIL PROTECTED]
Subject: Re: [R] Attn Heinz Tuechler: Re: problem with sp ecial characters (
=?iso-8859-1?Q?=E4?= =?iso-8859-1?Q?,=F6,=FC)?=
In-Reply-To: [EMAIL PROTECTED]
References: [EMAIL PROTECTED]
[EMAIL
Hello!
A problem with special characters seemed to me to be a bug. I sent a mail
to [EMAIL PROTECTED] concerning the problem (see below).
How can I find out, if this is considered as a bug or an error of myself?
Which part of FAQs or documentation did I miss to find the answer?
thanks in advance
?
Duncan Murdoch
On Sat, 27 Nov 2004 23:31:23 +0100, Heinz Tuechler [EMAIL PROTECTED]
wrote :
Dear Developers!
Using special characters I found a strange behaviour in R 2.0.1 and equally
in
R : Copyright 2004, The R Foundation for Statistical Computing
Version 2.0.1 (2004-11-15), ISBN 3-900051
-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Heinz Tuechler
Sent: Tuesday, November 30, 2004 1:25 PM
To: [EMAIL PROTECTED]
Subject: [R] How to know if a bug was recognised
Hello!
A problem with special characters seemed to me to be a bug. I
sent a mail to [EMAIL
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