Dear all,
Can anyone please shed some light onto how to do this?
This will give me all intensity columsn in my data frame:
intensityindeces - grep(^Intensity,names(dataframe),value=TRUE)
This will give me the maximum intensity for the first row:
intensityone - max(dataframe[1,intensityindeces])
Johannes Graumann wrote:
Dear all,
Can anyone please shed some light onto how to do this?
This will give me all intensity columsn in my data frame:
intensityindeces - grep(^Intensity,names(dataframe),value=TRUE)
This will give me the maximum intensity for the first row:
intensityone -
do.call(pmax, dataframe[,intensityindeces])
if I understand you aright.
On Mon, 19 Feb 2007, Johannes Graumann wrote:
Dear all,
Can anyone please shed some light onto how to do this?
This will give me all intensity columsn in my data frame:
intensityindeces -
On Monday 19 February 2007 11:53, Prof Brian Ripley wrote:
do.call(pmax, dataframe[,intensityindeces])
Thank you very much for your help!
Any idea why do.call(pmax,list(na.rm=TRUE),dataframe[,intensityindeces])
would give me
Error in if (quote) { : argument is not interpretable as logical
In
On Mon, 19 Feb 2007, Johannes Graumann wrote:
On Monday 19 February 2007 11:53, Prof Brian Ripley wrote:
do.call(pmax, dataframe[,intensityindeces])
Thank you very much for your help!
Any idea why do.call(pmax,list(na.rm=TRUE),dataframe[,intensityindeces])
You want something like
Try do.call(pmax,c(dataframe[,intensityindices],na.rm=TRUE))
This is like the second example in the help page for do.call
On 19/02/07, Johannes Graumann [EMAIL PROTECTED] wrote:
On Monday 19 February 2007 11:53, Prof Brian Ripley wrote:
do.call(pmax, dataframe[,intensityindeces])
Thank you
Thanks to you and Brian Ripley. Quite confusing all this ...
Thanks again.
Joh
On Monday 19 February 2007 13:42, David Barron wrote:
Try do.call(pmax,c(dataframe[,intensityindices],na.rm=TRUE))
This is like the second example in the help page for do.call
On 19/02/07, Johannes Graumann
