Gabor Grothendieck [EMAIL PROTECTED] writes:
Numbers, not in characters strings do not come out bold:
plot(1:5, type = n)
text(x=3,y=3, quote(bold(paste(a==a ~~ 0.5 == 0.5
(what's the paste() for?)
...and it is a design choice of course. Notice that operators are not
boldfaced either,
Frank Funderburk a écrit :
Singer Willett (2003) also cover this ground.
Singer, JD Willett, JB (2003). Applied longitudinal data analysis:
Modeling change and event occurrence. New Yok: Oxford University
Press.
-Original Message- From: Frank E Harrell Jr
[EMAIL PROTECTED]
Hey everyone,
I have made a package and wish to release it but
before then I have a problem. I have a few functions
in this package written in R that I wish to hide such
that after installation, someone can use say the
function foo(parameters = ) but cannot do foo.
Typing foo should not show the
What you ask is impossible. For a function to be callable it has to be
locatable and hence can be printed.
One possibility is to have a namespace, and something like
foo - function(...) foo_internal(...)
where foo is exported but foo_internal is not. Then foo_internal is
hidden from casual
On 30 Jul 2005 09:16:26 +0200, Peter Dalgaard [EMAIL PROTECTED] wrote:
Gabor Grothendieck [EMAIL PROTECTED] writes:
Numbers, not in characters strings do not come out bold:
plot(1:5, type = n)
text(x=3,y=3, quote(bold(paste(a==a ~~ 0.5 == 0.5
(what's the paste() for?)
I had a
You could set the source attribute like this:
R f - function(x) x+1
R # displays the word hidden instead of showing the source
R attr(f, source) - hidden
R f
hidden
R f(10) # still works as a function properly
[1] 11
Of course, someone knowledgable could change the source
attribute back but
I have a string '982323.1' and would like to replace everything after the
'.' with a '41'. So the string should look like '982323.41'. The code I
use to do this is
sub('\.$','41',982323.1)
This works fine as long as there is only 1 digit after the decimal. If I
have '982323.10', then the
Dhiren DSouza wrote:
I have a string '982323.1' and would like to replace everything after the
'.' with a '41'. So the string should look like '982323.41'. The code I
use to do this is
sub('\.$','41',982323.1)
You have to escape \, see ?regexp:
sub('\\.[[:digit:]]*$','\\.41',
Hi all,
I'm having a problem with the auto.key function in xyplot. I hate to bother the
list like this and I'm positive I must be missing something very simple, yet
I've spent the last day searching for a solution to no avail.
Essentially, I want a key that contains entries in which the plot
Quick correction:
The lines lines = T, type = b in the par.settings section should not
be there. They are remnants of my previous (failed) attempts at solving the
problem. Below is the correct code:
xyplot(
#basic settings
bias ~ sample_size | measure,
data = bias,
I am fairly new to R and I am writing a script that would take a file, as an
input, and generates a bunch of graphs out of it. My first task is to be
sure that the file is of the right type by looking if there is a valid
barcode in it as in (the barcode is beetween a double and single
underscore):
Another way to do it is:
sub([.].*, .41, x)
This says to replace the first dot and everything after by .41. When . appears
in a character class, i.e. [.], then you don't need backslashes. Also
you don't need backslashes in the second argument.
On 7/30/05, Uwe Ligges [EMAIL PROTECTED]
Thank you both :)
-Dhiren
From: Gabor Grothendieck [EMAIL PROTECTED]
Reply-To: Gabor Grothendieck [EMAIL PROTECTED]
To: Uwe Ligges [EMAIL PROTECTED]
CC: Dhiren DSouza [EMAIL PROTECTED], r-help@stat.math.ethz.ch
Subject: Re: [R] Wild card characters
Date: Sat, 30 Jul 2005 16:31:37 -0400
Another
On 7/30/05, Marco Blanchette [EMAIL PROTECTED] wrote:
I am fairly new to R and I am writing a script that would take a file, as an
input, and generates a bunch of graphs out of it. My first task is to be
sure that the file is of the right type by looking if there is a valid
barcode in it as in
You can use 'stop' instead of 'cat' -- in which case you
don't need the newline at the end of the string.
But I suspect you would be better off writing a function
rather than a script. S Poetry is one of many sources on
writing functions.
Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
Hello,
I use lme4 package.
library(lme4)
fit=lmer(y ~ time+dye+trt+trt:time + (1|rep), data=dataset, na.action='na.omit')
anova(fit)
The anova gives sequential F-tests and sequential SS.
My question is: how I can get partial F-tests and partial SS?
For lm (not lmer)
anova(lm(y~x+z))
we can
I just got 11 hits with RSiteSearch(minimum chi-square); none of
them seemed relevant.
If you still have time and interest for this, why don't you tell us
about the problem you are trying to solve and why you think minimum
chi-square is appropriate? You should be able to
Unfortunately, I don't know how to get any more information from nls.
My approach to this kind of problem is to write my own function to
compute the sum of squares and then use optim(..., hessian=TRUE).
This is less likely to choke, because optim will continue with a
singular
I know nothing about recresid, but does the following help:
x - 1:4
set.seed(1)
DF - data.frame(x=x, y=x+rnorm(4))
fit - lm(y~offset(x), DF)
recresid(fit)
[1] 1.2799320 0.7232336 3.4826581
spencer graves
Rick Ram wrote:
Hi all,
Just to clarify, I know that the
I just got 23 hits from 'RSiteSearch(errbar)'. The second was a
help file for errbar in sfsmisc, noting there was a similar function
in Hmisc.
PLEASE do read the posting guide!
http://www.R-project.org/posting-guide.html;. In particular, please
provide a self-contained,
On 7/30/05, Mike Lawrence [EMAIL PROTECTED] wrote:
Quick correction:
The lines lines = T, type = b in the par.settings section should
not
be there. They are remnants of my previous (failed) attempts at solving the
problem. Below is the correct code:
xyplot(
#basic settings
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