Hi Sam,

Have a look at the function prop.part: it is the working function of consensus and other similar functions.

EP

Sam Brown <s_d_j_br...@hotmail.com> a écrit :

Hello one and all

I'm wondering if there is any way of obtaining the consensus frequencies of nodes in majority-rule consensus trees where p=0.5.

i.e. given:


t1 <- "((t4,t8),((t10,((t2,t5),t3)),((t6,t9),(t1,t7))));"
t2 <- "((t4,t8),((t10,((t2,t5),t3)),((t6,t9),(t1,t7))));"
t3 <- "((t4,t8),((t10,((t2,t5),t3)),((t6,t9),(t1,t7))));"
t4 <- "((t2,t10),((t5,((t4,t3),t8)),((t6,t9),(t1,t7))));"
t5 <- "((t10,t5),((t8,((t2,t4),t3)),((t6,t9),(t1,t7))));"
t6 <- "((t4,t10),((t8,((t3,t5),t2)),((t6,t9),(t1,t7))));"
t7 <- "((t4,t3),((t5,((t2,t10),t8)),((t6,t9),(t1,t7))));"
t8 <- "((t4,t2),((t10,((t8,t5),t3)),((t6,t9),(t1,t7))));"
t9 <- "((t4,t3),((t8,((t10,t5),t2)),((t6,t9),(t1,t7))));"
t10 <- "((t10,t8),((t4,((t2,t3),t5)),((t6,t9),(t1,t7))));"

tr<-read.tree(text=c(t1,t2,t3,t4,t5,t6,t7,t8,t9,t10))

conTR<-consensus(tr, p=0.5)
plot(conTR)



The node (t3,t2,t5) will have a consensus frequency of 0.5 (50%) and the three nodes ((t6,t9),(t1,t7)) will each have a frequency of 1 (100%).

Are there any quick ways of getting this information?

Thanks for any help/pointers

Sam



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