Hi Folks,
The recent correspondence about strange fisher.test result,
and especially Peter Dalgaard's reply on Tue 03 April 2007
(which I want to investigate further) led me to take a close
look at the code for binom.test().
I now have a query!
The code for the two-sided case computes the
On 4/5/2007 5:35 PM, (Ted Harding) wrote:
Hi Folks,
The recent correspondence about strange fisher.test result,
and especially Peter Dalgaard's reply on Tue 03 April 2007
(which I want to investigate further) led me to take a close
look at the code for binom.test().
I now have a query!
@stat.math.ethz.ch
Subject: [R] binom.test
Date: Fri, 20 Oct 2006 17:18:02 -0400
A quick question, please.
46 e coli lab samples are tested, 6 of them returned positive.
So, the best point estimate for p is 6/46 = 0.1304348.
For a 95% CI for p, I thought binom.test would
A quick question, please.
46 e coli lab samples are tested, 6 of them returned positive.
So, the best point estimate for p is 6/46 = 0.1304348.
For a 95% CI for p, I thought binom.test would give me the correct
result, but it seems it is not the right function to use. What is
the R
Johnsons [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Subject: [R] binom.test
Date: Fri, 20 Oct 2006 17:18:02 -0400
A quick question, please.
46 e coli lab samples are tested, 6 of them returned positive.
So, the best point estimate for p is 6/46 = 0.1304348.
For a 95% CI for p, I thought
From: Ethan Johnsons [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Subject: [R] binom.test
Date: Fri, 20 Oct 2006 17:18:02 -0400
A quick question, please.
46 e coli lab samples are tested, 6 of them returned positive.
So, the best point estimate for p is 6/46 = 0.1304348
R-experts:
A quick question, please.
From a lab exp, I got 12 positives out of 50.
To get 90% CI for this , I think binom.test might be the one to be used.
Is there a better way or function to calculate this?
binom.test(x=12, n=50, p=12/50, conf.level = 0.90)
Exact binomial test
Ethan Johnsons wrote:
R-experts:
A quick question, please.
From a lab exp, I got 12 positives out of 50.
To get 90% CI for this , I think binom.test might be the one to be used.
Is there a better way or function to calculate this?
binom.test(x=12, n=50, p=12/50, conf.level = 0.90)
On 19-Oct-06 Ethan Johnsons wrote:
R-experts:
A quick question, please.
From a lab exp, I got 12 positives out of 50.
To get 90% CI for this , I think binom.test might be
the one to be used.
Is there a better way or function to calculate this?
What do you mean by better? For a
Thx much for the feedback.
It is a big help.
ej
On 10/19/06, Ted Harding [EMAIL PROTECTED] wrote:
On 19-Oct-06 Ethan Johnsons wrote:
R-experts:
A quick question, please.
From a lab exp, I got 12 positives out of 50.
To get 90% CI for this , I think binom.test might be
the one to be
)
Cheers,
Francisco
Dr. Francisco J. Zagmutt
College of Veterinary Medicine and Biomedical Sciences
Colorado State University
From: Chuck Cleland [EMAIL PROTECTED]
To: Ethan Johnsons [EMAIL PROTECTED]
CC: r-help@stat.math.ethz.ch
Subject: Re: [R] binom.test
Date: Thu, 19 Oct 2006 11:27:35 -0400
See also the binconf function in the Hmisc package.
Ethan Johnsons wrote:
R-experts:
A quick question, please.
From a lab exp, I got 12 positives out of 50.
To get 90% CI for this , I think binom.test might be the one to be used.
Is there a better way or function to calculate this?
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