Thank, Jerome
The question is if this generalized inverse can make
their product to be identity matrix?
- Original Message -
From: Jerome Asselin [EMAIL PROTECTED]
To: Feng Zhang [EMAIL PROTECTED]; R-Help
[EMAIL PROTECTED]
Sent: Thursday, August 14, 2003 11:52 AM
Subject: Re: [R] How to
As already pointed out ZZ' is not invertible. That is,
it is not one-to-one and onto. What we can do is restrict the domain
and range of ZZ' to the range of ZZ' or equivalently to the
range of Z. In operational terms this
means if y = ZZ'x then we only consider y's expressable as
y = Zu for
No. If B is singular, it's impossible to find a matrix A such that A%*%B
be the identity matrix (unless you can find a number x such that x*0=1).
Cheers,
Jerome
On August 14, 2003 10:02 am, Feng Zhang wrote:
Thank, Jerome
The question is if this generalized inverse can make
their product
Singular matrices are not invertible. However you can calculate the
generalized inverse with the function ginv() from package MASS.
HTH,
Jerome
On August 14, 2003 09:24 am, Feng Zhang wrote:
Dear R-listers,
I have a dxr matrix Z, where d r.
And the product Z*Z' is a singular square
