Hi Guys!

I've a problem.
( symfony 1.4 )

I've a master/detail form. A person have some contacts ( mail,
phone...etc..).

The contacts - on the GUI - is in a table under the person form. This
list uses ajax.
Pop up a modal box ( contact form inside ).
By this way the user can create and update.

In every contact row's end is a delete button. It have to work without
page refresh. But I want to use symfony's built in csrf protecton.

The link_to function creates a form ( on the fly ) when the user
click... but that HTTP call is a simple post...
... the csrf protection uses HTTP POST and a simple form ( width a
token...).


So what is the most simple, easiest... way to send that post ( from )
via HTTP XML request???

- Catch the submit event by jquery?
- Create a function that creates same form ( js ).. but sending it via
ajax???

Any other idea...??...
Please help!


Tanks!

Vikos

-- 
If you want to report a vulnerability issue on symfony, please send it to 
security at symfony-project.com

You received this message because you are subscribed to the Google
Groups "symfony users" group.
To post to this group, send email to symfony-users@googlegroups.com
To unsubscribe from this group, send email to
symfony-users+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/symfony-users?hl=en

To unsubscribe from this group, send email to 
symfony-users+unsubscribegooglegroups.com or reply to this email with the words 
"REMOVE ME" as the subject.

Reply via email to