options(CRAN='http://cran.r-project.org')
install.packages(RMySQL, type=source)
Warning: unable to access index for repository
http://www.ibiblio.org/pub/languages/R/CRAN/src/contrib
Warning: unable to access index for repository
http://www.stats.ox.ac.uk/pub/RWin/src/contrib
Warning
y
[1] 1 11 42 64 108 173 214
t
[1] 1 2 3 4 5 6 7
nls(1/y ~ c*exp(-a*b*t)+1/b, start=list(a=0.001,b=250,c=5), trace=TRUE)
29.93322 :0.001 250.000 5.000
Error in numericDeriv(form[[3]], names(ind), env) :
Missing value or an infinity produced when evaluating the
how to realize the following SQL command in R?
select distinct A, B, count(C)
from TABLE
group by A, B
;
quit;
Best Regards
-
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or T-Mobile.
How to make it correct?
[1]
Error in parse(file, n = -1, NULL, ?) : syntax error at
1: {\
#source('c:/Documents and Settings/xxx/My Documents/Archives/R/test.r')
#source(c:\\Documents and Settings\\xxx\\My
Documents\\Archives\\R\\test.r)
[2]
Error in file(file, r, encoding
Is there anyway to change any y[i] value (i=2,...6) to make following NLS
workable?
x - c(0,5,10,15,20,25,30)
y - c(1.0,0.82000,0.68000,0.64000,0.7,0.68667,0.64000)
lm(1/y ~~ x)
nls(1/y ~~ a+b*x^c, start=list(a=1.16122,b=0.01565,c=1), trace=TRUE)
#0.0920573 : 1.16122
How to convert the following ms() in Splus to Optim in R? The Calc function
is also attached.
ms(~ Calc(a.init, B, v, off, d, P.a, lambda.a, P.y, lambda.y,
10^(-8), FALSE, 20, TRUE)$Bic,
start = list(lambda.a = 0.5, lambda.y = 240),
control = list(maxiter = 10, tol = 0.1))
May I ask how to include following procedures into R script (such as first.r)
such that it will do an automatical call next time after I open R?
Packages - Load Packages - splines
Thanks,
Shelton
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I'm using R 2.1.1 and just successfully installed packages tseries, fseries.
I try to run example
http://www.maths.lth.se/help/R/.R/library/tseries/html/garch.html
But it shows
x.arch - garch(x, order = c(0,2)) # Fit ARCH(2)
Error: couldn't find function garch
Then I run
x-c(-1.873,-0.121) # 23 numerics;
x.arma12 - armaFit(x ~ arma(1,2))
#estimates y[t]= -0.11465 - 0.23767 y[t-1] - 0.14230 e[t-1] -0.85770 e[t-2] +
e[t];
# ? how to predict 46 steps ahead based on 23 data points?
# the following doesn't work since n is in armaSim rather than
I typed the following commands but it still use maxiter=50 after the 2nd
command:
nls.control(maxiter = 1000)
nls(..)
Thanks!
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How to obtain the FUNCTION for the following smooth curve?
x 0100 250 500 1000 4000
y 1.8 1.2 1.02 0.99 0.97 0.85
Thanks,
SJ
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