On Fri, 24 Feb 2006, Prof Brian Ripley wrote:
It is a bit more efficient to use as.data.frame in your apply.
You could make a copy of as.data.frame.matrix (under another name) and remove
the special-casing of character matrices. This would efficiently give you a
data frame with character
Dear R-Help,
Suppose I have a character matrix, e.g.,
(ch.mat - matrix(c('a','s','*','f','w','*','k','*','*','f','i','o'),
ncol=3))
When I convert 'ch.mat' to a dataframe, the columns are converted to
factors:
(d1 - data.frame(ch.mat))
mode(d1[,1])
is.factor(d1[,1])
To prevent this, I
You could do it directly like this:
structure(split(ch.mat, col(ch.mat)),
row.names = 1:nrow(ch.mat), .Names = 1:ncol(ch.mat),
class = data.frame)
On 2/23/06, John M. Miyamoto [EMAIL PROTECTED] wrote:
Dear R-Help,
Suppose I have a character matrix, e.g.,
(ch.mat -
It is a bit more efficient to use as.data.frame in your apply.
You could make a copy of as.data.frame.matrix (under another name) and
remove the special-casing of character matrices. This would efficiently
give you a data frame with character columns, but they would then not be
treated 'AsIs'
