ObjectDecorator does not implement Iterator or
ArrayAccess. maybe property_exists can do
On Feb 4, 5:09 pm, Mark Smith marksmith5...@jungle-monkey.com wrote:
That returns a fatal exception: Call to undefined method
sfOutputEscaperObjectDecorator::offsetExists()
The only static methods I can
)
A quick search through the library code reveals that this method
exists on an IteratorDecorator and an ArrayDecorator, but not an
ObjectDecorator...
On Feb 4, 4:44 am, ken marfillas...@gmail.com wrote:
sfOutputEscaperObjectDecorator::offsetExists
On Feb 4, 12:38 am, Mark Smith marksmith5
Hi,
I am trying to implement file size validation for an upload field on a
form.
For security / performance the php.ini post_max_size config setting is
set to 8 mb.
Now I want to limit the file size upload to about 1 mb. I am using the
built in sfValidatorFile:
$this-setValidator(file, new
Hi,
Is it possible to define a custom 500 error page for a specific
action?
Thanks
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Yes but that error message will be used for every module and every
action.
I need to override this and use a specific 500 error page for a
specific action.
On Jan 7, 12:42 pm, chrisyue blizzch...@gmail.com wrote:
yes
you can custom 500 in apps/APPNAME/config/error/error.html.php
Mark Smith
On Jan 7, 2:05 pm, Eno symb...@gmail.com wrote:
On Thu, 7 Jan 2010, Mark Smith wrote:
Yes but that error message will be used for every module and every
action.
I need to override this and use a specific 500 error page for a
specific action.
Doesn't really make sense since the error
customize
them:http://www.symfony-project.org/forms/1_2/en/02-Form-Validation#chapte...
On Mon, 2009-11-02 at 08:58 -0800, Mark Smith wrote:
Is it possible to customise the error message coming from an sfForm so
that the contents of the validated field don't get spat back out?
I.e
Is it possible to customise the error message coming from an sfForm so
that the contents of the validated field don't get spat back out?
I.e. at the moment the getMessage() function is returning:
ID [abc is not an integer.]
But I would rather have
ID is not an integer.
Thanks for any help
On Oct 19, 3:47 am, Eno symb...@gmail.com wrote:
On Fri, 16 Oct 2009, Mark Smith wrote:
However it all breaks the moment a user has more than one page open:
If while that second screen is open a new customer is selected in
another window the action will pick up the new id from session
On Oct 19, 1:52 pm, Eno symb...@gmail.com wrote:
On Mon, 19 Oct 2009, Mark Smith wrote:
Why would a user be logged in more than once at the same time?
It's pretty common for users to have multiple tabs or windows open.
Sure, but not with different user IDs...
Never said thats what
am, Gareth McCumskey gmccums...@gmail.com wrote:
http is a stateless protocol so no language can manage states. We fake
states by using session variables, cookies, etc. Symfony has loads of
session/cookie management features.
On Thu, Oct 15, 2009 at 4:48 PM, Mark Smith marksmith5...@jungle
a better description of what you're after, some kind of use case
perhaps, might better help people to answer the question?
On Fri, Oct 16, 2009 at 10:04 AM, Mark Smith
marksmith5...@jungle-monkey.com wrote:
Session is no good, as if the user has multiple windows open they
could
window? Something like
$this-getUser()-setAttribute($window_name.$cust_id, $default, $value);
On Fri, Oct 16, 2009 at 12:44 PM, Mark Smith
marksmith5...@jungle-monkey.com wrote:
Ok, as a simple example currently one of my screens might select a
customer and store this id in session
, 2009 at 1:14 PM, Mark Smith marksmith5...@jungle-monkey.com
wrote:
I like that idea a lot.
Is there already a key associated with each window that I can use, or
would I need to manually create a key and embed it on the page and
repost it myself?
On Oct 16, 11:52 am, Gareth McCumskey
Does symfony provide any mechanisms for managing page state?
Thanks
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I am working on a project using Symfony 1.2.0
In my action I have instantiated an sfForm.
I have the following line in the template: ?php echo $myForm[$myForm-
getCSRFFieldName()]; ?
That is outputting the following: input id=myForm__csrf_token
type=hidden name=myForm[_csrf_token]/
As you can
a csrf secret in your settings.yml ?
alecs
On Mon, Oct 12, 2009 at 6:11 PM, Mark Smith marksmith5...@jungle-monkey.com
wrote:
I am working on a project using Symfony 1.2.0
In my action I have instantiated an sfForm.
I have the following line in the template: ?php echo $myForm[$myForm
Symfony seems to implement forms in such a way that it uses tables for
html layout. Everything I have read to say this is incredibly bad web
design practice. It seems like an odd decision for such a well thought
out framework.
Is the only way to override this behavior to access the form field
Hi,
I am contructing a text area widget inside the configure method of my
form like this:
$this-setWidget(Notes, new sfWidgetFormTextarea(array(),array
('value'=$this-entity-Notes)));
In the template when I try to print out the widget like this:
?php echo $form['Notes']; ?
The resulting
Is that good practise to do with javascript that references page
specific element ids?
On Jun 1, 5:13 pm, Gábor Fási maerl...@gmail.com wrote:
Put it in the global js folder, and use the modules view.yml to
include it in the templates that need it.
On Mon, Jun 1, 2009 at 18:01, Mark Smith
If I am writing some page specific javascript where should I put it?
The way I see it I have 3 options:
1) Embed it in the page template (feels very hacky)
2) Stick it in a global .js and load it every time regardless. (could
cause problems and isn't really scalable)
3) Put it in its own .js
I have some of my own configuration that I will be reading from custom
yaml files.
At the moment I am reading them in using sfYaml::load, it works well,
but I get the feeling this is bad, because the yaml file will be
parsed each and every time I call the page.
Is there a mechanism in place to
I don't want to use my layout for one of my actions. I am doing $this-
setLayout(false) in the action. And that has stopped it from parsing
layout.php
However all my style sheets and javascripts are still being added.
How do I stop this?
Thanks for any help.
.
There might be a better way but it's hard to tell what you're trying
to accomplish from your email.
On Apr 29, 2009, at 10:02 AM, Mark Smith wrote:
I don't want to use my layout for one of my actions. I am doing $this-
setLayout(false) in the action. And that has stopped it from parsing
So you are saying the only way to change a form field once the object
exists, is to completely rebuild the form?
OK, I'll have to restructure my code a bit, but it seems to work.
Thanks.
On Apr 21, 11:56 am, Bernhard Schussek bschus...@gmail.com wrote:
Hi Mark,
What exactly is it what you
:23 AM, Mark Smith
marksmith5...@jungle-monkey.com wrote:
So you are saying the only way to change a form field once the object
exists, is to completely rebuild the form?
No. The question is _when_ you want to change the form. You can change
the default values any time in the object lifecycle
I can trigger the front end by running php web\index.php
But if I try and specify a module name I get an error:
php web\index.php/Test
Could not open input file: web\index.php/Test
Is there a way to trigger a specific module or action from the command
line?
Thanks
' . DIRECTORY_SEPARATOR
. 'ProjectConfiguration.class.php');
You may need to create a wrapper batch script with the code above that
will then call the module/action you want.
Perhaps someone else can clear up how to do this
On Thu, Apr 9, 2009 at 10:07 AM, Mark Smith marksmith5...@jungle
Hi,
I am having a problem with a custom filter not executing. It works on
my dev machine, but after deploying to another machine I am getting
exceptions thrown. The problem seems to be that one of my custom
filters is not being executed.
The filter is defined correctly in
of it's methods. You should then be able to see in
the log messages in the web debug toolbar if the filter ever get
instantiated.
However, this does sound like a pretty basic error - are you sure you
copied the filter to the second machine?
On 6 Apr 2009, at 11:09, Mark Smith wrote:
Hi
Hi,
I am trying to add an action that just returns a report as raw CSV
data.
Is it possible to bypass the template layer and just set my own
content?
My code looks like this so far:
public function execute($request)
{
$response = $this-getResponse();
$manager=new ReportManager();
Thanks to everyone, your responses where invaluble!
This is what I ended up using:
public function execute($request)
{
$manager=new ReportManager();
$response=$this-getResponse();
$response-setContentType(text/csv);
$response-setHttpHeader('Content-Disposition', 'attachment;
http://iamcam.wordpress.com/2008/01/15/unchecked-checkbox-values/
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Apologies for the double post. I accidentially hit return before I
had finished:
I am reading a dynamic form with a bunch of check boxes on it. It
would make my task so much easier if the unchecked fields got posted
with false or null values.
The common workaround for this is a hidden input
validating that at least one is checked (and
use this as a post validator). I've never implemented something
similar so take my words just as this is the way I'd go and not as
I'm sure this is the best way :-)
On Wed, Feb 18, 2009 at 2:49 PM, Mark Smith
marksmith5...@jungle-monkey.com wrote
I have a dynamic 2d array of checkboxes, and I want to require that at
least one is selected. Trying to write validation rules for this is
proving to be excruciatingly difficult.
The only way I could accomplish this is to override the isValid
function and put in some logic to manually check each
On Wed, Feb 18, 2009 at 1:16 PM, Mark Smith
marksmith5...@jungle-monkey.com wrote:
I have a dynamic 2d array of checkboxes, and I want to require that at
least one is selected. Trying to write validation rules for this is
proving to be excruciatingly difficult.
The only way I could
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