Hi Guys! I've a problem. ( symfony 1.4 )
I've a master/detail form. A person have some contacts ( mail, phone...etc..). The contacts - on the GUI - is in a table under the person form. This list uses ajax. Pop up a modal box ( contact form inside ). By this way the user can create and update. In every contact row's end is a delete button. It have to work without page refresh. But I want to use symfony's built in csrf protecton. The link_to function creates a form ( on the fly ) when the user click... but that HTTP call is a simple post... ... the csrf protection uses HTTP POST and a simple form ( width a token...). So what is the most simple, easiest... way to send that post ( from ) via HTTP XML request??? - Catch the submit event by jquery? - Create a function that creates same form ( js ).. but sending it via ajax??? Any other idea...??... Please help! Tanks! Vikos -- If you want to report a vulnerability issue on symfony, please send it to security at symfony-project.com You received this message because you are subscribed to the Google Groups "symfony users" group. To post to this group, send email to symfony-users@googlegroups.com To unsubscribe from this group, send email to symfony-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/symfony-users?hl=en To unsubscribe from this group, send email to symfony-users+unsubscribegooglegroups.com or reply to this email with the words "REMOVE ME" as the subject.