Dear List,
I have read that a lognormal mixture model having a pdf of the form
f(x)=w1*f1(x)+(1-w1)*f2(x) fits most data sets quite well, where f1
and f2 are lognormal distributions.
Any pointers on how to create a function that would produce the 5
parameters of f(x) would be greatly
On Fri, 7 Sep 2007, Jacques Wagnor wrote:
Dear List,
I have read that a lognormal mixture model having a pdf of the form
f(x)=w1*f1(x)+(1-w1)*f2(x) fits most data sets quite well, where f1
and f2 are lognormal distributions.
Whoa! There have to be a lot of qualifiers on an assertion like
I have exported a CSV file from my EXCEL worksheet and its last column
contained decimal values:
Subject;Group;Side;Difference;PercentError
M3;1;1;;
M5;1;1;375;18,75
M8;1;1;250;14,58
M10;1;1;500;12,50
M12;1;1;375;25,00
.
.
.
When I tried to do ANOVA test on it, R complained by givin error:
Your data file has commas as the decimal point. Use read.csv2 for such
files.
What happened was that PercentError was read as a factor, and you can't do
ANOVA on factors. The warning
In addition: Warning message:
using type=numeric with a factor response will be ignored in:
On 06-Sep-07 06:55:36, Emre Sevinc wrote:
I have exported a CSV file from my EXCEL worksheet and its last column
contained decimal values:
Subject;Group;Side;Difference;PercentError
M3;1;1;;
M5;1;1;375;18,75
M8;1;1;250;14,58
M10;1;1;500;12,50
M12;1;1;375;25,00
.
.
.
When I tried
Bin Sun wrote:
I need to extract t-test statistics from glm(). For example,
Coefficients:
Estimate Std. Error t value Pr(|t|)
(Intercept) 46.219911.6310 3.974 0.000106 ***
Var1 1.0440 0.5948 1.755 0.081088 .
Var2 -0.4717
Hi,
How can I extract part of an array? I would like to extract table
Supported from this array. If this is not possible, how do I convert
array to list? I'm sorry this is not an reproducible example.
spl - tapply(temp$var1, list(temp$var2, temp$var3, temp$var3), mean)
spl
, , Supported
Lauri Nikkinen wrote:
Hi,
How can I extract part of an array? I would like to extract table
Supported from this array. If this is not possible, how do I convert
array to list? I'm sorry this is not an reproducible example.
spl - tapply(temp$var1, list(temp$var2, temp$var3, temp$var3),
] On Behalf Of Sid Kouider
Sent: Friday, August 31, 2007 3:19 PM
To: r-help@stat.math.ethz.ch
Subject: Re: [R] How to obtain intercept statistics in anova
withwithin-subject factors?
Dear Greg,
Thanks very much for you advice.
Unfortunately, although summary.lm applied on aov objects
indeed
Hello R Users,
How to make a variable equidistance with time i.e. how to interpolate a
variable if it is not sampled at equal time interval.
Many thanks,
Regards,
Yogesh
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch
Use approx() if you just want linear interpolation.
On 9/4/07, Yogesh Tiwari [EMAIL PROTECTED] wrote:
Hello R Users,
How to make a variable equidistance with time i.e. how to interpolate a
variable if it is not sampled at equal time interval.
Many thanks,
Regards,
Yogesh
Yogesh Tiwari wrote:
Hello R Users,
How to make a variable equidistance with time i.e. how to interpolate a
variable if it is not sampled at equal time interval.
Hi Yogesh,
Don't know whether this will suit your purpose. I wrote it to enable
color-coded plotting of highly variable data. If
Keep in touch and keep mailing :-)
slow or fast, little or too much
Yogesh Tiwari [EMAIL PROTECTED]
Sent by: [EMAIL PROTECTED]
09/04/2007 04:04 PM
To
r-help@stat.math.ethz.ch
cc
Subject
[R] how to do interpolation
Hello R Users,
How to make a variable equidistance with time i.e
I need to extract t-test statistics from glm(). For example,
Coefficients:
Estimate Std. Error t value Pr(|t|)
(Intercept) 46.219911.6310 3.974 0.000106 ***
Var1 1.0440 0.5948 1.755 0.081088 .
Var2 -0.4717 2.0257 -0.233 0.816178
Hello 'R' Users,
I have a monthly mean CO2 necdf data file defined on 1x1 lat by lon
coordinate. I want to sub-sample this variable CO2 on the coordinates
of another ASCII data file. The coordinates of another ASCII data file are
as:
-24.01 152.06 -18.58 150.19 -13.46 148.35 -8.29 147.03
Dear Yogesh,
This question seems more appropriate for the r-sig-geo mailing list
(https://stat.ethz.ch/mailman/listinfo/r-sig-geo).
The sampling of the netcdf files can be done by using the overlay
function from the sp-package (available on CRAN). You would have to read
both the netcdf file
Hello R Users,
How to compute cross correlation between two time series. Data is in ASCII
format. I am using R on windows.
Many thanks,
Regards,
Yogesh
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
The simlest answer is that X and Y are two vectors of
length n then (un-normalized) cross correlation
between X and Y is sum(i=1 to n)
{X(i)-Xbar)*(Y(i)-Ybar)} where Xbar and Ybar are the
means of X and Y respectively.
You may need something different, so could you be more
specific? What do you
Julian Burgos wrote:
mode()... of course!
Wrong. See ?mode
Get or set the type or storage mode of an object.
Thomas P.
Raymond Balise wrote:
What is the name of the function to give me the mode (central tendancy) of a
numeric variable that can be negative?
[[alternative HTML version
Dear Greg,
Thanks very much for you advice.
Unfortunately, although summary.lm applied on aov objects indeed shows the
intercept's statistics, this function does not (seem to) work with
within-participant designs. As soon as I enter the info on the error term
(see the example in my first
I am using a for loop to read a table row by row and I have to specify how
many records are there in the table. I need to read row by row because the
table is huge and the memory not large enough for the whole table.:
number.of.records=100
fp=file(abc.csv,r)
pos=seek(fp, rw=read)
for (i in
What about trying to use a database system and make queries?
If you are at the end of a file, you will read elements of length 0...
Uwe Ligges
Yuchen Luo wrote:
I am using a for loop to read a table row by row and I have to specify how
many records are there in the table. I need to read row
Hello,
I want to calculate the weighted means of a table column, aggregated
by other elements of the same table.
For example I want to calculate mean species numbers weighted by area
and grouped by year, altitude and/or region.
I think a combination of aggregate() and weighted.mean() should work,
: woensdag 29 augustus 2007 19:41
Aan: r-help@stat.math.ethz.ch
Onderwerp: [R] How to signal the end of the table?
I am using a for loop to read a table row by row and I have
to specify how many records are there in the table. I need to
read row by row because the table is huge and the memory
--
View this message in context:
http://www.nabble.com/How-to-mask-or-escape-%22%3D%22-tf4354174.html#a12406926
Sent from the R help mailing list archive at Nabble.com.
__
R-help@stat.math.ethz.ch mailing list
I have defined a function with several arguments and have it stored in the
.RData file.
The 'function head' is defined as follows
EstimALIConc
-function(sdname,SZ,W,farea,watri,biomodel,start.part=1,nparts=20,method=c(optim,DEoptim))
{
[ blah-blah-blah ]
(function body doesn't matter)
}
your data.frame afterwards.
I work on a Windows machine with 4 Gb DRAM - just for comparison.
I hope this helps,
Monica
Message: 88Date: Wed, 29 Aug 2007 10:41:05 -0700From: Yuchen Luo [EMAIL
PROTECTED]Subject: [R] How to signal the end of the table?To:
r-help
For example,
fp-file(abc.csv,r)
c.row-scan(file=fp,sep=,,nlines=1) # what argument is omitted for
bevity as it doesn't matter
rows-c.row
while(length(c.row)0) {
c.row-scan(file=fp,sep=;,nlines=1);
rows-rbind(rows,c.row)
}
close(fp)
If you want to read a file by parts, then you do
Dear R users,
I am looking for an easy (i.e., direct) way of obtaining the F and p values
from the intercept in anovas with within-subject designs.
My data are from a psychophysics experiment where I am using d' (d-prime)
values obtained from 3 modalities of presentation in each subject. I would
What is the name of the function to give me the mode (central tendancy) of a
numeric variable that can be negative?
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Raymond Balise wrote:
What is the name of the function to give me the mode (central tendancy) of a
numeric variable that can be negative?
Similar questions appear occasionally on this list. Please see the
following help page for possible solutions:
mode()... of course!
Raymond Balise wrote:
What is the name of the function to give me the mode (central tendancy) of a
numeric variable that can be negative?
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
Dear collegues.
I am using scan( ) to read from a table (a csv file).
I am wondering how to let the program know that the end of the file is
reached?
Your help will be highly appreciated!
Best Wishes
Yuchen Luo
[[alternative HTML version deleted]]
Hi Yuchen,
I'm not sure my message will help you but who knows (I'm a newbie : I
discovered R one month ago).
To load data file, I use
donnees-read.table(datafile.dat, quote=\, sep=;, dec=,, skip=18)
and I don't need to tell when to stop. R knows it.
Good luck,
Ptit Bleu.
Yuchen Luo wrote:
Dear All,
How to cite the PDF user's guide for the LIMMA package?
This is not about how to cite the LIMMA package.
Roger
Roger L. Vallejo, Ph.D.
Computational Biologist Geneticist
U.S. Department of Agriculture, ARS
National Center for Cool Cold Water Aquaculture
11861 Leetown Road
, Roger; r-help@stat.math.ethz.ch
Subject: Re: [R] How to cite the the PDF user's guide for LIMMA
This depends on what style manual you , your
publisher, or your institution uses. One common syle
(APA ) recommends this:
http://library.osu.edu/sites/guides/apagd.php#sid
--- Vallejo, Roger
This depends on what style manual you , your
publisher, or your institution uses. One common syle
(APA ) recommends this:
http://library.osu.edu/sites/guides/apagd.php#sid
--- Vallejo, Roger [EMAIL PROTECTED]
wrote:
Dear All,
How to cite the PDF user's guide for the LIMMA
package?
This
Hello,
I have two data frames, X and Y, with two columns each and different numbers
of rows.
# creation of data frame X
Loc1.alleles - c(1,5,6,7,8)
Loc1.Freq- c(0.35, 0.15, 0.05, 0.10, 0.35)
Loc1 - cbind( Loc1.alleles,Loc1.Freq)
X- data.frame(Loc1)
#creation
matrix(Y[,2]%o%X[,2],ncol=1)
On Wednesday 29 August 2007 03:21 pm, Luke Neraas wrote:
Hello,
I have two data frames, X and Y, with two columns each and different numbers
of rows.
# creation of data frame X
Loc1.alleles - c(1,5,6,7,8)
Loc1.Freq- c(0.35, 0.15, 0.05,
Below is one way to do this:
Loc1.alleles - c(1,5,6,7,8)
Loc1.Freq- c(0.35, 0.15, 0.05, 0.10, 0.35)
Loc1 - cbind( Loc1.alleles,Loc1.Freq)
X- data.frame(Loc1)
Loc2.alleles - c(1,4,6,8)
Loc2.Freq - c(0.35, 0.35, 0.10, 0.20)
Loc2 -
Hi, I am writing a BRugs code and I need to specify the likelihood for the
gamma distribution and I am specifying it as the pdf:
(pow(b1,a1)/(exp(loggam(a1)))*(exp(-b1*lambda[i]))*pow(lambda[i],(a1-1)))
But it is not accepting it although I know that I could use the pdf in R to
estimate the
Dear Listers:
I have this task and suppose a0 is a list of 10 data.frames, I want to
calculate like this
(a0[[1]]+a0[[2]]+..+a[[10]])/10
Thanks.
--
Weiwei Shi, Ph.D
Research Scientist
GeneGO, Inc.
Did you always know?
No, I did not. But I believed...
---Matrix III
try:
colMeans(do.call('rbind', lapply(a0, mean)))
On 8/28/07, Weiwei Shi [EMAIL PROTECTED] wrote:
Dear Listers:
I have this task and suppose a0 is a list of 10 data.frames, I want to
calculate like this
(a0[[1]]+a0[[2]]+..+a[[10]])/10
Thanks.
--
Weiwei Shi, Ph.D
Research Scientist
Hi again,
This is the follow of my post Problem with save or/and if (I think but
maybe not ...).
In this post, I wrote that I solved my main problem. And it is true.
I also wrote that there was still another problem, which I managed to solve.
But I think there must be another way to solve it
Since no reply has been posted yet I will give it a shot. runs.test uses the
normal approximation and in your case it returned a z score of -1.8732. This
z score has a cumulative probability of
pnorm(-1.8732,0,1)
[1] 0.03052039
If you are concerned about having too many runs and too few
Donatas G. wrote:
On Tuesday 07 August 2007 22:09:52 Donatas G. wrote:
How do I include bar values in a barplot (or other R graphics, where this
could be applicable)?
To make sure I am clear I am attaching a barplot created with
OpenOffice.org which has barplot values written on top of each
Thanks everyone. I actually thought about ?Rscript.exe but, having used
only Rgui, I thought it was a instruction specific to this interface. I
will look into it.
Sebastien
Gabor Grothendieck a écrit :
There are also some batch files that can be used with Rscript on XP and info
in the README
Thanks for your reply.
When you say look into Rscript.exe, do you have a specific document in
mind ? I tried to google it but could not find much... I forgot to
mention in my first email that I am working under the Windows XP
environment.
Prof Brian Ripley a écrit :
Look into Rscript.exe (on
On 26/08/2007 7:14 AM, Sébastien wrote:
Thanks for your reply.
When you say look into Rscript.exe, do you have a specific document in
mind ? I tried to google it but could not find much... I forgot to
mention in my first email that I am working under the Windows XP
environment.
You could
There are also some batch files that can be used with Rscript on XP and info
in the README here:
http://batchfiles.googlecode.com
On 8/26/07, Sébastien [EMAIL PROTECTED] wrote:
Thanks for your reply.
When you say look into Rscript.exe, do you have a specific document in
mind ? I tried to
On Sun, 26 Aug 2007, Duncan Murdoch wrote:
On 26/08/2007 7:14 AM, Sébastien wrote:
Thanks for your reply.
When you say look into Rscript.exe, do you have a specific document in
mind ? I tried to google it but could not find much... I forgot to mention
in my first email that I am working
Hi,
I am still struggling with the data structures in R. I
know how it works in C++ but how can I get such a
structure in R?
Here is what I want:
x[a]$dataframe1
x[a]$dataframe2
x[a]$dataframe3
x[b]$dataframe1
x[b]$dataframe2
x[b]$dataframe3
x[c]$dataframe1
x[c]$dataframe2
x[c]$dataframe3
And
Is this what you want:
DF1 - DF2 - DF3 - df1 - df2 - df3 - head(iris)
list(a = list(DF1, DF2, DF3), b = list(df1, df2, df3))
or
x - list()
x$a - list(DF1, DF2, DF3)
x$b - list(df1, df2, df3)
On 8/26/07, Werner Wernersen [EMAIL PROTECTED] wrote:
Hi,
I am still struggling with the data
That gives you a list of data frames. An array is a vector with a dim
attribute to to make it into an array add the appropriate dim attirbute.
If x is the list we created before then:
dim(x) - 2
gives us an array of length 2 each of which has a list of 3 elements
or
dim(x) - 1:2
gives a 1x2
Installation Configuration: Windows XP version 5.1 with Service Pack 2, Rtools
(bin, MnGW, perl), and HTML HelpWorkshop, and R-2.5.1.
Files Located: Scrips build, check and install are in C:\Program
Files\R\R-2.5.1\bin.
Path Verified: Windows path begins with c:\Rtools\bin;
On 26/08/2007 3:55 PM, [EMAIL PROTECTED] wrote:
Installation Configuration: Windows XP version 5.1 with Service Pack 2,
Rtools (bin, MnGW, perl), and HTML HelpWorkshop, and R-2.5.1.
Files Located: Scrips build, check and install are in C:\Program
Files\R\R-2.5.1\bin.
Path Verified:
Dear Rusers,
When i start R, there always the following work to do first, how should i
cancel it?
*--- Please select a CRAN mirror for use in this session ---*
I don't know why it does so, maybe i have done something unintentionally.
Thanks.
--
With Kind Regards,
oooO:
On Sat, 25 Aug 2007, zhijie zhang wrote:
Dear Rusers,
When i start R, there always the following work to do first, how should i
cancel it?
*--- Please select a CRAN mirror for use in this session ---*
I don't know why it does so, maybe i have done something unintentionally.
You certainly
Dear R-users,
I have written a small application (in visual basic) that automatically
generate some R scripts. I would like to execute these scripts when my
application is being closed.
My problem is that I don't know how to pass the
'source(c:/.../myscript.r)' instruction when I
Look into Rscript.exe (on Windows), which is a flexible way to run
scripts. Neither using a GUI nor using source() are recommended.
On Fri, 24 Aug 2007, Sébastien wrote:
Dear R-users,
I have written a small application (in visual basic) that automatically
generate some R scripts. I would
nice presentation coming out in no time, R is the best!
Delfina
Date: Fri, 24 Aug 2007 20:26:53 +1000
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
CC: r-help@stat.math.ethz.ch
Subject: Re: [R] How to shade vertical bands in a graph?
del pes wrote
Hello wizards,
First of all, I'm a physicist and therefore I'm not much used to use
statistics. So, please forgive me if this is a FAQ or stupid, but I
failed to find the answer by myself.
I have used runs.test (Package tseries) for computes the runs test
for randomness , but I get this result:
Hello,
I would like to draw vertical yellow bands in my graph, but could not find how
to do that in the documentation.
I set up a page to show what I would like to achieve:
http://rstudent.blogg.de/eintrag.php?id=1 (the first picture was manually
colored with the Gimp).
Any help would be
This seems to work:
tmp - aggregate(DF$y, list(DF$x, DF$f), mean)
tmp2 - aggregate(DF$conc, list(DF$x, DF$f), paste,collapse=, )
names(tmp2)[3] - var1
final - merge(tmp,tmp2)
--- Lauri Nikkinen [EMAIL PROTECTED] wrote:
#Hi R-users,
#I have an example DF like this:
y1 - rnorm(10) + 6.8
del pes wrote:
Hello,
I would like to draw vertical yellow bands in my graph, but could not find
how to do that in the documentation.
I set up a page to show what I would like to achieve:
http://rstudent.blogg.de/eintrag.php?id=1 (the first picture was manually
colored with the Gimp).
?rect
Something like this should work but I did not take the
time to get the rectangles to fit properly.
aa - rnorm(25)
yl - -1.5
yh - 2.2
xleft - c(4, 9, 15 ,20)
xright - xleft + 3
plot(aa, ylim= c(yl,yh), type=n)
rect(xleft, yl, xright,yh, col=yellow)
points(aa, col=red)
--- del pes [EMAIL
There is an example using classic graphics here:
http://www.mayin.org/ajayshah/KB/R/html/g5.html
and one using lattice graphics here:
library(zoo)
?xyplot.zoo
On 8/23/07, del pes [EMAIL PROTECTED] wrote:
Hello,
I would like to draw vertical yellow bands in my graph, but could not
Please could anyone help me?
How can I fit a linear model where an intercept has no sense?
Thanks in advance..
Michael
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
At 10:56 23/08/2007, Michal Kneifl wrote:
Please could anyone help me?
How can I fit a linear model where an intercept has no sense?
Well the line has to have an intercept somewhere I suppose.
If you use the site search facility and look for known intercept
you will get some clues.
Thanks in
A number of alternatives, such as:
lm(y ~ 0 + x)
lm(y ~ x -1)
See ?formula
On 8/23/07, Michal Kneifl [EMAIL PROTECTED] wrote:
Please could anyone help me?
How can I fit a linear model where an intercept has no sense?
Thanks in advance..
Michael
?lm
Details
A formula has an implied intercept term. To remove
this use either y ~ x - 1 or y ~ 0 + x. See formula
for more details of allowed formulae.
Is this what you want?
--- Michal Kneifl [EMAIL PROTECTED] wrote:
Please could anyone help me?
How can I fit a linear model where
On 23-Aug-07 09:56:33, Michal Kneifl wrote:
Please could anyone help me?
How can I fit a linear model where an intercept has no sense?
Thanks in advance..
Michael
Presumably you mean where a non-zero intercept has no sense?
Suppose the model you want to fit is like
Response ~ B+C+X+Y
Michael,
Assuming you want a model with an intercept of zero, I think we need to ask you
why you want an intercept of zero. When a normal regression indicates a
non-zero intercet, forcing the regression line to have a zero intercept changes
the meaning of the regression coefficients. If for
#Hi R-users,
#I have an example DF like this:
y1 - rnorm(10) + 6.8
y2 - rnorm(10) + (1:10*1.7 + 1)
y3 - rnorm(10) + (1:10*6.7 + 3.7)
y - c(y1,y2,y3)
x - rep(1:3,10)
f - gl(2,15, labels=paste(lev, 1:2, sep=))
g - seq(as.Date(2000/1/1), by=day, length=30)
DF - data.frame(x=x,y=y, f=f, g=g)
DF$wdays
Good Mornig All,
How R you today? ;o)
I have lots of questions, but i l start with the simplest one,
to wich i am shy to say, i did not find the answer.
It is the following:
When i make a summary plot like for example plot( summary(glm)),
i get one window, one main title, and 4 graph's in
?title, look at the 'outer' argument.
You can see further discussion of the outer margins in 'An Introduction to
R'.
I don't know why you are using win.graph(): it is a deprecated form of
windows() with many of the arguments taking unchangable defaults.
On Wed, 22 Aug 2007, Tom Willems wrote:
To Mark Leeds and the others, thank you for solving my problem, and so quickly,
JM
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
my problem can be explained with the following example:
x - 1:12
y - 13:24
a - data.frame(x = x, y = y)
## if i write
a$x
## it returns
[1] 1 2 3 4 5 6 7 8 9 10 11 12
## but the function get doesn't recognize a$x. Instead it produces the
following error:
get(a$x)
Error in get(x, envir,
eval(parse(text=(a$x). You can only use get when it's an object. a$x isn't.
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Juan Manuel
Barreneche
Sent: Tuesday, August 21, 2007 3:35 PM
To: r-help@stat.math.ethz.ch
Subject: [R] how do i use the get
On 8/21/2007 3:35 PM, Juan Manuel Barreneche wrote:
my problem can be explained with the following example:
x - 1:12
y - 13:24
a - data.frame(x = x, y = y)
## if i write
a$x
## it returns
[1] 1 2 3 4 5 6 7 8 9 10 11 12
## but the function get doesn't recognize a$x. Instead
Hi, you can try this:
eval(parse(text=a$x))
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O
On 21/08/07, Juan Manuel Barreneche [EMAIL PROTECTED] wrote:
my problem can be explained with the following example:
x - 1:12
y - 13:24
a - data.frame(x = x, y = y)
##
One simple way that I haven't seen mentioned yet is to do:
get(a)$x
(which of course allows further variants such as get(a)$x[3:6] ...)
-- Tony Plate
Juan Manuel Barreneche wrote:
my problem can be explained with the following example:
x - 1:12
y - 13:24
a - data.frame(x = x, y = y)
I have several data frames, eg:
df1 - data.frame(x=seq(0,10), y=seq(10,20))
df2 - data.frame(a=seq(0,10), b=seq(10,20))
It is common to create loops in R like this:
for(df in list(df1, df2)){ #etc. }
This works fine when you know the name of the objects to put into the
list. I assume that
One way to do it is to pass in the character name of the dataframe you
want to reference and then use 'get' to access the value: e.g.,
df1 - data.frame(x=seq(0,10), y=seq(10,20))
df2 - data.frame(a=seq(0,10), b=seq(10,20))
# use the character names for referencing
for (df in c('df1', 'df2')){
You might want to store the data frames in a list to eliminate this
problem and make it more convenient to iterate over them:
L - list(df1 = df1, df2 = df2)
rm(df1, df2)
# reduce each data frame to its first few rows
for(nm in names(L)) L[[nm]] - head(L[[nm])
or if you don't need to modify
Hi,
I encounter a situation where I have a list whose element is a column matrix.
Says,
$'1'
[,1]
1
2
3
$'2'
[,1]
4
5
6
Is there fast way to collapse the list into a matrix like a cbind operation in
this case? Meaning, the result should be a matrix that looks like:
[,1] [,2]
[1,]
[EMAIL PROTECTED]
I encounter a situation where I have a list whose element is a column
matrix. Says,
$'1'
[,1]
1
2
3
$'2'
[,1]
4
5
6
Is there fast way to collapse the list into a matrix like a cbind
operation in this case? Meaning, the result should be a matrix that
looks like:
Ah, it works. I was using lapply and it doesn't seem to work. Thank you!-
Original Message -From: François Pinard Date: Sunday, August 19, 2007 8:36
pmSubject: Re: [R] how to collapse a list of 1 column matrix to a matrix?To:
[EMAIL PROTECTED]: r-help@stat.math.ethz.ch [EMAIL PROTECTED
Try this:
L - list(`1` = matrix(1:4, 4), `2` = matrix(5:8, 4))
sapply(L, c)
Note that the list component names are kept as column names in the result
On 8/19/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Hi,
I encounter a situation where I have a list whose element is a column matrix.
- Original Message -From: Gabor Grothendieck Date: Sunday, August 19,
2007 8:48 pmSubject: Re: [R] how to collapse a list of 1 column matrix to a
matrix?To: [EMAIL PROTECTED] Cc: r-help@stat.math.ethz.ch Try this: L -
list(`1` = matrix(1:4, 4), `2` = matrix(5:8, 4)) sapply(L, c) Note
-From: Gabor Grothendieck Date: Sunday, August
19, 2007 8:48 pmSubject: Re: [R] how to collapse a list of 1 column matrix
to a matrix?To: [EMAIL PROTECTED] Cc: r-help@stat.math.ethz.ch Try
this: L - list(`1` = matrix(1:4, 4), `2` = matrix(5:8, 4)) sapply(L,
c) Note that the list component
[EMAIL PROTECTED]
One more question. After I collapse everything into one matrix,
I would like to find the index of column that holds minimum value for
each row. I remember that there is a function like maxCols but I can't
seem to find the same thing for minimum value. Any suggestion
Thank you. I found the same answer.
- Original Message -From: Jared O'Connell Date: Sunday, August 19, 2007
9:56 pmSubject: Re: [R] how to collapse a list of 1 column matrix to a
matrix?To: [EMAIL PROTECTED] Cc: r-help@stat.math.ethz.ch x =
matrix(rnorm(9),3) x[,1
I'm trying to create two variables (dka and newsonset) from the
following composite character variable diagnosis:
diagnosis - c(hypoglycemia,diabetes ,newonsetdka, newonset,
diabetes, dkaGI, diabetesGI, newonset, dka)
I can extract the indices for dka and newonset using the following
On Fri, Aug 17, 2007 at 05:32:54PM -0400, Dale Steele wrote:
I'm trying to create two variables (dka and newsonset) from the
following composite character variable diagnosis:
diagnosis - c(hypoglycemia,diabetes ,newonsetdka, newonset,
diabetes, dkaGI, diabetesGI, newonset, dka)
I can
On Fri, 2007-08-17 at 14:40 -0700, Daniel Lakeland wrote:
On Fri, Aug 17, 2007 at 05:32:54PM -0400, Dale Steele wrote:
I'm trying to create two variables (dka and newsonset) from the
following composite character variable diagnosis:
diagnosis - c(hypoglycemia,diabetes ,newonsetdka,
Hi Yuchen,
First of all please notice that you may not have more
than 2^8 = 256 columns in Excel, so if you have more
than 256 time-series you can not put them all in one
Excel sheet. I also believe that you can not have more
than 2^16 = 65536 rows.
If you do not have more than 256 time-series, I
On Sun, Aug 12, 2007 at 10:50:59AM -0700, Yuchen Luo wrote:
Dear Professor Murdoch.
Thank you so much
Best Wishes
Yuchen Luo
On 8/12/07, Duncan Murdoch [EMAIL PROTECTED] wrote:
Yuchen Luo wrote:
Dear Colleagues.
I believe this should be a problem encountered by many:
Assuming that the daily.incomes are the same lengths, then your loop could be:
Lst - list()
for (i in 1:count) Lst[[i]] - list(..)
Lst.col - do.call('cbind', Lst)
On 8/12/07, Yuchen Luo [EMAIL PROTECTED] wrote:
Dear friends.
Every loop of my program will result in a list that is very long,
Dear Colleagues.
I believe this should be a problem encountered by many:
nls( ) is a very useful and efficient function to use if we are just to
display the estimated value on screen. What if we need R to store the
estimated parameter in a variable?
For example:
x=rnorm(10, mean=1000, sd=10)
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