RE: [R] nls, nlrq, and box-cox transformation

2003-11-21 Thread Philippe Grosjean
You suggest the solution yourself: transform the equation to have all parameters at the right, thus: y ~ ((b0 + b1 * x) * t + 1) ^ 1/t Bit this is still not correct, since the transformation changes the scale of the variance, and lesat squares will not be correct. There is needed a factor

RE: [R] nls, nlrq, and box-cox transformation

2003-11-20 Thread Philippe Grosjean
Dear r-help members I posted this message already yesterday, but don't know whether it reached you since I joined the group only yesterday. I would like to estimate the boxcox transformed model (y^t - 1)/t ~ b0 + b1 * x. Unfortunately, R returns with an error message when I try to perform this

RE: [R] nls, nlrq, and box-cox transformation

2003-11-20 Thread Prof Brian Ripley
On Thu, 20 Nov 2003, Philippe Grosjean wrote: Dear r-help members I posted this message already yesterday, but don't know whether it reached you since I joined the group only yesterday. I would like to estimate the boxcox transformed model (y^t - 1)/t ~ b0 + b1 * x. Unfortunately, R

RE: [R] nls, nlrq, and box-cox transformation

2003-11-20 Thread Roger Koenker
On Thu, 20 Nov 2003, Prof Brian Ripley wrote: Now nlrq uses a different criterion and Philippe's suggestion may work there. I can't tell quickly: the help page does not say what the criterion is. But if those are the same, then I suspect the criterion is uninteresting as a way to

RE: [R] nls, nlrq, and box-cox transformation

2003-11-20 Thread kjetil
On 20 Nov 2003 at 15:24, Philippe Grosjean wrote: Dear r-help members I posted this message already yesterday, but don't know whether it reached you since I joined the group only yesterday. I would like to estimate the boxcox transformed model (y^t - 1)/t ~ b0 + b1 * x. Unfortunately, R