On Fri, 7 Oct 2005, Prof Brian Ripley wrote:
On Fri, 7 Oct 2005, Paul Roebuck wrote:
I have a data file from which I need to read portions of
data but data location/quantity can change from file to file.
I wrote some code and have a working solution but it seems
wasteful to have to do
Hi ,
I have a vector,for example,
x=rnorm(100)
Then i rendom choose 20 of them.
chosen=sample(x,20).
And i want to get the remain values in x.
Is there a quick way to go?
Thanks in advance.
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Xiao Shi wrote:
Hi ,
I have a vector,for example,
x=rnorm(100)
Then i rendom choose 20 of them.
chosen=sample(x,20).
And i want to get the remain values in x.
Is there a quick way to go?
Thanks in advance.
[[alternative HTML version deleted]]
How about:
x - rnorm(100)
y -
one way is to use:
x[!x %in% chosen]
I hope it helps.
Best,
Dimitris
- Original Message -
From: Xiao Shi [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Sent: Sunday, October 09, 2005 11:26 AM
Subject: [R] How to get the remaining vector after sampling a subset?
Hi ,
I have a
On Sat, 8 Oct 2005, Erin Hodgess wrote:
Dear R People:
I have a question about the lm.ridge function, please.
In the example, there is one set of output values in the select
function but another in the comment section.
Am I missing something please?
The values in the examples were
Hi Everybody,
I am a total beginner at this so please bear with me.
I downloaded by hand the file WIG20.txt (Warsaw Stock Exchange Index of 20
most important stocks). The format is this:
Name,Date,Open,High,Low,Close,Volume
WIG20,19940414,1000.00,1000.00,1000.00,1000.00,71600.000
Dear All,
I am wondering if there is a way to change the color of the panels of the
xyplot (lattice package) from gray to white .. Because the printing
of the xyplot's graph is not visible with the gray color ... I've seen the
xyplot help but without any success
Thanks
see ?trellis.device
trellis.device(color=F)
Depth - equal.count(quakes$depth, number=8, overlap=.1)
xyplot(lat ~ long | Depth, data = quakes)
will get what you want.
=== 2005-10-09 22:32:10 您在来信中写道：===
Dear All,
I am wondering if there is a way to change the
Le 8 Octobre 2005 05:35, [EMAIL PROTECTED] a écrit :
Sam R. Smith a écrit :
Hi,
I have the following code to randomly generate the points:
csr -function(n=60){
x=runif(n)
y=runif(n)
f=cbind(x,y)
}
plot(csr())
I wonder how to code to make the first twenty points to be BLUE;
Does the following help:
n.subjects - 3
J - 4
K - 5
n.ijk - rep(2, each=n.subjects*J*K)
x - rep(1:K, n.subjects, each=J)
subj - factor(rep(1:n.subjects, each=K*J))
sa.subject - 1
sb.subject - 1
set.seed(2)
a.subj - rep(sa.subject*rnorm(n.subjects), each=K*J)
b.subj -
I know I've done this before, but it's been a while and I can't find quite
what I need in the help files or archives.
I have a text field in a very large data frame. I'd like to add a column
that represents the value from an existing field, from the next record (the
data are sorted). I'm trying
Hi dears,
I expect that Mr Thomas Lumley will read this message.
I have data from a complexe stratified survey. The population is divide in 12
regions and a region consist to and urban area and rural one. there to region
just with urbain area.
stratification variable is a combinaison of
I will attempt a brief comment on this post, as I've seen no replies.
It's difficult to comment on this, as you do not really provide enough
information to permit someone like me to understand your problem. Only
one portion of this problem is the fact that I can't find your
On Fri, 7 Oct 2005, Peter Muhlberger wrote:
The max function won't do the trick because I need the entire matrix. I
could do one cell at a time, but this is part of a ML routine that needs to
be evaluated hundreds of thousands of times, so I can't afford to slow it
down that much.
pmax,
When I run the acf() function using the acf(ts.union(mdeaths,
fdeaths)) example, the acf() function calls the acf.plot()
function to generate this plot...
http://members.cox.net/ddebarr/images/acf_example.png
The plot in the lower right-hand corner is labeled fdeaths mdeaths,
but the negative
Hi R-users,
In a plot, can I specify pch to be a greek symbol? (I looked at
show.pch() in the Hmisc package but couldn't see the right symbols in there).
If not, I guess I can get around this using text(x,y,expression()).
cheers!,
Matt.
Dr Matt Fischer
Postdoctoral Fellow - IPILPS
ANSTO
Hi everyone.
The function image() seems not to be correctly plotting some
matrices that I give it. (I’m using R 2.1.1)
The following code creates a matrix (denoted x) with 1500
rows and 3 columns, with all entries 0 or 1, and then plots
the image of this matrix.
On Mon, 2005-10-10 at 12:02 +1000, FISCHER, Matthew wrote:
Hi R-users,
In a plot, can I specify pch to be a greek symbol? (I looked at
show.pch() in the Hmisc package but couldn't see the right symbols in there).
If not, I guess I can get around this using text(x,y,expression()).
After I made a new plot, the old plot can not be found. How can I check all the
plots I have made?
-
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__
R-help@stat.math.ethz.ch mailing list
Select History Recording.
You can see previous plots using 'page up'.
Murray
-Original Message-
From: Sam R. Smith [mailto:[EMAIL PROTECTED]
Sent: Monday, 10 October 2005 1:27 PM
To: r-help@stat.math.ethz.ch
Subject: [R] plot
After I made a new plot, the old plot can not be found.
Dear all,
I successfully set up a local MySQL-database. Connecting via RODBC is
not problem, the same in fetching 3 of 4 tables. But trying to
connect to table 4 fails.
author-sqlFetch(test,author)
Error in fromchar(unclass(x)) : character string is not in a standard
unambiguous format
In
There are four points with coordinates:
2,3;4,9;1,6;3,10.
How to use Python to draw one perpendicular bisector between (2,3) and (4,9);
the other perpendicular bisector between (1,6)ºÍ(3,10);
then, makes the output like:
l1 a b c
l2 a b c
(Note: l indicates the perpendicular bisector with equation
Sorry for the typo, ask for R code.
Sam R. Smith [EMAIL PROTECTED] wrote:There are four points with coordinates:
2,3;4,9;1,6;3,10.
How to use Python to draw one perpendicular bisector between (2,3) and (4,9);
the other perpendicular bisector between (1,6)ºÍ(3,10);
then, makes the output like:
l1
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