Aimin Yan wrote:
I want to integrate R code to my WinEdt file.
Can someone tell me how to do this?
I copy R code to my WinEdt file, but it does't work.
I do not understand your question.
Are you trying to install the RWinEdt package, which acts as a plug in
for WinEdt to support writing R
Hm, have you installed it correctly?
latex usually returns error messages.
On windows latex is quite difficult to handle. I guess you have to
include a link to your sweave file:
\usepackage{C:/Programme/R-2.3.1/share/texmf/Sweave}
and also provide the package there.
furthermore take care, that
Hi,
I want to model different timeseries with ARMAX models in R because I think
that ARMAX models will map best to these data.
Besides I don't want to use the order of the AR or MA part but the lag e.g.
AR Part =ar1, ar2, ar7; MA Part =ma1, ma3 and I want to use exogenous
variables as well.
I
I wish to use R CMD BATCH to run a small R function which reads a text
file and plots a single graph to a PDF file.
version
_
platform x86_64-unknown-linux-gnu
arch x86_64
os linux-gnu
You can do this in arima() using arguments 'fixed' and 'xreg'.
On Thu, 23 Nov 2006, Katharina Vedovelli wrote:
Hi,
I want to model different timeseries with ARMAX models in R because I think
that ARMAX models will map best to these data.
Besides I don't want to use the order of the AR or MA
Hello,
Thanks for that. I've taken a look at the source code, and I see that
the bulk of the processing is done in C, with R acting as a wrapper.
Below is the function I think is doing the training in the network.
I'm guessing it's the standard Backpropagation with a decay term
algorithm?
Hi,
2006/11/22, James J. Roper [EMAIL PROTECTED]:
I often use dates and times in analyses. I just can't figure out how to
format my date or time column in R. So, apparently R sees the date as
something other than date (character). Let's say I am opening a CSV
file, one of the columns of
On Thu, 2006-11-23 at 09:39 +, Wee-Jin Goh wrote:
Hello,
Thanks for that. I've taken a look at the source code, and I see that
the bulk of the processing is done in C, with R acting as a wrapper.
Below is the function I think is doing the training in the network.
I'm guessing it's
Hello:
I recall something like this being discuss recently, but I can't seem
to locate an example in the archives. I have data like the following:
df - expand.grid(1:4, 1992:2002)
names(df) - c(MSA, YEAR)
df$IDUPREV - runif(44)
df$VALIDAT - rnorm(44)
I want to create an xyplot() with
Dear lister,
I would like to now if there a universal way to writing a character
vector to a file in UTF-8 encoding? By universal, I mean a way
which works under Linux, Windows and Mac.
Thanks in advance!
--
Ronggui Huang
Department of Sociology
Fudan University, Shanghai, China
Hello,
A brief question that I am not able to resolve by my own, but I presume
it's easy for you:
I've used apply to find the values closer to 0 in each row of a matrix:
closer.to.0 - apply(abs(myarray),MARGIN=1,min)
My question is how could I use which (or another way) to obtain a vector
that
Just wondering if it is possible to put something like
The excess level is M
in the xlab position of a plot but where the M is in italic font and
the rest in ordinary (or Roman) font.
Thanks - Phil Boland
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R-help@stat.math.ethz.ch mailing list
Hello,
Have a look at the function iconv, which converts a character vector
from one encoding to another.
If you're not interested in converting from one encoding to another,
and just want any character vector to be encoded as UTF-8, open the
file in the following way, passing
javier garcia-pintado [EMAIL PROTECTED] writes:
Hello,
A brief question that I am not able to resolve by my own, but I presume
it's easy for you:
I've used apply to find the values closer to 0 in each row of a matrix:
closer.to.0 - apply(abs(myarray),MARGIN=1,min)
My question is how
Something like:
xlab=expression(paste(The excess level is,italic( M)))
in your plot command should do the trick. See ?plotmath.
On 23/11/06, Philip Boland [EMAIL PROTECTED] wrote:
Just wondering if it is possible to put something like
The excess level is M
in the xlab position of a plot
javier garcia-pintado wrote:
Hello,
A brief question that I am not able to resolve by my own, but I presume
it's easy for you:
I've used apply to find the values closer to 0 in each row of a matrix:
closer.to.0 - apply(abs(myarray),MARGIN=1,min)
My question is how could I use which (or
Try this:
xyplot(IDUPREV + VALIDAT~ YEAR | MSA, data = df, type= c(smooth, o))
On 11/23/06, Chuck Cleland [EMAIL PROTECTED] wrote:
Hello:
I recall something like this being discuss recently, but I can't seem
to locate an example in the archives. I have data like the following:
df -
On Thu, 23 Nov 2006, ronggui wrote:
I would like to now if there a universal way to writing a character
vector to a file in UTF-8 encoding? By universal, I mean a way
which works under Linux, Windows and Mac.
You need to know what encoding the character vector is in. If you know it
to be
Dear all,
I have an error message, when I try to convert a zoo object (called
test) to ts (on R 2.4.0, Package zoo version 1.2-1, Windows XP)
test
1994-05-10 1994-06-09 1994-07-09
0.0024943889 0.0024881824 0.0006955831
str(test)
atomic [1:3] 0.002494 0.002488 0.000696
- attr(*,
Try this:
plot(1, xlab = quote(Level is ~ italic(M)))
or
plot(1, xlab = quote(Level ~ is ~ italic(M))
On 11/23/06, Philip Boland [EMAIL PROTECTED] wrote:
Just wondering if it is possible to put something like
The excess level is M
in the xlab position of a plot but where the M is in
Hi
I have a vector x of length n. I am interested in x[1]
being different from the other observations (ie x[-1]).
My null hypothesis is that x[1]
is drawn from a Gaussian distribution of the same
mean as observations x[-1], which are assumed
to be iid Gaussian. The (unknown) variance
of
There is no such thing as an unpaired t-test. A t-test can be a paired,
one sample or two sample t-test. Since you want to compare the sample
against a given mean, you need a one sample t-test. You tried to do a
two sample test. That didn't work because you need at least two
observations in each
Dear R-help community
I am trying to write an R object (data.out) to a file in order to re-access it
later and not have to re-load up the array with data every time. Here is the
form of data.out
data.out - list(lats=seq(88.542, -88.542, length=94),
lons=seq(0, 360-1.875,
Its a bug. Thanks. It will be fixed in the next version of zoo.
In the meantime I will send you a fix offline.
On 11/23/06, Albrecht, Dr. Stefan (AZ Private Equity Partner)
[EMAIL PROTECTED] wrote:
Dear all,
I have an error message, when I try to convert a zoo object (called
test) to ts (on
Hello everybody
thanks for your advice here.
I think I'm getting tangled up.
If I use Thierry's test on iid Gaussian data,
the returned p-value should be uniform(0,1),
right?
OK,
R f - function(x){t.test(x=x[-1],mu=x[1])$p.value}
R hist(replicate(1000,f(rnorm(5
This is very skewed
ONKELINX, Thierry [EMAIL PROTECTED] writes:
There is no such thing as an unpaired t-test. A t-test can be a paired,
one sample or two sample t-test. Since you want to compare the sample
against a given mean, you need a one sample t-test. You tried to do a
two sample test. That didn't work
Robin Hankin [EMAIL PROTECTED] writes:
Hi
I have a vector x of length n. I am interested in x[1]
being different from the other observations (ie x[-1]).
My null hypothesis is that x[1]
is drawn from a Gaussian distribution of the same
mean as observations x[-1], which are assumed
to
On Thu, 23 Nov 2006, ONKELINX, Thierry wrote:
There is no such thing as an unpaired t-test. A t-test can be a paired,
one sample or two sample t-test. Since you want to compare the sample
against a given mean, you need a one sample t-test. You tried to do a
two sample test. That didn't work
On Thu, 23 Nov 2006, Peter Dalgaard wrote:
Robin Hankin [EMAIL PROTECTED] writes:
Hi
I have a vector x of length n. I am interested in x[1]
being different from the other observations (ie x[-1]).
My null hypothesis is that x[1]
is drawn from a Gaussian distribution of the same
mean
23 Nov 2006 14:48:31 +0100, Peter Dalgaard [EMAIL PROTECTED]:
ONKELINX, Thierry [EMAIL PROTECTED] writes:
There is no such thing as an unpaired t-test. A t-test can be a paired,
one sample or two sample t-test. Since you want to compare the sample
against a given mean, you need a one
On Thu, 23 Nov 2006, Jenny Barnes wrote:
Dear R-help community
I am trying to write an R object (data.out) to a file in order to re-access it
later and not have to re-load up the array with data every time. Here is the
form of data.out
data.out - list(lats=seq(88.542, -88.542, length=94),
Patrick Connolly p_connolly at ihug.co.nz writes:
What I'd like to do is avoid the need to make the Month.r files and
have the script pass the month information directly to the function
that a single .r file would call.
?commandArgs
__
Try this:
gannet% cat month.R
x - commandArgs()
print(x[length(x)])
gannet% R --slave --args January month.R
[1] January
On Thu, 23 Nov 2006, Patrick Connolly wrote:
I wish to use R CMD BATCH to run a small R function which reads a text
file and plots a single graph to a PDF file.
Thank you for your response Professor Ripley,
Having tried again your suggestion of load() worked (well - it finished, which
I
assume it meant it worked). However not I am confused as to how I can check it
has worked.
I typed
data.out$data
which called up the data from the file - but I'm not
Hi,
seems as if you want to test if a single subject is a member of a population
from which you have drawn a sample. This question has been addressed by Payne
Jones and Crawford and collaborators. You should have a look at their
articles in case that I interpreted your null-hypothesis and
Hi there,
I have a barplot and the labels at the x-axis are strings, which are
rotated by 90°. But now the sub-title of the barplot is in between these
labels, which does not look very nice...
Could anybody help me finding the parameter-setting to prevent this?
par(mai=c(1.5,1,1,0.6))
On Thu, 23 Nov 2006, Jenny Barnes wrote:
Thank you for your response Professor Ripley,
Having tried again your suggestion of load() worked (well - it finished,
which I
assume it meant it worked). However not I am confused as to how I can check it
has worked.
I typed
data.out$data
which
On Thursday 23 November 2006 15:44, Prof Brian Ripley wrote:
Try this:
gannet% cat month.R
x - commandArgs()
print(x[length(x)])
gannet% R --slave --args January month.R
[1] January
Is the above
R --slave --args January month.R
the preferred way of using it?
I tend to use
R
Dear R-users,
we are using library(snow) for computation on a linux cluster with RMPI.
We have a problem with clusterEvalQ: after launching clusterEvalQ it seems
loading the required library on each node but if we type a function
belonging to the loaded package R doesn't find it.
library(snow)
Dear all,
I'm indirectly faced with the fact that setting the 'tsp' attribute of
an object modifies its class definition:
class( structure(1:2, tsp=c(1,2,1), class=c(myts,ts)) )
[1] ts myts
In general, this is of really little (ok, I admit: totally no)
interest for me because 'myts' class is
On Thu, 23 Nov 2006, Ramon Diaz-Uriarte wrote:
On Thursday 23 November 2006 15:44, Prof Brian Ripley wrote:
Try this:
gannet% cat month.R
x - commandArgs()
print(x[length(x)])
gannet% R --slave --args January month.R
[1] January
Is the above
R --slave --args January month.R
the
Hi all,
I want to apply lasso method in AFT model. can anybody help me how to get
lasso estimate using AFT model.
Hossain
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On Thu, 23 Nov 2006, Antonio, Fabio Di Narzo wrote:
Dear all,
I'm indirectly faced with the fact that setting the 'tsp' attribute of
an object modifies its class definition:
class( structure(1:2, tsp=c(1,2,1), class=c(myts,ts)) )
[1] ts myts
In general, this is of really little (ok, I
Jenny Barnes wrote:
Having tried again your suggestion of load() worked (well - it finished,
which I
assume it meant it worked). However not I am confused as to how I can check
it
has worked.
I typed
data.out$data
which called up the data from the file - but I'm not sure if this
Michela Cameletti wrote:
Dear R-users,
we are using library(snow) for computation on a linux cluster with RMPI.
We have a problem with clusterEvalQ: after launching clusterEvalQ it seems
loading the required library on each node but if we type a function
belonging to the loaded package R
Thank you Barry for your time in responding!
I think that will really help - the difference between attach and load were not
clear to me before your reply! Also I did not know about rm() - thank you for
the detail, I know you took longer than you had planned but I do appreciate it,
For those
2006/11/23, Prof Brian Ripley [EMAIL PROTECTED]:
On Thu, 23 Nov 2006, Antonio, Fabio Di Narzo wrote:
Dear all,
I'm indirectly faced with the fact that setting the 'tsp' attribute of
an object modifies its class definition:
class( structure(1:2, tsp=c(1,2,1), class=c(myts,ts)) )
[1] ts
On 11/23/06, Antonio, Fabio Di Narzo [EMAIL PROTECTED] wrote:
2006/11/23, Prof Brian Ripley [EMAIL PROTECTED]:
On Thu, 23 Nov 2006, Antonio, Fabio Di Narzo wrote:
Dear all,
I'm indirectly faced with the fact that setting the 'tsp' attribute of
an object modifies its class definition:
Hi
barplot(data, las=2, ylim = c(0,plotMax+1), ylab = Percentage,
main = filename, sub = subtitle)
Error in barplot.default(data, las = 2, ylim = c(0, plotMax + 1),
ylab = Percentage, :
'height' must be a vector or a matrix
Your code gives me an error, as I do not have data
Dear All
I am trying to convert from the type expression to the type
numeric. The following works:
x - expression(6.2)
as.numeric(as.character(x))
[1] 6.2
However, the following does not work:
x - expression(62/100)
as.numeric(as.character(x))
[1] NA
Warning message:
NAs introduced by
On 23 November 2006 at 16:08, Michela Cameletti wrote:
| Dear R-users,
| we are using library(snow) for computation on a linux cluster with RMPI.
| We have a problem with clusterEvalQ: after launching clusterEvalQ it seems
| loading the required library on each node but if we type a function
|
Paul Smith wrote:
x - expression(62/100)
as.numeric(as.character(x))
[1] NA
Warning message:
NAs introduced by coercion
Any idea about how to deal with the second case?
eval-uate the expression:
x - expression(62/100)
eval(x)
[1] 0.62
Barry
Hi,
I'm trying to teach myself R, and by the way, re-learning statistics using
Crawley's Statistics: an introduction using R.
I've reached the regression chapter, and when it deals with non-linear
regresion using the nls library I face the following problem:
I follow the steps---
On 11/23/06, Barry Rowlingson [EMAIL PROTECTED] wrote:
x - expression(62/100)
as.numeric(as.character(x))
[1] NA
Warning message:
NAs introduced by coercion
Any idea about how to deal with the second case?
eval-uate the expression:
x - expression(62/100)
eval(x)
[1]
On 11/23/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 11/23/06, Antonio, Fabio Di Narzo [EMAIL PROTECTED] wrote:
2006/11/23, Prof Brian Ripley [EMAIL PROTECTED]:
On Thu, 23 Nov 2006, Antonio, Fabio Di Narzo wrote:
Dear all,
I'm indirectly faced with the fact that setting the
UseRs,
We are using projection matrices in demographic analyses, and one
technique is to calculate partial derivatives of a matrix with respect
to a variable appearing in one or more of its elements. For example,
consider the matrix A:
| a*b a*c |
| d d |
If I'm not mistaken, the
Hi all,
I have a Date, that has been converted to a number that represent the
count of seconds since year 1970, how do i convert it to a date ?
Example :
Limite_x-c(1131408000,1163548800)
is(limite_x)
[1] numeric vector
But these numbers are dates, did R provide something that give
Paul Smith [EMAIL PROTECTED] writes:
Dear All
I am trying to convert from the type expression to the type
numeric. The following works:
x - expression(6.2)
as.numeric(as.character(x))
[1] 6.2
However, the following does not work:
x - expression(62/100)
Try the Ryacas package:
library(Ryacas)
a - Sym(a); b - Sym(b); c - Sym(c); d - Sym(d)
M - List(List(a*b, a*c), List(d, d))
deriv(M, a)
expression(list(list(b, c), list(0, 0)))
On 11/23/06, Ron E. VanNimwegen [EMAIL PROTECTED] wrote:
UseRs,
We are using projection matrices in demographic
On 23 Nov 2006 18:20:17 +0100, Peter Dalgaard [EMAIL PROTECTED] wrote:
I am trying to convert from the type expression to the type
numeric. The following works:
x - expression(6.2)
as.numeric(as.character(x))
[1] 6.2
However, the following does not work:
x -
COMTE Guillaume [EMAIL PROTECTED] writes:
Hi all,
I have a Date, that has been converted to a number that represent the
count of seconds since year 1970, how do i convert it to a date ?
Example :
Limite_x-c(1131408000,1163548800)
is(limite_x)
[1] numeric vector
Not really:
2006/11/23, Gabor Grothendieck [EMAIL PROTECTED]:
On 11/23/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 11/23/06, Antonio, Fabio Di Narzo [EMAIL PROTECTED] wrote:
2006/11/23, Prof Brian Ripley [EMAIL PROTECTED]:
On Thu, 23 Nov 2006, Antonio, Fabio Di Narzo wrote:
Dear all,
On 11/23/06, Paul Smith [EMAIL PROTECTED] wrote:
On 23 Nov 2006 18:20:17 +0100, Peter Dalgaard [EMAIL PROTECTED] wrote:
I am trying to convert from the type expression to the type
numeric. The following works:
x - expression(6.2)
as.numeric(as.character(x))
[1] 6.2
Thanks, Richard
Years ago, I recall reading a tech report on an elegant system
in APL for doing (M)ANOVA via a series of successive projections of
the response(s) on the series of (successively orthogonalized)
basis vectors of the design matrix. (Written by RMH) Perhaps this was
what you were
Paul Smith [EMAIL PROTECTED] writes:
Thanks, Peter. I did not know about the existence of the command
'eval', in spite of the fact of having searched the Internet for a
solution for my problem.
'eval' seems not working in connection with Ryacas:
library(Ryacas)
x - yacas(2/3*5/7)
x
Limite_x-c(1131408000,1163548800)
structure(Limite_x, class=c(POSIXt,POSIXct))
[1] 2005-11-07 19:00:00 Eastern Standard Time 2006-11-14 19:00:00
Eastern Standard Time
On 11/23/06, COMTE Guillaume [EMAIL PROTECTED] wrote:
Hi all,
I have a Date, that has been converted to a number that
Also note that Ryacas provides an Eval which has a yacas method
that simplifies writing this:
library(Ryacas)
Eval(yacas(1/2))
See ?Eval
On 11/23/06, Gabor Grothendieck [EMAIL PROTECTED] wrote:
On 11/23/06, Paul Smith [EMAIL PROTECTED] wrote:
On 23 Nov 2006 18:20:17 +0100, Peter Dalgaard
On Sat, Nov 11, 2006 at 05:22:30AM +, Prof Brian Ripley wrote:
I don't see how this code can work at all. '[-.data.frame' does not
accept three arguments, e.g.
women[1,2,3] - 17
Error in `[-.data.frame`(`*tmp*`, 1, 2, 3, value = 17) :
unused argument(s) (3)
If df is in fact
Dear All
I am doing the following:
x - yacas(3/2)
for (i in 2:400)
+x - yacas(paste(x,*,x))
x
expression(Inf^1.260864167e+117/Inf^6.304320836e+116)
Eval(x)
[1] NaN
No luck this way. However, I am successful with
y - yacas((3/2)^400)
y
hi
im a bioinformatics student as i have never had any previous programming
experience
i need help
this is the question i need to answer:
Random walk model
we want to model a random walk where you take a step to the left with
probability p
and one to the right with probability 1-p. Now
Hello,
I have another question on accessing arrays:
| a- array(0, c(1, 100, 10))
| b - c(1,4)
| for (i in 1:1) { for (j in 1:100) { a[i,j,b] - (1:10)[b] }}
Is there a way to replace the nested for loops by a faster operation?
I tried to use `a[1:1, 1:100, b] - (1:10)[b]' but that
Paul Smith [EMAIL PROTECTED] writes:
Dear All
I am doing the following:
x - yacas(3/2)
for (i in 2:400)
+x - yacas(paste(x,*,x))
x
expression(Inf^1.260864167e+117/Inf^6.304320836e+116)
Eval(x)
[1] NaN
No luck this way. However, I am successful with
y - yacas((3/2)^400)
There is likely some limitation in the Ryacas interface that needs to
be addressed by the Ryacas developers. yacas itself can support very large
numbers so just use yacas directly.
Aside from that I, as mentioned previously in this thread, yacas returns a
yacas object and that is a complex
On 23 Nov 2006 20:17:15 +0100, Peter Dalgaard [EMAIL PROTECTED] wrote:
I am doing the following:
x - yacas(3/2)
for (i in 2:400)
+x - yacas(paste(x,*,x))
x
expression(Inf^1.260864167e+117/Inf^6.304320836e+116)
Eval(x)
[1] NaN
No luck this way. However, I am successful
If Ryacas/Yacas cannot multiply fractions with simultaenously very
large numerators and denominators, what else should I use?
Did you try package gmp ?
Hth
Detlef
Thanks in advnace,
Paul
__
R-help@stat.math.ethz.ch mailing list
consider p as random effect with 5 levels, what is difference between these
two models?
p5.random.p - lmer(Y
~p+(1|p),data=p5,family=binomial,control=list(usePQL=FALSE,msV=1))
p5.random.p1 - lmer(Y
~1+(1|p),data=p5,family=binomial,control=list(usePQL=FALSE,msV=1))
thanks,
Aimin Yan
Hello.
As advised by Mick Crawley in his book on S+, I'm trying to use the lme
function to examine a linear relationship between two variables measured at
60 locations in 12 sites, while taking account of any spatial
autocorrelation (i.e. similarity in variation between the two variables that
is
Hi all,
I want to apply lasso in AFT model. Is there any R function available, I can
get lasso estimate.
Thanks
Rinco
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The word ``help'' does NOT constitute an informative subject line.
cheers,
Rolf Turner
[EMAIL PROTECTED]
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
consider p as random effect with 5 levels, what is difference between these
two models?
p5.random.p - lmer(Y
~p+(1|p),data=p5,family=binomial,control=list(usePQL=FALSE,msV=1))
p5.random.p1 - lmer(Y
~1+(1|p),data=p5,family=binomial,control=list(usePQL=FALSE,msV=1))
in addtion, I try these
p factor have 5 levels
aa factor have 19 levels.
totally it should have 95 combinations.
but I just find there are 92 combinations.
Does anyone know how to code to find what combinations are missed?
Thanks,
Aimin
__
R-help@stat.math.ethz.ch mailing
Also just to be clear this does not mean that you cannot use very
large numbers. It means that you need to keep them on the yacas
side and move them over right at the end and at that point they must
not be so large that R itself cannot handle them.
For example, this works because all the
Hello again,
And excuse me for not replying in real time. I am subscribed in digest
mode and the data that generated my question are in a computer not
connected to the Internet.
Douglas Bates replied to my original mail and he requested the
following:
Can you be more specific about which
Dear list,
I am having troubles increasing the fontize when plotting a
variogram{gstat} and its model (vgm) with plot and using jpeg(). Also
the resolution in the jpeg call does not work. I am using R2.4 on
Mandriva 10.2 linux.
I can change fontsize with cex.axis in a normal plot, so I presume
comments in line
Rick Xu wrote:
Dear All,
I have loaded package(tseries), but when I run
predict.garch(...) R tells me could not find function
predict.garch, however ?predict.garch shows me
The secret is methods dispatch.
predict
function (object, ...)
UseMethod(predict)
I haven't seen a reply to this post, so I will offer some comments
even though I do not recall any previous exposure to social network
analysis or the 'sna' package. I'm sorry I can't answer your question
directly. However, if you wouldn't mind posting a minimal example of
something
Here is a simple function that allow you to load the objects stored by
save() into an evironment (to avoid loading them into the global
workspace):
loadToEnv - function(...) {
env - new.env()
load(..., env=env)
env
}
x - 1:10
save(file=foo.xdr, x, letters, R.version)
objects -
On Thu, 23-Nov-2006 at 02:44PM +, Prof Brian Ripley wrote:
| Try this:
|
| gannet% cat month.R
| x - commandArgs()
| print(x[length(x)])
|
| gannet% R --slave --args January month.R
| [1] January
That's exactly what I needed. Thank you Brian for a concise and
thorough answer.
--
Dear list
I need to see the code behind a function. I used to be able to see the
code behind a function by typing e.g. mean(). Now I get the error message:
Error in mean.default() : argument x is missing, with no default. Please
advise.
Regards
Lize van der Merwe
--
This e-mail
Hi,
Just type mean.default without the () and the code of the function
will be displayed.
Wee-Jin
On 24 Nov 2006, at 06:31, Lize van der Merwe wrote:
Dear list
I need to see the code behind a function. I used to be able to
see the
code behind a function by typing e.g. mean(). Now
When I was running the function latex() I got an error about a not found
object : n.rgroup ...
I searched the archive of this (great!) list and found a solution (
http://tolstoy.newcastle.edu.au/R/e2/help/06/10/3995.html) :
source('http://biostat.mc.vanderbilt.edu/tmp/getLatestSource.s');
Hi
maybe
?aggregate
or
?merge
can help you.
cheers
Petr
On 23 Nov 2006 at 15:18, David Kaplan wrote:
Date sent: Thu, 23 Nov 2006 15:18:07 -0600
From: David Kaplan [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Subject:[R]
On Fri, 24 Nov 2006 [EMAIL PROTECTED] wrote:
Dear list,
I am having troubles increasing the fontize when plotting a
variogram{gstat} and its model (vgm) with plot and using jpeg(). Also
the resolution in the jpeg call does not work. I am using R2.4 on
Mandriva 10.2 linux.
I can
plotting variograms in gstat is done through xyplot in lattice; you'll
find where it gets it's defaults by
library(lattice)
trellis.par.get()
?trellis.par.set
--
Edzer
[EMAIL PROTECTED] wrote:
Dear list,
I am having troubles increasing the fontize when plotting a
variogram{gstat} and its
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