Hello,
i have continuous test results for dieased and nondiseased subjects, say X
and Y. Both are vectors of numbers.
is there any R function which can generate the step function of ROC curve
automatically?
Thanks!
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Here is my table
tt
A B
1 297 398
2 470 376
3 30 23
4 3 3
5 0 0
b/c two cells are zero, I can't use chisq.test() in R which gives the
following output;
chisq.test(tt)
Pearson's Chi-squared test
data: tt
X-squared = NaN, df = 4, p-value = NA
Warning message:
when producing boxplot from bwplot, I have five groups: Nitrogen, Duration,
Pressure, A, Z. I wish the graphical display is according to the original
order. But the R-function bwplot seems to automatically adjust the groups
according to the alphabetic oder and thus creat a graph for A, Duration,
Suppose I have a vector A=c(1,2,3)
now I want to compare each element of A to another vector L=c(0.5, 1.2)
and then recode values for sum(A0.5) and sum(A1.2)
to get a result of (3,2)
how can I get this without writing a loop of sums?
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find the position of the first value who equals certain number in a vector:
Say a=c(0,0,0,0,0.2, 0.2, 0.4,0.4,0.5)
i wish to return the index value in a for which the value in the vector is
equal to 0.4 for the first time. in this case, it is 7.
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I downloaded the tar.gz file from r-project website (and saved it in a local
directory) and wish to use the package in R.
But I am not sure how to use the install.packages command. I tried a few
times and still couldn't figure out the correct way to install this package.
[[alternative
i have a data set with repeated measures on same people, structure like
below:
id x1 x2 ...
001 10 20 ...
001 8 45 ...
001 4 2 ...
002
002 ...
002
002
003
...
what is the easist way to show how many observations for each subject id?
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[EMAIL PROTECTED] wrote:
gallon li wrote:
i have a data set with repeated measures on same people, structure like
below:
id x1 x2 ...
001 10 20 ...
001 8 45 ...
001 4 2 ...
002
002 ...
002
002
003
...
what is the easist way to show how many
i have a large longitudinal data set. The number of observations for each
subject is not the same across the sample. The largest number of a subject
is 5 and the smallest number is 1.
now i want to make each subject to have the same number of observations by
filling zero, e.g., my original sample
Two questions:
1. How do I replace NA with 0?
2. How can I sort the observations by their id instead of by time? (actually
i can see what you produced is automatically sorted by id; but in my case,
the output data is sorted by time)
On 1/27/07, Chuck Cleland [EMAIL PROTECTED] wrote:
gallon li
what if i want to order within each id by their time? is there such an
option? (right now some observation at time 100 were placed before 50 b/c R
treated 1 first)
On 1/27/07, Chuck Cleland [EMAIL PROTECTED] wrote:
gallon li wrote:
Two questions:
1. How do I replace NA with 0?
df.long2
I want to compute B=A^{1/2} such that B*B=A.
For example
a=matrix(c(1,.2,.2,.2,1,.2,.2,.2,1),ncol=3)
so
a
[,1] [,2] [,3]
[1,] 1.0 0.2 0.2
[2,] 0.2 1.0 0.2
[3,] 0.2 0.2 1.0
a%*%a
[,1] [,2] [,3]
[1,] 1.08 0.44 0.44
[2,] 0.44 1.08 0.44
[3,] 0.44 0.44 1.08
b=a%*%a
i have
Usually the y-axis is shown on the left-hand-side of a graph, is it possible
to artifically creat one more y-axis on the right-hand-side in R? What is
the main reference? Thank you in advance.
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__
I intend to draw a plot of y against x. In the background of this graph I
wish to creat a histogram of the horizontal variable x. Does any expert know
how to produce such a plot?
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__
R-help@stat.math.ethz.ch
-- Forwarded message --
From: gallon li [EMAIL PROTECTED]
Date: Sep 6, 2006 7:48 PM
Subject: Re: [R] plot axises on both sides of a graph
To: Jim Lemon [EMAIL PROTECTED]
Both of your suggestions are so helpful. By combining what you told me, now
I am able to produce a second y
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