The comment here is clearly wrong, since there is no division by two.
I think that the code is wrong, because this results in not starting
runners when it should start runners. Am I misanalyzing?
if (runners.isEmpty() || (queue.remainingCapacity() queue.size() // queue
// is
//
On Wed, May 29, 2013 at 11:29 PM, Benson Margulies bimargul...@gmail.comwrote:
The comment here is clearly wrong, since there is no division by two.
I think that the code is wrong, because this results in not starting
runners when it should start runners. Am I misanalyzing?
if
Ah. So now I have to find some other explanation of why it never
creates more than one thread, even when I make a very deep queue and
specify 6 threads.
On Wed, May 29, 2013 at 2:25 PM, Shalin Shekhar Mangar
shalinman...@gmail.com wrote:
On Wed, May 29, 2013 at 11:29 PM, Benson Margulies
I now understand the algorithm, but I don't understand why is the way it is.
Consider one of these objects configure with a handful of threads and
a pretty big queue.
When the first request comes in, the object creates one runner. It
then won't create a second runner until the Q reaches
