Carlo -- how do you get in touch with the BerkeleyDB folks? I've found and
fixed a couple issues with their SQLite build and have found no better
option that to post it on their "forum" and hope someone finds it.
Example I posted a few weeks ago with no response:
To close this thread, it looks like this issue is about a sqlite bug
which was fixed last year:
http://www2.sqlite.org/cgi/src/info/7daa687340e47597
Applying the changes described there to the BDB/SQLite code fixed the
issue I was experiencing.
Thanks for all the help,
Minollo
ven says a
lot about anticipated traffic volume.
>/-Original Message- />/From: sqlite-users [mailto:sqlite-users- />/bounces at mailinglists.sqlite.org
<http://mailinglists.sqlite.org/cgi-bin/mailman/listinfo/sqlite-users>]
On Behalf Of Charles Leifer />/Sent: T
sers-
>boun...@mailinglists.sqlite.org] On Behalf Of Charles Leifer
>Sent: Tuesday, 23 July, 2019 20:08
>To: SQLite mailing list
>Subject: Re: [sqlite] Seg fault using json_each() subquery
>
>Partial traceback (bdb 18.1.32):
>
>Program received signal SIGSEGV, Segmentation fa
Partial traceback (bdb 18.1.32):
Program received signal SIGSEGV, Segmentation fault.
0x7798e560 in jsonEachColumn () from ./lib/libdb_sql-18.1.so
(gdb) bt full
#0 0x7798e560 in jsonEachColumn () from ./lib/libdb_sql-18.1.so
No symbol table info available.
#1 0x779b29b6
I'm using sqlite with BDB as the persistence store; if you can't
reproduce it (same sqlite version), I suppose it means it's a BerkeleyDB
issue, and I'll follow up with them.
Thanks!
On 7/23/2019 12:01, Richard Hipp wrote:
Unable to reproduce. Are you sure you are sending the correct script?
Unable to reproduce. Are you sure you are sending the correct script?
What operating system are you running on? How did you compile
SQLite?
On 7/23/19, Carlo Innocenti wrote:
> I have a segmentation fault which happens when trying to run a subquery
> based on json_each() if the argument is
I have a segmentation fault which happens when trying to run a subquery
based on json_each() if the argument is the value of an outer
json_each() row:
CREATE TABLE mimmo (key TEXT PRIMARY KEY, value TEXT, valueJson
TEXT, blockNo INTEGER, txnNo INTEGER, metadata TEXT);
INSER INTO mimmo
8 matches
Mail list logo