[R-sig-phylo] randomizing clades within a node

2012-01-13 Thread Juan Antonio Balbuena

  
  
Hello

I would very much appreciate if someone can help me with this one. I
wish to compare two additive trees that are identical for some but
not all the clades.

So I use rtree of the ape package with, say, 10 tips to generate
tree "A". Then I wish to modify "A" to get tree "B" by randomizing
the clades and patristic distances in a given number of nodes. If
the number of nodes is, for instance, three, the 3 nodes furthest
apart from the origin will be randomized. Then "A" and "B" will be
compared. The whole procedure needs to be carried out a large number
of times (10,000). 

Any help would be much appreciated. 

Juan A. Balbuena

-- 
  
  
  
Dr. Juan A. Balbuena
  
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Institute of Biodiversity and Evolutionary Biology
  
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of
Valencia
  http://www.uv.es/~balbuena
  
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Box
22085
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Spain
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tel. +34 963 543 658 fax +34 963 543 733
  
  
  
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[R-sig-phylo] Lambda; PIC vs. PGLS

2012-01-13 Thread Karin Schneeberger
Dear all

I am currently analysing a set of traits from different species - let's say 
brain size and body mass - using a tree where branch lengths were set 
artificially (after Graphen) as the length was not available. 

I calculate phylogenetic independent contrasts (PIC) using the package caper 
and the crunch-algorithm. Beforehand, I used the function caic.diagnostic to 
test whether the model is appropriate (which was the case). In the end, this 
provided me with a significant correlation between brain size and body mass. 


I then calculate lambda as a measurement for phylogenetic signal, using  the 
package ape:


data - comparative.data(tree, data, Species)
result - gls(brainsize~bodymass, data = data, correlation = corPagel(value = 
1, phy = tree, fixed = FALSE), method = ML)
summary(result)

Here, lambda was 1, which - as far as I understood - means evolution under 
Brownian motion. I perform a phylogenetic generalised least square (PGLS) 
regression using caper, which includes lambda, as an addition to the PIC 
analysis:

data - comparative.data(tree, data, Species, vcv = TRUE)
Mod1 - pgls(brainsize~bodymass, data = data, lambda = ML)
summary(Mod1)


Surprisingly, lambda here was zero. Furthermore, the correlation between brain 
size and body mass became non-significant. 


I now have two contradiction values for lambda and results from both PIC and 
PGLS that differ dramatically in the way they can be interpreted. How does it 
come that with one method, lambda is zero and with the other lambda is one? And 
in the end, which method should be used, PIC or PGLS, or should both be 
discussed? 


I would be grateful for advice.Thank you very much in advance for your help.

Best regards

Karin Schneeberger
PhD candidate in Ecology and Evolution
[[alternative HTML version deleted]]

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Re: [R-sig-phylo] Lambda; PIC vs. PGLS

2012-01-13 Thread Liam J. Revell

Hi Karin.

gls(...,correlation=corPagel(...,fixed=F),method=ML) and 
pgls(...,lambda=ML) should produce the same result unless one or the 
other is not optimizing properly or unless different bounds on the 
fitted model parameters (in particular, lambda) are used.


To show this to yourself, you can try the following example which 
simulates and then fits the same model using three different functions.


I hope this is helpful. - Liam

set.seed(1)
require(phytools); require(caper); require(nlme); require(geiger)
# simulate tree
tree-pbtree(n=100,scale=1)
# simulate x under BM
x-fastBM(tree)
# simulate y  residual error under the lambda model
y-0.4*x+fastBM(lambdaTree(tree,0.7),sig2=0.5)
data-as.data.frame(cbind(x,y))
data-cbind(names(x),data)
colnames(data)-c(Species,x,y)
# fit using nlme:gls
r1-gls(y~x,data=data,correlation=corPagel(0.5,tree,fixed=FALSE),method=ML)
# fit using caper:pgls
r2-pgls(y~x,data=comparative.data(tree,data,Species),lambda=ML)
# fit using phytools:phyl.resid
r3-phyl.resid(tree,x,y,method=lambda)

--
Liam J. Revell
University of Massachusetts Boston
web: http://faculty.umb.edu/liam.revell/
email: liam.rev...@umb.edu
blog: http://phytools.blogspot.com

On 1/13/2012 6:04 AM, Karin Schneeberger wrote:

Dear all

I am currently analysing a set of traits from different species - let's say 
brain size and body mass - using a tree where branch lengths were set 
artificially (after Graphen) as the length was not available.

I calculate phylogenetic independent contrasts (PIC) using the package caper 
and the crunch-algorithm. Beforehand, I used the function caic.diagnostic to test whether 
the model is appropriate (which was the case). In the end, this provided me with a 
significant correlation between brain size and body mass.


I then calculate lambda as a measurement for phylogenetic signal, using  the package 
ape:


data- comparative.data(tree, data, Species)
result- gls(brainsize~bodymass, data = data, correlation = corPagel(value = 1, phy = 
tree, fixed = FALSE), method = ML)
summary(result)

Here, lambda was 1, which - as far as I understood - means evolution under Brownian 
motion. I perform a phylogenetic generalised least square (PGLS) regression using 
caper, which includes lambda, as an addition to the PIC analysis:

data- comparative.data(tree, data, Species, vcv = TRUE)
Mod1- pgls(brainsize~bodymass, data = data, lambda = ML)
summary(Mod1)


Surprisingly, lambda here was zero. Furthermore, the correlation between brain 
size and body mass became non-significant.


I now have two contradiction values for lambda and results from both PIC and 
PGLS that differ dramatically in the way they can be interpreted. How does it 
come that with one method, lambda is zero and with the other lambda is one? And 
in the end, which method should be used, PIC or PGLS, or should both be 
discussed?


I would be grateful for advice.Thank you very much in advance for your help.

Best regards

Karin Schneeberger
PhD candidate in Ecology and Evolution
[[alternative HTML version deleted]]




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