Tao Shi wrote:
Hi list,I apologize if you see funny fonts, b/c I'm using the new
Windows Live Hotmail and don't know how to turn off the rich text
mode.I have successfully built and installed a R package in
windowsXP for R-2.5.1. But when I tried to create a .zip file so I
can use
Hi List,
How would I go about best identifying the variables contributing most to
the specific clusters?
eg using either aglomerative or partitioning methods, but with mixed
variables (ie including categorical) eg:
factor(as.integer(runif(min=1, max=5,nrow(USArrests-t1
Hi, I don't know if is the more elegant way, but:
X-c(1,2,3,4,5)
X - c(X[1], 0, X[2:5])
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O
On 27/07/07, Nair, Murlidharan T [EMAIL PROTECTED] wrote:
Can I insert an element in an array at a particular position without
Can I insert an element in an array at a particular position without
destroying the already existing element?
X-c(1,2,3,4,5)
I want to insert an element between 1 and 2.
Thanks ../Murli
[[alternative HTML version deleted]]
__
Hi,
I have trouble with the heatmap function (package stats). The row labels
are wrongly ordered and don't correspond to the Rowv dendrogram. I know
there is a bug with the heatmap fonction. Emmanuel Paradis
(http://tolstoy.newcastle.edu.au/R/e2/help/07/05/16227.html )suggested a
modification
results=()#character()
myVariableNames=names(x.val)
results[length(myVariableNames)]-NA
for (i in myVariableNames){
results[i]-names(x.val[[i]])# this does not work it returns a
NULL (how can i convert this to x.val$somevalue ? )
}
On 7/27/07, Allan Kamau [EMAIL PROTECTED] wrote:
Hi
Thanks Max,
It looks as though that did actually solve the problem! It is a bit
of a mystery to me because I think that the 151x150 matrix can't be
that big, unless its elements are in turn huge datastructures. (?)
I am now calling randomForest() like this:
rf -
I compiled the newest R version on a Redhat Linux (uname -a =
Linux .cam.ac.uk 2.4.21-50.ELsmp #1 SMP Tue May 8 17:18:29 EDT 2007
i686 i686 i386 GNU/Linux) with 4GB of physical memory. The step when
the whole script crashed is within the randomForest() routine, I do
know that because I
Greetings to the group,
I would like to know if some one could help me with plot 3-d column
graph of a matrix (3-d column graph in Excel).
Many thanks in advance.
Regards,
Dong
__
R-help@stat.math.ethz.ch mailing list
Use get() instead of eval().
And, probably, some arguments are missing in call to paste().
Maybe, extension?
That is,
for(i in test)
write.table(get(i),file=paste(i,txt,sep=.),row.names=FALSE,sep=\t)
If you want file names matching exactly names of your matrices, and being
without
I am not sure this might help, but you are perhaps lookign at variable
selection. There is a 2006 JASA paper by Raftery and Dean which may
help.
Many thanks,
Ranjan
On Fri, 27 Jul 2007 17:32:02 +1000 [EMAIL PROTECTED] wrote:
Hi List,
How would I go about best identifying the variables
R-help,
I have a character vector whose elements are the names of matrixes.
Something like this:
test - ls(pattern=Oki)
[1] aaOkiaOki bOki c1Okic2Okic3Oki
cOki dOki eOki fOki gprsOki hOki iOki
[14] jOki kOki lOki mOki
Hi All,
I am having difficulties finding a way to find a substitute to the command
names(v.val$PR14) so that I could generate the command on the fly for all
PR14 to PR200 (please see the previous discussion below to understand what the
object x.val contains) . I have tried the following
You probably got some missing or undefined values.
Either eyeball the data or use sum(is.na(x)), sum(is.nan(x)),
sum(is.infinite(x)) to find out if you have such data. You may want to
use which() to find out where they are.
Regards, Adai
Bricklemyer, Ross S wrote:
I am attempting to run
Graphs that rely on 3-d effects tend to distort the data rather than enlighten
the viewer. If your goal is to distort the data (which I doubt), then most of
us don't want to help. On the other hand, if you really do want to enlighten
the viewer (even if that is just you), then tell us what
see scatterplot3d package
Justin BEM
BP 1917 Yaoundm
Tml (237) 99597295
(237) 22040246
- Message d'origine
De : Dong GUO ³¢Ö [EMAIL PROTECTED]
Y : [EMAIL PROTECTED]
Envoym le : Vendredi, 27 Juillet 2007, 15h45mn 15s
Objet : [R] plot
Greetings to the group,
I would like to
Hello R-listers,
I'm having trouble accessing sub objects (attributes?), e.g.,
x$silinfo$avg.width using the /get() /command; I'm using/ get()/ in a
loop as illustrated in the following code:
#FIRST MAKE CLUSTERS of VARYING k
/for (i in 1:300){
assign(paste(x.,i,sep=),pam(x,i)) #WORKS
'get' tries to retrieve the object given by the character string. The
error message says that object can not be found. You actually have to
'evaluate' the character string. See the example below:
x - data.frame(a=1:10, b=11:20)
x$a
[1] 1 2 3 4 5 6 7 8 9 10
z - 'x$a'
get(z)
Error
filame uyaco filams0704 at yahoo.com writes:
hi!
I would like to ask help how to generate numbers from g-and-h distribution.
This distribution is like
normal distribution but span more of the kurtosis and skewness plane. Has R
any package on how to generate
them?
Someone else
Can you really see much of the data in a 26*31 3d barplot? It seems like most
info would be hidden behind the first few rows and it would be so cluttered
that you would not be able to make out much of anything from it.
Why not try a line plot instead (year as the x axis, each region a
Warning: I am a complete newbie to R. I have read ISwR, but I am still
finding myself completely stuck on some simple concepts.
I have tried everything I can think of to solve this one, and finally
decided that enough was enough and I need a pointer to a solution.
I have the following summary
On Fri, 2007-07-27 at 15:52 -0600, D. R. Evans wrote:
Warning: I am a complete newbie to R. I have read ISwR, but I am still
finding myself completely stuck on some simple concepts.
I have tried everything I can think of to solve this one, and finally
decided that enough was enough and I
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